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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 4901. |
State the nature of the roots of the quadratic equation2x2-2x+15=0 from its discriminant. |
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| 4902. |
10. (a)There are three types of workers-men, women and children working in a factory-calculateaverage wage per day if a man is paid Rs. 80, woman Rs. 60 and child Rs. 40.[Ans. Rs. 60] |
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Answer» thanks 🙂🙂 |
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| 4903. |
so (a) There are three types of workers-men, women and children working in a factory--calculateaverage wage per day if a man is paid Rs. 80, woman Rs. 60 and child Rs. 40 |
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Answer» Average = 80 + 60 + 40/3average = 180/3average = 60 (80+60+40) /3=180/3=60 average= (80+60+40/3) = 180/3=60 |
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| 4904. |
25 m ^ { 2 } = 9 \quad ( 11 ) 7 m ^ { 2 } = 21 m |
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Answer» 10) 25m^2=9 m^2=9/25 so, m=+- 3/511) 7m^2=21m m=21/7 |
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| 4905. |
( \operatorname { sec } ^ { 2 } \theta - 1 ) \operatorname { cot } ^ { 2 } \theta = 1 \quad 11 . ( 1 - c ) |
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| 4906. |
\operatorname { cosec } \theta + \operatorname { cot } \theta = \frac { 11 } { 2 } \quad \text { then tan } \theta = |
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| 4907. |
Awallof100metrescanbe builtby 7 men or 10 women in 10 days.How many days will 14 men and20 women take to build a wall o600 metres?(1) 15(3) 25(2) 20(4) 30 |
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Answer» let no of days taken be xwall built by 10 women in 10 days=100mwall built by 1 woman in 1 day= 100/(100)=1mwall built by 20 women in 1 day= 20mwall built by 7 men in 10 days= 100mwall Built by 1 man in 1 day= 100/70 mwall built by 14 men in 1 day= 20mso, 20x+ 20x=600or, 40x=600or, x=600/40=15 days |
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| 4908. |
27. The total number of men, women and children working in afactory is 18. They earn Rs. 4000 in a day. If the sum of thewages of all men, all women and all children is in the ratio of18:10 : 12 and if the wages of an individual man, womanand child is in the ratio 6:5:3, then how much a womanearn in a day?(a) Rs. 400(b) Rs. 250(d) Rs. 120(C) Rs. 150f workers was put on a job. From the second day |
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| 4909. |
645% of the population of a town is men and 30% is women. What is the percentage of children? |
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Answer» 45% are men and 30% are women so remaining are children so remaining are 100-30-45=25%so remaining 25% are children |
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| 4910. |
(11 Sila hlas JJTUVICO TW Fun10. There are 28 men, 32 women and 16 children at a party. Find the ratio of:(a) the number of men to the number of women.(b) the number of women to the number of children.(c) the number of children to the number of men at the party. |
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Answer» a)28:32b)32:16c)28:16 (i) the ratio between men and women is 28/32=7/8 or7:8(ii)the ratio between women and children is 32/16=2:1(iii)the ratio between child a) 28x32 =7/8or7:8b) 32/16 =2:1c)28/16 =7/4or 7:4plz accept best answer a)28×32=7/8or7:8b)32/16=2:1c)28/16=7/4or7:4please like a)28:32b)32:16c)28:16 answer. |
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| 4911. |
s price of an item and isSole66. In:In a factory. womenbeing men. The nuthe total numbeory. women are 35% of all the workers, the rest of the WONThe number of men exceeds that of womental number of workers in the factory.Three bags contain 6467. Three |
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| 4912. |
e 24 : Factorise &' + 27y + 36r'y +54xy2 |
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Answer» 8x^3 + 27y^3 +36x^2y + 54xy^2 =>(2x)^3 + (3y)^3 + 3 (2x)^2 (3y) + 3 (2x)(3y)^2 we know , (a + b)^3 = a^3 + b^3 + 3a^2b + 3ab^2 use this =>(2x + 3y)^3 hence , factorization of given expression is (2x + 3y) , (2x + 3y) and (2x + 3y) |
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| 4913. |
ple 24: Factorise St+ 27y36ry+ 54x |
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| 4914. |
10. Find the values of p for which the quadratic equation(p + 1) x2-6 (p + 1) x + 3 (p + 9) = 0, pメ-1 has equal roots. Hence, findCBSE 2015]the roots of the equation. |
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| 4915. |
15. If - 5 is a root of the quadratic equation 2x2+pr 15 -0 and the quadratic equationp2 + x〉 + k 0 has equal roots, find the valueof p and k. Also find the second root of 2a2 +pa |
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| 4916. |
