InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 2951. |
Example-3.Find the roots ofthe equation 2x2-5x+3=0,by factorisation. |
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| 2952. |
What is the nature of roots of quadratic equation 5x2-7x + 2 = |
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| 2953. |
2. Ifone ofthe roots ofthe quadratic equation x2-10x + 2k=0is(h +2V6),findthe values of h and k. |
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| 2954. |
What product by rounding number to nearest Eastimate 376×154 |
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Answer» 376 * 154 = 57904 = 58000 estimate 367 = 400estimate 123 = 100=400*100=40000 376*154=57904=58000 58000 is the right answer. 58000 is the right answer |
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| 2955. |
The sum of the numbers 637, 376 and 763 is divided by 111, 16 and 37. Find the quotientin each case. |
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Answer» sum of no.s=637+376+763=1776when divided by 1111776/111=16quotient=16when divided by 161776/16=111quotient=111when divided by 371776/37=48quotient=48 thanks |
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| 2956. |
2(32.23dy3 |
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Answer» Which book are you referring |
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| 2957. |
\begin{array}{l}{23+89} \\ {43+29} \\ {96+68} \\ {248+374} \\ {518+423} \\ {842+376}\end{array} |
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| 2958. |
32. लुप्त संख्या ज्ञात करें|?10944622(A) 184(C) 1901. A(B) 376(D) 882. B4.C3.D |
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Answer» after calculations it's 190 ans 190 is right answer of this question |
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| 2959. |
On Monday, 376 students went on a trip to the zoo. AlIl 9buses were filled and 7 students had to travel in cars. How many students werein each bus? |
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Answer» 376 -7=369. 9 buses = 369 , hence 1 bus = 369/9=41. total no. of students = 376no. of buses = 9students that travelled in cars = 7total no. of students that were in 9 buses =376-7=369no. of students in 1 bus=369/9=41 |
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| 2960. |
Exercise 67and triangular plots. Use the information given in the diagram toquestions that follow.メ(--. Kikonde's land is in the shape shown below. He has divided itagramoto answer the90 mGRASSORANGETREESHOMESTEAD90 m30 m0 mおーMAIZEPOTATOES50 m70 mBANANAS30 mVEGETABLES40 m(a)(b)What is the area under grass?What is the area under maize? |
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| 2961. |
ORAta Ramzan Mela, a stall keeper in one of the food stalls has a largewindrical vessel of base radius 15 cm filled up to a height of 32 cm withorange juice. The juice is filled in small cylindrical glasses(see in figure ofradius 3 cm up to a height of 8 cm, and sold for Rs 3 each. How much moneydoes the stall keeper receive by selling the juice completely? |
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Answer» Total volume of orange juice = volume of cylindrical vessel=pi * r^2 * h= 22/7 * 15^2 * 32= 22*225*32/7 cm^3= 22628.57cm^3 volume of orange juice in 1 glass= 22/7 * 3^2 * 8cm= 22*9*8/7 cm^3= 226.29 cm^3 No. of glasses = total volume of orange juice/volume of juice in 1 glass= 22628.57 cm^3/226.29 cm^3= 100 glasses Therefore, Money stall keeper receive by selling the juice= 100*3= Rs 300 |
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| 2962. |
nt iuver Ul Water isaseu Dy 3 uH. What is the radius of the ball?19. A cylindrical bucket with base radius 15 cm is filled with water up to aheight of 20 cm. A heavy iron spherical ball of radius 9 cm is droppedinto the bucket to submerge completely in the water. Find the increasein the level of water. |
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| 2963. |
