Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

y' + 5y = 0

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ANSWER :ORDER 1; DEGREE 1
2.

Number of compounds having S-S linkage H_(2)S_(2)O_(3),H_(2)S_(2)O_(78),H_(2)S_(2)O_(5),H_(2)S_(4)O_(8),H_(2)S_(2)O_(4)

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ANSWER :`4.00`
3.

If the roots of x^(3)-kx^(2)+14x-8=0 are in geometric progression, then k=

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-3
7
4
0

Answer :B
4.

A coins is tossed three times,where E:atmost two tails, F: atleast one tail.Find P(E/F) in each case above.

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Solution :Here,S = {HHH,HHT,HTH,HTT,THH,THT,TTH,TTT}
E={HHH,HHT,HTH,THH,TTH,THT,HTT}
F= {HHT,HTH,THH,HTT,THT,TTH,TTT}`rArr` `EnnF = {HHT,HTH,THH,TTH,THT,HTT} therefore `P(EnnF)`=6/8and P(E) 7/8 THUS,P(E/F)=`(P(EnnF))/(P(F))`=6/8/7/8=6/7
5.

Integrate the following functions : int(x^(3))/(1+x^(8))dx

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ANSWER :`(1)/(4)TAN^(-1)(x^(4))+C`
6.

Let p,q and r be real number (p ne q, r ne 0) such that the roots ofthe equation (1)/( x + p) + (1)/( x + q) = (1)/(r)are equal in magnitude but opposite in sign, then the sum of squares of these roots is equal to :

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`(1)/(2) (p^(2) + q^(2))`
`p^(2) + q^(2)`
`2 (p^(2) + q^(2))`
`p^(2) + q^(2) + r^(2)`

ANSWER :D
7.

Let z_(1) , z_(2) be two roots of the equation z^(2) + az + b = 0 , z being complex . Further assume that the origin z_(1) and z_(2) form an equilateral triangle , then

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`a^(2) = B`
`a^(2) = 2b`
`a^(2) = 3B`
`a^(2) = 4b`

Answer :C
8.

A business man gets a profit of Rs. 2800 with probability 0.5, loss of Rs. 5000 with probability 0.3. and neither profit nor loss with probability 0.2. Find mean of his income.

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ANSWER :`-100`
9.

Find (dy)/(dx) in the following y= sec^(-1) ((1)/(2x^(2)-1)), 0 lt x lt (1)/(sqrt2)

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ANSWER :`(-2)/(1+ X^(2))`
10.

What is the value of arg omega+ arg omega^2?

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SOLUTION :`argomega=ARG omega^2=arg(omega.omega^2)`
`=arg(omega^3)=arg(1)=2NPI`
`:. "The PRINCIPAL ARGUMENT" =0.`
11.

Find both the maximum value and the minimum value of f(x)=3x^(4)-8x^(3)+12x^(2)-48x+25 on the interval [0, 3].

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ANSWER :`25, -39`
12.

{:(" "Lt),(x rarr 3):} (1)/(x-3) int_(3)^(x)e^(t)dt=

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`E^(3)`
`1/e`
`e^(2)`
e

Answer :A
13.

If P is ((1)/(2)+i(sqrt(3))/(2)) and OP is rotated through an angle (pi)/(2) in the clockwise direction then the new position of P is :

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`(1)/(2)i-i(SQRT(3))/(2)`
`(-sqrt(3))/(2)-(1)/(2)`
`-(1)/(2)i-i(sqrt(3))/(2)`
`(sqrt(3))/(2)-(i)/(2)`

ANSWER :D
14.

If A and B are events such that P(AuuB)=(5)/(6), P(barA)=(1)/(4), P(B)=(1)/(3), then A and B are

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MUTUALLY exclusive
independent
EXHAUSTIVE events
exhaustive and independent

Answer :B
15.

A balloon is filled in such a way that its volume increases at the rate of 40 cm^(3)/min. when radius is 8 cm, the rate of increases in the surface area is ……………. cm^(2)/min.

