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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 851. |
21. If i, denotes the number of triangles formedwith n points in a plane no three of which arecollinear and if tn+l-,-36, then n=71[EAM-201321 94) 10 |
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| 852. |
3. Four different angles are marked in four colours. Can you findother angles which are the same as the one marked in red?The Jammu and Kashmir State Board of School Education Jammu/Srinagar |
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Answer» write short note on prokaryotic cell |
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| 853. |
5x^3 +9x^2 + 8x + 20 x+2 |
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Answer» 5x^3+9x^2+8x+20=5x^3+10x^2-x^2-2x+10x+20=5x^2(x+2)-x(x+2)+10(x+2)=(5x^2-x+10)(x+2)by dividing x+2 we will get5x^2-x+10 |
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| 854. |
57. The value of \sqrt{\log _{0} \frac{2}{5}} 4, is |
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| 855. |
1. Convert the following mixed fractions into improper fractions: |
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Answer» 13/4 , 14/5 ,37/7 ,51 /8 is the correct answer of the given question isis znajbwhajxhhkkxnsj osksjwjwi d 13/4 14/5 37/5 51/8 13/4, 14/5, 37/7, 51/8 is its answer |
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| 856. |
3Write six improper fractions with denominator 5. |
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| 857. |
1.Write the mixed and improper fractions represented by the set of pictures.Mixed fraction:Mixed fraction:Improper fraction:Improper fraction:Mixed fraction:Mixed fraction:Improper fraction:Improper fraction:Cuactions One has be |
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Answer» what is your school name if you will tell I will tell the answer a) 1/20 b) 2/10 = 1/5 c) 2/18 = 1/9 d) 1/4 |
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| 858. |
express the following as improper fractions7 3-4 |
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| 859. |
36% of the maximum marks are required to pass a test. A student gets 109 marks and is declared failedby 35 marks. Find the maximum marks. |
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| 860. |
36% of the maximum marks is required to pass a test. A student gets 123 marks and isdeclared fail by 39 marks. Find the maximum marks. |
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| 861. |
ORFind the median of the following frequency distributionClassFrequency1-20 20-30 30-40 40-50 50-60 60-70 70-80 80-90915249819 |
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| 862. |
13. The mean of the following frequency distribution is 57.6 and the totalnumber of observations is 50.Class0-20 20-40 40-60 60-80 80-100 100-120fi12f28Frequency7Find f and f2.nthoats mer minute of 20 |
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Answer» thanks bro |
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| 863. |
terest and simple interest on12000 at 15% pa. for 3 yearsount if ? 30000 is compounded annually for 3 years and the rate of interest being 10% for first year,15% for the second year and 16% for the third4A certain sum was borrowed at 150year |
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| 864. |
(a-b)x + (a + b) y = a2-2ab-H |
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| 865. |
PRs. 5, 12, 000r 2 % Ń.Đ°. 2.5% p.a. 1.25% per half year,n 1 year 6 months 1 years-3 half-years. |
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| 866. |
3. Find the centre of a circle passing through the points (6,-6),(3,-7) and (3,3),nates of the |
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Answer» thank u |
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| 867. |
Find the number of ordered pairs (a, b) from the set A = {1,2,3,4,5) so that the functionf(x)=3+2x2+bx + 10 YxeRis an injective mapping |
