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3301.

If (a+b+c)^(2) = 3 (ab+ bc+ ca), then which one of the following is true?

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`a ne b ne C`
`a gt b gt c`
`a LT b lt c`
`a= b= c`

ANSWER :D
3302.

Match roster forms with the set builder form.

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Answer :(i) D (II) C (iii) a (IV) B
3303.

If the total value of the mutual fund scheme is 200 crores and 8 crore units are issued them find the NAV of one units.

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ANSWER :25
3304.

Water flows, at 9 km per hour, through a cylindrical pipe of cross-sectional area 25 cm? If this water is collected into a rectangular cistern of dimensions 7.5 m by 5 m by 4 m, calculate the rise in level in the cistern in 1 hour 15 minutes.

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ANSWER :75 CM
3305.

IfP=[(6,-2),(4,-6):}] and Q = [{:(5,3),(2,0):}]find the matrixM such that2Q - 3P - 3M =0

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ANSWER :` (1)/(3) [{:( -8, 12),(-8, 18) :}]`
3306.

A solid is in the form of a right circular cylinder with a hemisphere at one end and a cone atthe other end. The radius of the common base is 8 cm and the heights of the cylinderical and conical portions are 10 cm and 6 cm respectively. Find the total surface area of the solid. "" [Use pi=3.14]

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ANSWER :`1156/57 cm^2`
3307.

Draw a labelled figure showing information given in the following statement : If the altitudes drawn on two sides of a triangleare congruent then those two sides are congruent .Also write the antecedent and the consequent part with respect to the figuredrawn.

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Solution :
Antecedent : ALTITUDES draws on TWO sides of triangle are congruent .
seg CN `bot` side AB, A-N-B. seg BM `~=s`eg CN .
CONSEQUENT : The two sides are congruent . Side AB `~= `side AC.
3308.

Dipesh bought 3 notebooks and 2 pens for Rs. 80. His friend Ramesh said that price of each notebook could be Rs. 25. Then three notebooks would cost Rs.75, the two pens would cost Rs. 5 and each pen could be for Rs. 2.50. Another friend Amar felt that Rs. 2.50 for one pen was too little. It should be at least Rs. 16. Then the price of each notebook would also be Rs.16. Lokesh also bought the same types of notebooks and pens as Dipesh. He paid 110 for 4 notebooks and 3 pens What is the total cost if they will purchase the same type of 15 notebooks and 12 pens.

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Rs 410
Rs 200
Rs 420
Rs 240

Solution :TOTALCOST `15xx20 +12XX10 = 420` Rs
Thus (c) is correct option.
3309.

Dipesh bought 3 notebooks and 2 pens for Rs. 80. His friend Ramesh said that price of each notebook could be Rs. 25. Then three notebooks would cost Rs.75, the two pens would cost Rs. 5 and each pen could be for Rs. 2.50. Another friend Amar felt that Rs. 2.50 for one pen was too little. It should be at least Rs. 16. Then the price of each notebook would also be Rs.16. Lokesh also bought the same types of notebooks and pens as Dipesh. He paid 110 for 4 notebooks and 3 pens What is the exact cost of the pen?

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Rs 10
Rs 20
Rs 16
Rs 24

Solution :COST of 1 PEN = Rs. 10
Thus (a) is CORRECT option.
3310.

Dipesh bought 3 notebooks and 2 pens for Rs. 80. His friend Ramesh said that price of each notebook could be Rs. 25. Then three notebooks would cost Rs.75, the two pens would cost Rs. 5 and each pen could be for Rs. 2.50. Another friend Amar felt that Rs. 2.50 for one pen was too little. It should be at least Rs. 16. Then the price of each notebook would also be Rs.16. Lokesh also bought the same types of notebooks and pens as Dipesh. He paid 110 for 4 notebooks and 3 pens What is the exact cost of the notebook?

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Rs 10
Rs 20
Rs 16
Rs 24

Solution :Solving 3x + 2Y = 80 and 4x + 3y = 110 we get
x = 20 and y = 10
Thus cost of 1 notebook is 20 Rs and cost of 1 pen is 10 Rs
Thus (B) is correct option.
3311.

