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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 4401. |
is2V77V7rational or Irrational? |
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Answer» It is rationalas 2√7/7√7will be2/7and it is a p/q form |
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| 4402. |
2V7-3 527+3 5Rationalise the denominator ofand simplify |
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| 4403. |
28. In the given figure, ABC is an equilateraltriangle; PQ ll AC and AC is produced to Rsuch that CR - BP. Prove that QR bisects PC9 |
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| 4404. |
ORIn adjoining figure. a semicircle is drawn with O as centre and AB as diameter. Semicreles aredrawn with AO and O13 as diameters. IfAB 28 m, lind the perimeter of the shaded region. |
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| 4405. |
ORIn adjoining figure, a semicircle is drawn with O as centre and AB as diameter. Semicrcles aredrawn with AO and OB as diameters. IfAB 28 m. find the perimeter of the shardled region |
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| 4406. |
0°<A + B 900. A > B then find A and B |
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Answer» thanxxx |
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| 4407. |
Nin the given figure, ABC is an equilateraltriangle, PQI AC and AC is produced to Rsuch that CR- BP. Prove that QR bisects PCBP M |
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Answer» IN TRIANGLE OPQ AND OCR,CR = PQ (GIVEN)ANGLE PQO = ANGLE CRO (A.I.A, AS QP// AC OR AR AND QR ACTS AS A TRANSVERSAL)ANGLE QOP = ANGLE COR(V.O.A) SO TRIANGLE OPQ IS CONGRUENT TO TRIANGLE OCRAND AS BOTH ARE CONGRUENT THEIR AREA IS ALSO THE SAMESO, ar(OPQ) = ar(OPCR) |
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| 4408. |
Find the area of tiangle tome21012 |
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| 4409. |
and AB =AC. FindB and 2 CShow that the angles of an equilateral triangleare 60° each |
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| 4410. |
Area (Δ BCE)--Area (Δ AchEXAMPLE9 Prove that the area of the equilateral triangle described on the side of a squareaarea ofthe eqailateral triangle described on its diagonal.GIVEN A square ABCD. Equilateral triangles A BCE and A ACF have been describeBC and diagonal AC respectively. |
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| 4411. |
e. In the90<find the measure of 2AOB-AOD and CODgeven tigate, 2b-aes' and .BOCtb |
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Answer» Given:∠BOC=902b−a=65 From the figure,∠AOB+∠AOD+∠BOC+∠COD=360=>a+2b+90+(2a+b+15)=360=>a+b=85 Add the given equation with this equation, we get2b−a+a+b=65+85b=50then, a=85−b=85−50=35∠AOB=a=35,∠AOD=2b=2×50=100∠COD=(2a+b+15)=2×35+50+15=135 |
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| 4412. |
ěŹ.to Raio, and Ha distante tekueeth t.list te |
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Answer» Let the radius of the two circles be 5 cm and 3 cm respectively whose centre’s are O and O'. ➧ Hence OA = OB = 5 cm➾ O'A = O'B➾ 3 cm ➧ OO' is the perpendicular bisector of chord AB. ➧ Therefore, AC = BC ➧ Given, OO' = 4 cm ➧ Let OC =x ➧Hence O'C = 4 −x ➧ In right angled ΔOAC, by Pythagoras theoremOA² ➾ OC²+ AC² ➾ 5²= x² + AC² ➾ AC² = 25 −x²à ➧ (1)In right angled ΔO'AC, by Pythagoras theoremO'A² ➾ AC²+ O'C² ➾ 3² = AC²+ (4 –x)² ➾ 9 = AC²+ 16 +x²− 8x ➾ AC²= 8x −x²− 7 à ➧ (2)From (1) and (2), ➧ we get25 −x² = 8x −x²− 78x= 32 ➧ Therefore, x= 4 ➧ Hence, the common chord will pass through the centre of the smaller circle, O' and hence, it will be the diameter of the smaller circle. ➧ AC²= 25 −x² ➾ 25 − 4² ➾ 25 − 16 = 9 ➧ Therefore, AC = 3 m Length of the common chord, ➾ AB = 2AC➾ 6 m ...✔ |
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| 4413. |
The distante btreeaH:two ponds |
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Answer» distance between points (a,b) and (c,d) is given by formulaD^2 =(a-c)^2 +(b-d)^2where D is the distancewe have points (-2,1)&(5,-2)D^2 =(-2-5)^2 +(1-(-2))^2D^2 =(-7)^2 +(3)^2D^2 =49+9=58D=sqrt (58) IT is wrong please give me right answer what is the answer?? I NOW ABOUT ANSWER SO I CAN'T ASK YOU |
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| 4414. |
31. Harish started his journey at 18:40and finished at 22 20. The timetaken in completing the journey is(1) 3 hours 20 minutes3 hours 40 minutes(3) 3 hours 80 minutes(4) 4 hours 40 minutes |
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| 4415. |
Q.3 seema can type 651 words in 3 minutes. how many words can she type 1 minutes?and 20 minutes? |
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Answer» 651 divided by 3 : 217 words she type in 1 minute : 21720 minutes : 217 multiplied by 20 : 4340 words |
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| 4416. |
a-ibumro, prove that x2+y?=e-id+c +d |
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| 4417. |
CISE 11.2C FD.I. The area of parallelogramABCD is 36 cm2Calculate the height of parallelogram ABEFifAB 4.2 ст. |
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Answer» thank you so much |
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| 4418. |
(iii) 2V7717 |
