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Yes it is because all sides of equilateral triangle are equal hence the ratio is also 1

As all the angles of the triangle are same therefore all the sides of the triangle will be same hence the ratio of any two corresponding side will be same

Equi angular means..

that All Three Angles of A Triangle is Equal to all three angles of the Other triangle...

And By AAA(Angle Angle Angle) Similaritly Criterion They are Similar.

By this Does not mean that Their Sides are same... As Trangle with Equi-Angles May/May not have Equal Sides...So These Triangles are Similar (But not Congruent)....

5 examples : pipes, pen, test tube, bottles, pencils. Please hit the like button

A football

An orange

Earth

Round Sweet

ball bearing

sides are in 3 : 1 1/4 : 3 1/4 = 3 : 5/4 : 13/4 = 12 : 5 : 13 so its right triangle.

l=1/√3,m=1/√6 n=?nowl^2+m^2+n^2=1hence1/3+1/6+n^2=11/2+n^2=1n^2=1/2n=1/√2

equivalent rational numbers of 5/9:(5 × 2)/(9 × 2)= 10/18(5 × 3)/(9 × 3)= 15/27(5 × 4)/(9 × 4)= 20/36

1 ) 25 / 452 ) 45 / 813 ) 10 / 18

The other factors are 1/2 and 1.

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Let us assume that √3 is a rational number.

then, as we know a rational number should be in the form of p/q

where p and q are co- prime number.

So,

√3 = p/q { where p and q are co- prime}

√3q = p

Now, by squaring both the side

we get,

(√3q)² = p²

3q² = p² ........ ( i )

So,

if 3 is the factor of p²

then, 3 is also a factor of p ..... ( ii )

=> Let p = 3m { where m is any integer }

squaring both sides

p² = (3m)²

p² = 9m²

putting the value of p² in equation ( i )

3q² = p²

3q² = 9m²

q² = 3m²

So,

if 3 is factor of q²

then, 3 is also factor of q

Since

3 is factor of p & q both

So, our assumption that p & q are co- prime is wrong

hence,. √3 is an irrational number

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sin^-1(sin(3 theta/5); siny=sin(3theta/5); principle value of sin^-1 is 90° , -90°

3π\4 is the right answer

thanks

Split the middle term 7x2x² + 7x + 3 = 2x² + x + 6x + 3 Group the terms:2x² + 7x + 3 = x(2x + 1) + 3(2x + 1) = (2x + 1)(x + 3)

X=1/2 straight and direct answer time waste hai bc

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please help me solve all questions

Anexampleof aconeis a funnel.

Anexampleof aconeis the waffle pastry in which ice cream is served.

Anexampleof aconeis the brown scaly growth which is attached to wreathes.

any of the flask-shaped cells in the retina of most vertebrates, sensitive to bright light and color

cone shell

the diaphragm (sense ) of a speaker, usually cone-shaped

(a) is the correct answer but at the place of y, g will be

option a is the correct answer of the given question

a is the answer of the following

P=2 1/3=7/3Q=2 2/3=8/3R=−1 1/3=−4/3S=−1 2/3=−5/3

thanq soooooooooooo much ... but can u send this in a video plz

quick pls with steps

diagonal in a rectangle is basically the hypotenuse for the length and breadth as it makes a right angled triangle.That means,using Pythagoras theorem, √length^2+breadth^2=diagonal so,√28^2+b^2=3528*28+(b*b)=35*35784+b^2=1225b^2=441b=21so the answer is definitely 21.

a) 90°

b) 180°

c) 360°

d) 180°

a)90°b)180°c)360°d)180°

Minimum distance = LCM of 30,36,40

therefore ,

30 = 2×3×5

36 = 2×2×3×3

40 = 2×2×2×5

Thus the LCM of 30,36,40 = 360

Therefore the minimum distance each should walk = 3 m and 60 cm.

therefore the minimum distance it should walk is 3 m 60 cm

Let length (l)=x+1/2x=3/2xLet breadth (b)=xArea of floor=924×100/3850l×b=243/2x×x=243/2x^2=24x^2=24×2/3x^2=4^2x=4Area of 4walls=1320×100/5502 (l+b) h=24010×h=240/2h=12ml=3/2×4=6mb=x=4m

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cosec (theta) for this figure is -> hypotenuse/perpendicular

= AC/AB

Given :

Area of ∆ ABCArea of ∆QRP = 9/4

AB = 18 cm , BC = 15 cm So PR = ?

We know when two triangles are similar then " The areas of two similar triangles are proportional to the squares of their corresponding sides.

Area of ∆ ABCArea of ∆ QRP = AB2/QR2 = BC2/PR2 = AC2/QP2So , we take Area of ∆ ABC/Area of ∆ QRP = BC2/PR2

Now substitute all given values and get

9/4 = 15²/PR²

Taking square root on both hand side , we get

PR = 10 cm

option B is the correct answer

10:7 is the answer

the species of dainosaur which were enormous in size suddenly became extinct

correct answer is (B)

option But is the correct answer

BC²=AC²+AB² =8²+6² =64+36 =100

BC=10cm

Area of biggest semicircle= 1/2 * 3.14 * r² =0.5*3.14*5*5 =0.5*78.5 =39.25 cm²

Area of 2nd Largest Semicircle = 0.5*3.14*r² =0.5*3.14*3² =0.5*3.14*9 =14.13 cm²

Area of smallest Semicircle = 0.5*3.14*r² =0.5*3.14*4² =0.5*3.14*16 =25.12cm²

Area of Triangle = 1/2 *b*h = 0.5*6*8 =24 cm²

Area of shaded region = (24+25.12+14.13) - 39.25 = 63.25-39.25 =24 cm²

to repair a road it costs 24000,of length (1.6km)so for 1 km it will be 24000/1.6=15000rupees

1.6 km is correct answer.

14 laps as one lap covers 1/4 miles =0.25 milestotal 7/4 miles are thereso 0.25*x=7/4where x is the number of lapx= 14