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2001.

would have got JULe arowe 5cm less than it didEach yeal a tree grows 5cm less thethe precedingyear. If it grew by I'm in the first year, then in how manyyears will it have ceased growing?boud9y4_373-57*+91-3, if

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Hey its part of an Arithmetic progressionan Arithmetic progression(AP) isa sequence of numbers in which each differs from the preceding one by a constant quantityinwhicha(first term) = 100 cmd(common difference) = -5cmAn(nth term) = 0cmn = ?thereforeAn = a + (n-1)d0 = 100 -5n + 5-105 = - 5n21 = nhence in the 21 st year the tree will stop growing

Hey its part of an Arithmetic progressionan Arithmetic progression(AP) isa sequence of numbers in which each differs from the preceding one by a constant quantityinwhich a(first term) = 100 cmd(common difference) = -5cmAn(nth term) = 0cmn = ?thereforeAn = a + (n-1)d0 = 100 -5n + 5-105 = - 5n21 = nhence in the 21 st year the tree will stop growing

2002.

Anil deposited 20,000 in a bank. If the rate of interest paid by the bank is 6% per annum compoundedhal yearly, what amount will he get after one year?

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2003.

Anas deposited 20000 rupees in a bank which pays 6% interestcompounded annually. How much would he get back after 3 years?

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20000(1+6/100)³

= 20000*106*106*106/100*100*100

= 23,820.32 rupees

2004.

In a row, Anil is in the 11'. In a row, Anil is in the 11h position from thetheleft and Bhushan is in the 10'h position fromthe right. If Anil and Bhushan interchangedtheir places, then Anil becomes 18th from theleft. How many persons are there in the rowother than,Anil and Bhushan?

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Let Anil and Bhushan be A and B respectively.

The arrangement is as shown below:

Left 1.......10 11th .........10th 9.....1 A B

Now they interchange their positions

Left 1................10 11th ...................19, 18 th B A

Therefore, Total number of persons in a row

= 17+9+1= 27 persons

And total persons in arrow other than A and B =27-2 =25 persons

As the positions of A and B are 18th and 10th in respective arrangements.

2005.

Kalpana deposited 20000 for one year in fixed deposit with State Bank of India. Ifthe bank pays 8% interest per annum and the interest is calculated half-yearly,what amount will she get after one year?12.

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for 6 months it will be20,000*0.5*8/100= 800 it is the interest for 6 monthsnow 20,000+800= 20800 will be the amountnow interest = 20800*0.5*8/100= 832now total amount will be 20800+832= 21632

2006.

- TYPE - IONE DRAWER ONE DRAWEEPankaj draws a bill on Anil worth 8,000 for three months which was accepted byAnil. On the same date, Pankaj discounted the bill with his bank 10% p.a.On due date, Anil dishonoured his acceptance, Anil paid 4,000 to Pankaj andaccepted a fresh bill for two months for the balance including interest of 40. Anilbecame insolvent, before the maturity of the bill and 50 paise in a rupee werereceived as first and final dividend from his estate.Pass necessary Journal Entries in the books of Pankaj.40,160/-; Bad Debts = 2,020/-ms: Pankaj's Journal Total =(March, 1987)

Answer»

40,160 is the right answers

pankuj journal total answer is 40,160

40,160pankaj draws total is the correct answer

2007.

yearsSudhir lent䚏2000 at compound interest at 10%payable yearly, while Prashant lent 2000 atcompound interest at 10% payable half-yearly.Find the difference in the interest received bySudhir and Prashant at the end of one year.

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2008.

DATE DIUIdi Aman's income is 20% less than that Iof Anil how much percent is Anil incomemore than Aman's incomen

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20% is the correct answer

20% is the correct answer

2009.

5) 24 bananas were distributed between Anil and Shubham in the ratio 3:5,y then how many bananas did Anil get?a) 8b) 15c) 12

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let x be the common ratiothen anil got 3x bananas and shubham got 5x bananas 3x+5x=248x=24x=3

anil got 3x=3×3=9 bananas

2010.