A hemispherical vessel of radius 14 cm is fully filled with satfully filled with sand. This sand15 poured on a level ground. The heap of sand forms a cone shapis a cone shape of height7 cm. Calculate the area of ground occupied by the circular bad by the circular base of theheap of the sand. |
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Answer» Given,Radius of hemisphere r1 = 14 cm Height of cone h = 7 cm Let radius of base of cone = r2 Volume of hemisphere Vh= 2/3*pi*(r1)^3= 2/3*pi*(14)^3 Volume of cone Vc= 1/3*pi*r2^2*h= 1/3*pi*r2^2*7 As per given conditionVc = Vh1/3*pi*r2^2*7 = 2/3*pi*(14)^3r2^2 = 2*2*14*14r2 = 2*14r2 = 28 cm Therefore,Area of base of cone= pi*r2^2= 22/7*28*28= 22*4*28= 88*28= 2464 cm^2 |
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| 2964. |
15.A rope makes 125 rounds of a cylinder with base radius 15 cm. How many time can it go rounda cylinder with radius 25 cm?(a)100(b) 75(c) 80dan(d) 6516.Cost of 8 apples is 180. How many apples can be purchased for30?(a)16(b) 24(c)22(d) 1412 |
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Answer» Total 🍎purchased=8*180/30=48 is right answer |
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| 2965. |
7. A cylindrical bucket, 32 cm high and with radius of base 18 cm, is filled with sandbucket is emptied on the ground and a conical heap of sand is formed. If the heigtconical heap is 24 cm, find the radius and slant height of the heap. |
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| 2966. |
RILL.Ans.(3)(1)13 (2)17 (3)9 (4)715.7 का घन का इकाई अंक क्या होगा:(1)9 (2)7 (3)6 (4)346. यदि a=-1 और b = 2 तो ab + b का मान होगा :(4)3Ans. (4N___(15(2)(2(3)2 (4)3(3)2Ans.(T |
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Answer» 45. 3 is correct46. 3/2 is correct. 45 .3 is correct and 46.3/2is correct 45.3/2.......... is best. 3..................................... option 3 is the correct answer 3/2 is the corrct answer 45.option (3) is correct answer46.3/2 is correct answer 45.3 is right answer 3 option is the correct answer 3 is the correct answer 45.option (4).3 is correct46.option (1).3/2 is the correct answer. iska correct answer 3/2 question no 15 ka answer option number (4) yani 3ho question no. 16 ka answer hoga option number (1) yani 3/2 45.==3. 46==3/2. 1 . ii2iii is right answer 🌙⭐ ques.45》7^3=343 then ikai ka ank=3 ques.46》(-1)^2 + 2^(-1) =1+1/2 =3/2 45 Answer. 346 Answer. 3/2 15 ka ans hai 316 ka ans hai 3/216 ka ans h option 3 is correct I am sure 45. 3 is correct46. 3/2 is correct 45 ka ans hai (4) 346 ka ans hai (1) 3/2 45.(4)3 is right answer 46.(1)3/2 is correct answer 45.3 is correct answer 45) 3 is the correct answer46) 3/2 is the correct answer 45. 3 is Ans 46. 3/2 Ans Q. 45 answer 7×7×7=553 so 553 ka ikayi ank is 3 so answer is 3 3 is correct answer option (4) 45.3 correct.......... 46. correct answer 2/3 45. ka option (4) is correct answer 46. ka option (1).3/2 is the correct answer. 45. ka answer 3 46. ka answer 3/2 hoga 45ques =3 is the right answer46ques= 1 is the right answer 44.3 is correct and 46.3/2 is correct answer Q.No.45 answer is 3; 7×7×7 =343 (3)and(2) is right answer the answer is option number 4 3/2 is the correct answer 7 ka ghan ekai enk3 hoga A=1 and b=2 to =ab+ba=a ka maan =1hai and b maan 2 to =1+2=3answer.is right answer hoga 7×7×7=343 so last number be 3 45. 3 is correct answer 3 is correct answer 45.3 correct and46.3/2 correct answer question no 45. 3 is correct (45) 3 is correct.(46) 3/2 is correct 3 is correct ............ 3/2 is the correct answer 45. 3 is correct46. 3/2 is correct answer 1ans hai 4 2 ans hai 2 45.=3, 46.=3/2 answer option ( A ) , 3/2 is correct 45 . option (4) 3 is correct 3 is the right answer. 3 2 pahla wala Aayega 45 questions ka answer 3 h 46 questions ka answer 3/2 hoga q46 ka and point1 hai [1] is correct answer a & b ka value put kizia[-1]^2+[2]^-1 =1+1/2=3/2 answer q.no. 457×7×7=343 digit in unit place=3 45ans is (4)3and46ans is(1)3\2 45= 3 i.e,645= 3 i.e 2 correct option is A 7 ka ghan ka uni digit 3 hoga 45.3 is correct answer46.3/2is correct answer (4)3 Q.45. 