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1) 6+3/2 +2/3 + /62)63)7+2/104)3/ is the symbol of squareroot

leap year has 2 extra days than 52 weeks

so, probability for 53 sundays is 2/7 and probability of 53 Monday with 53 sundays is possible only when both sunday and Mondays takes the extra 2 days , out of those 7 pairs

so, probability is 1/7

Triple a sum so I = 2P 2P = P×16×T/100 T = 100/8 = 12.5 years

200-14(10) 200-14060 degree celsius

200-14 (10)200-14060 degree Celsius

(a-b)² = a² +b² -2ab.(X/2 - y/5)²= (X/2)² +(y/5)² -2(X/2)(y/5)= x²/4 +y²/25 -(2xy)/5

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Tank you mam

Let the first term of the given AP be ‘a' and the common difference be ‘d'. Then, the sum of first ‘n' terms of the AP is given by:

S(n)= n/2 {2a+(n-1)d} …….(1)

Here, it is given that:

S(p)=q and S(q)=p

Using (1), we get:-

q=p/2 {2a+(p-1)d}

and p= q/2 {2a+(q-1)d}

i.e. 2a+(p-1)d = 2q/p …..(2)

and 2a+(q-1)d = 2p/q …..(3)

Subtracting (3) from (2), we get:

(p-1-q+1)d= 2q/p - 2p/q

So, d= 2(q^2-p^2)/pq(p-q)

i.e.d= -2(p+q)/pq

Now, substituting the value of ‘d' in eq.n (2), we get:

2a + (p-1){-2(p+q)/pq} = 2q/p

i.e. 2a= 2q/p + 2(p-1)(p+q)/pq

This gives:

a= (p^2+q^2-p-q+pq)/pq

So, we have

S(p+q)= (p+q)/2 { 2(p^2+q^2-p-q+pq)/pq-(p+q-1) 2 (p+q)/pq}

i.e. S(p+q)= (p+q)/pq { p^2+q^2-p-q+pq-p^2-pq-qp-q^2+p+q}

So,S(p+q) = -(p+q). … :

thanks

please do this calculation in a expanded way please

u have given wrong answer for wrong statement

Principal = PSimple interest = P * 4/100 * 4 years = 0.16 P

Compound interest = P * (1 + 5/100)³ = 1.157625 P - P = 0.157625 P

Given, 0.16 P - 0.157625 P = Rs 228

P = Rs 94,736. 84

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A=p(1+r/100)n times then7500(219/200) 11times (beacuse() n/2=1+r/200then answeris=203544.45

D²+5D+6=0D²+3D+2D+6=0D(D+3)+2(D+3)=0(D+2)(D+3)=0D=-2,-3

2A = 3B = 4C = k A = k/2 B = k/3 C = k/4 A : B : C = k/2 : k/3 : k/4 = 6 : 4 : 3

lets compare all with constant kso 2A=3B=4C=kso A=k/2,B=k/3,C=k/4so A:B:C=k/2:k/3:k/4=6:4:3

A+3b-4c+4a-b+9c-2b+3c-a-(2a-3b+4c)=4a+8c-2a+3b-4c=2a+3b+4c

Product will be(12a + 17b) × 4c12a × 4c + 17b × 4c48ac + 68 bc

thank you

below are the coefficientsa)-a^2b^2c^2b)a^2b^2c^2c)-4ac^2d)-a^2b^2ce)-abcf)-4b^2g)-a^2ch)-4

3a + 5b - 4c + 2a - 5b - 4c = 5a - 8c

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Given a/b = 8/3

Then, 4a + 5b/4a - 5bDivide numerator and denominator by b

We get, (4a/b + 5) / (4a/b - 5) = (4*8/3 + 5)/(4*8/3 - 5)= (32 + 15) /(32 - 15)= 47/17

1)4 is the best answer

so it wrong answer don't use it

4 is the right answer

4 is the best answer

2/5 - (3/-5) or,2/5-(-3/5)2/5+3/5...... since [-(-)=+]5/51/1 or 1

thanks

Equations are: a) 3x - 1 = 10d) 3c +3 = 9

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not correct answer

7a + 14a = 21a

The coefficients are the same and therefore the two terms can be added.

-7a= 84a= (-84/7)a= -12will be the answer

a=1\4 is the right answer

a = 1/4 is the right answer

a= 1/4 is the correct answer me

a=1/4 is the correct answer

2 is the correct answer

64a^3-1=064a^3=1a^3=1/64a^3=1/4

a=1/4 is the right answer

64a³-27b³-144a²b+108ab²(4a)³-(3b)³-3(4a)(3b)[4a-3b]

(a)³-(b)³-3ab(a-b)=(a-b)³

(4a)³-(3b)³-3(4a)(3b)[4a-3b]=(4a-3b)³