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Answer» 2√7 2--------- = ----- 7√7. 7 |
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| 4419. |
D, E and F are midpoints of the sides of triangle ABCrespectively. IfAB 8cm, BC 7.2cm and AC 6cmthen find the perimeter of ADEF |
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| 4420. |
2.30), ifAB3 crn, AC3 cm. and LA-50° then ZB? |
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| 4421. |
13. In the adjoining figure ifAB AC, prove that BE EC |
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Answer» Like if you find it useful |
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| 4422. |
Can we construct ΔΑ BC, ifAB-65cri12A-60° and BC+AC-11cm |
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Answer» Yes, we can.1. Draw an line segment AB =6.5 cm2.At A construct an angle of 60 and produce it to X such that AX =11 cm3. Join BX and draw a perpendicular bisector of BX let it intersect AX at C4. Join BC . Now ABC is your required triangle. |
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| 4423. |
1. In the figure, ifAB-CD and <AOB-900 finaZCOD0 |
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Answer» Angle COD=90 because there chords are equal and it is theorem that equal chords subtend equal angles at the center |
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| 4424. |
ERCIS8E1. In the figure, ifAB-CD and ZAOB 90 find COD |
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Answer» Since, AB = CDAO = BOΔAOB is an isosceles trianglesimilarly, ΔCOD is an isosceles triangleAngle AOB = Angle COD |
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| 4425. |
3/4 (x-2)=5/3 (x+2)+x |
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Answer» your question abd answer is wrong |
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| 4426. |
Function ofCPU |
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Answer» There are four Primary Functions of the CPU. The CPU processes instructions it receives in the process of decoding data. Inprocessingthis data, the CPU performs four basic steps: Fetch Each instruction is stored inmemoryand has its own address. |
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| 4427. |
संघनन किसे कहते हैं ?R L L e |
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Answer» Ans :- गैससेद्रवबनने की परिघटना को संघनन कहते हैं। यहवाष्पनकी उल्टी है। प्रायः जल-चक्र के सन्दर्भ में ही इसका प्रयोग होता है। वर्षा भी एक प्रकार का संघनन ही है। PLEASE LIKE THE ANSWER Ans :- गैससेद्रवबनने की परिघटना को संघनन कहते हैं। यहवाष्पनकी उल्टी है। प्रायः जल-चक्र के सन्दर्भ में ही इसका प्रयोग होता है। वर्षा भी एक प्रकार का संघनन ही है। PLEASE LIKE THE ANSWER |
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| 4428. |
x J -X x न 70z _/ z£z¥+ x=%EJबट € 2६ |
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| 4429. |
. A parallelogram has sides 15 em and 7 em long. The length of one of the di20 em. What is the area of the parallelogram?RCn whose sides are AB- 15 cm, BC-7 cm and |
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| 4430. |
¡ The width of a rectangular room is 7 of its length x and its perimeter is), write anequation connecting r and y. Find the length of the room when the perimeter is 4400 em. |
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| 4431. |
| Find the reciprocal(EJ 3x(52 |
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Answer» 1/2 is reciprocal of the this number |
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| 4432. |
12. A parallelogram has sides 15 cm and 7 em long. The length of one of the dliao20 em. What is the area of the parallelogram? |
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Answer» Here, a = 15 cm b = 7 cm c = 20 cm s = a+b+c/2 = 15+7+20/2 = 42/2 = 21 cm Area = 2√(s(s-a)(s-b)(s-c)) = 2√(21*(21-15)*(21-7)*(21-20)( = 2√(21*6*14*1) = 2*7*3*2 = 84 cm² Like my answer if you find it useful! |
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| 4433. |
Adjacent sides of a rectangle are 7 em and 24 cm. Find the length of its diagonIf diagonal of a square is 13 cm then find its side. |
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| 4434. |
MATH9.26TRIANGLE23. In Fig. 9.48, what isy in terms of x?26. In AR(a) 43(a)r(c) χ(d) x33yFig. 9.4827. In |
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| 4435. |
24 A wire of length 86 em is bent in the form of a rectangle such that ts leagh is 7 en morethan ts breadth. Fnd the length and the breadth of the rectangte so formed. |
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| 4436. |
Math Steps 4Study the pattern shown by the sum of four consecutive number3 + 4 5 6 184 5 6 7 22.What is the pattern? Find 74+75+76+77 using the pattern. |
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| 4437. |
MathematicalPRACTICEalso3you could use thend 5 x 198.usions The Distributive Propertcombines subtraction and multiplication(5-2)For example,Distributive Property and mental math to(35)-(3 x 2). Explainhov5% 198 |
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Answer» Thank you!❤ |
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| 4438. |
