InterviewSolution
Saved Bookmarks
InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 4851. |
if the cost of 10 oranges is rupees 50 then what will be the cost of seventeen oranges? |
|
Answer» 10 oranges are of 50 Rs.seventeen oranges are of 17×50/10 = 85 Rs. If you find this answer helpful then like it. mam please tell this question also |
|
| 4852. |
vample 1: Calculate Arithmetic Mean from the data showing the marks obtainedby 7 students of class XTth in certain examination 5,11,16,17,19,24,30. |
|
Answer» Arithmetic mean = (5+11+16+17+19+24+30)/7 = 122/7 = 17.43 |
|
| 4853. |
bervabons.Euample 1: Calculate Arithmetic Mean from the data showing the marks obtaineds 7 students of class XIth in certain examination 5,11,16,17,19,24,30 |
| Answer» | |
| 4854. |
5Calculate the arithmetic mean of the following frequency distribution,using the step-deviation method:[CBSE 2001C1 |
| Answer» | |
| 4855. |
how to calculate central tendency and arithmetic mean in algebra? |
| Answer» | |
| 4856. |
Calculate mode when arithmetic mean is 146 and median is 130.(Ans. Mode 98) |
|
Answer» 2mean = 3median - mode mode = 3(130) - 2(146) = 390 - 292 = 98 |
|
| 4857. |
15.Iraand β are the zeros ofthe quadratic polynomialf(x)r-p(1+1)-c, show that |
| Answer» | |
| 4858. |
\frac{2+5 \sqrt{7}}{2-5 \sqrt{7}}=a+\sqrt{7 b} |
|
Answer» no |
|
| 4859. |
hat is the amount when interest is compounded half yearly.(a) P(1+R/100) 2n (b) P(1+R/200)'n () P(1+2R/100)* |
|
Answer» A= P(1+r/2/100)^2n--this is the required formula |
|
| 4860. |
P ( 5 , r ) = P ( 6 , r - 1 ) |
| Answer» | |
| 4861. |
(2*x - 3)/5 - 7/2=(5*n - 7)/3 |
| Answer» | |
| 4862. |
Riya purchase a book for rupees 120 then she sold that book for rupees 110.Find her profit or loss percent . |
|
Answer» loss=120-110=10loss %=10/120×100 =8.33% |
|
| 4863. |
John bought 2 horses add rupees 20000 each he sold one horse at a gain of 15% but he had to sell the other horse at a loss if he had suffered a loss of 1800 rupees on the whole transaction find selling price of second horse |
|
Answer» Profit on first horse = 20,000*15% 15/100 * 20000= Rs. 3000 SP = 23000 Loss on the second horse = x SP= CP-loss SP= 20000-x SP of both = 23000+20000-x CP of both = 40000 CP-SP=Loss = 1800 40000-(43000-x)= 1800 40000-43000+x=1800 -3000+x=1800 x= 4800 SP= cp-loss SP= 20000-4800 SP= 15200 He sold second horse for Rs. 15200. 00 |
|
| 4864. |
Thomas bought 10 cents of land at 75000 rupeesacent. He spent 50000 rupees to build a wall aroundand 60000 rupees to dig a well. He sold the plot at90000 rupees a cent. Was it a gain or loss for him?How much? |
|
Answer» it is a gain for him as it costed him 860,000but he sold it at 90,0000he got 40,000rs |
|
| 4865. |
sameer bought 1600 bananas at rs.3.75 a dozen.he sold 900 of them at 2 for rupees 1 and the remaining at 5 for rupees 2 . find his gain or loss percent |
|
Answer» Cost of 12 bananas = rs 3.75cost of 1 banana = 3.75/12cost of 1600 bananas = 1600*3.75/12= rs. 500s p. of bananasfirst case,s.p. of 2 bananas = rs. 1s.p. of 1 banana = rs. 0.5 s p. of 900 bananas = rs.0.5*900 = 450second case,no.of bananas = 1600-900 = 700cost of 5 bananas = rs. 2cost of 1 banana = rs.0.4cost of 700 bananas = rs 0.4*700= 280total selling price = 450+280= 730c.pSo, their is gain gain percent = xs.p.-c.p./c. p.*100 = x730-500/500*100=x230/500*100=46x = 46% Therefore, gain percent = 46% |
|
| 4866. |
63 rupees 50 paise write in figure |
|
Answer» 63 +0.5 rupees = 63.50 The correct answer is 63.50 |
|
| 4867. |