Dipesh bought 3 notebooks and 2 pens for Rs. 80. His friend Ramesh said that price of each notebook could be Rs. 25. Then three notebooks would cost Rs.75, the two pens would cost Rs. 5 and each pen could be for Rs. 2.50. Another friend Amar felt that Rs. 2.50 for one pen was too little. It should be at least Rs. 16. Then the price of each notebook would also be Rs.16. Lokesh also bought the same types of notebooks and pens as Dipesh. He paid 110 for 4 notebooks and 3 pens Whether the estimation of Ramesh and Amar is applicable for Lokesh?

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Ramesh’s ESTIMATION is WRONG but Amar’s estimation is correct.
Ramesh’s estimation is correct but Amar’s estimation is wrong
Both estimation are correct.
Ramesh’s estimation is wrong but Amar’s estimation is also wrong.

Solution :Consider the prices mentioned by Ramesh.
If the PRICE of one notebook is Rs. 25 and the price of one pen is Rs. 2.50 then,
The cost of 4 notebooks WOULD be : `4 xx 25 = 100` Rs
And the cost for 3 pens would be : `3 xx 2.5 = 7.5` Rs
Lokesh should have paid `100 + 7.5 = 107.5` Rs.
But he paid Rs. 110, thus Ramesh’s estimation is wrong.
Now, consider the prices mentioned by Amar.
The cost of 4 notebooks, if one is for Rs.16, would be : `4 xx 16 = 64` Rs
And the cost for 3 pens, if one is for Rs. 16, would be : `3 xx 16 = 64` Rs
Lokesh should have paid `64 + 48 = 112` Rs but this is more than the price he paid.
Therefore, Amar’s estimation is also wrong.
Thus (d) is correct option.
3312.

Let A(3,2), B(4, 1),C(3,1), and D(2, 4) be the vertices of a quadrilateral ABCD. Find the area of the quadrilateral formed by joining the midpoints of the sides of the quadrilateral ABCD.

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ANSWER :105 sq.units
3313.

Dipesh bought 3 notebooks and 2 pens for Rs. 80. His friend Ramesh said that price of each notebook could be Rs. 25. Then three notebooks would cost Rs.75, the two pens would cost Rs. 5 and each pen could be for Rs. 2.50. Another friend Amar felt that Rs. 2.50 for one pen was too little. It should be at least Rs. 16. Then the price of each notebook would also be Rs.16. Lokesh also bought the same types of notebooks and pens as Dipesh. He paid 110 for 4 notebooks and 3 pens Let the cost of one notebook be x and that of pen be y . Which of the following set describe the given problem ?

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`2x + 3Y = 80 and 3x + 4y = 110`
`3x + 2y = 80 and 4x + 3y = 110`
`3x + 2y = 80 and 4x + 3y = 110`
`3x + 2y = 80 and 3x + 4y = 110`

Solution :According to the STATEMENT, we have
`3x + 2y = 80 and 4x + 3y = 110`
THUS (b) is correct option.
3314.

A spiral is made up of successive semicircles, with centres alternately at A and B, starting with centre at A, of radii 0.5 cm, 1.0 cm, 1.5 cm, 2.0 cm, ... as shown in Figure. What is the total length of such a spiral made up of thirteen consecutive semicircles? (Take pi= 22/7) [Hint : Length of successive semicircles is 11, 12, 13, 14, ... with centres at A, B, A, B, ..., respectively.]

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ANSWER :143
3315.

Let A={1,2} and {3,4}. ThenAxxB=?

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`{(1,2),(3,4)}`
`{(1,3),(2,4)}`
`{(3,8)}`
`{(1,3),(1,4),(2,3),(2,4)}`

ANSWER :D
3316.

A solid metallic sphere of diameter 28 cm is melted and recast into a number of smaller cones, each of diameter 4""2/3 and height 3 cm. Find the number of cones so formed.

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ANSWER :672
3317.

If the sum of first 6 terms is 12 and sum of first 10 terms is 60, find the sum of its n terms.

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ANSWER :`N(n - 4)`
3318.

Some students planned a picnic. The total budget for picnic was Rs 2000 but 5 students failed to attend the picnic and thus the contribution for each student is increased by Rs 20. How much money they spent for travelling ?

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RS 500
Rs 1000
Rs 800
Rs 3750

Solution :Expanse on travelling `50xx20=1000`
Thus (B) is CORRECT option.
3319.

Some students planned a picnic. The total budget for picnic was Rs 2000 but 5 students failed to attend the picnic and thus the contribution for each student is increased by Rs 20. What is the total expanse for this picnic ?

