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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 3801. |
What time was it 3600 seconds before 12 midnight? |
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Answer» 3600 seconds = 1 hour Therefore, the answer is 11 PM 11pm was it before 12 of midnight |
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| 3802. |
The angle of elevation of an aeroplane from a point A on the ground is 60°. Afteraflight of 30 seconds, the angle of elevation changes to 30°. Ifthe plane is flying atconstant height of 3600 /3 m, find the speed in km/hour of the plane. |
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| 3803. |
What time was it 3600 seconds before 12 midnight?7. |
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| 3804. |
be 12years old. What is the date foday?What time will it be 3600 seconds after 12 mid-night? |
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Answer» 3600 seconds= 1 hournow after 12 mid night= 1:00AM |
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| 3805. |
Questot ubuTDAn equilateral triangle of areas 4sqrt3 cm^2 shares same base with a square. What is the area of squaFind the ratio of area of triangle to that of square. |
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| 3806. |
एप रउन कद कर - oL= \j 7-4v3 1 बन ही |
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| 3807. |
The angle of elevation of a jet plane from a point A on the ground is 60°. After alight of 30 seconds, the angle of elevation changes to 30°.If the jet-plane is fAyingat a constant height of 3600/3 m, find the speed of the jet plane. |
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| 3808. |
An equilateral triangle of areas 4 \sqrt{3} \mathrm{cm}^{3} shares same base with a square. What is the area of square?Find the ratio of area of triangle to that of square. |
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Answer» area of equilateral triangle = sq.root(3)/4 * side2so, 4sq.root(3) cm2= sq.root(3)/4 * side2on solving we get side = 4 cmnow base of equilateral triangle is the side of a square.so, side of square = 4 cmarea of square = 16 cm2reqd. ratio = (√3) : 4 |
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| 3809. |
2. सभी खण्ड को हल कर।क) सिद्ध कीजिए कि 1(x)-2x+3. R में निरन्तर वृद्धिमान फलन |
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| 3810. |
दे कि N__ (क) समीकरण को हल कीजिए-- डिक 1एक J6—x =6Lt 2 अल |
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| 3811. |
।(तोय, दोनों गधों में -। के अलावा रागान राशि 5 से ।यही अज्ञात संख्या मूगताज ने सोच रखी थी। अंजू ने दिये गए ।बनाया तथा उपर्युक्त विधि से उसका हल ज्ञात किया। नगा ।हैं कि यदि किसी ने परिणाम में 60 बतया हो तो उसके द्वारा योहोगी?। ॐ भाग 1[देश गए क।जावया आप अ५ यह। क ।प्रश्नावली-11.21. तुला संतुलन में है तो x का भार बताओ?(+5)(15)(3+।-15-S10 |
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Answer» अगर संतुलन में दोनों परिस्थितियों में सामान हुआ x+5= 15x= 10 15 metre lamba bagiche ki Charon aur bahar se ek metre choura Rasta hai to raste kshetrafal nikaalen 15 metre lamba 12 metre chauda bagiche ke Charon aur bahar se ek metre choura Rasta hai to raste ki chetrafal nikale |
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| 3812. |
The angle of elevation of a jet plañe from a point A on the ground is 60. After aflight of 30 seconds, the angle of elevation changes to 30. If the jet. plane is flyingat a constant height of 3600 3 m, find the speed of the jet plane. |
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Answer» like the solution |
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| 3813. |
८0०59(1- ८०56) 1+ भा 8sin’0(1-sin®) 1+ ८056 21. (1) |
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Answer» Like my answer if u find it useful |
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| 3814. |
7"X If cot θ, evaluate:(1 + sin 0) (1-sin θ)(1 + cos 0) (1-cos θ)(i) |
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| 3815. |
equal functions?10. Iff, g, h are three functions defined from R to R as follows:(1) f(x) = x? (ii) 8(x) = sin & (iii) h(x) = x² +1u |
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| 3816. |
625x635) + 6625) X 65 |
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Answer» THE ANSWER IS - 42,500 18750 is the correct answer |
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| 3817. |
If tan-1(1)+cos-1()-sin-IX, thenfindthe value ofx.in X, then find the value of x. |
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| 3818. |
The value of1-cos2A+sin2A1+COS2A+sin2A=The value of 1.6082a+sin2A =Options :1 sinA2. COSA3. tanA4. cotA |