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Answer» put the values in equationX=1(1)^3/3+a/2(1)^2+b(1)+101/3+a/2+b+10X=22^3/3+a/2*2^2+2b+108/3+4a/2+2b+10for injective mapping the above two equations should be equalhence 1/3+a/2+b+10=8/3+2a+2b+101/3-8/3=2a+2b-a/2-b-7/3=3a/2-b----1similarly put x=3 and X=4X=33^3/3+a(3)^2/2+3b+109+9/2a+3b+10and X=44^3/3+a(4)^2/2+4b+10equate these two equations9+9/2a+3b+10=64/3+8a+4b 9-64/3=8a-9/2a+4b-3b27-64/3=16-9/2a+b-37/3=7/2a+b----2now solving 1 and 2add the two equations-44/3=5aa=-44/15now put in equation 1-7/3=3*(-44/15)-b-7/3=-44/5-bb=-44/5+7/3b=-132+35/15b=-98/15 |
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| 868. |
3. If the ordered pairs (a,-) and (5, b) belong to {(r, y): y-2 r-31, find the values ofh)(2x+ y, x -y) (8, 3)a and b |
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Answer» Bhai apne khud se banaya |
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| 869. |
\left. \begin{array} { l } { \text { The solution of the equation } 3 x + 7 = 13 \text { is: } } \\ { \text { (a) } 1 } & { \text { (b) } - 1 } & { \text { (c) } 2 } & { \text { (d) } 3 } \end{array} \right. |
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Answer» 3x+7 = 133x = 13-73x = 6x = 2 |
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| 870. |
(J) 74757(-2022 |
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Answer» 1-702-573-104-685-57 |
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| 871. |
At what rate per cent of simple interest will Rs6200 amount to Rs 9920 in 4 years? |
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| 872. |
-4 -57 29 '12' 18' 3Compare-, |
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| 873. |
x+7-\frac{8 x}{3}=\frac{17}{6}-\frac{5 x}{2} |
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| 874. |
| ........2. हद P ¢ 1f 57 €S ¢ gyशा. |
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Answer» Like if you find it useful |
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| 875. |
12.き20,000 are invested at 8% per annumcompound interest for 3 years. Calculate thefollowing:a. The amount after one yearb. The compound interest for the 2nd yearc. The amount after three years |
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| 876. |
x + 7 - \frac { 8 x } { 3 } = \frac { 17 } { 6 } - \frac { 5 x } { 2 } |
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| 877. |
PartC5751. AajkB2 |
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Answer» A and B average age=200C and D average age=250so overall average age=(200+250)/2=225 use full app |
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| 878. |
3(7+ 17)+i (7 + 17) |
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Answer» 3(7+i7) + i (7+i7) 21 + 21i + 7i + 7i² 21 - 7 + 28i 14 + 28i |
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| 879. |
Q12. If A and B are the points (-6, 7) and (-1,3) respectively hdistance 2AB is ............... |
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| 880. |
Q12. If A and B are the points (-6, 7) and (-1,5) respectively then thedistance 2AB is |
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Answer» AB=√(-1-(-6))^2+(-5-7)^2AB=√(5)^2+(-12)^2AB=√25+144AB=√169hence AB=13therefore 2AB=2×132AB=26 AB=√(-1-(-6))^2+(5-7)^2AB=√(5)^2+(-2)^2AB=√25+4AB=√29hence AB=√29therefore 2AB=2×√292AB=2√29 |
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| 881. |
Q12. If A and B are the points (-6, 7) and (-1,5) respectively then thedistance 2AB is ........................... |
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Answer» distance AB=root((-1+6)^2+(5-7)^2) =root(25+4)=root(29)2AB=2root(29) |
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| 882. |
Q12.IrA-(1,2) and B (3,4), then write AxB. How manysubsets will AxB have? List them.PTO |
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| 883. |
How many ordered pairs of integers satisfy the13 7 1equation |
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Answer» There are two variables, there are infinite possiblity as everytime we fix a value of x we can find corresponding value of y |
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| 884. |
QUALITY OF ORDERED PAIRSind x and y, if (x +3,5)(6, 2x + y) |
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| 885. |
6)Express {(x, y) / x2 +y2 = 100 wherex, y e W} as a set of ordered pairs. |
