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6801.

Show that f(x) = [x] (x in R) is continuous at only those real numbers that are not integers.

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ANSWER :a
6802.

Simplify (x + sqrt(1+x^(2)))^(3) -(x-sqrt(1+x^(2)))^(3)

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ANSWER :`SQRT(1+x^(2))[2+ 8X^(2)]`
6803.

Consider the function f:(-oo,oo)to|(-oo,oo) defined by f(x)=(x^(2)-a)/(x^(2)+a),agt0 . Whichof the followingis not true ?

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MAXIMUM value of f is not attained EVEN thoughf is bounded.
f(x) is increasing on `(0,oo)` and has minimum at x=0
f(x) is DECREASING on `(-oo,0)` and has minimum at x=0.
f(x) is increasing on `(-oo,oo)` and has NEITHER a local maximum nor a local minimum at x=0

Answer :D
6804.

(6x + 7)/(sqrt((x -4)(x - 5)))

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Answer :`6sqrt(X^2 - 9X + 20) + 34 [LOG(x - 9/2) + SQRT(x^2 - 9x + 20)] + c`.
6805.

A circle centred at the vertex of parabolax^(2)= 4y intersects it at theends of its latus-rectum . Equation of this cirlce is

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`x^(2) + y^(2) = 5`
`x^(2) + y^(2) = 4`
`x^(2) + y^(2) = 1`
`x^(2) + y^(2) = 2`

SOLUTION :N/A
6806.

Using the value of cos 315 ^(@) , find the value of sin 157 ""(1)/(2) ^(@and cos 157 (1)/(2) ""^(@).

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ANSWER :`=1/2 SQRT (2 + SQRT2)`
6807.

Number of points with integral coordinates which lie inside the triangle formed by (0,21), (21,0) and (0,0) is

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`sum19`
`sum20`
`sum21`
`sum22`

ANSWER :A
6808.

Evaluate the following limits in Exercises lim_(xto3)x+3

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ANSWER :6
6809.

2 tan h^(-1) ((1)/(2)) =

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0
`log_(E) 2`
`log_(e)3`
`log_(e)4`

Answer :C
6810.

If tan((alpha)/(2)) and tan (( beta)/(2)) are the roots of the equation 8x^(2)-26x+15=0 then cos (alpha+ beta)=

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`(627)/(725)`
`(-625)/(725)`
`-1`
1

Answer :B
6811.

Let f(x) be a polynomical function in x satisfyingthe conditionf(x) f(1//x)=f(x) +f(x) and f(3) = 28x ne 0 Find the coordinatesof (f(-2), f(0))

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(-2, 1, 9)
(-7, 1, 9)
(-5, 1, 9)
(0, 0, 0)

Answer :B
6812.

Given:(i)1-cot^2 theta =cosec^2 theta(ii)Is cos2 A +cos2 B=0then sin^2 A +sin^2 B =2(iii)tan2theta=(2tantheta)/(1-tan^2theta)(iv)sinx is periodic function with period pi/2Find which pair is true:

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(i) and (II) are TRUE
(i) and (IV)are true
(ii) and (III) are true
(iii) and (iv) are true

Answer :C
6813.

If a,b,c are real numbers such that (3a+2b)/(c+d) +( 3)/( 2) = 0then the equation ax^(3) + bx^(2) + cx + d = 0has

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at least ONE ROOT in [-2,0]
at least one root in [0,2]
at least TWO roots in [-2,2]
No root in [-2,2]

Answer :B
6814.

If a sin^(3)x+b cos^(3)x= sin x cos x and a sin x= b cos x then a^(2)+b^(2)=

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`1//2`
2
1
`1//3`

ANSWER :C
6815.

Which value of theta listed below leads to 2^(sin theta)gt1 and 3 cos (theta) lt 1?

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`70^(@)`
`140^(@)`
`210^(@)`
`280^(@)`

Answer :B
6816.

A committee of 7 members has to be formed from 9 boys and 4 girls . In how many ways can this be done when the committee consists of exactly 3 girls.