Eight chairs are numbered from 1 to 8. Two women and 3 men wish to occupy onechair each. First the women choose the chairs from amongst the chairs 1 to 4 and thepmen select from the remaining chairs, Find the total number of possible arrangements

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1,2,3,4,5,6,7,8 are 8 chairs.two women first choose two chairs from 1,2,3,4in 4p2 ways = 12 different ways3 men selects 3 chairs from the rest 6 chairs = 6p3 = 6*5*4 = 120.

Total number of possible arrangement = 12*120 = 1440.

2011.

AB16) In the adjoining igure,AB DE.Prove thatConsider two parallei lines and a transversal. Among themeasures of 8 angles formed, how many distinct numbers arethere?

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hiiii meri.. friend banogi to reply me apni facebook likh do

2012.

n how many ways can 7 men and 7 women be seated around a circular table so that no twomen/no two women sit next to each other?

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2013.

find the compound interest on 10,000 at 10% per annum for 3 years, the interest payable yearlyFind the compound interest on 15,000 at 6% for 1 1/2 years, the interest payable half-yearly1.

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2014.

3. Sum of the digits of a two-digit number is 9. When we interchange the digifound that the resulting new number is greaterthan the original number by 27is the two-digit number?4. One of the two digits of a two digit number is three times the other digit.interchange the digits of this two-digit number and add the resulting numberginal number, you get 88. What is the original number?Shobo's mother's present age is six times Shobo's present age.Shobo's agyears from now will be one third of his mother's present age. What arepresent ages?There is a narrow rectangular plot, reserved for a school, in Mahuli villaglength and breadth of the plot are in the ratio 11:4. Atthe rate 100 per metrecost the village panchavat t 75000to f

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2015.

compound interest-(5408-5000)-き408EXERCISE 11A1. Find the amount andthe compound interest on2500 for 2 years at 10% per annumcompounded annually.

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2016.

compothucalculated half yearly?successive years are 10% and 5% respectively.12. What is the compound interest on 8,000 at 10018. Calculate the amount due in 2 years on1000, if the rates of compound interest forround interest payable annually at 10% per annum for

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2017.

Let us write by calculating compound interest on 6250 at the rate of 10% compoundinterest per annum compounded at the interval of 3 months

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this right answer 6406.25

2018.

4 MARKS QUESTIONS1. In △ABC, seg MMN ll side AC. Seg MN dividesAABC into two parts equal in area. DetermineAMMB(HOTS)

Answer»

in ΔABC and ΔAMN

segment MN ║ BC

∠AMN=∠ABC (corresponding angle)

∠ANM=∠ACB (corresponding angle)

∠A si common

so ΔABC≅ΔAMN (CPCT)

given that 2*(area of ΔAMN )= area of ΔABC

so

AM/MB =√(ar(ABC)/ar(AMN))

= √2/1

= √2

Like my answer if you find it useful!

2019.

l comm, Pind amount and compound interest on 2 10000 for 1 years at 10% er ante compoundedannually?te vearly, Would this interest be more than the interest he would get if it was compoundedand compound interest on 10000 for 1 1

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2020.

uestionsof 4 marks each.ere is no overall choice. However, an internal cof 1hoicemark each, two questions of 2 marks each, fouthree questions of 4 marks each.se of caleulators is not permitted.SECTION-A.Very short answer type questions:-18Find the standard form ofS2. a) Write the coefficient of x: 12ry?+25.(OR)Simplify: 5x+12-(3r7)In the given figure, find 4P

Answer»

standard form of -18/45=-2/5

cofficient of x in 12xy²+25 is 12y²

simplify: 5x+[2-(3x-7)]5x+2-3x+72x+9

2021.