197. The cost price of a bag and a book is Rs.371. 197.If the bag costs 12% more than the book, thencost price of bag is:-1. Rs. 175Rs. 1963. Rs. 15012%1.3.4. Rs. 221198. In the given figure, AE DC-13cm, BE-5cm, 198 |
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Answer» Cost price of bag and book = 371 Let cost price of book = cpThen cost price of bag = cp( 1 +12/100) Given,cp + cp(1 + 12/100) = 371cp + cp(1 + 3/25) = 371cp + cp(28/25) = 371cp (1 + 28/25) = 371cp (53/25) = 371cp = 371*25/53 = 7*25cp = 175 Cost price of bag= cp(1 + 12/100)= 175(28/25)= 7*28= 196 |
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| 4439. |
Giz) How many solid cylinders of radius 6 cm and height12 cm canbe made by melting a solid sphere of radius 18 cm?Activity : Radius of the sphere, r 18 cmFor cylinder, radius R = 6 cm, height H= 12 cmVolume of the sphereNumber of cylinders can be made -44x18 x 18 x183)Selre the following questions (Any two):4 |
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Answer» Number of cylinders can be made = volume of the sphere/ Volume of cylinder= 4/3*pi*r^3/ pi*R^2*H= 4/3*18*18*18/ 6*6*12= 3*3*2= 18 |
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| 4440. |
In the given figure, ABCD is a trapezium with ABlIDC, AB- 18 cm, DC 32 cm and the distance between AB andAC is 14 cm. If arcs of equal radii 7 cm taking A, B, C andD as centres, have been drawn, then find the area of theshaded region.32 cm18 cm |
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| 4441. |
uple 9 : The perimeter of a regular hexagon is 18 cm. low18 cm. Ilow long is ius onede |
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| 4442. |
As shown in the given figure, AABis divided into six smaller trianglesby lines drawn from the verticesthrough a common interior point.The areas of four of6 triangles are as indicated, then thearea of AABC is843540 30 |
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| 4443. |
EXAMPLE 14. A college awarded 38 medals in football, 15 in basketball and 20 incricket. If these medals went to a total of 58 sportsmen and only three sportsmen gotmedals in all the three sports, houw mans sportsmen received medals in exaetly itno ofthe three sports?NCERT |
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Answer» 1 2 3 4 thanks bro |
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| 4444. |
The. Ce-stCeetej potabes feLl |
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Answer» Actual cost is = 13 -20%(13) = 13-0.2(13) =13-2.6 = 10.4 Rs/kg thank u |
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| 4445. |
77 m50 mLength and breadth of a rectangular garden are 77 m and 50 m. There is a circular lake in thegarden having diameter 14 m. Due to wind, a towel from a terrace on a nearby building fellinto the garden. Then, find the probability of the event that it fell in the lake. |
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Answer» Probability = favorable event/ total eventin this case favourable event is that lake and total event is the area of the square so we will do accordinglyarea of that lakeπr^2=7x7*10= 49πand total area of square = 77*50mxm3850 m^2probability = 49π/38500.03 |
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| 4446. |
(c) In the month of April, a school worked for only 24 days. What is thepercentage of working days? |
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Answer» In April total days 30 working days 24 so working days percentage = 24*100/30 = 80% 26÷30×100this is the formula |
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| 4447. |
There were 8 mangoes on a tree.5 mangoes fell down.How many mangoes are left on the tree now?Step 1: 5 mangoes fell down.So, cross out 5 mangoes.Step 2:Count the mangoes which are not crossed.We find that there are 3 mangoes which are not crossSo, 3 mangoes are left on the tree.n2 |
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Answer» the mango tree contains 8 mangoes of which 5fell down therefore 8-5=3there are 3 mangoes left There were 8 mangoes on a tree.5 mangoes fell down So, 8 subtract 5 = 3 mangoes |
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| 4448. |
31. A man works in a factory from 10th July to 14th August. How many days he worked?32. If 9 dozen and 12 apples were distributed in each class, how many apples were4044distributed in 12 classes of the school? |
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Answer» 31. from 10th july to 14th August , no of days he worked will be 31+5 = 36 days. 32. total no. of apples are 9*12 +12 = 10*12 = 120 apples and for all 12 classes .. the no of apples are 120*12 = 1440. |
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| 4449. |
8. The areas of three adjacent faces of a cuboid areIf the volumeof a cylinder is 3080 cm" and the base radius is 7 cm, find the height of the cylinder.Also, find (a) curved surface area (b) total surface area. |
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| 4450. |
4. In January, Diya worked for a total of 15 days and in February, she worked for 26.5days. What percentage did Diya's working days increase in February? 76 |
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Answer» correct answer is 76.67 is the best answer .Sahi hai to like plss .🥇🥇🎗🎗🏅🏅🎗🎗🏆🏆🎖🎖 correct answer is 76.67% |
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