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for original rectangle breadth is xand length is 2x-5now for new rectangle length=2x-8and breadth x+2perimeter is 72so 2x-8+x+2=363x=42so x=14area original rectangle=14*23=322 cm^2

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Let the breadth be a

Then length = 2(a) = 2a.

We know that, Perimeter of rectangle = 2( length + breadth) .

Given perimeter = 72 m

72m =2( a+2a)

36=3a

a =12

Hence, Length is 2(12) = 24 m

Breadth is a =12 m

the area is 323cm

Area of square = 35*35Area of rectangle = 25*l=> 35*35= 25*l=> l = 49cm.

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perimeter=2( l+b); 200=2(l+b); 200=2(12+2b); 200=24 + 4b; 200-24=4b; 176=4b; b=176/4=44

let breath = x cmlength = x+122(length+ breath)=perimeter2(x+12+x)=2002x+12= 1002x= 100-12=88x= 88/2= 44.so breath = 44.cmlength = 44+12=56cmarea of rectangle= length×breath= 44×56= area of circle let radius of circle =rπr^2= 44×5622/7×r^2= 44×56r^2= 44×56×7/22 = 2×56×7r= √2×56×7 =√2×2×2×2×7×7 = 2×2×7= 28cmdiameter = 2r= 2×28=56cm

Make preparations for medical care

Managing the finances

Organizing their medication

Providing healthy and safe surroundings

Arranging for adequate social interaction

Making provision for care when you are away

Consider their financial and emotional problems, besides how you deal with them at home, which can save you a lot of last-minute trouble – if the need arises.

4+5+1+x=10+X; 10+x/20=14.4; 10+x=20 x 14.4=288; x=288/10=28.8

Price of 100 pens = 2503/5Price of 1 pen =2503/500

Price of 50 pencils = 501/5Price of 1 pencil = 501/250

Therefore,Price of 3 Pens = 2503*3/500= Rs 15.018

Price of 5 Pencils = 501*5/250= 501/50 = Rs 10.02

Mean = (4×4+6×8+8×14+10×11+12×3)/(4+8+14+11+3) = (16+48+112+110+36)/(40) = 322/40 = 8.05

The largest number of boys will be 36

Each boy will get

pencil - 3

rubber- 5

Let number of boys = 3xNumber of girls = 2x

Number of scholarship holder boys =( 20/100)3x = 3x/5

Number of scholarship holder girls = (30/100)2x = 3x/5

Then,Percentage of students who are not scholarship holder=[ (5x - 6x/5)/5x]*100= (19/25)*100= 19*4 = 76%

(d) is correct option

1)45pens=₹45loss by 1 pencil=40 paiseloss of 5 rs =40/5=8pencils

Selling price of milk/litre = 586.50/85 = 6.9rs

total gain is = 0.40*85 = 34rs

so, cost price is = S.P - gain = 586.50-34 = 552.50rs

now , if the total selling price is 600.10rs

so, total gain would be = 600.10-552.50=47.6rs

so, gain/litre = 47.6/85 = 0.56rs = 56paise/litre

total number of balls played=40no of boundaries=8no of no boundaries=40-8=32henceprobability =32/40=4/5

STEPS OF CONSTRUCTION:-

1)Draw a ray OA .

2)With O as centre and any suitable radius draw an arc cutting OA at B .

3)With B as centre and same radius cut the previous drawn. arc at C and then with C as centre and radius cut the arc at D.

4(With C as centre and radius more than half Cd draw an arc .

5)With D as centre and same radius draw another arc to cut the previous arc at E.

6=)Join OE ,then angle AOE ==90°.

7))Draw the bisector OF of Angle AOE ,then Angle AOF =45°.

Justify......

By construction.Angle AOE ==90° and OF is the bisector of Angle AoE

So, Angle =1/2/_AOE =1/2×90°==45°

thanks

1 rs=100 paisaso total pencils=total price/cost of 1 pencil =2400/25=96

24÷100×25 .......... ......

110.776% loss is the correct answer

110.776% is the best answer

Area of plot = A= 95x72=7125Area of Grass laid down =G G = (95-7)x(72-7) G =5720Area of path constructed, P = A-G P= 7125-5720 P= 1405

* Expense for constructing the path, E1= 80 x P = 80x1405 E1= 112400 rupees * Expense for laying the grass, E2 = 40 x G = 40 x 5720 E2 = 228800 rupees

he gains 120 rupees in pen and lost 50 rupees in pencils

shopkeeper gain 70 rupees

120 rupees pen and lost 50 ru in pencils

Gain = 120 Loss= 50

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Cost of 2 dozen (24) bananas = 24/7

so, cost of 1 banana = 24/7 ÷24

24/7 × 1/24 = 1/7.

cost of two bananas= 24/7cost of 1 banana= 12/7hence cost of 1 banana is 12/7

cost of 2 bananas= 24/7cost of 1 banana= 12/7

cost of 24 bananas=24/7cost of 1 banana= 1/7

cost of 2 dozwn banana= 24/7cost of 1 banana = 2/7

Constructa perpendicular line.

Place compass on intersection point.

Adjust compass width to reach start point.

Drawan arc that intersects perpendicular line.

Place ruler on start point and where arc intersects perpendicular line.

Draw 45 DegreeLine.

radhika scored 36marks.final score of radhika is 20.she got 16 marks negative.therefore she made8incorrect answer.

2)mohini scored 21marks.final score of radhika is -5.she got 26 marks negative.therefore she made13incorrect answer.

11*5 - 6*2 = 55-12

= 43 marks

A) 40×4/100=1.6kg=1600gB) 2.35=235%C) 0.78=78%D) 17/20×100=85%

Marks for correct answer= 5Marks for incorrect answer=-1Number of correct answers=2Number of incorrect answers=18so total marks = 18(-2)+2(5) = -36+10 = -26. ( answer)

Total questions are 15Rahul attempts 15 questionsCorrect answers are 10incorrect answers are 5marks for correct answers =10*4=40marks for incorrect answers=5*(-2)=(-10)Total marks=40+(-10)=40-10=30

by basic subtraction2 banana-1 banana=1 banana so 1 banana you have left

Cost of 1 banana=10.8/12=90 paise

Ans :- Seeds such as beans ,grams, etc. are called dicotyledon seed. When opened,these seeds show two thick parts or seed leaves called cotyledons. In the external part of seeds,one sees the protective layer called test or seed coat while the inner concave side of seed, a scar called hilum is seen where the seed was attached to fruit wall. A pore called mycropyle is present above hilum which absorbs water required for germination. Cotyledons contains stored food required by seedlings for growth.

4 balls = 8.24 kg

1 ball = 8.24/4 = 2.06 kg

The AP is given by a,(a+d),(a+2d),(a+3d)

Where, a is first term and d is common difference.

Finite AP Example,

i) 1,3,5,7 with a =1 and d=2

ii)2,4,6,8 with a=2 and d=2

iii) 7,13,19,25 with a=7 and d=6

Infinite AP example

i) 1,3,5,7,................(set of odd numbers) with a =1 and d=2

ii)2,4,6,8,................(set of even numbers) with a=2 and d=2

iii) 7,13,19,25,.................. with a=7 and d=6

I=PRN/100=2500*4*6/100=600

no its wrong it is rupees 625