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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1751. |
A cylindrical bottle is of radius 5 cm and height 28 cm. How many such bottles ofwater are required to fill a container of capacity 11 L(Use Tt 22/7) |
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Answer» Cylindrical bottleradius r = 5 cm, height h = 28 cm Volume of bottle = 2pi*r*h= 2*22/7*5*28= 44*20= 880 cm^3= .88 lit Let n number of bottles required to fill container of 11 litres n*.88 = 11n = 1100/88 = 100/8 = 25/2n = 12.5 |
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| 1752. |
\left. \begin array l \text (A) \quad 0 \\ \text (A) \quad 0 \end array \right. |
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Answer» sin 18°/cos 72= cos(90-18)/cos 72= cos 72/cos 72= 1 (B) is correct option |
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| 1753. |
Find the perimeter and area of the givenshape. (Hint: You will need to find themeasures of x and y.)3.10 cm319 cm |
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| 1754. |
ratio 25: 64, uieil imiucorresponding sides.iieir10. A solid cuboidal slab of iron of dimension77 cm x 10 cm x17 cm is used to castiron pipe. If the outer diameter of the niis 5 cm and thickness is 0.5 cm. Thencalculate the length of the pipe.an |
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Answer» Dimension of cuboidal slab of iron are 77 cm × 10 cm × 17 cm Outer Diameter of pipe = 5 cm & thickness of pipe = 0.5 cm To find : Length of pipe let the length of pipe be l. Inner diameter of pipe = 5 - ( 0.5 + 0.5 ) = 4 cm ⇒Inner radius of pipe, = r1=4/2 = 2 cm ⇒Outer radius of pipe, =r2=5/2 = 2.5 cm According to question, volume of pipe = volume of Slab of ironπ(r2)^2h-π(R1)^2h=lbhl=1851.1cm |
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| 1755. |
ne of the acute angles of a right triangle is 36. Find the other. |
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Answer» it is right answer |
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| 1756. |
Anil borrowed a sum or į 2300 for a certain period at the rate of 10% per annum and returned t 15450on expiry of the time. Find the time for which money was borrowed by him. |
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| 1757. |
171331251529343(iv) 16001292,575615(vii)(villVil |
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Answer» असांत |
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| 1758. |
DENCE-VillQ. 8. What is the difference between noiseasic? Can music become noise sometimes? |
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Answer» thanx bhaiya |
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| 1759. |
(-1 %2B sqrt(3))/(1 %2B sqrt(3)) %2B (-sqrt(3) %2B 2)/(sqrt(3) %2B 2) %2B (sqrt(3) %2B 2)/(-sqrt(3) %2B 2) |
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| 1760. |
: Sanjeev borrowed a sum of18,500 for a certain period at the rate of 10% per annumand returned 27,750 on expiry of the time. Find the time for which money wasborrowed by him. |
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Answer» tnq |
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| 1761. |
%2B \frac 1 1 %2B 2 %2B \frac 1 1 %2B 2 %2B 3 %2B \dots %2B \frac 1 1 %2B 2 %2B 3 %2B \cdots %2B n = \frac 2 n n %2B 1 |
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Answer» Like if you find it useful |
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| 1762. |
1 %2B \frac 1 1 %2B 2 %2B \frac 1 1 %2B 2 %2B 3 %2B \ldots %2B \frac 1 1 %2B 2 %2B 3 %2B \ldots %2B n = \frac 2 n n %2B 1 |
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| 1763. |
(text*((i*(s*(r*(a*(t*(i*(o*(n*(a*l)))))))))*(quad*(text*((i*i)*(((-3*i %2B 2)/(-4*i %2B 3))*((3*i %2B 2)/(4*i %2B 3))))))))*((-2*i %2B 3)/(5*i %2B 2)) %2B (2*i %2B 3)/(-5*i %2B 2) |
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Answer» 1)(3+2i/2-5i)+(3-2i/2+5i)=(3+2i)(2+5i)+(3-2i)(2-5i)/4+5=6+15i+4i-10+6-15i-4i+10/9=12/9=4/3 hence rational |
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| 1764. |
2.Three angles of a quadrilateral are 83°, 49° and 67°. Find the measure of fourth angle. |
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Answer» sum of all the angle of a quad. is 360.let the unknown angle be x76+54+108+x=360238+x=360x=360-238=122 answer |
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| 1765. |
(-4*2^n %2B 16*2^(n %2B 1))/(-2*2^(n %2B 2) %2B 16*2^(n %2B 2)) |
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| 1766. |
dx*(y %2B x*y %2B 2*x %2B 2) %2B dy*(x^2 %2B 2*x)=0 |
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| 1767. |
Average of 10 numbers is 12. If 3 is added to each number then find new average. |
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Answer» Average will be 2/3+ 12as if we add x the average change by avg+xso average will be12+(2/3)38/3 |
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| 1768. |
The sum of three prime numbers is 100. If oneof them exceeds another by 36, then one of thenumbers is:a. 7b.29 c.41 d.67 e. 68 |
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Answer» 31 and 67 are 2 prime numbers whose difference is 36so third one is 2.so 31+67+2=0so prime numbers are 31 67 and 2. |
