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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 3201. |
6. How many prime factors are there inprime factorisation of 1001? |
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Answer» 1001 = 7 × 11 × 13 in prime factors |
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| 3202. |
2. Find the area of each of the followingparallelograms.12 em3 cm8.4cm6.8 em |
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| 3203. |
Two circles of radii S em and 3 em intersect at twopoints and the distancebetween their centre is 4 em. Find the length of common chord. |
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Answer» Let the radius of the bigger circle be 'R' and the radius of the smaller circle be 'r'.It is given that R=5cm=OB and r=3cm=OD and AB is the chord whose length we have to find.AD=BD and OD⊥AB(radius is perpendicular to a chord and it divides the chord into two equal parts)therefore, ΔODB is a right angled trianglewhere, OD²+BD²=OB² (3)²+BD²=(5)² 9+BD²=25BD²=25-9BD²=16BD=4cm Since AD=BD=4cm therefore, AB=AD+BD AB=4+4 AB=8cm no it is wrong the length of common cord is 6cm |
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| 3204. |
side(a) 12/3 em(b) 1B42 om(c) 18 em |
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Answer» kindly post the question clearly! Answer question is not clearly visible, so I am unable to answer it. |
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| 3205. |
74. Suppose B takes 10% less time than A. to cover the same distance. If A walks at a9 km/h, then the speed of B in m/sec., is : |
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| 3206. |
Profit and Loss159vendor bought lemons at 6 for a rupee and sold them at 4 for a rupee. His gain% is10.(b)23(a) 50%40%(c) 33 %(d) 16%3,Hint. Suppose he bought 12 temons. |
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| 3207. |
é3 tong. = 3 sino , then Rnd . he value ob |
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Answer» thanks |
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| 3208. |
If a tower 30m high casts a shadow 10v3m tong on the ground, then what, is the angte ofelevation of sun. |
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| 3209. |
3. A hostel had rations for 60 days for 500 students. After 12 days, 300 more students join the hostet. Howtong wil the remaining rations last ? |
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Answer» It's a question of inverse variationLet for n days ration last Then as per given condition60*500 = 12*500 + n*80060*5 = 12*5 + n*8300 - 60 = n*8n = 240/8 = 30 Ration last for 30 days more |
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| 3210. |
3. Construct an isosceles right-angled triangle ABC, where m<ACB = 90° andAC = 6 cm. |
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| 3211. |
(5)A side of an isosceles right angled triangle is x. Find its hypotenuse. |
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Answer» By phythagorus theorem h^2=a^2+b^2=x^2+x^2=2x^2Then h=√2x |
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| 3212. |
Construct an isosceles right-angled triangle ABC, where mZACB 90 andAC 6 cm. |
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| 3213. |
show that (7,10),(-2,5) and (3,4) are the vertices of an isosceles right angled triangle |
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Answer» but how did u probe that it's a right angle triangle??? |
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| 3214. |
Q.2)Prove that the points (-3, 0), B(1, -3) and C(4, 1) are thevertices of an isosceles right-angled triangle. Find the area of this triangle. |
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Answer» AB=root(16+9)=root(25)=5BC=root(9+16)=root(25)=5=ABAC=root(49+1)=root(50)=5root(2)so AB^2+BC^2=AC^2so these are the vertices of isosceles right angled trianglebase and height is AB and BCso area=1/2×5×5=25/2=12.5 |
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| 3215. |
3 ँokSreck ¥ 5 X5 के |
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Answer» Your question is wrong..... |
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| 3216. |
| O REDMI NOTE 5 PROMI DUAL CAMERA 2019/1/ |
