Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The sum of three numbers in A.P. is 27, and their product is 504, find them.

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ANSWER :`4,9,14`
2.

ABCD is a square of side l. A line parallel to the diagonal BD at a distance 'x' from the vertex A cuts two adjacentsides. Express the area of the segment of the square with A at a vertex, as a function of x. Find this area at x=1//sqrt(2) and at x=2, when l=2.

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Solution :There are TWO CASES
CASE -I : when `x=AP le OA, i.e., x le (l)/(sqrt(2))`

`:. Ar(triangle AEF)=(1)/(2)x,2x=x^(2) "" ( :' PE =PF=AP=x)`
Case-II : when` x=AP gt OA, i.e., x gt (l)/(sqrt(2)) " but " x le sqrt(2) l`

`ar(ABEFDA)=ar(ABCD)-ar( triangle CFE)`
`=l^(2)-(1)/(2)(sqrt(2)l-x)*2(sqrt(2)l-x) "" [ :' CP=sqrt(2)l-x]`
`=l^(2)-(2L^(2)+x^(2)-2sqrt(2)lx)=2sqrt(2)lx-x^(2)-l^(2)`
So, the required function s(x) is
`s(x) ={(x^(2)","0le x le (l)/(sqrt(2))),(2sqrt(2)lx-x^(2)-l^(2)","(l)/(sqrt(2)) lt x le sqrt(2)l):}`
` :. s(x) ={((1)/(2)" at " x=(1)/(sqrt(2))),(8(sqrt(2)-l)" at " x=2):}`
3.

underset(x to pi//2)"Lt" [sin x]=

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1
0
`-1`
none

Answer :B
4.

Find the area enclosed between the curves y= 2-x^(2) and y= x^(2)

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ANSWER :`((8)/(3))`
5.

Find the equation of the circle for which the point given below are the end points of a diameter. (0,0) ,(8,5)

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ANSWER :` X^(2)+ y ^(2)-8x -5Y =0`
6.

If 7l^(2)-9m^(2) + 8l + 1 = 0and we have to find equation of circle having lx + my + 1 = 0 is a tangent and we can adjust given condition as16l^(2) + 8l + 1 = 9(l^(2) + m^(2)) or (4l + 1)^(2) = 9(l^(2) + m^(2)) rArr (|1 4l+1|)/(sqrt((l^(2) + m^(2)))) = 3 Centre of circle = (4, 0) and radius = 3 when any two non parallel lines touching a circle, then centre of circle lies on angle bisector of lines. On the basis of above information, answer the following questions : If 4l^(2) – 5m^(2) + 6l + 1 = 0, then the centre and radius of the circle which have lx + my + 1 = 0 is a tangent is

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`(0, 4), SQRT(5)`
`(4, 0), sqrt(5)`
`(0, 3), sqrt(5)`
`(3, 0), sqrt(5)`

Answer :D
7.

For the circle C with the equation x^(2)+y^(2)-16x-12y+64=0 match the list-I with the list-II given below:

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I) d. ii). B, iii). a, iv). C
I) d. ii). a, iii). b, iv). e
I) c. ii). d, iii). a, iv). b
I) c. ii). e, iii). b, iv). a

Answer :C
8.

If 7l^(2)-9m^(2) + 8l + 1 = 0and we have to find equation of circle having lx + my + 1 = 0 is a tangent and we can adjust given condition as16l^(2) + 8l + 1 = 9(l^(2) + m^(2)) or (4l + 1)^(2) = 9(l^(2) + m^(2)) rArr (|1 4l+1|)/(sqrt((l^(2) + m^(2)))) = 3 Centre of circle = (4, 0) and radius = 3 when any two non parallel lines touching a circle, then centre of circle lies on angle bisector of lines. On the basis of above information, answer the following questions : If 16l^(2) + 9m^(2) = 24lm + 6l + 8m + 1 and if S be the equation of the circle having lx + my + 1 = 0 is a tangent when the equation of director circle of S is

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`X^(2) + y^(2) + 6X + 8y = 25`
`x^(2) + y^(2) - 6x + 8y = 25`
`x^(2) + y^(2) - 6x - 8y = 25`
`x^(2) + y^(2) + 6x - 8y = 25`

ANSWER :C
9.

