Explore topic-wise InterviewSolutions in .

Probability of exactly 2 head =3c2 x (1/2)^3 = 3/8.

Let H be the heads and T be the tails.

Sample Space(S)={HHH,HTH,THH,TTH,HHT,HTT,THT,TTT}

n(S)=8

Let A be the set of getting at most 2 tails.(two or less than two tails)

Therefore,

A={HHH,HTH,THH,TTH,HHT,HTT,THT}

n(A)=7

Since,

P(A)=n(A)/n(S)

P(A)=7/8

Therefore, the probability of getting at most 2 tails is7/8.

tan x=V1+x^2-1/x=V1+4-1/4=2/4=1/2

tan^-1(√1-cosx/1+cosx)tan^-1(√2sin^2x/2/2cos^2x/2)tan^-1(tanx/2)X/2

No

for an expression to be polynomial the power on variables should always be whole number.

so , a, and c are not polynomial.

b,d where is

give b

give question b

The list of 3 digit number that leaves a remainder of 3 when divided by 4 is :

103 , 107 , 111 , 115 , .... 999

The above list is in AP with first term, a = 103 and common difference, d = 4

Let n be the number of an the AP.

Now, an= 999

103 + ( n - 1 ) 4 = 999

103 + 4n - 4 = 999

4n + 99 = 999

4n = 900

n = 225

Since, the number of terms is odd, so there will be only one middle term.

middleterm=(n+12)thterm=113thterm=a+112d=103+112×4=551

Weknowthat,sumoffirstntermsofanAPis,Sn=n2[2a+(n−1)d] Now,Sum=112/2[2×103+111×4]=36400 Sumofalltermsbefore middleterm=36400sum of all numbers= 225/2[2×103+224×4]=123975

Now,sumoftermsafter middleterm=S225−(S112+551)=123975−(36400+551)=87024

thanks bhai

The sequence are formed by all the numbers between 9 and 95 , which leaves remainder 1 when it is divided by 3 : 10, 13, 16, .........94 Here you can see 10, 13 , 16 , .....94 are in AP where first term , a = 10 and common difference , d = 94 . From AP nth term formula , Tn = a + (n -1)d 94 = 10 + (n -1)3 84/3 = n -1 ⇒n = 29

Hence, there are 29 terms between 10 and 94 It means middle term is (n + 1)/2 th term e.g., middle term = (29+1)/2 = 15th term So, T₁₅ = a + (15 - 1)d = 10 + 14 ×3 = 52 Hence, 15th term is 52

here middle is 15th , it means 14 terms are in left side of it and 14 terms are in right side of it. So, sum of first 14 term {left side } = 14/2 [ 2 × 10 + (14 -1)×3 ] [∵Sn = n/2[2a + (n-1)d]= 7[20 + 39] = 7 × 59 = 413

Now, sum of last 14 term { right side of middle term } = S₂₉ -[ S₁₄ + T₁₅ ]= 29/2[2 × 10 + (29-1) × 3 ] - 413 - 52 = 29/2[20 + 84 ] - 465 = 1508 - 465 = 1043

Numbers between 9 and 95 is in APSo first term a = 10,Common difference = 11-10 = 1Total number of terms = 85Middle term = (85 + 1)/2= 86/2 = 43 rd term

Value of middle term= a + 42d= 10 + 42*1 = 52

Sum of terms left of 52= 42/2(10 + 51)= 21(61) = 1280

Sum of terms right of 52= 42/2(53 + 94)= 21(147) = 3087

1

2

ratanamala how can you say that the nth term is 65

okk thanks

ae ...questions are different bhaiyya

🤔🤔

The list of 3 digit number that leaves a remainder of 3 when divided by 4 is :

103 , 107 , 111 , 115 , .... 999

The above list is in AP with first term, a = 103 and common difference, d = 4

Let n be the number of terms in the AP.

