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The factors of 280 are: 1, 2, 4, 5, 7, 8, 10, 14, 20, 28,35, 40, 56, 70, 140, 280280 के गुण आज होंगे

The factors of 455 are: 1, 5, 7, 13,35, 65, 91, 455455 के गुण आज होंगे

The factors of 735 are: 1, 3, 5, 7, 15, 21,35, 49, 105, 147, 245, 735735 के गुण आ जाओगे

Then the greatest common factor is 35.

Area of recatngle = L × B

Area of recatngle =12.25×7.35=90.0375m²

Let unknown digit be n

Then 46/3 + 106x3 + n = 400n = 400 - 318 - 46/3n = 82 - 46/3n = (246-46)/3n = 200/3

200/3 is ans

11.5 is the correct answer of this question

11.5 is the right answer

400 ÷ 200 of 2×2+18-7 = 2 (15) = 30 so is the correct answer

11.5 is right answer hai

400÷200 of 2×2+18-72(4+11)2(15)30

400/200 of 2*2+18-7400/400*2+18-71*2+18-72+18-720-713 answer

11.5 is the correct answer

11.5 is the right answer

If A = {2, 4, 6, 8} B ={6, 8, 10, 12}

Then,AnB = {6, 8}

Profit =SP-CPCP=SP-profit=400-35=365

cost price=selling price - profit Cp =400 - 35=365

(a) 25/30 = 5/6

(b) 125/400 = 5/16

let,a=203,d=7,tn=399Tn=a+(n-1)d399=203+(n-1)7196/7=(n-1)n=29s29=29/2[2a+(n-1)d]29/2[406+196]29/2×60229×301=8729.

Let the original speed of the train be x km/h.Time taken to cover a distance of 360 km = 360/x hours.New speed of the train = (x+5) km/h.Time taken to cover a distance of 360 km at new speed = 360/x+5 hours.Since, the train takes 1 hour less time,∴ 360/x - 360/ x+5 = 1⇒360 (x+5-x)/x(x+5) = 1⇒360 (5) = x² + 5x⇒1800 = x² + 5x⇒x² + 5x - 1800 = 0⇒x² + 45x - 40x - 1800 = 0⇒x (x+45) - 40( x +45) = 0⇒(x+45) (x-40) = 0⇒x = (-45), 40But since speed cannot be in negative.∴ x = 40 km/hr.Hence, the original speed of the train is 40 km/h.

Consider a set of every four years (So as to include the leap year with Feb 29).So in 3 years, 29 will occur 11 times, and once it would accur 12 times.So in 4 years, there will be 3*11 + 12 = 45 days in which you will have 29th.So in 400 years, it would be 4500 times.

thanks

B) is the correct answer

210

By using the formula :sum of first n numbers is equal to n(n+1)/2.=20(20+1)/2=420/2=210

natural number kon kon se he

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For proportions

product of mean = product of extremes

a) 5×150 = 750 , 6×125 = 750 ✓c) 4*20 ≠ 8*5 e) 1*105 = 3*35 ✓ g) 1×10 ≠ 2*2

cosecA= 2

sinA = 1/2

A= 30

cot A + Sina/(1+ cos A)

cot 30. + sin30/(1+ cos30)

√3 + 1/2 ( 1+ √3/2)

√3 + 1/(2+√3)

cosec A=2/1; sin a=1/2=A=30, cot a+ sina/1-cosa=cot 30+ sin 30/1-cos30=V3+1/2/1-V3/2=V3+1(2+V3)

1/(1+cosθ) + 1/(1-cosθ)=(1-cosθ)/(1-cos²θ) + (1+cosθ)/(1-cos²θ)=(1-cosθ)/sin²θ + (1+cosθ)/sin²θ=cosec²θ+cosec²θ=2cosec²θ

the pair of triangles in option d are not similar triangles

i) (2+3i)(2+3i) = 4 + 12i + 9i*i = 12i + 4 - 9 = -5+12i ii) (i+1)(i+1)(i+1) = i*i*i + 3i*i + 3i + 1 = -i - 3 + 3i + 1 = 2i - 2 = -2 + 2i

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distributed amount = 910/9 = 101 rupees each approximately

As7*(3/5)= 7*3= 21now21/5thanks

7*(3/5)=(7*3)/5=21/5=4.2

7×3/5=21/5=4.5your answer is 4.5

7 × 3 --- 5= 35 ×3 = 105

East and west is opposite direction so 40+20=60

if an insect moves East 20m then from that point it moves West the required distance to reach the initial point is -20m and from initial point insect moves to West 20mSo the equation is 20-20+20

Let x is subtracted from 2a+8b+10 to get -3a+7b+162a+8b+10-x=-3a+7b+16x=5a+b-6

He is at point C. AC= AB - BC = 2.3km - 900m = 2300 - 900 = 1400 metres = 1.4 km.

On the average the ampere- hour efficiency of an Edison cell is about 80%.