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Answer» 2tan30/(1+tan30*tan30) = (2*1/√3 )/ (1+1/√3 * 1/√3) = (2/√3 )/ (1+1/3) = (2/√3)/(4/3) = √3/2 |
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| 3217. |
PROFIT AND LOSS SIMPLE INTERESTREDMI NOTE 6 PROMI DUAL CAMERALEqjat brrowed ? 15,000 from a bank at 12% per annum. He paid25,800 to thebank. Find the time for which the money was borrowed |
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| 3218. |
the missing number.2019/4/16 14:63272 ) 3(6) 25(d) 22REDMI NOTE 7 PROAI DUAL CAMERA |
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Answer» 81 is the right answer 7×9=638×9=729×9=81your answer is 81 81 is the right answer |
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| 3219. |
2REDMI NOTE 5 PROMI DUAL CAMERA |
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Answer» 2101 is your Answer mate 2101 is your answer mate |
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| 3220. |
123.5 352a+ aShot on Y83 Provivo dual camera |
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| 3221. |
6/N 610Activity: If two coins are tossed simultaneouslyHT, TH,(i)Event A : at least getting one head.A-HH(ii) Event B to get no head. |
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Answer» If two coins are tossed S = {HH, HT, TH, TT} (1) Getting at least one head A = {HH, HT, TH} (2) Getting no head B = {TT} |
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| 3222. |
18. The internal dimensions of a closed box, made up of iron 1 cm thick, are24 cm by 18 cm by12 cm. Find the volume of iron in the box. |
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| 3223. |
A cylindrical tube open at both ends is made of iron 3 cm thick. If the external diameter is 42 cm and length is 140 cm .Find the volumn of metal used in it. |
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Answer» Given, thickness of iron =3cm external diameter = 42cm Length of tube = 140cmWe know, volume of hollow cylinder = πh(R²−r²)∴ internal diameter = external diameter−2×thickness of iron= 42−2×3 = 42−6 = 36cm => Outer radius(R) = 42÷2 = 21cm inner radius(r) = 36÷2 = 18cm∴ Volume of hollow cylinder = πh(R²−r²) = 3.14×140(21²−18²) = 3.14×140×117 = 51433.2 cm³ |
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| 3224. |
wall cocentimetres of iron are there in an open box whosesions are 36 cm, 25 cm and 16.5 cm, the iron beingout? If 1 cm of iron weighs 15 g, fird the weight11. How many cubiciron15 cm thick throughof the empty box in kilograms. |
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| 3225. |
equal?10. The exterior angle at C of a ΔABC is equal to 120°. Find the measure of all the anglesof the triangle if <A <B. What type of triangle is this? |
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| 3226. |
9.Write the prime factorisation of 15470 |
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Answer» The number15470is a composite number so, it is possible to factorize it. The prime factorization of15470= 2•5•7•13•17. The prime factors of15470are 2, 5, 7, 13 and 17. |
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| 3227. |
value of r.3 cms em |
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Answer» Total is 8 and the radius of bigger circle is 3cm hence diameter is 6cmHence remaining will be 8-6=2cmthat means diameter for smaller circle is 2 cm hence radius will be 2/2=1cm |
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| 3228. |
Construct the following quadrilaterals:(6) MQuadnilateral MORE(u) Quadrilateral PLANPL = 4 cmLA 6.5 cmOR 4.5 cm2M = 600P 90<A= 1100= 1050R 105) Parallelogram HEAR(iv) Rectangle OKAYHE 5 emEA 6cmOK = 7 cmKA 5 enm<R = 85. |
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Answer» please crop one question and then send. we can't solve multiple question |
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| 3229. |