Now, an= 999

103 + ( n - 1 ) 4 = 999

103 + 4n - 4 = 999

4n + 99 = 999

4n = 900

n = 225

Since, the number of terms is odd, so there will be only one middle term.

middleterm=(n+12)thterm=113thterm=a+112d=103+112×4=551

Weknowthat,sumoffirstntermsofanAPis,Sn=n2[2a+(n−1)d] Now,Sum=112/2[2×103+111×4]=36400 Sumofalltermsbefore middleterm=36400sum of all numbers= 225/2[2×103+224×4]=123975

Now,sumoftermsafter middleterm=S225−(S112+551)=123975−(36400+551)=87024

the right answer is 3:11

hope this will help you like my answer

3:11 is the best answer

3:11 is the right answer

3:11 is correct answer.

To find:tan-¹√3

theta= tan-¹(√3)tan theta=√3theta= 60°=π/3thus tan-¹(√3)=π/3

tan-1 (✓3)=r/3IFB six

Xl is the correct answer

vvv is answer.........

biggest symbol possible in any number (so XV, notVVV, to make 15) and use symbols left to right in decreasing value. Thus 1,666 is written MDCLXVI.RomanRule II: No symbol should be repeated four or more times, so IV not IIII (but see 'Exceptions' below!).

15 is answer in Hindu Arabic

v can not be reapeated..

15 is the answer of the

probably 15 is the answer

hello raushan kumar your answer is below: put a dash or line on top of x .....(I can't put it cause my keyboard has no function of it.)

ten thousand is the correct answer of the given question

10000=MMMMMMMMMM, Roman mein aise likhte hai

X is the right answer

Break the number (decompose it) into place value subgroups:

350 = 300 + 50;

2. Convert each subgroup:

300 = 100 + 100 + 100 = C + C + C = CCC;50 = L;

3. Wrap up the Roman numeral:

350 = 300 + 50 = CCC + L = CCCL;

I know you don't know

69 in roman numerals - LXIX

दोनो का ब्याज समान है। समय x मानते है। x×3×8000/100 = 6000×5×4/100 240x = 120 x = 120/240 = 1/2 6 महिने

If you find this answer helpful then like it.

The answer is "MCDXIX"

LXI,LIX,CV is the answer of the following

61=LXI59=LIX105=CV

LXILIXCVis the answer of your question

61=LXI59=LIX105=CV

LXILIXCVIs the right answer.

61=XLI59=LIX105=CV

415000 - 415000*x/100 = 356900

415000*x = 58100*100

x = 580/415

x = 1.4%

I'm sorry but answer is wrong

Since the annual rate of population is 12%, which means the population of the town increases by 12% every year.Then after 2 years population will increase 2 x 12 %=24%.So after 2 years population will increase by 24%.Now 24 % of 186040 = (24 × 186040)/100 = 44649.6.so the total population is equals to= 186040 + 44649.6 = 230689.6which is the proximity equals to 230690, around 2 Lacs 30 thousands 6 hundred and 90.

X=8000

ANSWER= OPTION IS III

2x/3 + 1 = 7x/15 + 3Take LCM of 3, 15 =15Multiply with 152x(5) +15 = 7x +3(15)10x + 15=7x+4510x-7x=45-153x=30x=10

15x-7x=8

8x=8

x=1.

15x-7x=88x=8x=8/8x=1is the best answer

x=1 is the correct answer

X=1.................

x= 1 is the correct answer of the given question

In a partical year the male population of a city men are 23, 59,324 and more women's are 68, 13,674

Explanation : x*x - 15x + 54 = 0 x*x - 6x - 9x + 54 = 0 x(x-6)-9(x-6) = 0 (x-6)(x-9) = 0 x = 6,9

Solution : 6,9

If you find this answer helpful then like it.

the correct answer will be ( c ) i.e.12000

15000 number of females in the town

the answer could be option d

d is a correct answer

Please like the solution 👍 ✔️

92,103+1,07,631=1,99,734then , 4,10,210-1,99,734=2,10,476

First add 92103 and 107631 then subtract the result from 410210the answer will be 210467

92,103+1,07,631=1,99,734then,4,10,210-1,99,734=2,10,476

92, 103 + 1, 07, 631= 1, 99,734; 4, 10, 210 - 1, 99, 734 = 2, 10, 476

27 ka ans he 6685 28.ka1115. 29ka 3357. 30ka. 12019

acab is the right answer