A shopkeeper buys a T.V. set for Rupees 4,950 and spends Rupees 50 on its relair.He sells it for Rupees 5,500.Find his profit percent. |
|
Answer» Cp=4950+50=5000sp-cp =profit5500-5000=500500/5000×100=10%profit% =10% |
|
| 4868. |
7/Draw a circle with the help of a bangle. Take a point outside the circle. Construct the pairof tangents from this point to the circle. |
| Answer» | |
| 4869. |
lat, polIf x² + x2 = 27 find+ |
|
Answer» 1+√7/-6 is right answer √29 is correct answer |
|
| 4870. |
lat ,UM |
| Answer» | |
| 4871. |
Lat-10his 261o |
| Answer» | |
| 4872. |
eccolat565454i) |
| Answer» | |
| 4873. |
Do THISTake several cut-outs of(i) an equilateral triangle(ii) an isosceles triangle and(ii) a scalene triangle.Find their altitudes and medians. Do you find anything special about them? Discussit,with your friends. |
|
Answer» an equilateral triangles an equilateral triangle an equilateral triangle is the option, a is the right answer |
|
| 4874. |
( 5+ ( - 3) ) - 2\quad 5) ( - 7) + |
|
Answer» Please post a clear image. =5-3-2=0 |
|
| 4875. |
1-पघ के |. 803 2lotoz 359 ‘6007 41y HION| |
|
Answer» cos¯¹ 12/13 + sin¯¹ 3/5 = sin¯¹ 56/65Taking L.H.S. : ⇒ sin¯¹ 5/13 + sin¯¹ 3/5 Using the formula, sin¯¹x + sin¯¹y = sin¯¹ ( x√1-y² + y√1-x² ) ⇒ sin¯¹ ( 5/13 √1-9/25 + 3 √1-25/169)⇒sin¯¹ ( 5/13 × 4/5 + 3/5 × 12/13)⇒sin¯¹ (30 + 36 / 65)⇒ sin¯¹ (56/ 65) please like the solution 👍 ✔️ |
|
| 4876. |
The sum of the ages of Ashok and his father is 45 years and the product of their ages is 126. Find the agesof the father and the son. |
| Answer» | |
| 4877. |
\left. \begin{array} { r } { 3 A } \\ { + \quad 2 \quad 5 } \\ \hline B \\ \hline \end{array} \right. |
|
Answer» A+5=2lets take A=7so 7+5=12so B=1+3+2=6so 37+25=62 so A=7 and B=6 |
|
| 4878. |
What is the eccentricity of the conic4x^2+9y2=144?\frac{\sqrt{5}}{3} \quad(b) \frac{\sqrt{5}}{4} \quad(0) \frac{3}{\sqrt{5}} |
| Answer» | |
| 4879. |
Problrite the factors of the following numbers(1) 8 (2)5 (3) 14 (4) 10 (5 |
| Answer» | |
| 4880. |
- writethesolution -Equationvalue ofvosibleSolutionCyes (No)I + 10 = 30 |
|
Answer» Noright ans like this answer x+10=30x=30-10x=20NO, is correct answer. |
|
| 4881. |
1. Write the degree of each of the following polynomia(a) 4x+ 5x3 -7 (b)16xA((d) 52 -161xmials? |
|
Answer» a) degree- 4b)degree-5c) degree- 0d) degree-9 where is statement degree of a polynomial is the highest power in a polynomial.hence write the highest power |
|
| 4882. |
Aftab tells his daughter, "Seven ycars ago, I was seven times as old as youwere then. Also, three years from now, I shall be three times as old as youwill be." (Isn't this interesting?) Represent this situation algebraically andgraphically |
| Answer» | |
| 4883. |
22Theages of two friends Anil and Bipin differ by 3 years. Anil's father Dharmananda is twice as old as Anil and Bipinis twice as old as his sister Roopa. The ages of Roopa and Dharmananda differs by 30 ycars. Form the pair of linearqustions |
|
Answer» Replace Ani as Anil and Biju as Bipin. |
|
| 4884. |
18. Raju is 19 ycars younger than his cousin. After 5 years, their ages will be in the ratio 2Find their present ages. |
| Answer» | |
| 4885. |
Achinta bought a pair of shoes worth 359.85. If he gave aR 500 note, how much money should the shopkeeper return? |
|
Answer» Cost of shoes = ₹ 359.85 Cost paid = ₹ 500 Cost return = 500 - 359.85 = ₹140.15 |
|
| 4886. |
Sum of the ages ofa father and the son is 40 ycars. If father's age is three times thatof his son, then find their respective ages. |
|
