This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
(i) Find the area bounded by x^(2)+y^(2)-2x=0 and y = sin'(pix)/(2) in the upper half of the circle. (ii) Find the area bounded by the curve y = 2x^(4)-x^(2), x-axis and the two ordinates cooreponding to the the minima to the function. (iii) Find area of the curve y^(2) = (7-x)(5+x) above x-axis and between the ordinates x = - 5 and x = 1. |
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| 2. |
If x - coordinateof a point P on theline joining the [points Q(2,2,1) and R (5,1,-2)is 4 , then the z - cossrdinate of P is |
| Answer» Answer :B | |
| 3. |
Find the sum of n-terms of the series 2.5 + 5.8 + 8.11 +…….. |
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| 4. |
Evaluate the following integrals (vi) int_(0)^(1)e^(x) sin h x dx. |
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| 5. |
The solution of (dy)/(dx) + (3x^(2) y)/(1 + x^(3)) = (1+ x^(2))/(1 + x^(3)) is |
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Answer» `y(1+X^(3)) = x+(x^(3))/(3)+C` |
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| 6. |
Using integration find the area of region bounded by the triangle whose vertices are (1, 0), (2, 2) and (3, 1). |
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| 8. |
Determine if the set A ={-1,1,3}is a proper subset of the set B={x:x in R and x^3-2x^2-x+2=0} |
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Answer» SOLUTION :Solving `x^3-2x^2-c+2=0` we have `x^2(x-2)-1(x-2)=0` or, `(x-2)(x^2-1)=0` `:.`x=1,-1,2` `:. B ={-1,1,2}` `:.`A is not a subset of B. |
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| 9. |
From the point A(0,3) on the circle x^(2)+4x+(y-3)^(2)=0, a chord AB is drawn and extended to a point P, such that AP=2AB. The locus of P is |
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Answer» `X^(2)+4X+(y-3)^(2)=0` |
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| 11. |
For all values of A, B, C and P, Q, R |(cos(A-P), cos(A-Q),cos(A-R)),(cos(B-P), cos(B-Q), cos(B-R)),(cos(C-P), cos(C-Q), cos(C-R))|= |
| Answer» Answer :C | |
| 12. |
A man running on a race course notices that the sum of the distances of the two flag posts from him is always 10m and the distance between the flag posts is 8m. Find the equation of the race course traced by the man. |
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| 15. |
If the chord of contact of tangents from a point to a given circle passes through Q , then the circle on PQ as diameter |
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Answer» CUTS the given CIRCLE orthogonally |
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| 16. |
Let omega=-(1)/(2)+i (sqrt(3))/(2), then the value of [[1,1,1],[1,-1-omega^(2),omega^(2)],[1,omega^(2),omega^(4)]] is |
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Answer» `3OMEGA` |
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| 17. |
If [(alpha,beta),(gamma,-alpha)] is square root of identity matrix of order 2 then- |
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Answer» `1+ALPHA^(2)+betagamma=0` |
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| 18. |
If the first three terms in the expansion of (1 -ax)^n where n is a positive integer are 1,-4x and 7x^2 respectively then a = |
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Answer» `1//5` |
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| 19. |
Find the slope of the tangent to the curve y = x^(3) –3x + 2 at the point whose x-coordinate is 3. |
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| 20. |
The solutionof(dy)/(dx)=( x+y)/(x-y) is |
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Answer» `tan ^(-1) ((y)/(x))= logsqrt(x^2+y^2)+C` |
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| 21. |
If -2-i is a root of the equation ax^(2)+12x+b=0 (where a and b are real), then the value of ab is equal to |
| Answer» ANSWER :A | |
| 22. |
The equation of parabola whose latus rectum isthe line segment joining the points (-3,1) , (1,1) is |
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| 23. |
Find P^(-1), if the exists, given P=[(10,-2),(-5,1)] |
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Answer» <P> |
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| 24. |
If x=sinh^(-1)[log(1+sqrt(y)], " then "(dy)/(dx)= |
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Answer» `2(y+sqrt(y))SINHX` |
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| 25. |
Out of 52 cards 4 are drawn at random without replacement. What is the probability that (i) they belong to different suits (i.e., one from each suit) (ii) they belong to different denominations |
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| 26. |
1/2.""^10C_0 -""^10C_1 +2.""^10C_2 - 2^2.""^10C_3+…..+2^9. ""^10C_10 = |