In a class test, the sum of Shefali's marks in Mathematics and English is 30. Had she10, nnt 2 marks more in Mathematics and 3 marks less in English, the product of hermarks would have been 210. Find her marks in two subjects. ICBSE 2014, NCERT]go

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2022.

3In a class test, the sum of Shefali's marks in Mathematics an2 marks more in Mathematics and 3 marks less in English, the pwould have been 210. Find her marks in the two subjects.English is 30. Had she g

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thankyou

2023.

5. In a class test, thesum of Shefali's marks in Mathematics and English is32 marks more in Mathematics and 3 marks less in English, the prowould have been 210. Find her marks in the two subjects.re

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2024.

a) What per cent of 72 is 18?

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suppose x percent of 72 is 18so x*72/100=18so x=18*100/72=25%

2025.

Yash scored 40 marks in a test, getting 3 marks for each right answer and losing imark for each wrong answer. Had 4 marks been awarded fand 2 marks been deducted for each incorrect answer, then Yash would havescored 50 marks. How many questions were there in the test?(iii)or each correct answer

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2026.

g 3 marks for each right answer and losing 1mark for each wrong answer. Had 4 marks been awarded for each correct answerand 2 marks been deducted for each incorrect answer, then Yash would havescored 50 marks. How many questions were there in the test?

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2027.

Had Ajita scored 10 more marks in her mathematics test out of 30 marks, 9 times these marks would have been the square of her actual marks. How many marks did she get in the test?

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2028.

5 Shanta got 215 marks in an examination. If she had got 10 marksmore, she would have scored 60% of the total marks. What are themaximum marks for the examination?

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2029.

PRACTICE PAPERe number is(even/odd)of a numbertiples of the largest 3-digit numberf two primes.nk space in number 63 809 so that it becos(1/ number itself)termine four factors of 7216number which when divided by 5 and 9

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four factors of 7216 =1,2,4,8

2030.

It cost t 1 to photocopy a sheet of paperHowever, 2% discount is allowed on allphotocopies done after first 1000 sheets. Howmuch will it cost to photocopy 5000 sheetsof paper?

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2031.

PILOT PROJECT:2018-19 PRACTICE PAPERA metallic cylinder of diameter 9 cm and height 16 cm is melted and recast into smallSection-C12.spherical balls of radius 0.30 cm. Find howmany such spherical balls are made ?a so CS

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2032.

6.Aditi got 20% less marks than Isha. How much per cent is Isha's marks more than that of Aditi?

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2033.

MATHEMATICS (PART-t)QUESTION PAPER 2ime 2 Hours JMax. NasAll questions are compulsoryUse of calculaior is not allowedQuestions of 8 marks (20%) are based on the IXth standard sylve the following questions : (Any Four)If n(A)130, n(B) 180, n(AnB) 110, find n(A/2Write rationalizing factor of-

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Given,n(A) = 130, n(B) = 180, n(AnB) = 110, n(AUB) =?

n(AUB) = n(A)+ n(B) - n(AnB) = 130 + 180 - 110 = 310 - 110 = 200

2034.

Ajit secures 12.5% more marks than Baiju. Then how much less per centdid Baiju secure than Ajit?

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suppose Ajit scores 125 marks bajju got 100marks difference = 25percentage = 25/100*100= 25 percentage

2035.

Anubhav's marks are 20% less than Abhishek'smarks. By what per cent are Abhishek's marksmore than Anubhav's marks?

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Abhishek's marks = xAnubhav's marks = x - (20% of x) = x - 0.2x =0.8 xdifference in marks = x - 0.8x = 0.2 xAbhishek's marks is more than by Anubhav's marks by

[difference/(Anubhav's marks)]×100= (0.2/0.8)×100=25%

thank u

2036.

(0ि; चन्द्र प्रकाश ने अपना रेडियो 10% हानि पर बेचा. यदिवह उसको 45 रुपए अधिक में बेचता तो उसको 5%लाभ होता. उसने रेडियो कितने रुपए में बेचा?(A) 315 रुपए (8) 270 रुपए(C) 300 रुपए (0) 345 रुपए

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2037.

