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3x+4 = 49

3x = 45

x = 15 years

Let the given polynomials be f(x) and g(x).

ATQ,When f(x) and g(x) are divided by (x-2) they leave the same remainder.

I.e (x-2) is a factor of f(x) and g(x). It means 2 is the zero of f(x) and g(x)

So that,

f(2) = g(2)

2x³+ax²+3x-5 = x³+x²-4x+a

2(2)³+a(2)²+3(2)-5 = 2³+2²-4(2)+a

2(8)+a(4)+6-5 = 8+4-8+a

16+4a+1 = 4+a

17+4a = 4+a

4a-a = 4-17

3a = -13

a = -13/3.

then 8 divided by your digit to get answers

Number lies between 11 and 1111 When divide by 9 a remainder of 6and when divided by 21 leave a remainder of 12=33, 96, 159 (all separated by 63)

a =33 d=63

1111=a+(n-1)631111=33+(n-1)631078=(n-1)631078/63=n-1n=(1078+63)/63n= 1141/63n = 18.11then total number=18

Answer is 18..

Sum of 24 observations = 15.5 * 24 = 372

Mistake = 42 - 24 = 18

So actual sum = 372 -18

= 354

Correct mean = 354 / 24

= 14.75

To find the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case, we have to find the L.C.M. of 6, 15 and 18 and then add 5 in that number.

L.C.M. of 6, 5 and 186 = 2*315 = 3*518 = 2*3*3

L.C.M. of 6, 15 and 18 = 2*3*3*5 = 90

Now,5 + 90 = 95

Hence, 95 is the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case.

-86/3 plz like and comment

- 86/ 3 plz like and comment

-86/3 is the correct answer of the given question

7n^4 + n^3(a calculator was used)

-35 is Right answer.

17×(-4)-(-3)×11=(-68)-(-33)=(-68)+33=(-35)your answer is (-35)

-35 is the correct answer of the given question

Mean * total number of observations = sum of all observations.Sum = 40 *160 = 6400Now we have taken 125 instead of 165 so the sum must be 6440Mean = 6440/40 = 161.

[(17.5 x 11)-15]/10 hence the answer will be 17.75

17.5*11=192.5 is the total observation192.5-15=177.5Now,mean=177.5/10=17.75

Let the maximum marks be 'x'.Then, according to the question.(25 % of x) + 30 = (50 % of x) - 20⇒ x/4 + 30 = x/2 - 20⇒ (x/4) - (x/2) = - 20 - 30⇒ (x - 2x)/4 = - 50⇒ - x/4 = - 50⇒ - x = - 200⇒ x = 200So, the maximum marks are 200.

Minimum passing marks are = x/4 + 30= 200/4 + 30= 50 + 30= 80 marks

Minimum passing marks are 80.

let total marks=100xgot 30xpass marks=30x+152nd case got =60xpass marks=60x-35A/S60x-35=30x+1530x=45x=45/30=3/2total marks=100*3/2=150pass marks= 30*3/2+15=60pass %= 60*100/150 =40% of total marks = 45+15

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A The Pacific Ocean

It is bordered on the west by the Pacific Ocean.

thanks

Ashish

nth term are equalso 9+(n-1)(-2)=24+(n-1)(-3)n-1=15so n=1616th term=9-30=-21

Thank u

We have polynomial p (x) =x^3- 2x^2 - 5x+ 6

So two verify 3 , -2 and 1 are zeros of our given cubic polynomial , we check As :

Atx = 3 we get

p ( 3) = ( 3 )^3- 2 ( 3 )^2 - 5( 3 ) + 6

p ( 3) = 27 - 18 -15 + 6

p ( 3) = 0

SO 3 is a zeros of our given polynomial .

Now Atx = - 2 we get

p ( -2) = ( -2 )^3- 2 ( -2 )^2 - 5( -2 ) + 6

p ( -2 ) = -8 - 8 + 10 + 6

p ( -2 ) = 0

SO -2 is a zeros of our given polynomialNow Atx = 1 we get

p ( 1 ) = ( 1 )^3- 2 ( 1 )^2 - 5( 1 ) + 6

p ( 1) = 1 - 2 -5 + 6

p ( 1 ) = 0

SO 1 is a zeros of our given polynomial .

So it is verified that 3 , -2 and 1 are zeros of given polynomial .

thank you

लाभ =(1140-950)*100/950 = 190*100/950 = 20%

2040 se 2060 tk ka profit hua hai

1624 rupees ka profit hua

it's answer is 1624 profit

19488 ₹ ka profit hua

19488 profit.........

₹19488 is the answer of the following

selling price of each phone = 14,056 ₹Actual selling price of 12 phone = 14,056 × 12 = ₹ 1,68,672but reena sale 12 phones on ₹ 1,88,160therefore she earn profit = 1,88,160-1,68,672= ₹ 19,488

5. Let ∠C = 3∠B = 2∠(A+B) = x

∠C = x, -----(1)3∠B = x∠B = x/3 ----(2)2∠(A + B) = x∠A + ∠B = x/2∠A = x/2 - ∠B∠A = x/2 - x/3 -----(3)sum of the three angles in a triangle is 180degree∠A + ∠B + ∠C = 180x/2 - x/3 + x/3 + x = 180 [from(1),(2),(3)](3x - 2x + 2x + 6x)/6 = 1809x/6 = 180x = 180*6/9x = 20*6x = 120

thereforeA = x/2 - x/3 = 120/2 - 120/3 = 60 - 40 = 20B = x/3 = 120/3 = 40C = x = 120

1

2

of f(x) is continuous , then

f(2) = (2)²+a(2)+6 = 3(2)+2=> 10+2a = 8=> a = -1

also, f(4) = 3(4)+2 = 2*(-1)*(4) +5b=> 14 = 5b-8=> b = 22/5

f

Sum of (3x-y+11) +(-y-11) = 3x - 2y

Now subtract (3x - 2y)-(3x-y-11)= - y + 11 ans

according to euclid division lemma (x)=g(x)*q(x)+r(x) , where q(x)≠0, degree of r(x)=0 or degree of r(x)<degree of g(x)

(i) degree of p(x)= degree of q(x) the degree of quotient or dividend can be equal , if the divisor is a constant (degree 0)

iam sorry i was not able to put whole answer

the degree of quotients or dividend can be equal, if the divisor is constant

Ek Ghan ki Bhuja se semi hai iska vakra prasthiy kshetrafal tatha aayatan gyat

5/9 is the right answer

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5/9 it is right answer

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5/9 is the correct answer

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0.2460 is right answer

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5/9 is correct answer for this Question

Let the age of arun be x

so, age of ankit = x/2+7 = 35

=> x/2 = 35-7 = 28=> x = 28*2 = 56 age of arun