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BASIC PROPORTIONALITY THEOREM (BPT) : If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points then the other two sides are divided in the same ratio. This is also known as Thales theorem.

GIVEN:∠Q= 90° , XY || QR, PQ = 6cm, PY = 4cm & PX : XQ = 1 : 2

Since, XY || QR,PX/XQ = PY/YR

[ By Thales theorem (BPT)]½ = PY/YR [PX : XQ = 1 : 2]½ = 4 /(PR - PY)

[YR= PR - PY]

½ = 4 /(PR - 4)PR - 4 = 2 × 4PR - 4 = 8PR = 8 +4

PR = 12cm

In right ∆PQR,PR² = PQ² + QR²

[ By Pythagoras theorem]12² = 6² + QR² [Given : PQ= 6cm]144 = 36 + QR²144 - 36 + QR²108 = QR²

QR =√108 =√ 3×36 = 6√3 cm

Hence, the lengths of PR and QR is 12 cm.& 6√3 cm.

then we convert 8.56rupees in paise then equal 856paise

1 rupee is equal to 100 paise8.56 rupees is equal to 856 paise

8.56 is 856 praise ,that is 1rupee is 100 paise

Perimeter = 450sides in ratio = 12:5:13suppose the sides in ratio =12x , 5x ,13x12x + 5x + 13x = 450 ( perimeter of triangle ) 30x = 450x =450/30x =15

1st side = 12x = 12*15 = 180 m2nd side = 5x = 5*15 = 75m3rd side = 13x = 13*15 = 195m

find s,we know that s = a+b+c/2 ( semi - perimeter )180+75+195/2 = 450/2= 225

area of triangle = √s(s-a)(s-b)(s-c) = √ 225(225-180)(225-75)(225-195)= √ 225*45*150*30= √45562500= 6750m square ans

let the sides be 12x, 5x, 13x respectively. perimeter=12x + 15x + 13x

perimeter = 30xArea = 45030x=450x=15sides are 12*15=180cm 5*15=7513*15=195

12x + 5x + 13x =12x + 18x =30x; x=450/30=15, ;; 12(15) + 5(15) + 18 (15)= 180 + 75 + 270 = 3, 645, 000/450 =810

1rupees =1000paisehence8.25rupees=8.25*1000=8250paise

825 paisa is the answer

1 rupee = 100 paise so, ₹8.25= 8.25×100= 825paise

since 100cm=1mthat's why 5000cm=50m

if 100cm is1 mso 5000cm is 50 m

Answer is, 5000cm=50m

5000cm/10050m in 5000cm

50 m is the correct answer of the given question

50m is correct answer.

50 is correct answer according to your question.

5000 cm = 5×1000 cm= 5m

5m is the right answer

50 my is a right answer

50 metre is right answer

since 100cm =1mthat's why 5000cm =50m

5000cm =50 because 100cm=1m

since 100cm =1mthat's why 5000cm = 50m

100cm=1m

5000=50m

(a) 5000 cm = 50 m is the correct answer

(a) 5000 cm = 50 m is the correct answer

50 m is the correct answer of the given question

5000 cm = 50 m is the best answer.

50 m kyggvdgjgdsfvbjhg

5000cm=50m is the best answer

50 m is correct answer of this question

5000cm=50m is the correct answer

50 meter is correct answer.

we know that,100cm=1m5000cm=50m

let me explain like i am 5Thok, let's startas we know 1km is equal to 1000 M and 1 M is equal to 100 Cm

as your questions

We shall discuss about Cm to M So, we Know 1M = 100 Cm 1 Cm = 1/100 m Now we multiple it by 5000 Cm

(5000*1/100 )= 50 M 50 M is finel answer.

..{ here * mean multiple sign}

7. ×100=7000

1 Rs = 100 paise 7 Rs = 7*100=700

7. × 100=700=700

1 rupee = 100 paise7 rupees = 700 paise

1 rupees=100paisa 7rupees=700paisa

1Rs=100 paiseand 7Rs=7×100=700 paisethis is the answer

1 rupees=100 paisa7 rupees= 700 paisa7× 100= 700

this question answer is =700paise

7 rupees = 70 paise.

solve:- 1Rs.=100 paisethen, 7Rs.=7×100 = 700 paisethis is the correct ans.

1 rs =1007rs=700 right answer

700 rs is right answer

i)In ΔADC and ΔCBA,

AD = CB

(Opposite sides of a ||gm)

DC = BA

(Opposite sides of a ||gm)

AC = CA (Common)

Therefore,

ΔADC ≅ ΔCBA

( by SSS congruence rule.)

∠ACD = ∠CAB ……(i)

(by CPCT)

∠BCA= ∠CAD…..(ii)

(By CPCT)

& ∠CAB = ∠CAD…..(iii)

(Given)

From eq i,ii,iii,

All 4 above angles are equal to each other..

Hence, ∠ACD = ∠BCA

Thus, AC bisects ∠C also.

(ii) ∠ACD = ∠CAD (Proved)

AD = CD (Opposite sides of equal anglesof a triangle are equal)

But, AB= CD & AD= BC

[Opposite sides of a parallelogram]

AB = BC = CD = DA

Hence, ABCD is a rhombus.

Inmathematics, anequivalence relationis abinary relationthat isreflexive,symmetricandtransitive. The relation "is equal to" is the canonical example of an equivalence relation, where for any objectsa,b, andc:

a=a(reflexive property),ifa=bthenb=a(symmetric property), andifa=bandb=cthena=c(transitive property).

As a consequence of the reflexive, symmetric, and transitive properties, any equivalence relation provides apartitionof the underlying set into disjointequivalence classes. Two elements of the given set are equivalent to each other if and only if they belong to the same equivalence class.

so accordingly Option (c) is not an equivalence relation

what is the answer

p(p-q) + q(q-r) + r(r-p)p²-pq + q² -qr+ r² -rpp²+q²+r² - pq-qr-rp

a)2*2/4=1b)3(2)^2(4)/(4)^3=3/4c)(8-8+4)/-16=-1/4d)2*4/2+3*(-2)/4-4*2/(-2)=4-3/2+4=13/2e)(4+2+16)/4=22/4=11/2

A. l and m are parallel as they have same alternative angle

B. l and m are not parallel as they dont have same alternative angles

Explanation -Let the Points A(1,-3), B(2,-5), C(-4,7) beA(x₁, y₁), B(x₂,y₂), C(x₃,y₃).

Let us first find the Slope of AB, y(2) - y(1)m= ---------------- x(2) - x(1)

∴m = (-5 + 3)/(2 - 1) = -2/1 =-2

Now For th Slope of BC,= (7 + 5)/(-4 - 2) = 12/-6 = -2

Since, the Slope of both the lines AB, and BC are same therefore, Points are Collinear.

ans .2,59,81,80,000.00Indian Rupee

Explanation : 8 kg is of 1240 5 kg is of = 775 Rohit pays 775 Rs. Total payment = 775 + 1240 = 2015

Solution : 775 , 2015

If you find this answer helpful then like it.

775 Kaise Aaya Hai

Total money=650+1350=2000Answer=650×100÷2000=32.5%

Tq

complete revolution = 396m/0.42

= 942.8

= 943 revolutions

5x-y=02x+y=7.............7x+0=7

7x=7x=7/7x=1

5(1)-y=05-y=0y=5

Please provide better solution

Assumed mean = 13a.mean = (4+21+13+17+5+9+10+20+19+12+20+14)/12(154)/1212.8assumed mean = 12.8a.mean = 154/12a.mean = 12.8yes i got the same result

Thanks 🙂🙂🙂