Answer» When Sum of the ages of a father and the son is 40 years then age of father will be 3 times that of his son find their respective ages Let father age is x, Son age is y. Then x+y=40 -------- (1) x=3y ----------- (2) Substitute x value in equation (2) from equation (1) 3y+y=40 then y=10 and x=30 |
|
| 4887. |
a theamounttobepaidattheendof4 ycars in each case"t1.600 at the rate of 8% per annum.-t24 ,000 at the rate of 4% per annum.when simple interest at 5% pa, for 15 years is?2.500.1Find the princt24,000 into two parts such that the simple interest on the first part for 4 years at 12% peris equalto the simple interest on the second part for 6 years at 16% per annum.s A sam of money at simple interest doubles itself in 4 years. In how much time will t tmple |
|
Answer» A certain sum of money amount to$756 in 2 year and to $ 873 in 3.5 year. find the sumand the rate of interest |
|
| 4888. |
HereI1.Baichung's father is 26 years younger than Baichung's grandfather and 29 yearsolder than Baichung. The sum of the ages of all the three is 135 ycars. What is the ibtractrm invage of each one of them? |
| Answer» | |
| 4889. |
6. A car covers a certain distance at a uniform speed of 66 - km per hour. How muchCOINwill it cover in 9 hours? |
| Answer» | |
| 4890. |
5. Got is being suudacar covers a certain distance at a uniform speed of 66 km per hour. How much distance110DNwill it cover in 9 hours?Ru3 |
| Answer» | |
| 4891. |
The wheels of a car are of diameter 80 cm each. How many complete revolution does each wheel make in 10 minutes when the car is travelling at a speed of 66 km per hour |
|
Answer» 2 3 this answer is wrong akul ok now it's correct |
|
| 4892. |
(4*quad)/5 %2B 3/11 |
|
Answer» 4/5 + 3/11= (44+15)/55= 59/55 59/55 is the right answer 59/55 is the right answer |
|
| 4893. |
\left. \begin array l \text (a) 5,9,13 , \\ \text (a) 11 \quad 21,3 \end array \right. |
| Answer» | |
| 4894. |
226MATI IEMİTICS2. The wheels of a car are of diameter 80 cm each. How many complete revolutions doeseach wheel make in 10 minutes when the car is travelling at a speed of 66 km per hour? |
| Answer» | |
| 4895. |
The wheels of a car are of diameter 80 cm each. How many complete revolutions doeseach wheel make4.in 10 minutes when the car is travelling at a speed of 66 km per hour? |
| Answer» | |
| 4896. |
2 \left( \cos ^ { 2 } 45 ^ { \circ } + \tan ^ { 2 } 60 ^ { \circ } \right) - 6 \left( \sin ^ { 2 } 45 ^ { \circ } - \tan 30 ^ { \circ } \right) = 6 |
| Answer» | |
| 4897. |
Daily wages of 45 workers in a factory are given below1251751220010150Daily wages (in 3)Number of workers100Find the median, mean and mode of the above data. |
| Answer» | |
| 4898. |
226MATHI MAICThe wheels of a car are of diameter 80 cm each. How many complete revolutions doeseach wheel make in 10 minutes when the car is travelling at a speed of 66 km per hour?id iuctifc rour choice: If the perimeter and theW |
| Answer» | |
| 4899. |
ple 25 : Factorise : 8ry27z3 - 18ryz |
| Answer» | |
| 4900. |
Megha bought 10 note-books for40 and soldthem at R 4.75 per note-book. Find her gainpercent. |
|
Answer» Cost for 10 notebooks = 40 RupeesSelling price of Megha per notebook = 4.75Selling price for 10 notebooks = 4.75 * 10 = 47.5 RsGain = SP - CP = 47.5 - 40 = 7.5 Rs Gainpercentage = Gain/ CP * 100 = 7.5/40 *100 = 7.5*100 /40 = 7.5 * 5/2 = 37.5/2 = 18.75 % The gain percentage is 18.75% = Cost of 10 note books = rs 40= cost of one notebook = rs 4.= Cost price of one note book = rs 4= Selling price = rs 4.75= Gain = 4.75 - 4 = rs 0.75. |
|