triangleWe know (AB) 11121or (BC) (AC 8Since() Here, the longer side is 11 cm ABBC (AC 5+8-25+6"У89121SinceThe triangle with the given sides is not a right triangloof theWorksheet 4The hypotenuse o, a right triangle is 17 cm long. If one of the remaining two sides,1 ol a tlength 8 cm, find the length of the third side.2. The length of the hypotenuse of a right triangle is 13 cm. If one of the side oftriangle be 5 cm long, find the length of the other sideThe length of two sides of a right triangle are equal. The square of the hypotenus800 cm2. Find the length of the each side.4. Two poles of heights 6 m and 11 m stand on a plane ground. If the distance betwtheir feet is 12 m, find the distance between their tops.5 Find the length of the diagonal of a rectangle whose sides are 15 cm and 8 cm..The foot of a ladder is 6 m away from a wall and its top reaches a window 8 m abonthe ground.If the ladder is shifted in such a way that its foot is 8 m away from the7. A right angled triangle s lsosceleos. I the square of the hypotenuse is 50 m2, what is the8. If the sides of a triangle are 3 m, 4 m and 6 m long, determine whether the triangle is a9. Verity whether the following triplets are Pythagorean or not.to what height does its top reach?length of each of its sides?right angled triangle.di8, 9, 10)(() (5, 7, 12)(iv) (5, 12, 13)(iii) (3, 4,(v) (9, 12, 15)152 |
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Answer» Please post single question as we are not allowed to answer multiple questions in a single query 4 question The length of one side of a right triangle is 4.5cm and the length of its hypotenuse is 7.5cm find the length of its third side plz solve this q uestion |
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| 3230. |
A window of a house is metre above the ground. From the window, the angles ofelevation and depression of the top and bottom of another house situated on theopposite side of the lane are found to be α and β respectively. Prove that the heightof the house is w (1 + tan α tan!) met res.ake is 19height dINCERT EXEMPLAR |
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Answer» Like if you find it useful |
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| 3231. |
If the difference between the sides of a right-angled triangle is 3 cm and its area is 54 cm, find itsperimeter12. |
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| 3232. |
Line lis the bisector of an angle Z A an) B is anypoint on i BP and BQ are perpendiculars from Bto the anns of Z A (see Fig. 7.20) Show thatS.) BPB0 or B is equidistant from the armsof ZAia 7.22 |
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| 3233. |
A room is um 20cm long and3cm 65 cm wide. How many soumeter of carpet is needed to conthe floor of the room 3 |
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Answer» length=4m20cm =4+20/100 =4.2mwidth=3m65cm =3+65/100 =3.65mTherefore area of carpet=length×breadth =4.2m×3.65m =15.33m 15.33 is the correct answer 15.33 is the correct answer. |
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| 3234. |
8.Anironpipe20cmlonghasexteriordiameterequalto25cm.If the thickness of the pipe sthe whole surface of the pipe3168 cm?) |
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Answer» Height of pipe = 20 cmExternal diameter = 25 cmExternal radius = 25/2 = 12.5 cmInternal diameter = 25 - (1 + 1)= 23 cmInternal radius = 23/2 = 11.5 cm Let the external radius be R and the internal radius be r.Total surface area of the pipe = 2πh(R + r) + 2π(R² - r²)⇒ 2*22/7*20(12.5 + 11.5) + 2*22/7*{(12.5)² - (11.5²)⇒ (44*480)/7 + (44*24)/7⇒ 21120/7 + 1056/7⇒ 22176/7= 3168 cm²So, the total surface area of the pipe is 3168 square cm. |
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| 3235. |
20. An iron pipe 20cm long has exterior dian eter equal to 25cm. If the thickness of the pipe is lcm,find the whole surface of the pipe. |
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Answer» Solution:- Height of pipe = 20 cmExternal diameter = 25 cmExternal radius = 25/2 = 12.5 cmInternal diameter = 25 - (1 + 1)= 23 cmInternal radius = 23/2 = 11.5 cm Let the external radius be R and the internal radius be r.Total surface area of the pipe = 2πh(R + r) + 2π(R² - r²)⇒ 2*22/7*20(12.5 + 11.5) + 2*22/7*{(12.5)² - (11.5²)⇒ (44*480)/7 + (44*24)/7⇒ 21120/7 + 1056/7⇒ 22176/7= 3168 cm²So, the total surface area of the pipe is 3168 square cm. |
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| 3236. |
(2) Find the volume of the cone with the base radius6 cm and height 7 cm. | πSolution: |