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| 1769. |
Find the compounded interest for six months on Rs.10,000 at an annual rate ofinterest of 12% if the interest is compounded every 3 months. |
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Answer» thanku but it's worong answer .answer is 609 thanku but it's worong answer .answer is 609 thanku but it's worong answer .answer is 609 thanku but it's worong answer .answer is 609 okkk..given the question is compounded interest for six month so it's half year then we can 'one and half '=3 so rate is 3 per |
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| 1770. |
population of 1st block of colony is 1000 in the beginning of July 2007. It is increases at the rate of 5% every six months. Find the population of 1st block after 18 months. |
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Answer» Initial Population= 1000After 6 months, population= 1000+ (5/100)*1000= 1000+50=1050 After 12 months, population =1050+(5/100)*1050=1050+52.5=1103 After 18 months, population= 1103+ 1103*(5/100)=1103+55=1158 |
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| 1771. |
Calculate the simple interest onsix months.1,200 at 32% interest per annum for |
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Answer» SI = Principal × Rate of Interest × Time / 100 = 1200 × 3.5 × 6 / (12 × 100) = 3.5 × 6 = 21 If you find this answer helpful then like it. thankyou |
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| 1772. |
Hemchand depositsR 1,00,000 for 1 year and six months as fixedinterest rate of8% per annum. If the interest is compounded every three months, howill Hemchand get on maturity?deposit in a Rural Bank at anw much money |
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Answer» using compound interest formulaA=P (1+r/n)^ntas n is no. of times interest is compounded in a year and here interest is compounded 4 times in a year every 3 monthsn=4given thatt=1year 6 months=1.5yearsr=8%=0.08P=Rs1,00,000putting values in formulaA=100000 (1+0.08/4)^(4×1.5)A=100000 (1.02)^6=100000×1.126162A=Rs112616.2 |
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| 1773. |
II(iii) the interest accruel III15,000 for 18 months at a6. Geeta borrowedcertain rate of interest compounded semi-annually. If at the end of six months itamounted to 15,600; calculate :(i) the rate of interest per annum.(ii) the total amount of money that Geetamust pay at the end of 18 months inorder to clear the account. |
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Answer» From where did you get 48.96 |
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| 1774. |
oltrocwhose sides are-5of the corresponding sidesA man on the top of a vertical observation tower observes a car moving at a uniform speedcoming directly towards it. If it takes 12 minutes for the angle of depression to change from30° to 450. how long will the car take to reach the observation tower from this point?OR |
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| 1775. |
3.Find the simple interest on122,000 for six months at the rate of 4% per annum. |
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Answer» smjh nhi aay detail me slove krke send kijiye smjh me nhi aaya detail me send kijiye |
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| 1776. |
of the no of observation, n is add the mediantodo (6) Lant11th observation(n+11th observation as I in 11th ObservationPT. |
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Answer» option c. is the correct answer mark as best bro option C is the correct answer (c) ÷ (n+1/2)^2 is the correct answer option no C is the correct answer... |
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| 1777. |
2. After spending 3/4 of his money, a man is left with Rs 65. How much money he had in hispocket? |
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Answer» let X be the total moneyhenceX-3/4*X=651/4x=65X=65*4=260rupees this is it |
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| 1778. |
Exa3.Manish bought a T-shirt for Rs 485 and a trouser for Rs 940. Estimate the costhe has to pay to the shopkeeper and then compare with the actual cost.Three jars contained 67, 83 and 108 chocolates,.respectively. All of them werepoured into a big jar. How many chocolates are there altogether in the big jar?olt4.Estimate the sum and then find out the actual sum. |
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Answer» 3.total cost to be paid =485+940=1425rupees4.total chocolates=67+83+108=258chocolates |
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| 1779. |
ניוטון6. A lawyer willedmuch did eachh did each of them inherit?willed his 3 sons Rs 250000 to be divided into portions 30%, 45% and 2570.Lan hoe Ann etudante Ana ...1th |
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| 1780. |
3. A joker's cap is in the form of a right circular cone of base radius7 cm and height 24 cm. Find the area of the sheet required to make10 such caps |
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| 1781. |
C) A bag has $5.7 kg wheat. How much wheat wil be there in 1,00bags? |
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| 1782. |