7×7×7= 49×7= 333 (4) ✓Q.46. 3/2 (1)✓ 3/2 hoga iska answer 1) answer is 3 and 2) answer is 3/2 45 and 46 is write answer 3 45.) 4th option46.) 1st option ans.45. ( 4)3ans46. (1)3/2 45.3 correct and 46.3/2 is the answer 16th qu..ka ans 2/3 hai.......option 2 is crct 45._(4)_346._(2)_(2/3) 46._(2) 45 =3 is correct46=3/2 is correct 45- 3 option is correct46- 1 option is correct 45.3 is correct and 46.3/2 is correct 45.me option no. 4 is right answer Question no. 47 me 3/2 is right answer 7×7×7=343so unit digit is 3 1+1/2=3/2 45. 3 is correct and 46. 3/2 is correct 2/3 answer hoga hiiiiiiiiiiii 45 option 4 is correct 46 option 1 is correct answer is (4).3 is a correct answer iska answer 3 hai uper and nichaye dono ka 45. (4) 3 ans46. (1)3/2 ans 45 ma option 4 sahi hai and 46 ma 1st options Sahi ha 45. 3 is correct46. 3/2 is correct 45 .3is correct and 46.3/2 is correct 45. (4) 3 is correct46. (1) 3/2 is correct 3 is the correct answer answer no 1 : option no 4 answer no 2: option no 1 |
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| 2967. |
35. Find three consecutive numbers whose sum is 108.Section:-D |
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| 2968. |
\frac{-(4-3 \sqrt{3})(4-3 \sqrt{3})}{(1)^{2} \cdot(2 \sqrt{2})^{2}}=\frac{-(4-3 \sqrt{3})}{16-27} |
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| 2969. |
le 3.2 The position of an objectmoving along x-axis is given by x a+bewhere a 8.5 m, b 2.5 m s2 and t ismeasured in seconds. What is its velocity att-O s and t 2.0 s. What is the averagevelocity between t # 2.0 s and t:40 s?amp |
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Answer» X = a + bt^2v = 2bt Velocity at t = 0 is 0Velocity at t = 2s is = 2*2.5*2 = 10 m/s At t = 2sx = 8.5 + 2.5*2^2x = 18.5m At t = 4s x = 8.5 + 2.5*4^2x = 48.5m Average velocity = (48.5 - 18.5) / 2 = 15m/s |
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| 2970. |
((3/4)*3)2÷(3/4)2×(1/3)-2×(1/6) |
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| 2971. |
5 ^ { 2 } + 7 ^ { 2 } + 9 ^ { 2 } + \dots + 39 ^ { 2 } |
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Answer» please tell me easily. Not understanding for me. |
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| 2972. |
((3/4)^2)^(-4)*(((-3)/4)^(-3))^(-2) |
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Answer» bro 16 heee 9 |
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| 2973. |
7. The volume of a cuboid is 3600 cm3 and its height is 12 cm. The cross-section isawhose length and breadth are in the ratio 4:3. Find the perimeter of the |
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Answer» Let l =4x B=3x h =12cmV = L×B×H=3600 or 4x×3x×12 =3600 12x²×12 =3600 x² = 3600 \12×12 or x² =300\12or x² =100\4 =25or x = 5then L =4×5=20 and B=3×5=15L=20 B =15 ans. |
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| 2974. |
5*25^(n %2B 1) - 25*5^(2*n) |
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| 2975. |
5^(2*x %2B 1)/25=125 |
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Answer» X= 2 is the correct answer of the given question x=2 is the correct answer |
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| 2976. |
x^2 %2B 1/(25*x^2)=9*(2/5) |
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| 2977. |
(text*(((-(11*i %2B 2))/25)*(a*(d*n))))*((-i %2B 2)/(-2*i %2B 1)^2) |
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| 2978. |
5/(-sqrt(2) %2B 3) - 3*sqrt(2)/(3 %2B 2*sqrt(3)) %2B (4*sqrt(3))/(-sqrt(2) %2B 2) |
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Answer» [4root(3)/2 - root(2)] - [3root(2)/3 + 2root(3)] + [5/3 - root(2)] = [4root(3)(2 + root(2))/(4-2)] - [3root(2)(3 - 2root(3))/(9 - 12)]+ [5(3 + root(2))/(9 - 2)] = 2(2 + root(2)) + root(2)(3 - 2root(3)) + 5(3 + root(2))/7 = 4 + 2root(2) + 3root(2) - 2root(6) + 15/7 + 5root(2)/7 =(4 + 15/7) + (2 + 3 + 5/7) root(2) - 2root(6) = (28 + 15)/7 + (14 + 21 + 5)/7 root(2) - 2root(6) = 43/7 + 40root(2)/7 - 2root(6) |