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Answer» V=πr^2h/3=3.14×(6)^2(7)/3=263.893cm^3 |
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| 3237. |
khilesh is 150 cm tall. When he raises his arms up he touches 215 cm. How long iskhilesh's arm? |
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Answer» Akhilesh height = 150cmTotal height ( including arm) = 215cmLength of arm = (215 - 150)cm = 65cm |
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| 3238. |
find the cost of constructing a wall 8 m long 4m high and 20cm thick at the rate of rs25 per m cube |
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Answer» Given l=8m, h=4m and b=20/100 = 1/5m then volume of wall = lbh = 8×4×1/5 = 32/5 = 6.2m³given per m³ = 25rs per 6.2m³ = 6.2×25 = 160 Rs |
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| 3239. |
4. Tina has 17m 64cm long lace. She wants to cute 4m 20cm length of pieces from this. How manypieces can she cut? |
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Answer» 17m 54cm -4 m 20cm=13 m 34 cm 17.64/4.20= 4.2 therefore she can cut 4.2 pieces or 4 pieces from lace. 17.54/4.20= 4.2 pieces 17.54/4.20=4.2 pieces |
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| 3240. |
find the cost of painting all round outer surface of the box with lid 60cm long,40cm wide,and 30cm high at 50p per 20cm |
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| 3241. |
Find the area of a right-angled triangle whose base is 5 cm and the hypotenuse is 13 cm.Let XYZ be the given triangle with XZ = 13 cm and YZ = 5 cm.By Pythagoras theorem, |
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Answer» Find the height of triangle using pyth theoramH^2 = P^2 + B^213*13 = P*P + 5*5169 - 25 = P*PP = 12 cm Area of triangle = 1/2*B*H = 1/2*12*5 = 30 cm^2 |
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| 3242. |
A right angled triangle whose sides 12 cm and 5 cm is mabout its hypotenuse. Find the volume and the surface area of the Cialcone so formed.the base and height of solid right circular cylinder |
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| 3243. |
4013c in the adjoining Figure, XYll BC. Find the values of x, y. zzaah nt the three angles. |
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Answer» ABC is a traingle so <Abc+<bca+<cab=180°.so z=110°and z and y is corresponding angles..so z=y or y=110°.And AXY is a traingle so <axy+<xya+<yax=180°so x=30°. |
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| 3244. |
[NCERT EXEMLparts is 4623.s of a triangle are in AP. The greatest angle is twice the least. FindINCERT EXEMPLangles. |
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Answer» Let a - d, a, a + d be the three angles of the triangle that form AP.Given thatthe greatest angle is twice the least.Now, 2(a - d) = a + d2a - 2d = a + da = 3d ---------------(1)Now by angle sum property,(a - d) + a + (a + d) = 180°3a = 180°a = 60°----------------------(2)from (1) and (2),3d = 60°d = 20°Now, the angles are,a - d = 60°- 20° = 40°a = 60°a + d = 60° + 20° = 80° |
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| 3245. |
Q. 4. If |u3a,l=5, then find the value of 13c3b3d |
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| 3246. |
Find the area of a right-angled triangle, the radius of whosedircumcircle measures 8 cm and the altitude drawn to the hypotenusemeasures 6 cm.5. |
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| 3247. |
16.A die is tossed twice. 'Getting a number greater than 4' is considered aprobability distribution of the number of successes. |
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| 3248. |
One Number is chosen randomly from the integers 1 to 50. The probability that it is divisible by 4 or 6 is. |
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| 3249. |
One number is chosen randomly from the integers 1 to 50.Find the probability that it is divisble by 4 or 6 |
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| 3250. |
(-6*a^12*(b^16*c^20))*(2*(a^10*(b^2*c^3))) |
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Answer» -12a^22.b^18.c^23 is the answer -12a^22.b^18.c^23 is the right answer |
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