Nikhil'than that of Nikhil's?s income is 20% less than that of Akhil. How much per cent is Akhil's income moreIout much ner cent is the income of

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2038.

IfSeema's height is 10% more than Reena's, howmuch per cent less is Reena's height than seema's?

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= 10/100+10 * 100

= 10/110 * 100

= 9.09%

2039.

income is 20% less than that of l. Dy what per cent is fys income moe price of petrol goes up by 10%. By how much per cent must asumption of petrol so that the expenditure oa it remains unchangednvore54000

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2) let the petrol consumption before hike be X and petrol price be Y.

Total expenditure incurrred by motorist = XYafter hike, the petrol price = Y + 10%ofY =1.1Y let the new consumption be Z

according to question, the expenditure needs to remain same.therefore,Z*1.1Y=XY Z = X/1.1=10X/11

Therefore change in consumption = Z-X =-X/11

negative sign means the motorist have to reduce the consumption.Thus, while calculating reduction percentage we will consider magnitude of change.Therefore, percent reduction={(X/11)/(X)}*100% =9.09%Hence, the motorist has to reduce consumption by 9.09% to keep the expenditure same.

2040.

dt was the onginalHcRetA's salary is 10% more than that of B. How much per cent is B's income less than A's?

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2041.

3 \frac { 1 } { 2 } + 2 \frac { 3 } { 4 } + 1 \frac { 1 } { 4 } + 5 \frac { 1 } { 2 } =

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7/2+11/4+5/4+11/218/2+16/49+412

2042.

Determine an AP whose 3rd term is 16 and when 5th term is subtracted from 7th term, we get 12

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Let AP have first term a and common difference d.Given: a(3) = 16According to question,a(7) - a(5) = 12a + 6d - a - 4d = 122d = 12d = 6So, a(3) = 16a + 2d = 16a = 16 - 12 = 4a = 4

So, AP is 4, 10, 16, 22.......

2043.

1. Find the area of the sector of a circle with radius6cm, if θ-600

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2044.

Q24 Find the height of the cone formed by a sector of radius 6cm andsectorial angle 120°

Answer»

LET WE CUT OUT THE SECTOR FROM THE CIRCLE.

LENGTH OF THE ARC= 120/360 X 2 PIE r = 1/3 X 2 PIE 6 = 4 PIE.

NOW, THE SECTOR IS ROLLED TO MAKE A CONE.

RADIUS OFTHE CIRLE= SLANT HEIGHT OF THE CONE= 6 UNITS.

LENGHT OF THE ARC= CIRCUMFERENCE OF THE BASE OF THE CONE = 4 PIE.

2 PIE r = 4PIE.

RADIUS OF THE CONE= 2 UNITS.

HEIGHT OF THE CONE= h

h2= 6²- 4²= 12, h= √12.

2045.

Find the angle of a sector of a circle with radius 6cm if the angle of the sector is 60°

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2046.

Find the area of a sector of a circle with radius 6cm if angle of the sector is 60 degrees

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area of sector = (angle of sector/360)*πr^2 = (60/360) * 3.14 * 6 * 6 = 18.84cm^2

2047.

7. Find the 31st term of an AP whose 11th term is 38 and the 16th term is 73.8An AP consists of 50 terms of which 3rd term is 12 and the last term is 106. F

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2048.

Prove that a diameter of a circle which bisects a chord of the circle also bisects theangle subtended by the chord at the centre of the circle.

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thnak you

2049.

chord of a circle is equal to the radius of thecirele. Find the angle subtended by the chord ata point on the minor arc and also at a point on themajor arc.

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2050.

Achordofacircleisequaltotheradiusofthecircle. Find the angle subtended by the chord ata point on the minor arc and also at a point on themajor arc.

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