The sum of last ten coefficients in the expansion of(1+x)^(19) when expanded in ascending powers ofxis

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`2^(18)`
`2^(19)`
`2^(18)-""^(19)C_(10)`
NONE of these

Answer :B
10.

Whenf: R to Rand g: R to Rare two functions defined by f(x)= 8x^(3)and g(x) == x^((1)/(3)) respectivelyand (g of ) (x) = k (f o g ) (x) , then k is

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`4`
` 2`
` (1)/(2)`
NONE of these

ANSWER :A
11.

Using the letters of the word 'RAM' How many 6 letter words can be prepared so that all the 3 letters are to appear in the same word atleast once.

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ANSWER :540
12.

If 7l^(2)-9m^(2) + 8l + 1 = 0and we have to find equation of circle having lx + my + 1 = 0 is a tangent and we can adjust given condition as16l^(2) + 8l + 1 = 9(l^(2) + m^(2)) or (4l + 1)^(2) = 9(l^(2) + m^(2)) rArr (|1 4l+1|)/(sqrt((l^(2) + m^(2)))) = 3 Centre of circle = (4, 0) and radius = 3 when any two non parallel lines touching a circle, then centre of circle lies on angle bisector of lines. On the basis of above information, answer the following questions : If 16m^(2) – 8l– 1 = 0, then equation of the circle having lx + my + 1 = 0 is a tangent is

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`X^(2) + y^(2) + 8x = 0`
`x^(2) + y^(2) - 8x = 0`
`x^(2) + y^(2) + 8y = 0`
`x^(2) + y^(2) - 8y = 0`

ANSWER :B
13.

The normal at a point P on the ellipse x^(2)/a^(2)+y^(2)/b^(2)=1(a gt b) meets the axis in M and N so that (PM)/(PN)=2/3. Then the value of eccentricity is

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`1-E^(2)`
`e^(2)-1`
`1+e^(2)`
`e^(2)`

ANSWER :A
14.

Consider a 2xx2 matrix A=[a_(ij)] , where a_(ij)=(i+2j)^2/2 Find A+A^T

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SOLUTION :`a_11=(1+2xx1)^2/2=9/2,`
`a_12=(1+2xx2)^2/2=25/2`
`a_21=(2+2xx1)^2/2=16/2=8`.
`a_22=(2+2xx2)^2/2=36/2=18`,
HENCE, `A=[[9/2, 25/2],[8, 18]]`
15.

I= int "arc" tan x dx.

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ANSWER :`= x "ARC" tan x - (1)/(2) "In" (1+ x^2) + C`.
16.

int((1+x^(2))(2+x^2))/((xco sx+sinx)^(4))dx equals

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`tan(x+cot^(-1)x)+(tan^(3)(x+cot^(-1)x))/(3)+C`
`tan(x-cot^(-1)x)+(tan^(3)(x-cot^(-1)x))/(3)+c`
`-(1)/(3)((1-xtanx)/(x+tanx))^(3)-((1-xtanx)/(x+tanx))+c`
`-(1)/(2)((1+xtanx)/(x-tanx))^(3)-((1+xtanx)/(x-tanx))+c`

Answer :B::C
17.

If f:R rarr [(pi)/(3),pi) defined by f(x)=cos^(-1)((lambda-x^(2))/(x^(2)+2)) is a surjective function, then the value of lambda is equal to

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0
3
2
1

Answer :D
18.

For a > 0, let the curves C_(1) : y^(2) = ax and C_(2) : x^(2) = ayintersect at origin O and a point P. Let the linex = b(0 lt b lt a) intersect the chord OP and the x-axis at points Q and R, respectively. If the line x = b bisects the area bounded by the curves, C_(1)and C_2, and the area of triangleOQR = 1//2, then 'a' satisfies the equation:

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`x^(6) - 12X^(3) + 4=0`
`x^(6) - 12x^(3) - 4=0`
`x^(6) + 6x^(3) -4=0`
`x^(6) - 6x^(2) + 4=0`

ANSWER :A
19.

