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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 3951. |
11. Calculate the median for the following data:Age (in years) 19-25 26-32 33-39 40-46 47-53 54-60FrequencyHINT Convert it to exclusive form.359668102354 |
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| 3952. |
64656667686970Single Choice+47-1The point (0.5) is closest to the curve r = 2y at:A(0,0)B(2.2)c(-4.12.16)D(2./2.4)Submit |
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Answer» correct option is D |
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| 3953. |
example 1 ..write all the factors of 68solution we note that 68=1×68 |
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Answer» factors of 6868=*2*2*17hence factors will be1,68,2,2,17 what is gornmentdevelement |
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| 3954. |
2. The average of 13 numbers is 68,the average of first 7 numbers is 63and the average of last 7 numbers is70. What is the 7th number?(a) 43 (b) 45(C) 47(d) 49 |
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Answer» 47 is the right answer.... Option C is the right answer. option c is the right answer |
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| 3955. |
14. Find the cost of laying grass in a triangular fieldof sides 50 m, 65 m and 65 m at the rate ofper m2(A) 9500(C) 10500(B)(D)1100012500 |
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Answer» using heron's formula. s = (50+65+65)/2 = 180/2 =90the area of triangle = √s(s-a)(s-b)(s-c) = √90*(40)(25)*(25) = 1500 m² so total cost will be = cost/m² × area = 7×1500= 10500rs |
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| 3956. |
If cos";cos β= 13, then cos(ëś6531 644) 652) 656411 65 |
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| 3957. |
Q. 41If (65)2 -(25)2 m2, then find m- 2(1) 60(2) 40(3) 45(4) 50 |
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Answer» a²-b²=(a-b)(a+b) (65)²-(25)²=(65-25)(65+25)=(40)(90)=3600 m²=3600m=√3600m=60 Option 1 is correct |
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| 3958. |
10. A tank 30 m long, 24 m wide and 4.5 m deepis to be made. It is open from the top. Find thecost of iron-sheet required, at the rate of65 per m2, to make the tank. |
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| 3959. |
1. A plastic box 1.5 m long, 1.25 m wide and 65 cm deep is tobe made. It is to be open at the top. Ignoring the thickness of theplastic sheet, determine:(i) The area of the sheet required for making the box.(ii) e cost of sheet for it, if a sheet measuring 1 m2 cost Rs. 20. |
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| 3960. |
A gardener wants to fence a circular garden of diameter 21m. Find the length of therope he needs to purchase, if he makes 2 rounds of fence. Also find the cost of the |
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Answer» the total length of wire needed is (2*circumference) = 2*(2*pi*r) = 2*2*(22/7)*(21/2) = 132 m. |
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| 3961. |
100+65-65-100 |
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Answer» answer is 0.ye shi answer h 100+65-65-100=165-165=0 0 is the correctanswer 100+65-65-100165-165=0 |
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| 3962. |
65+65 |
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Answer» 130..HOPE U GET UR ANSWER.. 130 respectively 😁😁 |
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| 3963. |
. A beam 4 m long, 50 cm wide and 20 cm deep is made of wood which weighs 25kg per m. Find the weight ofthe beam |
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Answer» Length of beam(l)=4 mBreadth of beam(b)=50 cm =0.5 mDepth of beam(h)=20 cm =0.2 mVolume of beam=lbh = 4×0.5×0.2 m³ =0.4 m³Given,weight per cubic metre=25 Kgweight for 0.4 m³=0.4×25 = 10Kg |
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| 3964. |
ll be only twice as old as his son.1. A man is 4 times as old as his son. After 16 years he wilFind their present ages. |
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| 3965. |
5. A beam 9 m long, 50 cm wide, and 20 cm deep is made of wood which weighs 30 kg per m3, find theweight of the beam. |
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| 3966. |
lS,5. A beam 9 m long, 50 cm wide, and 20 cm deep is made of wood which weighs 30 kg per m3, find theweight of the beam. |
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Answer» Volume of beam= 9*50*20/10000=.9m^3Weight=30*.9=27Kg |
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| 3967. |
A playground is 38 m 50 cm long and 61 m 50 cm wide(a) the cost of levelling itat40 per m2the number of rounds along the boundary one should take to run 2 km |
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| 3968. |
E. Solve.1. Hari Ram has to put a fence around his rectangularfield of length 15 m and breadth 10 m. What is thelength of the fence needed? If he has fenced 20 m, howmuch more fence is needed to complete the boundary'? |
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Answer» fence needed =perimeter=2(l+b)=2(15+10)=2(25)=50mhe fenced 20hence remaining =50-20=30m more |
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| 3969. |
: If the circumference of a circle is 176 cm, find its radiusd it cnst to put a 4-round fence |