9. 4, B, C, D have Rs 270 between them; A has three times asmuch as C, and B five times as much as D; also A and B togetherhave Rs 50 less than eight times what Chas. Find how much each hascoins h23. Iof whi |
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| 1783. |
1. H earns twice as much as S, but spends thrice as much as s does. If S spends one-fourth of herearnings and saves Rs. 170610, what is the ratio of H's savings to S's. |
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| 1784. |
How much is the loss if a chair is purchased for 600 and sold for 5781) Rs.222) Rs 203) Rs 244) Rs 25 |
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Answer» Loss will be (600-578)22 rupees |
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| 1785. |
the price of a wheat bag weighing 50 kg is Rs.425 wheat price of 62 kg wheat? |
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Answer» 1 kg wheat = 425/50 = 8.5 rs 62 kg = 8.5*62 = Rs. 527 |
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| 1786. |
?) A bag has 85.7 kgWheat. How much wheat will be there in 1,000 suchwheat willbags? |
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| 1787. |
The triangular side walls of a flyover have been used for advertisements. The sides ofthe walls are 122 m, 22 m and 120 m (see Fig. 12.9). The advertisements yield arnearning of行000 per m2 per year. A company hired one of its walls for 3 months. Howmuch rent did it pay?122m22m120m |
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| 1788. |
The hypotenuse of a right triangle is 13 cm long, If one of the remaining two sides is of 12 cm length, find the length of the other sides. |
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| 1789. |
The hypotenuse of a right triangle is 26 cm long, If one of the remaining two sides is 10long, find the length of the other side |
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| 1790. |
|-(६) 320. 70, 040, 000, 000 का मानक रुप होगा।(क) 7.004 X 100(ग) 0.7004 X 100(ख) 7.04 X 10(घ) 0.704 X 10 |
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Answer» This answers is very difficult (20) ka (क) 7.004 × 10^10 70,040,00,000 = 7.004 × 10 ^4 option (क) is correct 7.004×10^10is the correct answer |
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| 1791. |
The base of a triangular field is 3 times its height. If the cost of cultivating the field atthe rate of 25 per 100 m2 is 60000, find its base and height. |
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Answer» Let height = x, then base = 3x and area = 1/2 *x*3x=3/2*x^2 m2. Cost per m2 is = 25/100= 1/4. Cost for 3/2*x^2 is = 1/4*3/2*x^2 which is equal to 60000. Solving x =400. Height is 400, base is 1200. |
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| 1792. |
1 210 per 100 m2A joker's cap is in the form of a right circular cone of base radius 7 cm24 cm. Find the area of the sheet required to make 10 such caps |
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| 1793. |
ntalcross-sectionof a water tank isof a rectangle with semi-circle atThe horizontalend, as shown in the following figure. Theoneter is 2-4 metres deep in the tank. Calculatethe volumeof water inthe tank in3gallons21 mGiven : 1 gallon 4.5 litres |
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Answer» Area of cross section = Area of rectangle + Area of semi circle =21m*7m+1/2*22/7*(7/2m)^2 So volume of tank = Area of cross section × depth = 166.25 m^2× 2.4 m = 399 m^3 =399000l =399000/4.5gallons=266000/3gallons |
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| 1794. |
The profit earned by selling an article for Rs680 isequal to the loss incurred when the same article is soldfor Rs 420. What should be the sale price of the articlefor making 60 per cent profit?a) 870c) 880b) 890d) 990 |
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| 1795. |
Hameed has built a cubical water tank with lid for his houster edge 1.5 m long. He gets the outer surface of the tank excludivered with square tiles of side 25 cm (see Fig. 13.5). Find how mund for the tiles, if the cost of the tiles is 360 per dozen. |
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| 1796. |
Explain uheBriefly discuss the changes in Indian economy after 1991. |
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Answer» Ans :- The economic liberalisation in India refers to the changes and reforms, initiated in 1991, of the country's economic policies, with the goal of making the economy more market- and service-oriented, and expanding the role of private and foreign investment. |
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| 1797. |
uhe Humber line.35. Insert a rational number betweenand57 |
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| 1798. |
\frac { ( 1 - 2 x ) + ( 1 + 2 x ) } { ( 4 x + 1 ) + ( x - 3 ) } = \frac { 1 } { 2 } |
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| 1799. |
Simplify:\left(2 x-\frac{1}{2 x}\right)^{2}-\left(2 x+\frac{1}{2 x}\right)\left(2 x-\frac{1}{2 x}\right) |
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Answer» I hope you got it 4x*x-2+1/4x*x-4x*x+1/4x*x=2+2/4x*x=2+1/2x*x |
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| 1800. |
Solve for x:\frac{1}{2 a+b+2 x}=\frac{1}{2 a}+\frac{1}{b}+\frac{1}{2 x} |
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