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ANSWER :`504`
6817.

Consider the expansion of ((4x)/5-5/(2x))^9 Find the 7th term in the expansion

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SOLUTION :`10500/x^3]`
6818.

cos h^(-1)(2) =

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`log_(E)(2+sqrt(3))`
`log_(e)(2+sqrt(5))`
`log_(e)(2-sqrt(5))`
`log_(e)(2+sqrt(2))`

ANSWER :A
6819.

0leale3,0leble3 and the equation x^(2)+4+3cos(ax+b)=2x has atleast one solution then the value of a+b

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`PI//2`
`pi//4`
`pi//3`
`pi`

ANSWER :D
6820.

cos ^(2) ((A)/(2))+ cos ^(2) ((B)/(2))+cos ^(2)(( C )/(2))=

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` 1- ( r )/( R ) `
` 1- ( R )/( r ) `
` 2+ (r ) /( 2 R) `
` 1 - ( r ) /(2R ) `

ANSWER :C
6821.

Identify the quantifier and write the negation of the statement ''There exists a number which is equal to its square.''

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Answer : ''There EXISTS''. The NEGATION is
There does not EXIST a number which is equal to its square.
6822.

4sqrt(x)-2

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ANSWER :`(2)/(SQRT(X))`
6823.

Find the component statements of thecompound statement "All integers are positive or negative" ?

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ANSWER :All INTEGERS are POSITIVE; all integers are NEGATIVE (FALSE).
6824.

Simiplify :(1+ i)^(-1)

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ANSWER :`(1-i)/(2)`
6825.

Consiser the system of equations x cos^(3)y+3xcosysin^(2)y=14to(1) and xsin^(3)y+3xcos^(2)y=13to(2) The value of x is/are

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`+-5sqrt(5)`
`+-SQRT(5)`
`+-1/(sqrt(5))`
`+-1/(5sqrt(5))`

ANSWER :A
6826.

If f(x)=2x^(2)+3x-5,x=3,deltax=0.1 then deltaf=A (2) If f(x)=x^(2)+4x,x=2,deltax=0.1 then deltaf=B (3) If f(x)=x^(2)+3x,x=3,deltax=0.1 then deltaf=C The ascending order of A, B C is

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A, B, C
B, C, A
C, A, B
A, C, B

Answer :B
6827.

Find the points at which the functions f(x) = x^(3) - 6x^(2) + 9x + 15

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ANSWER :15
6828.

If the area enclosed by the curves f(x)=cos^(-1)(cosx) and g(x)=sin^(-1)(cosx)" in "x in [(9pi)/4, (15pi)/4] is api^(2)//b (where a and b are coprime), then the value of (a-b) is

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ANSWER :1
6829.

For an G.P. a = 16 and fifth term is 81 then common ratio ........

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ANSWER :`3/2`
6830.

Find the middle term (terms ) in the expansion of (3x - (x^(3))/6)^(9)

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ANSWER :`= (189)/8 xx x^(7)`
6831.

If the mean and variance of the observations x_(1), x_(2), x_(3),…,x_(n) are barx and sigma^(2) respectively and a be a nonzero real number, then show that the mean and variance of ax_(1),ax_(2),ax_(3),…,ax_(n)" are "abarx and a^(2) sigma^(2) respectively.

