Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

IfF(x)=underset0overset(x)inte^(2t)cos5tdt, what is F'(x)?

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Solution :F(X)=underset0overset(x)inte^(2T)COS(5t)dtifff(x)=E^(2x)cos(5X).`
2.

Let the position vectors of vertices of a DeltaABC be OA=3i+j+2k, OB=i+2j+3k" and "OC=2i+3j+k. If length of altitude of DeltaABC from A is p, then 2p^(2)= ________

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ANSWER :9
3.

Find the remainder when 32^(32^(32)) is divided by 7.

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SOLUTION :N/A
4.

Let vec(a),vec(b) and vec( c ) be three vectors such that |vec(a)|=3,|vec(b)|=4,|vec( c )|=5 and each one the them being perpendicular to the sum of the other two, find |vec(a)+vec(b)+vec( c )|.

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ANSWER :`5sqrt(2)`
5.

Let p: Kiran passed the examination, q: Kiran is sad The symbolic from of a statement "It is not true that Kiran passed therefore he is said" is

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<P>`(~prarr`Q)
(p`RARR`q)
~(p`rarr`~q)
~(p`harr`q)

Answer :B
6.

Values of c of Rolle's theorem for f(x)=sin x-sin 2x on [0,pi]

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Solution :We have,`F(x) = SINX - sin2x "in" [0,pi]`
(i) SINCE , we know thatsinefunctionsare continuous functionshence `f(x)=sinx - sin2x` isa continuous function in `[0,pi]`
(ii) `f(x) = cosx -COS2X. 2 = cos x - 2 cos 2X ` , which existin `(0,pi)`
So, `f(x)`is differentiable in `(0,pi)`.Conditionsof mean value theoremare satisfied.
Hence`3c in (0,pi)` such that,`f'(c) = (f(pi)-f (0))/(pi-0)`
`rArr cos - 2 cos 2x = (sin pi - sin 2pi - sin 0 + sin 2.0)/(pi-0)`
`rArr 2cos2c -cos c = (0)/( pi)`
`rArr 2.(2cos^(2)c-1)-cosc= (0)`
`rArr 4 cos^(2)-2-cosc=0`
`rArr 4 cos^(2)c-cosc-2 = 0`
`rArr cosc = (1+-sqrt(1+32))/(8) = (1+-sqrt(33))/(8)`
`:. c= cos^(-1)((1+-sqrt(33))/(8))`
Also, `cos^(-1) ((1+-sqrt(33))/(8))in (0,pi)`
Hence, meanvalue therem has been verified.
7.

Using integration find the area of the triangular region whose sides have the equations Y =2x + 1, y = 3x+1 andx=4.

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ANSWER :`= 8` SQ. UNIT.
8.

If A is square matrix such that A^(2)=A, then (I+A)^(3)-7A is equal to

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A
`I-A`
`I `
3A

ANSWER :C
9.

The quardritic equation in x such that the arithmetic meanof its roots is 5 and geometric mean of the roots is 4, is given by

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`X^(2) + 20X + 16 = 0`
`x^(2) - 10x + 16 = 0`
`x^(2) + 10x + 16 = 0`
`x^(2) - 10x - 16 = 0`

Answer :B
10.

Observe the following list {:("List-I","List-II"),(A. [vec(a)vec(b)vec(c )],1. |vec(a)||vec(b)| cos (vec(a).vec(b))),(B.(vec(c ) xx vec(a)) xx vec(b), 2. (vec(a). vec(c )) vec(b) - (vec(a). vec(b)) vec(c)),(C. vec(a) xx (vec(b) xx vec(c )),3.vec(a).vec(b) xx vec(c )),(D. vec(a). vec(b), 4.|vec(a)| |vec(b)|),(,5.(vec(b) - vec(c )) vec(a) - (vec(a) . vec(b)) vec(c)):} Then the correct match for List-I from list II is

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1,2,3,4
3,5,2,1
3,2,5,1
2,3,4,1

Answer :B
11.

Find a point on the curve y = (x – 2)^(2) at which the tangent is parallel to the chord joining the points (2, 0) and (4, 4).

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ANSWER :(3,1)
12.

Let A, B, C be three sets. If AinBandBsubC then

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`AsubC`
`AcancelsubC`
`AINC`
`AcancelinC`

ANSWER :B
13.

Examin the following functions for continuity. f(x)= (1)/(x-5), x ne 5

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ANSWER :CONTINUOUS FUNCTIONS.
14.

