Explore topic-wise InterviewSolutions in .

suppose total no. of students in xso 0.77x passed in science and 0.66x passed in Hindi.0.13x failed in both subjects.so 0.77x+0.66x+0.13x-x=0.56x passed in both the subjects.so 0.56x=280x=280/0.56x=500

Answer:

500 Students

Step-by-step explanation:

Let Total number of students = S

Passed in Science = 0.77 S

Failed in Science = S - 0.77S = 0.23S

Passed in Hindi = 0.66 S

Failed in Hindi = S -0.66S = 0.34S

Failed in Both = 0.13S

Total Failed in Any subject = 0.23S + 0.34S - 0.13S = 0.44S

Passed in both subject = S -0.44S = 0.56S

0.56S = 280

S = 280/0.56

S = 500

please like the solution 👍 ✔️

iska answer 8 hoga, it's right answer

8 is the right answer

8 is 100% correct answer

8 is the right answer of this question

answer 1 is correct answer

Let total number of students are n

Number of students passed in science = 77n/100

Number of students passed in Hindi = 66n/100

Number of students passed inboth = 13n/100

Number of students failed in both = 280

Then total students= 77n/100 + 66n/100 +13n/100 - 280

We get,n = .77n +.66n +.13n - 2801.56n - n = 280.56n = 280n = 28000/56 = 500

Therefore total number of students are 500

The question says that , 33% is the minimum percentage required to pass, but he fails by 40 marks when he got 125..... thus we can conclude that 33% = 165So if 33/100 x Maximum Marks = 165Maximum marks = 165 x100/33so we get , maximum marks is equal to 500

total maximum mark is 500

Answer:C)23%Explanation:

sir please define

The general term of the expansion is

15Cr *(x²)^(15-r) × (3/x)^r

so, for power on x to be 18.

x^(2*15-2r). x^-(r) = x^18=> x^(30-3r) = x^18=> 30 -3r = 18=> 3r = 12 => r = 4

so, term will be 15C4. x^22. 3⁴/x⁴= (15C4)(81)x^18

1

2

3

67 khana sai aya

x/5 + x/4 + 2x/3 = 1072

12x + 15x + 40x/60 = 1072

x = 1072*60/67

x = 960

The shares are

960/5 = rs.192

960/4 = rs.240

2*960/3 = rs. 640

how 40x/60

Option B is correct

28 years is the correct option

b is the best answer

28 year is right answer...

option B is correct answer.

average age 16*2=a+b32/8=4mother age 7*4=28

28 is the right answers

thanks

etna jaldi karte kaise ho

As each person needs 4 sq.m space on groundSo 11 person will need 44 sq.m space on the ground.Therefore,Area of ground = 44sq.mπr = 44sq.mr = 44/π .......(1)and each person needs 20cu.m of airSo 11 persons will need 220 cu .m of airTherefore volume of tent = 220 cu.m1/3πr h = 220cu.m(1/3*π)*(44/π)*h = 220 ( from 1 )1/3*44*h = 220h = 220*3 / 44h = 5*3h = 15 cm

very difficul questiom it was cant answer it very hard

As each person needs 4 sq.m space on groundSo 11 person will need 44 sq.m space on the ground.Therefore,Area of ground = 44sq.mπr = 44sq.mr = 44/π .......(1)and each person needs 20cu.m of airSo 11 persons will need 220 cu .m of airTherefore volume of tent = 220 cu.m1/3πr h = 220cu.m(1/3*π)*(44/π)*h = 220 ( from 1 )1/3*44*h = 220h = 220*3 / 44h = 5*3h = 15 cm

As each person needs 4 sq.m space on groundSo 11 person will need 44 sq.m space on the ground.Therefore,Area of ground = 44sq.mπr = 44sq.mr = 44/π .......(1)and each person needs 20cu.m of airSo 11 persons will need 220 cu .m of airTherefore volume of tent = 220 cu.m1/3πr h = 220cu.m(1/3*π)*(44/π)*h = 220 ( from 1 )1/3*44*h = 220h = 220*3 / 44h = 5*3h = 15 cm

Let Meera's age be x.

So mother's age = 4x

After 5 years,

➡ 4x + 5 = 3(x+5)

➡ 4x + 5 = 3x + 15

➡ 4x -3x = 10

➡ x = 10

Meera is 10 years old.Hence, her mother's age = 10 × 4 = 40 yrs old.

N Ι Ι ____ Ι______ E Ι W Ι S

Draw a rough diagram according to the given data in the problem,

we get a right angled triangle ,

distance traveled towards North = 24 m

distance traveled towards East = 10 m

distance from the starting point =Joining the to end points

Hypotenuse of the right triangle

using Pythagoras Theorem ,

( Hypotenuse )² = ( base )² + ( height )²

= ( 10 )² + ( 24 )²

= 100 + 576

= 676

= ( 26 )²

Now required distance from starting point =√ ( Hypotenuse )²

=√(26)²

= 26 m

The person goes 30 m in north, and then 20 m in east and then 30√2 m in south west. Now, if we draw this diagram on a paper, then it would form a right-angled triangle kind of thing. So, the final position would lie on the hypotenuse of the triangle. Now, studying the diagram a more, we get,

length of hypotenuse = root(302+ 202) = 10√13 m

net displacement vector = 10√13 - 30√2

==> 42-36.6

==>5.4 m

1

Area to be covered = L.S.A. + Area of lid = 4a^2+a^2=5a^2. Now 2.5m = 250 cm

Area= 5* 250 *250 = 312500 cm^2

Area of 1 tile = 25* 25 =625cm^2

No. of tiles = Total area /Area of 1 tile =312500/625 = 500 tiles

thanks

tan47°= cot43°tan12°= cot78°

9+6=1511+4=1512+3=1515+1+8+15=3915+2+7+15=3910+5=15

C(n,r)=n!r!(n−r)! ;Required number of ways=nC2+nC3+.......+nCn−3+nCn−2;⇒2n−(nC0+nC1+nCn−1+nCn−1+nCn);⇒2n−2(n+1);⇒2n−2(n+1);⇒2n−2n−2;

Correct answer is B

thanks

Every day Varun waste's 1/2 roti , So in 20 days he will waste 20 *1/2 = 10 rotis .As they have consumed 110 rotis in 20 days , they have taken 110 + 10 = 120 rotis.(10 are wasted).Let Rosa eat x rotis and Varun eat 2x rotis .So x +2x = 120⇒3x = 120⇒x = 120/3⇒ x = 40So Varun eat's 80 rotis(2x) and Rosa eat's 40 rotis (x).Therefore, Varun eat's 80/20 = 4 rotis per dayand Rosa eat 40/20 = 2 rotis per day.

a rope long peace of equal size are cut Is 63m long length of one peace is