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Answer» 1-cos(2A) + sin (2A)___________________1 + cos(2A) + sin(2A) 1 - ( 1 - 2sin^2(A)) + 2sin A cos A_____________________________1 + 2cos^2(A) - 1 + 2sin A cos A 2sin^2(A) + 2sin A cos A______________________2cos^2(A) + 2sin A cos A 2sin A( sin A + cos A)___________________2cos A(cos A + sin A) = sin A / cos A = tan A 3.tanA is the right answer |
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| 3819. |
In a school there are 50 students in class VI A. 88% of the students passeMathematics test. The same number of boys and girls lated in the oxam.t 42of the total students are girls, how many boys passed the test?2.s a |
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Answer» In a school there are 50 students in class 6- A 88℅ of the students passed a mathematics testso 16% failed the same number of boys and girls failed in the exam. 42℅ of the total students are girls42℅ of the 50 students are girlsso [42/100*50]=21 girls so 50-21=29 boys 88%0f 50=44 students passedwe see that 6 failed the same number of boys and girls failed in the exam.so 6/2= 3 boys failed |
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| 3820. |
An equilateral triangle of areas 4v3 cm' shares same base with a square. What is the area of square?Find the ratio of area of triangle to that of square. |
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| 3821. |
An equilateral triangle of areas 4/5 cm' shares sarne base with d square. What is the area of square?Find the ratio of area of triangle to that of square.e? |
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| 3822. |
1. Find1 1247(1) 3+271 144(1) 5+32.Find the recital1.1 |
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| 3823. |
1-8, find the values of (a) x2+12fx+-=-3, find the values of (a) x2 +b) *.1,2.9, If a +2b-5 2O +9y2-9 and xy -1, find (2x +6y)11 Ifx- y 12 and xy 6, find x +y5, and ab 2, find a +4b4 |
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Answer» Crop only the question that you want a solution for. We will not be able to provide solutions to multiple questions. |
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| 3824. |
(6) समीकरण 2y + 5 =3y-10 को हल कीजिए।3 |
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Answer» 2y+5=9y-30 ,. 9y-2y=-30-5=7y=-35=y=-5answer write answers y=five hoga 2y+5=3(3y-10)2y+5=9y-309y-2y=30+57y=35y=5 |
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| 3825. |
MATHEMATICSTHESEFind:(1)Find ox1. Find the sum:2. Find |
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Answer» (I) -2/3 (ii) 82/99 (iii)34 |
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| 3826. |
Q. 1. Find:(1) 6421 |
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Answer» (64)^1/2= (2*2*2*2*2*2)^1/22*2*2= 8 |
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| 3827. |
Find the maximum value of 11 + sin 01 1 111 +cosI2find the simn |
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| 3828. |
16 Mathematics16. x+1+-I4then the value of x is15a)17b)d) 21. (b)Explanation256 = 2x2x2x2Ă2x2x2x2 |
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| 3829. |
EXERCISE- 2.2(ii) (15625)1/61. Find the value of each of the following(1) (9)12(ii) (625)/22. Find the value of :(1) (32768)1/5 (11) (279936173. Find the value of:(1)(it)21613314. Evaluate :0(1(390625 86561)90625(1)() 1771561)1176496561 |
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Answer» 1.1.9×1/2 = 4.52.625×1/2=312.53. 15625×1/6=2604.16666 2.1.6553.62.39990.8 57143 3. 1.0.05762.0. 0331260821 4.1.0.76207895132.0.0011616873 (9) 1.1. 9x1/2=4.52.625×1/2=312.53. 15625×1/6=2604.16666 in an no no no no no nn no no ch ch I'm |
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| 3830. |
16A Text Book of Mathematics-X1-cos-θ,432-sin2θ |
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| 3831. |
vx+1+vx-1 2, then find theIf x > 1 and= 2, then find thevx+1-w-1value of x. |
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Answer» what is it in iit in 9th class |
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| 3832. |
3Mathematics Class XI5. ter te,, et [Find the values of t1616 |
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Answer» Sin²π/8+sin²3π/8+sin²5π/8+sin²7π/8=sin²π/8+sin²3π/8+sin²(π/2+π/8)+sin²(π/2+3π/8)=sin²π/8+sin²3π/8+cos²π/8+cos²3π/8=(sin²π/8+cos²π/8)+(sin²3π/8+cos²3π/8) [∵, sin²Ф+cos²Ф=1]=1+1=2 Ans. |
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| 3833. |
349. The volume of a sphere with radius Ďăcm3_447T50. Three metallic spheres with radii 3 cm, 4 cm and 5 cm are melted and recast toproduce one sphere. Then, the radius of this newly produced sphere is.cmA. 12 B. 6 C.8 D. 10 |
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| 3834. |
The scores in mathematics test (out of 25) of 15 studenis is as follows19, 25, 23, 20, 9, 20, 15, 10, 5, 16, 25 20, 24, 12,20 |