The term independent of x in (2x^(1//2)-3x^(-1//3))^20

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`""^20C_(7) 2^(8) 3^12`
`""^20C_(8) 2^(7) 3^13`
`""^(20)C_(8) C^(8) 3^12`
`""^20C_(7)2^(7) 3^13`

ANSWER :C
15.

Two trains start from the same place. A person travel in a train whose speed is 50 km/h and it go to south direction. Another person travel in another train whose speed is 60 km/h and it go to west direction. After two hours, find the rate of distance between them.

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ANSWER :`16sqrt(61)` km/h
16.

If the two circles (x-1)^(2)+(y-3)^(2)=r^(2) and x^(2)+y^(2)-8x+2y+8=0 intersect in two distinct points, then

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`rgt2`
`2ltr LT 8`
`rlt2`
`r=2`

ANSWER :B
17.

If ((1-i)/(1+i))^(96)=a+ib, then (a,b) is

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(1,1)
(1,0)
(0,1)
(0,-1)

ANSWER :B
18.

The point of contact of the circle x^(2)+y^(2)+2x+2y+1=0 and x^(2)+y^(2)-2x+2y+1=0

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(0,1)
(0,-1)
(1,0)
(-1,0)

ANSWER :B
19.

If sqrt(1-x^(2)) + sqrt(1 -y^(2))= a(x-y), then prove that (dy)/(dx)= sqrt((1-y^(2))/(1-x^(2))). (Where |x| le 1, |y| le 1)

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ANSWER :`(SQRT(1-y^(2)))/(sqrt(1-x^(2)))`
20.

The value of a for which the points (9, 5), (1, 2), (a, 8) are collinear is equal to

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17
8
7
71

Answer :A
21.

int((x^(2)-1)dx)/((x^(4)+3x^(2)+1)Tan^(-1)((x^(2)+1)/(x)))=

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ANSWER :`L ntan^(-1)(X+(1)/(x))+C`
22.

Which of the following undergoes partial hydrolysis?

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`B_(2)H_(6)`
`BCl_(3)`
`SiF_(4)`
`BF_(3)`

Solution :Due to Back bonding.
23.

Internal angle bisecotors of DeltaABC meets its circum circle at D, E and F where symbols have usual meaning. Q. The ratio of area of triangle ABC and triangle DEF is :

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`GE1`
`LE1`
`GE 1//2`
`le1//2`

ANSWER :B
24.

Match the following lists:

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Solution :a. `I=int_(-2)^(2)(alphax^(3)+betax+gamma)dx`
`alphax^(3)+betax` is an odd function
`I=0+2int_(0)^(2)gamma dx=2xx2gamma=4gamma`
b. `I=1/2 int_(0)^(1)2sin alpha x sin beta x dx`
`=1/2int_(0)^(1)(cos(alpha-beta)x-cos(alpha+beta)x)dx`
`=1/2[(sin(alpha-beta)x)/(alpha-beta)-(sin (alpha+beta)x)/(alpha+beta)]_(0)^(1)`
`=1/2[(sin (alpha-beta))/(alpha-beta)-(sin (alpha+beta))/(alpha+beta)]`...........1
Also `2 alpha=tan alpha` and `2beta=tan beta`
`:. 2 (alpha-beta)=tan alpha-tan beta ` and `2(alpha+beta)=tan alpha+tan beta`
`2(alpha-beta)=(sin(alpha-beta))/(cos alpha cos beta)` and `2(alpha+beta)=(sin (alpha +beta))/(cos alpha cos beta)`
substituting these values, we get
C.`f(x+alpha)+f(x)=0`
or `(x+2alpha)+f(x)+alpha)=0`
or `f(x+2alpha)=f(x)`
Thus, `f(x)` is periodic with periodic `2 alpha`. Hence
`int_(beta)^(beta+2gamma alpha) f(x)dx=gamma int_(0)^(2alpha) f(x)dx`
d. Let `I=int_(0)^(alpha)[SINX]dx, alpha epsilon[(2beta+1)pi,(2beta+2)pi],beta epsilon N`,
( wher [.] denotes the greatest INTEGER function)
`=int_(0)^(2betapi) [sinx]dx+int_(2betapi)^((2beta+1)pi) [sinx]dx+int_((2beta+1)pi)^(alpha) [sinx] dx`
`=betaint_(0)^(2PI) [sinx]dx+0+int_((2beta+1)pi)^(alpha) (-1)dx`
`=-betapi+(2beta+1)pi-alpha`
`=(beta+1)pi-alpha`
Thus, `gamma int_(0)^(alpha) [sinx]dx` depends on `alpha beta` and `gamma`.
25.