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8
10
20
None of these

ANSWER :B
16.

Let S = sum _(r=1)^(30) (""^(30+r)C_(r) (2r-1))/(""^(30)C_(r)(30+r)),K=sum_(r=0)^(30) (""^(30)C_(r))^(2) and G=sum_(r=0)^(60) (-1)^(r)(""^(60)C_(r) )^(2) The value (SK_SG) is

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0
1
`2^(30)`
`2^(60)`

Solution :`because S = sum _(r=1)^(30) (""^(30+r)C_(r) (2r-1))/(""^(30)C_(r)(30+r))=sum_(r=0)^(30) (""^(30+r)C_(r))/(""^(30)C_(r))(1-(30-r+1)/(30+r))`
`=sum_(r=0)^(30)[ (""^(30+r)C_(r))/(""^(30)C_(r)) -(""^(30+r)C_(r))/(""^(30)C_(r))CDOT ((30-r+1))/((30+r))]`
`=sum_(r=0)^(30)[ (""^(30+r)C_(r))/(""^(30)C_(r)) -""^((30+r)/(r)cdot ^(29+r)C_(r-1))/(""^(30)C_(r))cdot ((30-r+1))/(30+r)]`
`=sum_(r=0)^(30)[ (""^(30+r)C_(r))/(""^(30)C_(r)) -( ""^(29+r)C_(r-1))/(""^(30)C_(r-1)) ][because (""^(n)C_(r))/(""^(n)C_(r-1))=(n-r+1)/r]`
For n = 30 `((31-r)/rcdot ""^(30)C_(r)=""^(30)C_(r-1))`
`=(""^(30+30)C_(30))/ (""^(30)C_(30)) - (""^(29-1)C_(0))/(""^(30)C_(0))= ""^(60)C_(30)-1`
`K = sum _(r=1) ^(30) (""^(30)C_(r))^(2) = ""^(60)C_(30) and G = sum_(r=0)^(60) (-1)^(r) (""^(60)C_(r))^(2)`
`(""^(60)C_(0))^(2) - (""^(60)C_(1))^(2)+(""^(60)C_(2))^(2)-...+(""^(60)C_(60))=""^(60)C_(30)`
[`because n=60` is EVEN ]
`SK - SG = S (K- G) = (G- G) = 0 [ because K= G]`
17.

Write the following functions in the simplest form : tan^(-1) sqrt((1-cos x)/(1+cos x)), 0 lt x lt pi

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SOLUTION :`tan^(-1)SQRT((1-cos X)/(1+cos x)) = tan^(-1) sqrt((2sin^2 x//2)/(2cos^2 x//2)) = tan^(-1)(tan frac X2) =x/2`
18.

Evalute the following integrals int x cos^(-1)xdx

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Answer :`(1)/(4) [ (2x^(2) - 1) COS^(-1) x - x SQRT(1 -x^(2)) ]+ C `
19.

Determine the intervals of concavity of the curve y=3 +sin x.

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ANSWER :`x=npi`
20.

The value of|(veca,vecb,vec c),(veca*vecp, vecb*vecp, vecc*vecp),(veca*vecq,vecb*vecq, vec c*vecq)| is equal to :

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`(vecp XX vecq)[veca xx vecb" "vecb xx vecc" "vecc xx veca]`
`2(vecp xx vecq)[veca xx vecb" "vecb xx VEC c" " vec c xx veca ]`
`4(vecp xx vecq)[veca xx vecb" "vecb xx vec c" " vec c xx veca]`
`(vecp xx vecq) SQRT([veca xxvecb" " vecb xx vec c" "vec c xx veca])`

Answer :D
21.

Integrate the following functions e^(2x+3)

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SOLUTION :`INT E^(2x+3) DX = e^(2x+3)/2+C`
`int e^x dx = e^x +c`
22.

Obtain the equation of straight lines : Passing through the points (2,3) and (-4,1) .