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| 3970. |
3. Write each of the following as decimals(a) Seven-tenths |
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Answer» seven tenths is 7/10 how the 17 is the answer |
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| 3971. |
A man walks a distance of 3 units from the origintowards the north-east (N 45° E) direction. Fromthere, he walks a distance of 4 units towards thenorth-west (N 45° W) direction to reach a pointP. Then the position of P in the Argand plane is |
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| 3972. |
man goes10 m due east and then 24 m due1r ishe from the starting point? |
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| 3973. |
Two cars start together in the same direction from the sameplace. The first goes with uniform speed of 10 km/houThe second goes at a speed of 8 km/hour in the first houand increases the speed by 1/2 km each suAfter how many hours will the second car overtake the firstif both cars go non stop ?9.man bhaims wil f ecomd ar ocereding hous |
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| 3974. |
A circulinner circle are 110 m and S8 m, find the width of the road.ar road runs around a circular garden. If the circumferences of the outer circle and the |
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Answer» Like my answer if you find it useful! |
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| 3975. |
21. A path of uniform width runsround the inside of a rectangularfield 38 m long and 32 m wideIf the path occupies 600m2, thenthe width of the path is(1) 30 m(3) 18.75 (4) 10 m(2) 5 mssc co. Prelim Exam. 04.02.2007 |
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| 3976. |
A gardener has to put double fence all round a triangularpath with sides 120 m, 80 m and 60 cm. In the middle ofeach sides, there is a gate of width 10 m. Find the length ofthe wire needed for the fence.(a) 250 m (6) 490 m (c) 230 m (d) 460 m |
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| 3977. |
(ICSE)13. A lawn is in the shape of a semi-circle of diameter35 dm. The lawn is surrounded by a flower bed ofwidth 3.5 dm all round. Find the area of the flower(ICSE)bed in dm?.14. A road which is 7 m wide surrounds a circular parkwhose circumference is 352 m. Find the surface area(ICSE)of the road |
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Answer» radius of lawn = 35/2 dm radius of lawn including flower bed = 35/2 + 3.5 = 21 dm area of flower bed = area of lawn including flower bed - area of lawn = 1/2 * 22/7 * 21 * 21 - 1/2* 22/7* 35/2* 35/2 = 1/2* 22/7 ( 441 - 1225/4 ) =11/7 * 539/4 = 11 * 77/4 = 211.75 dm |
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| 3978. |
1.round off 138.288 to the nearest thousandth2. round off 2.3701 to the nearest hundreth3. round off 67.307 to the nearest tenths4. round off 9,182.5 to the nearest ones |
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Answer» 1.nearest 4 digit number is: 1000 but that is far from 0henceanswer 0 Pls I don't understand |
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| 3979. |
2. Round each of the UMUWI,(b) 1254(c) 43120(a) 8143. Round each of the following numbers to the nearest(b) 48264. Round each of the following numbers to the near(c) 16719(a) 793(d) 28394he nearest thousand:the nearest ten thousand:(d) 272685c) 34890 |
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Answer» (a)1000,(b)5000,(c)17000,(d)28000 (a)1000,(b)5000,(c)17000,(d)28000 is the correct answer |
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| 3980. |
Find the square roots of natural numbers from 1 to 20 (upto two decimal places) |
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| 3981. |
1 Find the sume sum of all even natural numbers upto 74(1) 1518(4) 1406(3) 1618(2) 1471(5) of these2t is 28% of that number |
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Answer» All natural numbers before 74 can be arranged to form an AP, Where a=2 an=74 d=2 an=a+(n-1)d 74=2+(n-1)2 72=(n-1)2 36=n-1 n=37 Sn=(n/2)[2a +(n-1)d] = (37/2) [2*2+(37-1)2] =(37/2)*(4+72) =(37/2)*(76) =37*38 Sn=1406 Plz snd number My no 9596523078 |
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| 3982. |
2. Find the sum of first 200 natural numbers. |
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Answer» n(n+1)/2=200(200+1)/2=201*100=20100 so simple use n(n+1)/2 and answer is 20100 200+1=201 sum of first and last natural number Total no of numbers=200÷2=100Sum=201×100=20100 20100 hoga answer esaka |
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| 3983. |
Q.28) Find the sum of all natural numbers between 100 and 200which are divisible by 4. |
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| 3984. |
Q.28) Find the sum of all natural numbers between 100 and 200which are divisible by 4 |
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| 3985. |
Q.27)Findthesumof all two -digit numbers which whenield as remainder.divided by 7Q.28) Find the sum of all natural numbers between 100 and 200which are divisible by 4 |
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Answer» plz give me clear pic in 27 |
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| 3986. |
[CBSE 2013)21. How many natural numbers are therebetween 200 and 500, which are divisibleICBSE 2011]22. Find the number of three digit naturalisible by 7?by T? |