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| 2979. |
hether the number is even or odd:30(b) 1375(c) 7 003(d) 66 358 |
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Answer» (a),(d) are even since divisible by 2 and (b),(c) are odd since not divisible by 2 |
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| 2980. |
she drawncorrey1orm a linearExercise 5w the following pairs of angles as adjacent angles. Checkwhether theyfomm inc35°14090°90 |
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| 2981. |
a)Perform the following steps listed below and check whether the answormultiple of ,Step-1 Choose a numbser between 100 and 1000Step 2 Interchange its first anad last digits to make another numberStep 3 Subtrasct the smull mumber from the largest mamberStep-4 Repeat slep.21 the number (tauncul in¡tcp-3Step-5 Now add the numbers otained in step-3 and wepTry with scone䞝her starting number between 100 and 100 and teckw hether the answer is a again a multuple of |
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Answer» 1) 123 2) 321 3) 321-123 = 198 4) 891 5) 198+891 = 1089 1089/9 = 121 its too short how can u solve |
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| 2982. |
Is 16/3cm Find its perimeterSECTION :B25The area of an equilateral &hether the point (3,2) is on |
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| 2983. |
Choose the correct option for the given equationWaa2ab + b?2.The equation is true for all the values of a and b.The equation is true for all the values of a but only fewvalues of blThe equation is true for all the values of b but only fewvalues of aThe equation is not true for all the values of a and b. |
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Answer» the first option is correctthe equation is true for all values of a and b however there is an exception in case a and b are matrices Option A(a+b)² = a² + 2ab + b²The equation is true for all the values of a & b. |
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| 2984. |
MATHEMATICS0.51001 .Assertion: 0.5% ofa is 3-,--kReason: p% of x x, where x number and p-required percent.a) Both A and R are true and R is the correct explanation of Ab) Both A and R are true but R is not the correct explanation of Ac) A is true but R is false100d) A is false but R is true |
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Answer» option a is correctBoth A and R are true and R is the correct explanation of A |
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| 2985. |
1) State whether true or false. Correct the false3) Hefollstatements.(i) Three vertices of a quadrilateral aysometimes be collinear |
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Answer» (i) False Three vertices of a quadrilateral cannot be collinear. true because opposites side are make the the three vertices |
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| 2986. |
Q6.State whether True or False(i) All rhombuses are parallelograms.(ii) All parallelograms are trapeziums.(iii) All squares are not parallelograms.(iv) All squares are trapeziums. |
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Answer» I) True2)False; All trapeziums are parallelograms, but all parallelograms can’t be trapezoid.3)False; all squares are parallelograms4)True thankd😀😁😂 |
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| 2987. |
wire.7.Find the curved surface area of a right circular cone of height 15cm and base diameter is 16 cm. |
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Answer» CSA = π × r × l = (22/7) × (8) × √{(15)^2 +(8)^2} = (22/7)×8×17 = 267.4 cm^2 |
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| 2988. |
Find the volume, curved surface area and the total surface area of ahaving base radius 10.5 cm and height 18 cm. |
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| 2989. |
1. If base of a parallelogram is 18 cm and its height is 11 cm, find its area. |
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Answer» galat answer hai bhai |