Locus of the point of intersection of the tangents at the points with eccentric angle theta and (pi)/(2)+thetais

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`x^(2)+y^(2)=a^(2)`
`x^(2)+y^(2)=b^(2)`
`(x^(2))/(a^(2))+(y^(2))/(b^(2))=2`
`(x^(2))/(a^(2))+(y^(2))/(b^(2))=1`

ANSWER :C
20.

Integrate the following functions sinx sin(cosx).

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SOLUTION :Let t = COSX. Then dt = -sinx dx
therefore `int sinx SIN(cosx) dx = int sintxx-dt`
=`-int sintt dt = -(-cost)+C`
=`cost=c = cos(cosx)+c`
21.

IFa = x hati+ y hatj+ z hatkthen( a xx hati) . ( hati+ hatj )+ ( a xxhatj) . ( hatj + hatk ) + ( axx hatk ) . ( hatk + hati ) =

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`X-y+z`
`x+y+z`
`x+y-z`
`-x +y+z`

ANSWER :B
22.

Using integration find the area of the triangular region whose sides have the equations y =2x+1, y =3x +1 and x= 4.

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ANSWER :8
23.

If f(x)=x+(1)/(x), then :

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RELATIVE MINIMUM gt relative MAXIMUM
relative maximum gt relative minimum
relative maximum does not exist
relative minimum does not exist.

Answer :A
24.

Integrate the following functions w.r.t. x: (i) sinmx (ii) 2xsin(x^(2)+1) (iii) (tan^(4)sqrtxsec^(2)sqrtx)/(sqrtx) (iv) (sin(tan^(-1)x))/(1+x^(2))

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Answer :`-(1)/(m) cos (mx)+C, (II) -cos(x^(2)+1)+c`
(III) `(2)/(5)TAN^(5)( sqrt(x))+c, (iv) -cos(tan^(-1)x)+c`
25.

If ""^(n)P_(7)=42. ""^(n)P_(5). find n.

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ANSWER :12
26.

Find the point of contant of the tangent line 4x+y-7=0 with the ellipse x^(2)+3y^(2)=3

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ANSWER :`((12)/(7),(1)/(7))`
27.

From any point on the hyperbolax^(2) -y^(2) =a^(2) -b^(2)two tangents are drawn to the ellipsex^(2)//a^(2) +y^(2) //b^(2) =1Then they make anglesalpha and betasuch that

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` tan alpha -tan beta +1`
` tan alpha + tan beta =1`
` tan alpha tan beta =1`
` tan alpha tan beta =-1`

Answer :C
28.

If z_(0) is one of the roots of the equation z^(n)cos theta_(0)+z^(n-1)cos theta_(1)+…+z cos theta_(n-1)cos theta_(n)=2, where theta_(i) in R, then

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`|z_(0)|lt (1)/(2)`
`|z_(0)|GT (1)/(2)`
`|z_(0)|=(1)/(2)`
none of these

Answer :B
29.

The value of the determinant |{:(x,x+y,x+2y),(x+2y,x,x+y),(x+y,x+2y,x):}|" is "".........."

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`9x^2(x+y)`
`9y^2(x+2y)`
`3y^2(x+y)`
`7x^2(x+y)`

ANSWER :B
30.

For any three vectors bara,barb,barc prove that [barb+barc barc+bara bara+barb] = 2[bara barb barc].

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ANSWER :`=2[BARA BARB BARC]`
31.

Using the example from #27, what's the remainder when xy is divided by 9?

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ANSWER :3
32.

Two persons A and B toss a die. The person who first throws 6 wins. If A starts then find the probability of A winning the game.

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ANSWER :`(6)/(11)`
33.