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Solution :Let `barx` be the mean of `x_(1),x_(2),x_(3),x_(n)` and a be nonzero real number.
Then, `barx=(1)/(n)(x_(1)+x_(2)+x_(3)+ +x_(n)).`
Let `y_(i)=ax_(i)" for each i=1, 2, 3,n. Then",`
`bary=(1)/(n)(y_(1)+y_(2)+y_(3)+...+y_(n))`
`=(1)/(n)(ax_(1)+ax_(2)+ax_(3)+ +ax_(n))=acdot(1)/(n)(x_(1)+x_(2)+x_(3)+...+x_(n))=abarx.`
Thus, `bary=a barx.`
Now, the variance of new observations is given by
`"variance "(y)=sigma_(1)^(2)`
`=(1)/(n)cdotoverset(n)underset(i=1)Sigma(y_(i)-bary)^(2)`
`=(1)/(n)CDOT overset(n)underset(i=1)Sigma(ax_(i)-abarx)^(2)" "[because y_(i)=ax_(i)" for each i and "bary=abarx]`
`=a^(2)cdot(1)/(n)cdotoverset(n)underset(i=1)Sigma(x_(i)-barx)^(2)`
`=a^(2)cdot{"variance"(x)}=a^(2)sigma^(2).`
`THEREFORE" new variance"=a^(2)sigma^(2).`
`"REMARK "sigma_(1)=SQRT(a^(2)sigma^(2))=|a|cdot sigma.`
6832.

Using the following data. Find out the trend using Quarterly moving average and plot them on graph

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ANSWER :TREND VALUES are `43,38,51,63,53,75,56,38,52,12,47,88,50,25`
6833.

This section contains 2 questions. Each question contains STATEMENT-I (Assertion) and STATEMENT-2 (Reason). Each question has 4 choices (A), (B), (C) and (D) out of which ONLY ONE is correct. Statement - 1 : The maximum and minimum values f(x) = (1)/( 3 sin x + 4 cos x-2) does not exist Statement - 2 : The given faction is an unbounded function.

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STATEMENT -1 is True, Statement-2 is True, Statement -2 is a correct EXPLANATION for Statement-3
Statement-1 is True, Statement-2 is True, Statement-2 NOT a correct explanation for Statement-1.
Statement-1 is True, Statement-2 is FALSE.
Statement-1 is False, Statement-2 is True.

Answer :A
6834.

For 0 lt theta lt 2 pi sin^(-1)(sin theta)gtcos^(-1)(sin theta) is true when

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`((PI)/4,pi)`
`(pi,(3pi)/2)`
`((pi)/4,(3pi)/4)`
`((3pi)/4,2pi)`

Answer :C
6835.

Find the equation of line which makes a triangle witharea (50)/( sqrt(3) ) unit with axis and perpendicular from origin makes an angle (pi)/(6) with positive side of X-axis.

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ANSWER :`SQRT(3) X + y=10`
6836.

An A.P. consists of 21 terms. The sum of the three terms in the middle is 129 and of the last three is 237. Find the series.

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ANSWER :3,7,11,15 ………..
6837.

Evaluate the following limits in Exercises lim_(xto0)(cosx)/(pi-x)

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ANSWER :`(1)/(PI)`
6838.

If f(x)=log_(e)(1-x)andg(x)=[x] then find: (i) (f+g)(x) (ii) (fg)(x) (iii) ((f)/(g))(x) (iv) ((g)/(f))(x). Also find (f+g)(-1),(fg)(0),((f)/(g))(-1),((g)/(f))((1)/(2)).

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Solution :Clearly, `log_(e)(1-x)` is defined only when `1-xgt0,i.e.,xlt1`.
`:."dom "(F)=(-oo,1)`.
ALSO, dom (g)=R.
`:."dom "(f)nn"dom "(g)=(-oo,1)nnR=(-oo,1)`
(i) `(f+g)"(-oo,1)toR` is GIVEN by
`(f+g)(x)=f(x)+g(x)=log_(e)(1-x)+[x]`.
(ii) `(fg):(-oo,1)toR` is given by
`(fg)(x)=f(x)xxg(x)={log_(e)(1-x)}xx[x]`.
(iii) `{x:g(x)=0}={x:[x]=0}={0,1)`.
`:."dom "((f)/(g))="dom "(f)nn"dom "(g)-{x:g(x)=0}`
`=(-oo,1)nnR-[0,1)=(-oo,0)`.
`:.(f)/(g):(-oo,0)toR` is given by
`((f)/(g))(x)=(f(x))/(g(x))=(log_(e)(1-x))/([x])`.
(iv) `{x:f(x)=0}={x:log_(e)(1-x)=0}={0}`.
`:."dom "((g)/(f))="dom "(g)nn"dom "(f)-{x:f(x)=0}`.
`=Rnn(-oo,1)-{0}=(-oo,0}uu(0,1)`.
`:.(g)/(f):(-oo,0)uu(0,1)toR`
`((g)/(f))(x)=(g(x))/(f(x))=([x])/(log_(e)(1-x))`.
Now, we have:
`(f+g)(-1)=f(-1)+g(-1)=[-1]+log_(e)(1+1)=(log_(e)2)-1`.
`(fg)(0)=f(0)xxg(0)=log_(e)(1-0)xx[0]=(log_(e)1xx0)=(0xx0)=0`.
`((f)/(g))(-1)=(f(-1))/(g(-1))=([-1])/(log_(e)(1+1))=(-1)/(log_(e)2)`.
`((g)/(f))((1)/(2))=g((1)/(2))/(f((1)/(2)))=([(1)/(2)])/(log_(e)(1-(1)/(2)))=([05.])/(log_(e)((1)/(2)))=0`.
6839.