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SOLUTION :Equation of the LINE is
`y-y_1 = (y_2-y_1)/(x_2-x_1) (x-x_1)`
or, `y-3 = (1-3)/(-4-2) (x-2)`
or, `y-3 = (-2)/(-6) (x-2)`
or, y-3 = 1/3 (x-2)
or, 3y-9 = x-2
or, x-3y+7 = 0
23.

If z = x + iy is a complex number such that Z^((1)/(3)) = a + ib, then the value of (1)/(a^(2) + b^(2)) ((x )/(a) + (y)/(b)) is equal to

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`-1`
`-2`
0
2

Answer :B
24.

If two positive numbers are in the ratio 3 + 2sqrt(2) : 3 - 2sqrt(2), then the ratio between their A.M. and G.M. is

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`6 : 1`
`3 : 2`
`2 : 1`
`3: 1`

ANSWER :D
25.

Evaluate : int(sin x + cos x)/(9 + 16 sin 2x) dx.

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ANSWER :`(1)/(40) log |(5+4(sin X - COS x))/(5-4(sin x - cos x))| + c`
26.

By using the properties of definite integrals, evaluate the integrals int_(0)^(pi/2)(sin^(3/2)xdx)/(sin^(3/2)x+cos^(3/2)x)

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ANSWER :`pi/4`
27.

If phi (x) is a differentiable real valued function satisfying phi (x) +2phi le 1, then it can be adjucted as e^(2x)phi(x)+2e^(2x)phi(x)lee^(2x) or (d)/(dx)(e^(2)phi(x)-(e^(2x))/(2))le or (d)/(dx)e^(2x)(phi(x)-(1)/(2))le0 Here e^(2x) is called integrating factor which helps in creating single differential coefficeint as shown above. Answer the following question: If p(1)=0 and dP(x)/(dx)ltP(x) for all xge1 then

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<P>`P(x)GT 0 forall x gt 1`
P(x) is a constant function
`P(x) lt 0 forall x gt 1`
none of these

Solution :`(DP(x))/(dx)GTP(x)`
or `E^(-x)(dp(x))/(dx)-e^(-x)p(x)gt0`
or `(d)/(dx)p(x)e^(-x)gt0`
thus P(x) `e^(-x)` is and increasing function i.e
`p(x)e^(-x)gt9(1)e^(-1)forallxge1`
or `p(x)e^(-x)gt 0 forall xgt1 or p(x)gt0 forall x gt1`
28.

The vertices of a triangle are A(3, 7), B(3, 4) and C(5, 4). The equation of the bisector of the angle /_ABC is

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y=X+1
y = x - 1
y = 3X - 5
y = x

Answer :A
29.

If bara is a non-zero vector are two vectors such that bara xx barb= bara xx barc and bara.barb=bara.barc, then prove that barb=barc.

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ANSWER :`:.BARB= BARC`.
30.

Evaluate the definite integrals . underset(0)overset(a)int (a^(2)x-x^(3))dx

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ANSWER :`(a^(4))/(4)`
31.

If a = 2i + k, b = I + j + k, c = 4i - 3j + 7k. The vector r satisfying r xx b = c xx b and r.a = 0 is

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I +8J + 2K
I - 8j + 2k
`-1 - 8j + 2k`
I - 8j - 2k

Answer :C
32.

Resolve into Partial Fractions (iv) (x^(4))/((x-1)(x-2))

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ANSWER :`X^(2)+3x+7- (1)/((x-1))+(16)/((x-2))`
33.

Find the probability that in a family of 5 children, there will be exactly 3 male children.

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ANSWER :`(5)/(16)`
34.

The probability of the event A occuring is 0.5 and of B occurring is 0.3. If A and B are mutually exclusive events then the probability of neither A nor B occuring is

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ANSWER :`0.2`
35.

If int(dx)/(1+sinx)=tan((x)/(2)+a)+b, then..