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| 3835. |
SECTIONAMATHEMATICSThe face value of each share is Rs 10. If dividend is 16% then what will be the incrom 600 shares?a) Rs 900Rs 800(b) Rs 960(c) Rs 860 |
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Answer» Value of 1 share = 10Value of 600 share = 600*10 = 6000 Dividend on share = 16% Total dividend = (16/100)*6000 = 960 (b) is correct option |
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| 3836. |
33. A tank with a square base has a volumeof 384 cm3, If its height is 6 cm, find thelength of the side of the square base.(A) 10 cm(C) 12 cm(B) 8 cm(D) 6 cm |
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Answer» Volume=side*side*height 384=side² *height 384=side²*6 side²=384/6=64 side=8cm this is not correct answer |
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| 3837. |
8 cmtriangle PRS is drawn with ZPRS=YUV andRS = 12 cm. Find the area of PQRS. 75.72vo20 cm3. In quadrilateral ABCD, ZB = ZD = 90°AB = 7 cm, AC = 25 cm, CD = 20 cm.Find the area of ABCD.25 cm007 cm4. In quadrilateral ABCD, AB = 10 cm, BC = 6 cm |
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| 3838. |
6x=5x+8 |
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Answer» Ans :- 6x=5x+8 6x-5x=8 x=8 |
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| 3839. |
(a)x* +6x +8 |
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Answer» x²+6x+8 = x²+4x+2x+8 = x(x+2) +4(x+2) = (x+4) (x+2) |
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| 3840. |
6x-3y=-10;3x+5y-8=0 |
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Answer» 6x-3y = -10 3x+5y =8 multiply second equation with 2 and subtract from first equation. 6x-3y-6x-10y = -10-16 -13y = -26 so y=2 3x+10 = 8 so 3x=-2 so x=-2/3 |
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| 3841. |
Find the perimeter of the triangle ABC in1 AB 3 cm, BC - 5 cm, AC 4 cm2 AB 6 cm, BC 9 cm, AC -8 cm3. AB 14 cm, BC 20 cm, AC 16 c |
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Answer» Perimeter=sum of all sides1. 3+5+4=12cm 2. 6+9+8=23cm 3. 14+20+16=50cm |
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| 3842. |
(2) A tent is in the form of a cylinder whose height is 5 m surmounted by a cone of equualbase. The diameter of base is 105 m. The slant height of cone is 60 m. Find the costcloth at R 15 per sq metre to make the tent.of |
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Answer» Cylinder h = 5m Cone d = 105m r = 105/2 l = 50m r of cone = r of cylinder To find : CSA of the tent + cost CSA of tent = CSA of cylinfer + CSA of cone Proof : CSA of cylinder =2πrh22×15×51650m² CSA of cone = πrl=8250m²Total area = 1650+8250 = 9900m²Cost = 9900×15 =148500 rupees Read more on Brainly.in - https://brainly.in/question/6794442#readmore |
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| 3843. |
(2) A tent is in the form of a cylinder whose height is 5 m surmounted by a cone of equalbase. The diameter of base is 105 m. The slant height of cone is 50 m. Find the cost ofcloth at ? 15 per sq metre to make the tent. |
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| 3844. |
(iv) 2m-8=6m-4 |
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Answer» -8 + 4 = 6m - 2m -4 = 4m m = -1 So, the value of m is -1. |
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| 3845. |
(iv) 2m -8 =6m -4 |
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Answer» 2m - 8 = 6m - 46m - 2m = 4 - 84m = - 4m = -4/4m = -1 |
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| 3846. |
3The outer diameter of a drainage water pipe is 1.4 m and it is 35 m long.Find the cost of paintingits outer surface at the rate of R 1.50 per sq metre. |
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| 3847. |
The diameter of a cylindrical well is 4.5 m anddepth of the well is 14 m. Find the cost ofcementing its inner curved surface at the rate of12.50 per sq. metre. |
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| 3848. |
12. A room 9.5 m long and 6 m wide is surrounded by a verandah 1.25 m wide. Caleulateo ecementing the floor of this verandah at t28 per sq metre |
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| 3849. |
The dimensions of a cuboidal room are inthe ratio 4:5:6 and its total surface area is5328m2. Find the dimensions and the costof painting it at inside at 20 per sq metre1emo are 1oined |
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| 3850. |
What decimal fraction of 0.3 metres Is 6 centimetres?(A) 0.2(B) 0.18(D) 0.02(E) of these |
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Answer» x*0.3 = 6 x = 6/0.3*1/100 x = 0.02 wrong ans |
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