Match the following lists:

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Solution :`lim_(nto oo) [(int_(0)^(2)(1+t/(n+1))^(n)dt)/(n+1)]=lim_(n to oo) [(1+t/(n+1))^(n-1)]_(0)^(2)`
`=lim_(nto oo) (1+2/(n+1))^(n+1)-1`
`=E^(2)-1`
`f'(x)=f(x)impliesf(x)=Ce^(x)` and since `f(0)=1, 1=f(0)=C`
Therefore `f(x)=e^(x)` and HENCE `g(x)=x^(2)-e^(x)`.
THUS, `int_(0)^(1)f(x)g(x)DX=int_(0)^(1)(x^(2)e^(x)-e^(2x))dx`
`=x^(2)e^(x)|_(0)^(1)-2int_(0)^(1)xe^(x) dx=int_(0)^(1)(x^(2)e^(x)-e^(2x))dx`
`=x^(2)e^(x)|._(0)^(1)-2int_(0)^(1)xe^(x)dx-(e^(2x))/2|_(0)^(1)`
`=(e-0)-2xe^(x)|._(0)^(1)+2e^(x)|_(0)^(1)+2e^(x)|_(0)^(1)-1/2(e^(2)-1)`
`=(e-0)-2e+2e-2-1/2(e^(2)-1)`
`=e-1/2e^(2)-3/2`
`I=int_(0)^(1)e^(e^(x))(1+xe^(x))dx`
Let `e^(x)=t`
`:. int_(1)^(e)(1+tlogt)(dt)/t int_(1)^(e)e^(t)(1/t +logt)dt`
`=[e^(t)logt]_(1)^(e)=e^(e)`
d. `L=lim_(kto0)(int_(0)^(k)(1+sin2x)^(1/x)dx)/k` (form `0/0`)
`=lim_(kto0) (1+sin2k)^(1/k)`
`=e^(lim_(kto0)1/k(sin2k))=e^(2)`
26.

Find the projection of the vector hati+3hatj+hatk on thevector 7hati-hatj+8hatk

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ANSWER :`= ( 6)/( SQRT(114))`
27.

Match the following lists:

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SOLUTION :a. `I_(1)=int_(pi//6)^(pi//3) sec^(2) thetaf(2sin THETA) d theta`
Applying property `int_(a)^(b)f(a+b-x)dx=int_(a)^(b)f(x)dx`
`I_(1)=int_(pi//6)^(pi//3)sec^(2)((pi)/2-theta)f(2sin2((pi)/2-theta))d theta`
`=int_(pi//6)^(pi//3)cosec^(3) theta f(2sin 2 theta) d theta=I_(2)`
b. `f(x+1)=f(x+3)` or `f(x)=f(x+2)`
Thus, `f(x)` is periodic with period 2.
Then `int_(a)^(a+b)f(x)dx` is independent of `a` for which `b` is multiple of 2.
Thus, `b=2,4,6`...........
c. Let `I=int_(1)^(4)(tan^(-1)[x^(2)])/(tan^(-1)[x^(2)]+tan^(-1)[25+x^(2)-10x])`.............1
Appling `int_(a)^(b)f(x)dx=int_(a)^(b)f(a+b-x)dx`, we get
`I=int_(1)^(4)(tan[(5-x)^(2)])/(tan^(-1)[(5-x)^(2)]+tan^(-1)[x^(2)])dx`.............2
Adding equatiions 1 and 2 we get
`2I=int_(1)^(4)dx` or `2I=3` or `I=3//2`
d.Let` y=SQRT(x+sqrt(x+sqrt(x+)))..............=sqrt(x+y)`
or `y^(2)-y-x=0`
or `y=(1+-sqrt(1+4x))/(2.1)=(1+sqrt(1+4x))/2( :' YGT1)`
`:.I=int_(0)^(2)(1+sqrt(1+4x))/2 dx`
`=[x/2+((1+4x)^(3//2))/(3/2xx2xx4)]_(0)^(2)`
`=[(1+27/12)=(0+1/12)]`
`=1+26/12=19/6`
`:. [I]=3`
`[I]=3`
28.

The value of the expression (1+cot7^(@))(1+cot9^(@))(1+cot11^(@))......(1+cot45^(@))(1-cot52^(@))(1-cot54^(@))......(1-cot88^(@)) is equal to

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`2^(18)`
`2^(19)`
`2^(20)`
`2^(21)`

SOLUTION :Using`(1+costheta)(1-cot(45^(@)+THETA))=2`
` (1+cot45^(@))(2^(19))=(2^(19))=20^(20)`
29.