In a group of 70 persons there are 15 boys, 20 girls,30 men and rest women. Find the probability thata selected person is a woman. |
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| 4917. |
6.b) Add the following fractions1)14 1227 272)3) 2332 |
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| 4918. |
If-5 is a root of the quadratic equation 2x2 +p x-15-O and the quadratic equationp(x +x) +k-0 has equal roots, find the value of k |
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| 4919. |
Iff: [-6, 6]â R is defined by f (x)-r-3,VIE R , then (fofon (-1 ) + (fofon(0) + (fofof)(1) =b) f3 2)e) f2/2)d) f2) |
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| 4920. |
12. Is 0.3 a root of the equation2 0.9-0 Justity.13. If (-5) is a root of the quadratic equation 2x2px 15 0 and the quadratic equationp(x2+x)k 0 has equal roots, then find the value ofk? |
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Answer» 12. no not true as (0.3)^2 -0.9= .81 not equal to 0. |
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| 4921. |
9. A number has 33 as its factor. Name threeother factors of that number. |
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Answer» 33 prime factorization is 1× 3 × 11 So, other factor than 33 are 1, 3, 11 wrong |
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| 4922. |
2. Use quadratic formula to solve the following quadratic equation for xp^{2} x^{2}+\left(p^{2}-y^{2}\right) p-q^{2}=0 |
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Answer» thanks bro |
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| 4923. |
x*(a*(r*(r*(o*(w*(2*(quad*((11*x %2B x^3 - 6*x^2 - 6)/(x^2 - 6*x %2B 8))))))))) |
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| 4924. |
1.Express as rupees using decimals.(i) 5 paise(iii) 750 paise(ii) 85 paise(iv) 50 rupees 90 paise |
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Answer» 0.05. 0.85. 7.50. 50.90. |
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| 4925. |
निर्देश (प्र.सं. 12 और 13) नीचे दिए गए विकल्पों में से लुप्त अंकज्ञात कीजिए।12.{ ? | 918 | 12(d) 27 |
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Answer» 273 × 3 = 93 × 4 = 123 × 6 = 183 × 9 = 27 Here यहां 27 सब उस खाली स्थान में भरा जाएगाक्योंकि 3*3= 93*4= 123*6= 183*9= 27 27 answer (3*3=9/3*4=12/3*6=18/3*9=27 |
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| 4926. |
years3600 amount to4410 at 9% per annum simple interest?4. In what time will |
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| 4927. |
ALRCISE 8.4Express as rupees using decimals.(a) 5 paise(d) 50 rupees 90 paise(b) 75 paise(c) 20 paise(e) 725 paise-Xpress as metres lla. |
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| 4928. |
X. Represent the following irrational numbers on number line.(1) VTO (1) V7 LAT 2+12 |
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| 4929. |
\frac{x^{2}+12 x}{6 x^{2}+8}=\frac{y^{3}+27 y}{9 y^{2}+27} |
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| 4930. |
\frac { x ^ { 3 } + 12 x } { 6 x ^ { 2 } + 8 } = \frac { y ^ { 3 } + 27 y } { 9 y ^ { 2 } + 27 } \cdot |
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| 4931. |
() Using properties of proportion, find xyif\frac{x^{3}+12 x}{6 x^{2}+8}=\frac{y^{3}+27 y}{9 y^{2}+27} |
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| 4932. |
(4*(12^4*9^3))/((27*(6^3*8^2))) |
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| 4933. |
U wilt 15 dieger but not a natud8. Find five rational numbers between 1 and 2. |
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Answer» 1×6/1×6,2×6/2×6=6/6,12/6,therfore the five rational numbers are 7/6 , 8/6 , 9/6, 10/6 , 11/6 1=1×4=4×2=82=2×4=8×2=16therefore the no.s are 9,10,11,12,13. Five rational numbers between 1 & 2 are: 1.1 , 1.2 , 1.3 , 1.4 , 1.5 |
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| 4934. |
8. On one page of a telephone directory, there are 200 phone numbers. Thefrequency distribution of their units digits is given below:Units digit 0Frequency 19 22 23 19 21 24 23 18 16 15One of the numbers is chosen at random from the page. What is theprobability that the units digit of the chosen number is (i)5? (ii) 8? |
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| 4935. |
Date, 1-1Page DX18 1 |
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Answer» 8x*x*x + 27y*y*y + z*z*z - 18xyz = (2x+3y+z)(4x*x+9y*y+z*z-6xy-3yz-2xz) |
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| 4936. |
Page No.Date* mt=18 then findthe value oy |
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| 4937. |
find in how much time will rupees 4000 amount toRupees 4410 at 5 % p.a. interest compound annually |
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Answer» Here the amount A = 4410 principle is = 4000 and rate is 5% = 5/100 = 0.05 per annum... let n = time so A = p(1+r)ⁿ=> 4410 = 4000(1+0.05)ⁿ=> (1.05)ⁿ = 441/400 = 1.1025 => n = 2. so, time is 2 years. |
