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Equilateral triangle (a=b=c=8)Heron's formula,s=a+b+c/2=8+8+8/2=24/2=12

Area=√(s(s-a)(s-b)(s-c)√(12(12-8)(12-8)(12-8))√(12)4*4*4√(3*4*4*4*4=16√3cm²

Also,Area of triangle=(1/2)*base*altitude16√3=(1/2)8*altitudealtitude=4√3cm

thanku

Perimeter of equilateral traingle is 3× side

1

solution from ith diagram

a)The first angle of the triangle is 90 degree as it is right-angled

As the triangle is isosceles, the other angles are 45 degree as its two opposite sides are equal.

b)

in right angled triangle one angle is 90 and other two angle are equal let them be xso x+x+90= 1802x = 90x = 45b) is correct option

a)The first angle of the triangle is 90 degree as it is right-angled

As the triangle is isosceles, the other angles are 45 degree as its two opposite sides are equal.

b)

Since the hypotenuse of the right isosceles triangle is 16√2. the the legs of the triangle (represented byaain the illustration) are16units each.The area of a right isosceles triangle can be obtained from this formula:A=a^2/2Substituting:A=16^2/2⇒256/2⇒128squareunits.

a) 9a+6=24

b) b/7=5

c) 5y-12=40

27 is the right answer

27 is the right answer

Send in detail

Thx

prabability is 1-0.6=0.4

since 1 x 1= 12 x 2 = 43 x 3 = 94 x 4 = 165 x 5= 256 x 6 = 367 x 7 = 49

Therefore 36 is the perfect square between 30 and 40.Since 7 x 7 = 49 and 8 x 8 = 64, therefore there is no perfect square between 50 and 60

square root=30x30=900, 31x31=961; 32x32=1024, 33x33=1089; 34x34=1156; 35x35=1225; 36x36=1296; 37x37=1369; 38x38=1444; 39x39=1521; 40x40=1600

50 to 60; 50x50=2500;51×51=2601, 52x52=2704;, 53x53=2809; 54x54=2916; 55x55=3025; 56x56=3136, 57x57=3249; 58x58=3364, 59x59=3481; 60x60=3600

the perimeter of this this frame would be the answer so it is a rectangle then the perimeter of a rectangle is 2(l+b)2(40+25)130 cm

l x h x h; L=15 m 5 CM =15.05m, b=12 m 50cm=12.50 m, h=7m 40cm/7.40 m;;V=LXBXH=15.05X 12.50 X 7.40=1392.125 m^3

2

these equations cannot be solved

Multiplaying 1st eqn by 618x-30y=120Multiplaying eqn 2nd by 318x-30y=120Both eqn are same. Therefore Infinite ans can be found....

3x - 5y = 20 and 6x - 10y =40

x = 20 + 5y /3 .............1

6x - 10y = 40

now put .........1 in 6x - 10y = 40

6(20+5y/3) - 10y =40

2(20+5y) - 10y = 40

40+10y - 10y =40

40 = 40

0

infinite many solutions

Let weight of child be x and weight of man be y

So, according to question

y = 4x

Sum of ages is 28 and difference is 2. Find the ages of the two persons. x+y = 28y-x = 2=> x=13 years old.

Triangles. If the measures of the corresponding sides of two triangles are proportional then the triangles are similar. ... Lastly, if two triangles are known to be similar then the measures of the corresponding angle bisectors or the corresponding medians are proportional to the measures of the corresponding sides

red line is x = 2blue line is y = -3

(4) Solution hai mere dost

unique solution is the awnser

3y+2x=12xy........(1)2y+3x=13xy........(2)multiply (1)by 2and (2) by 36y+4x=24xy6y+9x=39xy5x=15xy1/3=yput y=1/3 in (1)2+4x=8x2=4x1/2=x

unique solution intersection lines consistent

this is an unique solution because lines are intersection consistant

7 is your answer because 6 is aand b is your 8 so c is your 7

a+b+c=14. c=7ddddddddddd

answer 6. hoga

this question's answer is seven

this question answer is seven. seven is a right answer

answer 7 hoga....,. ....

7 is the correct answer

c is the correct answer.........

d is the correct answer.....

a+b+c=14 c=7ddddddddddd

A+B+C=14 c=7DDDDDDDDD

8 it is a write answer

7 answer correct gai

the answer of this question is 7

7 is correct it is right

8 is the exact answer for this question

answer is 8 using equality formula

correct answer is 7 option dddddddddddddd

7 it is a write answer

The right answer is7

correct answer is 8 (c)

9 it is a write answer

7sghffhchyhgcvxcgdg ccvhffh

compression between same sidethen a+b=6put this value in a+b+C=14 6+C=14 C==14-6 C=8option c

Q.no. 10Ans. (b) 6

6 I don't know but sorry

7 is the correct answer

7 is the right answer

Answer 7 hoga bhai sab

7DDDDDDddddddddddddddddd

4 &&&&

this question, answer is sevan7

7 is the correct answer of the given question

(a+b)=6(b+c)=7(c+a)=8(a+b+c)=14(a+b)+c=146+c=14c=14-6c=8

option no c hoga a b c d me (d) is the right answer

ddddddddddddddddddd=7

a+b =6 and a+b+c =14 14-6 =8 thus (c) 8

your answer is C=7 this

the answer is = seven

the question answer is seven

options number C is the correct answer please like my answer

d. 7.

c=4 it is a write answer

a+b+c=14C=?a+b=66+c=14C=14- 6 =8

I guess... ans is 7🤔🤔🤔🤔🤔

4is right answer the question

......................8

(d) 7 is the correct answer

option (d) 7 is right answer.

The right answer is 7

how worst are all of you the answer is 6

a+b+c= 14 than c = 8

a+b+c=14 and a+b=6so, (a+b)+c=14 6+c=14 c=8 (ans)

your answer is 7........

This is tha answar D

Let (a+b) = 6x.......(I)(b+c) = 7x.......(ll)(c+a) = 8x.......(lll)

(l)+(ll)+(lll)

2(a+b+c) = 21x=>2×14=21x

we get=> x = 4/3

Applying x value in above Equationwe get a = 14/3, b = 10/3 and c = 18/3.

for the given question answer of c=7

right answer for this question (d)

7 is the right answer

77777777777777777777777777

Given:

A right angled ∆ABC, right angled at B

To Prove- AC²=AB²+BC²

Construction: draw perpendicular BD onto the side AC .

Proof:

We know that if a perpendicular is drawn from the vertex of a right angle of a right angled triangle to the hypotenuse, than triangles on both sides of the perpendicular are similar to the whole triangle and to each other.

We have

△ADB∼△ABC. (by AA similarity)

Therefore, AD/ AB=AB/AC

(In similar Triangles corresponding sides are proportional)

AB²=AD×AC……..(1)

Also, △BDC∼△ABC

Therefore, CD/BC=BC/AC

(in similar Triangles corresponding sides are proportional)

Or, BC²=CD×AC……..(2)

Adding the equations (1) and (2) we get,

AB²+BC²=AD×AC+CD×AC

AB²+BC²=AC(AD+CD)

( From the figure AD + CD = AC)

AB²+BC²=AC . AC

Therefore, AC²=AB²+BC²

This theroem is known as Pythagoras theroem.