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Rs 1500
Rs 2000
Rs 1000
Rs 2100

Solution :Expanse PER Student `=5+10+25+50+15=105`
Total expanse, `""105xx20=2100`
Thus ( c ) is correct OPTION.
3320.

Some students planned a picnic. The total budget for picnic was Rs 2000 but 5 students failed to attend the picnic and thus the contribution for each student is increased by Rs 20. What is the number of students who attended the picnic?

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20
40
15
25

Solution :Thus, `""x=25-5=20` STUDENTS ATTENDED PICNIC
Thus (a) is CORRECT option.
3321.

Some students planned a picnic. The total budget for picnic was Rs 2000 but 5 students failed to attend the picnic and thus the contribution for each student is increased by Rs 20. What is the number of students planned for picnic ?

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30
40
25
20

Solution :We have `""X^(2)-5x-500=0`
`x^(2)-25x+20x-500=0`
`(x-25)+20(x-25)=0`
`(x-25)(x+20)=0`
`x=25,-20`
Thus ( c ) is CORRECT option.
3322.

Some students planned a picnic. The total budget for picnic was Rs 2000 but 5 students failed to attend the picnic and thus the contribution for each student is increased by Rs 20. If x is the number of students planned for picnic, which is the correct quadratic equation that describe the situation.

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`x^(2)-5x-500=0`
`x^(2)+4x-400=0`
`x^(2)+5x-500=0`
`x^(2)-4x+400=0`

Solution :We have `""(2000)/(x)+20=(2000)/(x-5)`
`2000(x-5)+20x(x-5)=2000x`
`-10000+20x^(2)-100x=0`
`x^(2)-5x-500=0`
Thus (a) is CORRECT option.
3323.

Which term of the following A.P. is 560? 2,11, 20, 29,……

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ANSWER :63RD TERM
3324.

Check weather statement is true or False : A pair of tangents can be constructed to a circle or radius 5 cm from a point P situated at a distance of 4 cm from the centre.

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ANSWER :FALSE
3325.

If from an external point B of a circle with centre O, two tangents BC and BD are drawn such that angleDBC=120^(@), prove that BC+BD=BO.

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SOLUTION :`angle1+angle2=120^(@)""`(fiven)
But `angle1=angle2""`(tangents are equally inclined at the centre)
`:.""angle1+angle1=120^(@)`
`implies""2angle1=120^(@)`
`implies""angle1=60^(@)`
ALSO, `angleOCB=90^(@)`
(radius through point of contact is `_|_` to the tangent)
Now, in right `triangleOCB,`
`cos60^(@)=(BC)/(OB)`
CIRCLES
`implies""(1)/(2)=(BC)/(OB)`
`:.""OB=2BC""implies""OB=BC+BC`
`implies""OB-BC+BD`(`:.` length of tangents from an external point are equal)

Hence Proved.
3326.

What should be added to the polynomial x^(3)-3x^(2)+6x-15, so that it is completely divisible by x-3 ?

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ANSWER :On dividing `X^(3)-3x^(2)+6x-15` by `x-3`, remainder is `+3`, hence `-3` MUST be added to `x^(3)-3x^(2)+6x-15`.
3327.

Which one is different from the other four given below ?

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Rose
Lotus
Apple
lily

Answer :C
3328.

Find the next three terms of the sequence : 36,12,4, . . . . . . . . . . ..

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ANSWER :`(4)/(3),(4)/(9)" and "(4)/(27)`
3329.

Solve the quadratic equations by factorisation method:

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ANSWER :` =-10 , - 5`
3330.

Evaluate : if possible (i) [3,2] [{:(,2),(,0):}] (ii) [1 , -2] [{:(,-2,3),(,-1,4):}] (iii) [{:(,6,4),(,3,-1):}] [{:(,-1),(,3):}] (iv) [{:(,6,4),(,3,-1):}] [{:(,-1),(,3):}]

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Answer :(i) [6] (II) [0, -5] (iii) `[{:(,6),(,-6):}]` (IV) Not POSSIBLE, as the no. of columns in first matrix is not equal to no. of rows in the second matrix.
3331.

In triangleABC,D and E are points on the sides AB and AC respectively such that DE||BC. If (AD)/(DB)=(3)/(4) and AC=15cm find AE.

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ANSWER :6.43 CM
3332.