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| 4938. |
18. Tanveer bought 20 pencils för50 and sold them at3 each. What was her profit or loss percent?5 each. If he had paid85 for the pens, what was his profit. Vicky bought 20 pens and sold them ator loss? |
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Answer» 18)20 pencil cost price= ₹5020 pencils selling price= 20×3=₹60profit= sp - cp = 60 -50 = 10%profit= profit×100/cp = 10×50/100 = 5%19)20 pens cost price= ₹8520 pens selling price= 20×5= ₹100so>cpso profit=sp -cp = 100-85 = ₹15%profit= profit×100/cp = 15×100/85 =300/17% profit% =5% is the correct answer is profit is 5 % it is the correct ans cp of 20 pencil=₹50sp of 20pencil=20×3=₹60profit=sp-cp =₹60-50=₹10 cp=50sp=20×3=60profit =sp-cp=60-50=10profit %=10/50×100=20%. 20% profit is the right answer 20%profit is the correct answer of the given question i think 20 % is the right answer of this question |
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| 4939. |
rite the equation of two lines passing through (3, -5) |
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Answer» If a line parellel to x-axis then slope equal zerohence equation of line (y-3)=0= (x-(-4)y=3 again a line parellel to y-axis then slope is 1/0hence equation of line is (y-3)=1/0= (x+4)0=x+4hence x=-4 Read more on Brainly.in - https://brainly.in/question/1075581#readmore |
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| 4940. |
The pens bought at 18 each were sold at12%. What is the selling price ofthe pens? |
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| 4941. |
A shopkeeper bought some pens at 3 for Rs.10 and the double pens at 4 for Rs. 13. If hesold all the pens at Rs. 59 a dozen, find thepercentage profit. |
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| 4942. |
3 5 5Q.6 The weight of 14 boxes is 30 kg. Find teQ.7 Expressed 20 rupees 5 paisa in decimalsQ. 8 Subtract : 93–2(0.9 Solve : * * * * |
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Answer» 12/15×16/24×30/60×1/2= 3x2/3×5 × 4x4/6×4×30/60×1/2= 2/5 × 6/4 ×2/2=2/5×6/4=30/2=15 A.9:-2/15 is right answer of this question. please like my answer 8) 9(3/4)-2(1/2)=39/4-5/2= 39(2)-5(4)/8=78-20/8=58/8=7.25 3x2/3×5 × 4x4/6×4 × 30/60×1/2=2/5×4/6x1/2×1/2=20/12×2/2=5/3×2/2=3/5 answer is the 2/15............ |
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| 4943. |
A stationary shopkeeper sold 600 pens at a profit of 15%. If a pen costs him 26, find the selling pricethe pens. |
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| 4944. |
7 Rupees 5 Paisa in Rupees |
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Answer» 1 paise = 1/100 ruppes 5 paise= 1/100*5 =5/100 =1/20=0.05 RS.7 rupees 5 paisa=7rupees+0.05rupees=₹7.05 |
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| 4945. |
5, Write 12 rupees 75 paise in terms of rupees. |
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Answer» We know,One rupee = 100 paise Then,12 rupees 75 paise= 12 + 75/100= 12.75 rupees 12 rupees+75/100 rupees=12.75 rupees 12.75rs is the right answer this is the right answer 12.75 rupees is the correct answer of the given question 12.75 is the best answer |
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| 4946. |
ORIn fig. APB and AQPase semi-cirdes, and AO- OB If the perimeter of the following figthe area of the shaded region. | Use Ďis 47 cm, findin |
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| 4947. |
after what time will rupees 4000 give an interest of rupees 500 at 5 % p a |
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Answer» 500 = 4000*t*5/100 t = 500*100/5*4000 t = 10/4 = 2.5 years |
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| 4948. |
(6) The total cost of 8 books and 5 pens is 420 rupees and the total cost of 5 books and 8pens is 321 rupees. Find the cost of 1 book and 2 pens. |
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Answer» Let cost of one book be x and cost of one pen be y 1st.equation 8X + 5Y = 4202nd.equation 5X + 8Y = 321 1st.eq × 5 40X + 25 Y = 21002nd.eq×8 40X + 64Y = 2568 Subtracting(-) 39Y = 468 Y= 12Putting the value of Y in eq.1 we get , X=45 cost of 1book = 45 cost of 2 pen = 2×12=24 |
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| 4949. |
18. Solve for : (a)|-x +4]1(b)loz-2| = 8(c)12c + 11 = x + 3 |
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Answer» a) |4-x| ≤ 1..... open modulus with both the signs (-1 and +1) => -1≤ 4-x ≤1 so, -5 ≤ -x ≤ -3 => 3≤ x ≤ 5 b) |5x-2| = 8.....open modulus with both the signs (-8 and +8) => 5x-2 =8 => 5x=10 ,so x = 5or 5x-2 = -8 => 5x = 6 or x = 6/5 c) |2x+1| = x+3 so 2x+1 = x+3 or , x = 2 or 2x+1 = -x-3 => 3x = -4or x = -4/3. |
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| 4950. |
if 12c+6cd=co9,find the value of c and d |
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Answer» : please post the complete question |
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