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| 2990. |
Da...IntegersHOIVState whether true or false. Do working and give examples to prove yourSum of any integers is always greater thantheir difference.2. (-28 +46) + 46+ (-28) |
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Answer» The answer of this questions are 1) is true and 2) false option 1 is true and 2 is false is the correct answer of the given question the answer if the question are;(1) true.(2) false. |
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| 2991. |
5% more is gained by selling a cow for 350 than by selling it for340. The cost price of the cow is |
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Answer» Let Cost price of the article = Rs XWhen SP is Rs 340, then gain %={(340−X)/X}×100When SP is Rs 350, then gain %={(350−X)/X}×100Hence Additional % gain {(350−X)/X}− {(340−X)/X}×100Hence {(350−X)/X}×100− {(340−X)/X}×100 = 5→35000−100− 34000+ 100X) = 5Xor 5X = 1000or X = Rs 200 |
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| 2992. |
1 रमेश एक वस्तु ₹ 434 में बेचकर 24% लाभकमाता है। रमेश ने वह वस्तु किस कीमत परखरीदी थी? [UP Police (Constable) 2018](a) ₹350 (b) ₹ 360 (c) ₹340 (d) ₹ 375 |
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Answer» simple solution..,434*100/124=350 A, option is correct answer a. 350 is the right answer a.350 is the correct answer 350 is the right answer a is the correct answer rs.350 is the right answer. ,350 is the right answer x×124/100=434x=434×100/124x=434×50/62x=217×50/31x=7×50x=350is the right answer |
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| 2993. |
(c) gainsR 100d) galls24, if 5% more is gained by selling an article for340, then the cost350 than by selling it forof the article is:nISC |
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| 2994. |
53. A एक घड़ी B को 10% लाभ पर बेचता है. B उसे 50% के लाभ परC को दे देता है. यदि A ने घड़ी 200 रु० में खरीदा है, तो c के लिए।इसका लागत मूल्य क्या है?(1) 300 रु० (2) 320 रु० (3) 330 रु०(4) 350 रु० (5) इनमें से कोई नहीं |
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Answer» 330. ...... .. option no.(3)-330 rs |
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| 2995. |
at a mother dairy vegetable booth.Mrs. Khanna bought the following vegetables:Price/kg325VegetablesPotatoesOnionsPeasCarrotsCauliflowerPotatoesOnions 3 kg;33037034032peas į kg:Carrots 14 kg.She gave a 500-rupee note to the man at the counter. How much balance did she getCompleto |
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| 2996. |
25B tan 6 + sec 6 = x, सिद्ध करें कि 509 न ZX |
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| 2997. |
ad Dthe following prodesoch rumba, theolmak cair ofby rounding ofnearest burderedvin-123 264 X 1917 -1914.5 X 158 =11101 302& 179=111392138 =11124271 339 -1 |
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Answer» (7) 46248=46200(8) 112728=112700(9) 66834=66900(10) 91111=91100(11) 54096=54100(12) 91869=91900 7) 278 x 128=35584. 8) 284×147=41748, 9)509x179=91111, 10)392x138=54096, 11)271x339=91869 |
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| 2998. |
Hello and thank you for helping me eproblems that l circled are the problemsIneed help with and make sure you fothe directions!!Estimate by rounding S4. 688, 392 x 46 |
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Answer» 7. 79 ~ 80 56 ~ 60 79 × 56 ~ 80 × 60 ~ 48008. 392 ~ 390 46 ~ 50 392 × 46 ~ 390 × 50 ~ 19500 Thank you so much!😁 |
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| 2999. |
Xp X (509 I =119 |
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| 3000. |
which is in the two given vessels.H. A wooden pole is 7 m high and 20 cm in diameter. Find its weight if the wood weighs225 kg per mnlume is cut from a wooden cuboid of length 30 cm andli alinder and the volume |
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Answer» If you find this solution helpful, Please give it a 👍 |
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