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Answer» Given that {(x, y) / x² + y² = 100, where x, y ∈ W} Since x, y ∈ W Let x = 0 , then y² = 100 ⇒ y = ± 10 But y ∈ W, so y = 10 Hence (0, 10) is an ordered pair. Let x = 1 ⇒ 1² + y² = 100 ⇒ y² = 99 ⇒ y = ±√99 ∉W So on continuing for each value of x , we observe that for x = 6 6² + y² = 100, ⇒ y² = 100 - 36 = 64 ⇒ y = ± 8 but -8∉W, hence y = 8 So, (6, 8) is an ordered pair Similarly (8, 6) and (10, 0) are also ordered pair by interchanging x and y values, and also there are no other ordered pairs such that both x, y ∈ W and x² + y² = 100. Hence, the only ordered pairs are {(0, 10), (6, 8), (8, 6), (10, 0)} hope this will help you like my answer and MARK IT AS BEST ANSWER. nice hai toh sawal okk |
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| 886. |
ratelyears22. A sum of money lent at simple interest amounts to 783 in 2 years and to 837 in 3Find the sum and the rate per cent per annunmrs and to |
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| 887. |
rate of interest22. A sum of money lent at simple interest amounts to z 783 in 2 years and to 837 in 3 years.Find the sum and the rate per cent per annum.rs and to 5475 in |
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| 888. |
Solve the following equations.3.6=z+2177âŁ372x7)--185.) 6x = 125=1048. 1.6=1.5 |
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| 889. |
rate of interest22. A sum of money lent at simple interest amounts to ? 783 in 2 years and to 837 in 3Find the sum and the rate per cent per annum.11. Inatto to 4745 in 3 years and to 5475 |
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| 890. |
39Convert the following improper fractions into mixed Ir(ii) 23(iii)(i) 1217 |
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| 891. |
17 ^ { 2 } \cdot 17 ^ { 5 } = 17 ^ { 7 } |
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Answer» 17^2.17^5=17^2+5 (base same power add)=17^7 17^2.17^5=17^2+5=17^7 |
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| 892. |
2. Verify the following:(a) 18x 17+-3)1 [18 x 71 18x (3)](b) 5 x 17+-6)]-5 7+5 x (-6) |
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Answer» (a)18×[7+(-3)]=[18×7]+[18×(-3)]18×[7-3]=126+[-54]18×4=126-5472=72(b)5×[7+(-6)]=5×7+5×(-6)5×[7-6]=35-305×1=55=5 |
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| 893. |
Solve the following equations.I. x-2 72. y+3=1037177^ 5. 6x= 124.1.53 |
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Answer» 1.x-2=7x = 7+2x = 9 |
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| 894. |
that-33 55 14517 14) 5 7 |
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Answer» LHS= 3/5*(-1/7 - 5/14) = 3/5*(-2-5)/14 = 3/5*(-7)/14 = 3/5*(-1)/2 = - 3/10 RHS= (3/5 * - 1/7) - (3/5*5/14) = (-3/35) - (3/14) = (-6 - 15)/70 = - 21/70 = - 3/10 LHS = RHSHence proved |
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| 895. |
1. Simplify the following expressions.3 (5+57)(2+15)jy (13 +17)in (5+15)(5-15)iv) (VII-17) (VT+7) |
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| 896. |
\frac { - 5 } { 17 } \text { and } 7 \frac { 11 } { 17 } |
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Answer» please clarify the operation between them |
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| 897. |
Solve the following equations.1.x-2 73717745, 6 x12 |
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| 898. |
Find the mean of the following frequency distribution0-50 50-100 100-150150-200 200-250 250-300 3003s0ClassFrequency1015302015 |
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Answer» CI. f. x. xf0-50. 10. 25. 25050-100. 15. 75. 1125100-150. 30. 125. 3750150-200. 20. 175. 3500200-250. 15. 225. 3375250-300. 8. 275. 2280300-350. 2. 325. 650 summation of xf= 14930summation of f =100mean= 14930/100=149.3 |
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| 899. |
1. Find the mean, median and mode of the following data0-20 20-40 40-6060-8080-100 100-120 120-14012Class3Frequency106 |
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| 900. |
Sample Question Papers7. The mcan of the following frequency distribution is 54, find the value of PClasses 0-20 20-40 40- 60 60 80 80 100Frequency 7109 |
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Answer» answer do |
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