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Answer» Im the interval 200 to 500,203 is the smallest number divisible by 7. 497 is the largest number divisible by 7. a=203 d=7 tn=497 tn=a+(n-1)d 497 =203 +(n-1)7 294=(n-1)742=n-1 n=43 So there are 43 numbers divisible by 7. |
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| 3987. |
In an election meena, Raju and Vijay scored 8500 votes , 7600votes and 3400 votes respectively and 500 votes were invalidWhat was the percentage of votes scored by each candidate andwhat percentage of votes were invalid ? |
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Answer» total votes = votes of meena + votes of Raju + votes of Vijay + invalid votes = 8500 + 7600 + 3400 + 500 = 20000 percentage of Meena = 8500/20000 * 100 = 42.5% percentage of Raju = 7600/20000*100 = 38% percentage of Vijay = 3400*100/20000 = 17% percentage of invalid votes = 500*100/20000 = 2.5% |
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| 3988. |
4 There were three candidates in an election. They received 687905 votes, 495086 votes and93756 votes respectively. The number of invalid votes was 13849. If 25467 persons did notvote, find how many votes were registered. |
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| 3989. |
The residents of a city voted on whether to ralse property taxes. The ratio of yes votes to no votes was 7 to 4. If there were 4375 yes votes, what was thtotal number of votes?total votes |
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Answer» No. Of yes votes = 7xNo. Of no votes = 4x Given7x = 4375x = 625 Total votes = 7x + 4x = 11x = 11*625 = 6875 |
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| 3990. |
in an election betware 2% of the total votes. What per cent of the votes were in fav ourwhateen A and B, A secured 9740 votes and 487 votes were declared inof A?percent of alte%wharpercentofth40vo esanre487 votes were declared invalid whichper cent of votes Were in favour of B? |
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Answer» 487 votes are invalid which is 2% of the original.SO, 9740 votes are 40% of the originalA secured 40% of votesTotal votes = 24350B's votes = 24350-9740-487 = 14123B secured 58% of votes |
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| 3991. |
0y 381304S. What is that number?There were three candidates in an election. They received 687905 votes 495086 votes and93756 votes respectively. The number of invalid votes was 13849. I1 25467 persons did notvote, find how many votes were registered |
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| 3992. |
In an election. 4,98,656 votes were found valid, 6768 votes were found invalid and83.865 persons did not cast their votes. How many votes were registered in all? |
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| 3993. |
In an election 8,32,45,678 votes were polled. Of these 83271 votes were invalid.If the winning candidate got 5,67,84,132 votes, find the votes poled by thedefeated candidate. |
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Answer» Total number of votes polled = 8,32,45,678Number of votes were invalid = 83,271Number of votes winning candidate got = 5,67,84,132Number of votes defeated candidate got = Total number of votes polled - ( number of votes winning candidate got + number of votes were invalid )= 8,32,45,678 - ( 5,67,84,132+83271)= 8,32,45,678 - 5,68,67,403= 2,63,78,275 |
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| 3994. |
15. In an election 4.98,656 votes were found valid, 6768 votes were found invalid and83.865 persons did not cast their votes. How many votes were registered in all2 |
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Answer» an election 4.98.656 were found |
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| 3995. |
7. A playground is 38 m 50 em long and 61 m 50 cm wide. Find:(a) the cost of levelling it at 40 per m(b) the number of roundsalong the boundary one should take to run 2 km |
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Answer» L= 38*100+50 = 3850 CM B = 61*100+50 = 6150 CMArea = L*B= (3850*6150) = 1937.25 m square Total cost = 1937.25*40 = 77490 Rs |
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| 3996. |
1. Benjamin runs 2 km 300 m a day. How far does he run in a week? |
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Answer» 14km 2100m benjamin run 16.1 km its simply multiplication |
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| 3997. |
| प्रश्न 6. गुणा करो-735 x 27 = ? |
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Answer» Guna karne par milega 19845 The right answer is 19845 |
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| 3998. |
35. An umbrella is made by stitching 12triangular pieces of cloth, each measuring(50 cm x 20 cm x 50 cm). Find the area ofthe cloth used in it. |
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| 3999. |
(e) Cylinder: r ,DL 1UIII2. A cuboidal box 90 cmx 50 cm x 35 cm is to be covered with metal sheet. How many metres ofsheet of width 94 cm is required to cover 50 such boxes? |
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| 4000. |
A cuboidal box 90 cm x 50 cm x 35 cm is to be covered with metal sheet. How many sheet of width 94 cm is required to cover 50such boxes? |
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