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`a=(PI)/(4),B=3`
`a=-(pi)/(4),b=3`
`a=(pi)/(4),b=` Arbitary CONSTANT
`a=-(pi)/(4),b=` Arbitary constant

Answer :D
36.

Number of binary operations on the set {a,b} are

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10
16
20
8

Solution :N/A
37.

(a+b).(a-b)+((a+b)(a-b)(a^2+b^2))/(2!)+((a+b)(a-b)(a^4+b^4+a^2b^2))/(3!)+.....=

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`E^(a) +e^b`
`e^(a+b)`
`e^(a^2)-e^(b^3)`
`e^(a^2)-e^(b^2)`

ANSWER :C
38.

Write the first three terms of the expansion of (1+(x^(2))/(2))^(-5)

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SOLUTION :N/A
39.

If 1,alpha,alpha^2,alpha^3,…,alpha^(n-1) be the n^(th) roots of unity, then prove that 1^p+alpha^p+(alpha^2)^p+(alpha^3)^p+…+(alpha^(n-1))^p={{:(0,if" "pnekn),(n,if" "p=kn):}" where p,k"epsilonN

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40.

Let p and q be two statements and let r and s be the following statements: r : p harr q s: ~ q harr ~ p Then which of the following is not true

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R `EQUIV`s
`r ^^ s equiv` s
`r VEE s equivs`
`r NE s `

ANSWER :D
41.

The probabilities that at least one of the events A and B occurs is 0.8 and the probabilitythat both events occur simultaneously is 0.25. Find the probability P(barA)+P(barB).

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0.95
0.05
0.5
None of these

SOLUTION :N/A
42.

If (1.05)^(50) = 11.658 then sum _(n = 1) ^(49) (1.05)^(n) equals

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208.34
212.12
212.16
213.16

Answer :C
43.

the matrix S is rotation through an angle 45^(@) and G is th reflection about the line y=2x, then (SG)^(2) is equal to

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7I
5I
3I
I

Answer :D
44.

If I(x)=intx^2(logx)^2dx and I(I)=0 then I(x)

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`x^3/18[8(LOGX)^2-3logx]+7/18`
`x^3/27[9(logx)^2+6logx]-2/27`
`x^3/27[9(logx)^2+6logx+2]-2/27`
`x^3/27[9(logx)^2+6logx-2]+2/27`

ANSWER :C
45.

Fromthe polynomial equation whose roots are1+I,1-I,-1+I,-1-I

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ANSWER :`x^4+4=0`
46.

If ab ne 0 and the sum of the coefficient of x^7 and x^4 in the expansion of ((x^2)/(a)-(b)/(x))^11 zero, then

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a = B
a + b = 0
ab = -1
ab = 1

ANSWER :D
47.

If A and B are two events such that P (A) = 0.3, P (B) = 0.6 and P ((B)/(A)) = 0.5 find P (A cup B)

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ANSWER :0.75
48.

For the matrixA={:[( 3,2),( -1,2) ]:} .Find the numbers a and b such that A^(2) +aA+bI =O.

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ANSWER :` a=-4,b=1`
49.

The unit vector in the opposite direction of bar(x)+bar(y)-2bar(z) is ………… where bar(x)=(1,1,0),bar(y)=(0,1,1) and bar(z)=(1,0,1).

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`((1)/(SQRT(6)),(-2)/(sqrt(6)),(1)/(sqrt(6)))`
`((1)/(6),(-2)/(6),(1)/(6))`
`((-1)/(sqrt(6)),(2)/(sqrt(6)),(-1)/(sqrt(6)))`
`((-1)/(6),(2)/(6),(-1)/(6))`

ANSWER :A
50.

A firm has a marginal revenue function given MR=(a)/(x+b)-c ,where x is the output a, b, c are constants. Then demand function is given by p=(k)/(x)log((x+b)/(b))-c , where k is(i) a(ii) c(iii) 1(iv) -1

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a
C
1
`-1`

ANSWER :C