If 3 fair dice are rolled, find the probability of getting sum 12.

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ANSWER :`(25)/(216)`
30.

The locus of the centre of a circle which touches externally the circle x^(2)+y^(2)-6x-6y+14=0 and also touches the y-axis is given by the equation.

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`y^(2)-6x-10y-14=0`
`y^(2)-6x+10y+14=0`
`y^(2)+6x+10y+14=0`
`y^(2)-6y-10x+14=0`

ANSWER :D
31.

A channel 27m wide falls at a right angle into another channel 64m wide. The greatest length of the log that can be floated along this system of channels is

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120
125
100
110

Answer :B
32.

If |vec(a)+vec(b)|=60,|vec(a)-vec(b)|=40 and |vec(b)|=46 find |vec(a)|.

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ANSWER :22
33.

Thenormalat thepoint(2,-2)on thecurve3x^2-y^2 =8 is _____

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`x+y =0`
` x+2y =-2`
`x-3y=8`
` 3X +y=4`

ANSWER :D
34.

If (barb xx barc) xx (barb xx bara) = 3barc, then find [barb xx barc barc xx bara bara xx barb].

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ANSWER :`= 9`
35.

Which of the following is/are periodic?

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f(x) = x - [x], where [x] DENOTES the greatest integral function
f(x) = x (where x is a CONSTANT)
`f(x) = 2tan.(1)/(2)(x-pi)`

ANSWER :A::B::D
36.

Integrate the functions 1/(x-x^(3))

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ANSWER :`1/2logabs((X^(2))/(1-x^(2)))+C`
37.

Evaluate the definite integrals int_(0)^(1)(2x+3)/(5x^(2)+1)dx

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ANSWER :`3LOG2+(3PI)/8`
38.

The solution of tany(dy)/(dx)=sin(x+y)+sin(x-y) is

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`secy=2cosx+c`
`secy=-2cosx+c`
`tany=-2cosx+c`
`SEC^(2)y=-2cosx+c`

ANSWER :B
39.

Solve 4xdy - y dx = x^(2) dy.

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ANSWER :`c.y^(4)(x-4)`
40.

In triangleABC,a(cosB+sinBcot((A)/(2)))=

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`a+b+c`
`c+a`
`a+b`
`b+c`

ANSWER :D
41.

Find the numerically greatest terms in the expansion of(3y + 7x)^10 whenx = 1/3, y = 1/2

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ANSWER :`T_7 = 5/24.7^7`
42.

Two cards are drawn simultaneously (or successively without replacement) from a well shuffled pack of 52 cards. Find the mean, variance and standard deviation of the number of kings.

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ANSWER :`(34)/(221), (6800)/((221)^(2))` and 0.37
43.

Find the approximate value of f(2.01), where f (x) = 4x^(2) + 5x + 2.

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ANSWER :28.21
44.

int_(-1)^(1)log ((2019 -x)/(2019+x)) dx =………

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0
LOG 2019
1
2. log( 2019 )

ANSWER :A
45.

Findthe principalvalueofsin ^(-1)(-1/2)( in radiusand degrees .)

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ANSWER :`- 30 ^@`
46.

Solve the following linear programming problem graphically: Maximise Z=4x+y ………….1 subject to the constraints: x+yle50 ……………2 3x+yle90…………..3 xge0, yge0…………..4

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ANSWER :(30,0)
47.

Find the equation of plane passing through the point (-1,1,2) and parallel to the plane x + 2y + 3z - 5 = 0.

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ANSWER :`x + 2Y + 3Z - 7 = 0`
48.

A : If x=sin(alpha - beta ) sin (gamma - delta), y=sin(beta - gamma ) sin (alpha - delta) , z=sin(gamma - alpha ) sin ( beta - delta) " then " x+y+z=0 R :2 sin A sin B = cos(A-B)+cos(A+B)

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A is TRUE , R is true and R is CORRECT explanation of A
A is true , R is trueand R is not correct explanation of A
A is true , R is FALSE
A is false , R is true

ANSWER :C
49.

Evaluate: lim_(x to 0)(cotx)^(sin2x)

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ANSWER :1
50.

Prove that : Find the numerically greatest term in the binomial expansion of (1-5x)^(12) when x=(2)/(3).

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SOLUTION :N/A