Determine whether the values given against each of the quadratic equations are the roots of the quadratic equation or not :

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Solution :Substituting m=2,
`LHS=2(2)^(2)-5(2)`
=2(4)-10
=8-10
`=-2neRHS`
`:.m=2` is not the ROOT of the GIVEN QUADRATIC equation.
Substituting `m=(5)/(2)`
`LHS=2((5)/(2))^(2)-5((5)/(2))`
`=2((25)/(2))-(25)/(2)`
`=(25)/(2)-(25)/(2)=0=RHS`
`:.m=(5)/(2)` is the root of the given quadratic equation.
3333.

From a solid cylinder, whose height is 8 cm and radius is 6 cm, a conical cavity of height 8 cm and of base radius 6 cm is hollowed out. Find the volume of the remaining solid.

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ANSWER :`603 (3)/(7) cm ^(2)`
3334.

X and Y play a game of tossing all the coins in their pockets. X has 2 fair coins and Y has 3 fair coins. It is the decided that whoever throws all heads, stands as the winner. Compare their chances of winning the game.

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ANSWER :`2:1`
3335.

Find the middle term of the sequence formed by all numbers between 9 and 95, which leave a remainder 1 when divided by 3. Also find the sum of the numbers on both sides of the middle term separately.

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ANSWER :52;1043
3336.

Given thatPQ = 7.5 angleQOP = 45^(@) , angle PQR = 75^(@) , angleQPS = 60^(@) , angle PQS = 60^(@)Constructthe trianglePQRandPQSin sucha waythat thepoints R and S lie on the samesideof PQ. Thenby drawingthecircumcircleof DeltaPQR writethe positionof the pointsS within , onandoutsidethecircumcircle. Alsoexplainyour answer.

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ANSWER :S and R CONCYCLIC
3337.

Find the median from the following data :

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ANSWER :`16.67`
3338.

Find the median from the following data :

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ANSWER :`37.44`
3339.

If the points (-1,3),(2,p) and (5,-1) are col-linear, the value of p is

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1
`-1`
0
`SQRT(2)`

ANSWER :A
3340.

Find the median from the following data :

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ANSWER :`26.43`
3341.

Find the median from the following data :

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ANSWER :`22.5`
3342.

Find the median from the following data :

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ANSWER :`22.56`
3343.

Find the median from the following data :

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ANSWER :`22.56`
3344.

Find the median from the following data :

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ANSWER :`26.25`
3345.

Find the median from the following data :

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ANSWER :23
3346.

To construct a triangle similar to a given triangle ABC with its sides (3^(th) )/(7) the corresponding sides of triangle ABC, first draw a ray BX such that CBX is an acute angle and X lies on the opposite side of A with respect to BC. Them, locate points B_1, B_2, B_3, ... on BX at equal distance and the next step is to join

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1)`B_(10` to C
2)`B_3` to C
3)`B_7` to C
4)`B_4` to C

Answer :C
3347.

Three identical coins are tossed together. What is the probability of obtaining : at least one head ?

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ANSWER :`7/8`
3348.

A flagstaff of height 1/5 of the height of a tower is mounted on the top of a tower. If the angle of elevation of the top of the flagstaff as seen from the ground is 45° and the angle of elevation of the top of a tower as seen from the same place is 8, then the value of tan theta is:

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`5/6`
`6/5`
`(5sqrt(3))/6`
`4/5`

ANSWER :A
3349.

Find the roots of the equation 5x^(2)-6x-2=0 by the method of completing the square.

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ANSWER :`x=(3PM SQRT(19))/(5)`
3350.

The total of the ages of father and son is 55 years. If the father was to live till his son's age equals his present age, the total of their ages would be 93 years. Find their present ages.

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Solution :We know that the SUM of AGES of two persons will not be the same everytime. But the difference of their ages remains the same forever. Using this concept we will SOLVE this problem. First of all we make a rough sketch.

When age of son will be 55 - X, then what will be the age of FATHER. Let at that time father will be of y years. So, difference of their ages will remain 55 - 2x years.
`thereforey - (55 - x) = 55 - 2x`
impliesy = (55 - 2x) + (55 - x) = 110 - 3x
Now, according to the problem,
(55 - x) + (110 - 3x) = 93
implies165 - 4x = 93
implies4x = 72
impliesx = 18
`{:(therefore"Present age of son = 18 years."),("and present age of father = 55 - 18 = 37 years."):}}`