A biased die is tossed and the respective probabilities for the face to turn up are given below : {:("Face",1,2,3,4,5,6),("Probability",0.1,0.24,0.19,0.18,0.14,0.15):} If an odd face has turned up, then the probability for the face turned up is 3 or 5 is

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`(3)/(4)`
`(30)/(43)`
`(33)/(43)`
`(10)/(43)`

ANSWER :C
34.

int (2x-sin 2x)/(1-cos 2x) dx

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ANSWER :`-X COT x+c`
35.

There are 5% defective items in a large bulk of items. What is the probability that a sample of 10 items will include not more than one defective item?

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ANSWER :`((29)/(20))((19)/(20))^(9)`
36.

int(sec^(4)x+tan^(4)x)dx=

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`2/3tan^(3)x-2/3tanx+x+C`
`1/3sec^(2)xtanx+5/3tanx+(tan^(3)x)/3+x+c`
`2/3tan^(3)x+x+c`
`1/3sec^(2)xtanx-5/3tanx+(tan^(3)x)/3+x+c`

ANSWER :C
37.

If P is a point on the parabola y^(2)=8x and A is the point (1,0) then the locus of the mid point of the line segment AP is

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`y^(2)=4 (X-(1)/(2))`
`y^(2)=2(2x+1)`
`y^(2)=x-(1)/(2)`
`y^(2)=2x+1`

ANSWER :A
38.

Find the approximate volume of metal in a hollow spherical shell whose internal and external radii are 3 cm and 3.0005 cm, respectively.

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ANSWER :`=0.018 PI (CM)^(3)`
39.

y=sinxcdotsin2xcdotsin4xcdotsin8x

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ANSWER :`sinxcdot sin2xsin4xcdot sin8x[cotx+2cot2x+4cot4x+8cot8x]`
40.

Find the coefficient of x^(7) in the expansion of (1-x-x^(2)+x^(3))^(6).

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SOLUTION :N/A
41.

Show that A(-3,0) lies on x^(2)+y^(2) + 8x+ 12 y + 15 = 0 and find the other end of diameter thorugh A.

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ANSWER :` (-5,-12) `
42.

If |2x-3| lt |x+5| , then x lies in the interval

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`(-3,5)`
`(5,9)`
`(-2/3,8)`
`(-8 , 2/3)`

ANSWER :C
43.

A man has 5 male and 4 female relatives. His wife has 4 male and 5 female relatives. The number of ways in which they can invite 5 male and 5 female relatives so that 5 of them are man's relatives and remaining 5 are his wife's relatives

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A5426
B5226
C5526
D5626

Answer :D
44.

Evaluate int_(0)^(pi)ln(1+bcosx) dx, 'b'being parameter.

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SOLUTION :N//A
45.

If A = {:[(4, 2),(-1,1)]:}, the (2I - A) (A -3I) is

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1
`-1`
`O_2`
`A^(-1)`

ANSWER :C
46.

(3 - omega) ( 3- omega^(2)) ( 3- omega^(4)) (3 - omega^(8)) =

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81
`13^(4)`
`169`
0

Answer :C
47.

Whichof thefollowingfunctionhas / havea reaovablediscontinuityattheindicated point ?

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`F(x) =(x^(2)-2x-8)/(x+2)at x=-2`
`f(x) =(x-7)/(|x-7|)at x=7`
`f(x) =(x^(3)+64)/(|x+4|)at x=-4`
`f(x) =(3-sqrt(x))/(9-x)at x=9`

ANSWER :A::C::D
48.

IF theequationk ( 6 x^2+ 3)+ rz+ 2x^2-1=0and6k( 2 x^2+1) + px + 4x ^2-2=0haveboththerootcommon, thenthe valueof2r-pis

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0
1
2
3

Answer :A
49.

Computethe areaboundedby thelinesx+ 2y = 2 , y - x=1 and2x +y =7

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ANSWER :`=6` SEQ . UNIT
50.

Differentiate cosec 3x

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SOLUTION :LET`y=COSEC 3X`
Then `dy/dx=-3"cosec"3x CDOT cot3x`