The sum of first two terms of a G.P. is (9)/(2). Its 6^(th) term is 8 times its 3^(rd) term. Find the sequences.

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ANSWER :`(3)/(2), 3, 6, 12`
6840.

If A and G are the arithmetic and geometric means respectively of two numbers then prove that the numbers are (A+sqrt(A^(2)-G^(2)))and(A-sqrt(A^(2)-G^(2)))

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SOLUTION :N/a
6841.

Expand (1-x^2)^4

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ANSWER :`1 - 4x^2 + 6x^4 - 4x^6 + x^8`
6842.

B,C are two points on 3x+4y-15=0 such that OB+OC=10 then maximum possible area of triangle OBC is

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12
10
15
13

Answer :A
6843.

If p^(th), q^(th), r^(th) terms of a geometric progression are the positive numbers a,b,c respectively, then the angle between the vectors (log a^(2)) I + (log b^(2)) j + (log c^(2))k and (q - r) I + (r - p) j + (p - q) k is

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`PI/4`
`pi/2`
`pi/6`
`pi`

ANSWER :B
6844.

Let f(x) = (sqrt(x - 2 sqrt(x - 1)))/(sqrt(x - 1) - 1)x, then

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`f'(10) = 1`
`f'(3//2) =-1`
DOMAIN of `f(x) ` is `x GE 1`
RANGE of `f(x) ` is `(-2, -1] uu (2, oo)`

Answer :A::B::D
6845.

If the parabola y^(2) = 4ax passes through the point (3,2), then the length of its latus rectum is ……

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`(2)/(3)`
`(4)/(3)`
`(1)/(3)`
4

Answer :B
6846.

(sin 3 thea - sin theta sin ^(2) (2 theta ))/( sin theta + sin 2 theta cos theta ) = cos x implies x =

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`4 theta `
`2 theta `
`theta `
`3 theta `

Answer :B
6847.

Let cup be the set of all boys and girls in a school, G be the set of all girls in the school, B be the set of all boys in the school and S be the set of all students in the school who take swimming. Some but not all, students in the school take swimming. Draw a Venn diagram showing one of the possible inter relationship among sets cup, G, B and S.

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ANSWER :`(##KPK_AIO_MAT_XI_C01_E12_026_A01##)`
6848.

Find the equation of each of the following parabolas : (i) Directrix x = 0, focus at (6, 0) (ii) Vertex at (0,4), focus at (0,2) (iii) Focus at (-1, -2), directrix x - 2y + 3 = 0.

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Answer :`4X^(2) + y^(2) + 4XY + 4x + 32y + 16 = 0.`
6849.

Mean and standard deviation of 100 items are 50 and 4, respectively . Find the sum of all the item and the sum of the squares of the items.

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250000
251600
49910
499100

Answer :B
6850.

Find the values of thetabetween 0^(@) and 360^(@) which satisfy the equation 3 cos 2 theta - sin theta = 2.

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ANSWER :`330^(@)`