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Answer» `1//2` |
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| 27. |
Which of the following is noth the number of ways of selecting n objects from 2n objects of which n objects are identical |
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Answer» `2^(n)` `:.` Total no. of solutions `=sum_(r=0)^(n).^(n)C_(r )=2^(n)` No. of possible subsets of a set containing `n` elements is `2^(n)` and `.^(2n+1)C_(0)+^(2n+1)C_(1)+^(2n+1)C_(2)+...+^(2n+1)C_(n)=2^(2n)` |
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| 28. |
Let A, B, C, D, E represent vertices of a regular pentagon ABCDE. Given the position vector of these vertices be veca, veca + vecb, vecb, lamda veca andlamda vecb, respectively. AD divides EC in the ratio |
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Answer» `cos""(2pi)/(5) : 1` Let position vector of POINT A and C be `VECA and veb`, respectively. `AD` is parallel to BC and AB is parallel to EC. Therefore, AOCB is a PARALLELOGRAM and position vector of B is `veca + VECB` The position vectors of E and D are `lamdavecb and lamda veca`respectively. Also `OA = BC = AB= OC =1` (let) Therefore, AOCB is rhombus. `angle ABC = angle AOC = (3pi)/(5)` and `angleOAB = angle BCO = pi - (3pi)/(5) = (2pi)/(5)` Further `OA = AE = 1 and OC = CD = 1 ` Thus, `DeltaEAO and Delta OCD` are isosceles. In `Delta OCD`, using sine rule we get `(OC)/(sin""(2pi)/(5))= (OD )/( sin""(pi)/(5))` `rArr OD = (1)/( 2 cos ""(pi)/(5)) = OE` `rArr AD = OA + OD = 1 + (1)/(2 cos ""(pi)/(2))` `rArr (AD)/(BC) =1 + (1)/(2 cos""(pi)/(5)) = (1 +2 cos""(pi)/(5))/( 2 cos""(pi)/(5))` And `(OE)/( OC) = (1)/( 2cos ""(pi)/(5))` |
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| 29. |
Let A, B, C, D, E represent vertices of a regular pentagon ABCDE. Given the position vector of these vertices be veca, veca + vecb, vecb, lamda veca andlamda vecb, respectively. The ratio (AD)/(BC) is equal to |
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Answer» `1-cos""(3pi)/(5) : cos""(3pi)/(5)` Let position vector of point A and C be `veca and veb`, respectively. `AD` is parallel to BC and AB is parallel to EC. THEREFORE, AOCB is a parallelogram and position vector of B is `veca + vecb` The position vectors of E and D are `lamdavecb and lamda veca`respectively. Also `OA = BC = AB= OC =1` (let) Therefore, AOCB is rhombus. `angle ABC = angle AOC = (3pi)/(5)` and `angleOAB = angle BCO = pi - (3pi)/(5) = (2pi)/(5)` Further `OA = AE = 1 and OC = CD = 1 ` Thus, `DeltaEAO and Delta OCD` are isosceles. In `Delta OCD`, using SINE RULE we get `(OC)/(sin""(2pi)/(5))= (OD )/( sin""(pi)/(5))` `rArr OD = (1)/( 2 cos ""(pi)/(5)) = OE` `rArr AD = OA + OD = 1 + (1)/(2 cos ""(pi)/(2))` `rArr (AD)/(BC) =1 + (1)/(2 cos""(pi)/(5)) = (1 +2 cos""(pi)/(5))/( 2 cos""(pi)/(5))` And `(OE)/( OC) = (1)/( 2cos ""(pi)/(5))` |
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| 30. |
A line makes an angle alpha,beta and gamma with axes repectively, The values of alpha, beta and gamma are respectively theta, 60^@ and 30^@ then sin theta = ............. |
| Answer» ANSWER :A | |
| 31. |
Find the order and degree (if defined) of the following differential equations. (d^2y)/(dx^2) = cos 3x + sin 3x |
| Answer» Solution :The ORDER of the highest order derivative in the DIFFERENTIAL EQUATION = 2. `therefore` The order of the differential equation = 2 . Since the degree of `(d^2y)/(dx^2)` is 1, the degree of the differential equation = 1. | |
| 33. |
If |{:(2x,5),(8,x):}|=|{:(6,-2),(7,3):}|, then value of x is "........." |
| Answer» Answer :C | |
| 34. |
A curve C has the property that if the tangent drawn at any point 'P' on C meets the coordinate axes at A and B, and P is midpoint of AB. If the curve passes through the point (1,1) then the equation of the curve is |
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Answer» XY = 2 |
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| 35. |
If x^(2)+y^(2)=1 then minimum and maximum values of (x+y) are |
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Answer» `-SQRT(2),sqrt(2)` |
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| 36. |
If A+B+C=180^@" then " 4 cos""((pi-A)/(4)) cos""((pi-B)/(4)) cos""((pi-C)/(4))= |
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Answer» `cos A + cos B + cos C ` |
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| 37. |
Angle between the asymptotes of a hyperbola is x^(2)-3y^(2)=1 is |
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Answer» `15^(@)` |
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| 38. |
Evaluate the following:lim_(ntoinfty) n/(n+1) |
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Answer» SOLUTION :`lim_(ntoinfty) N/(n+1)` `=lim_(ntoinfty)1/(1+1/n)=1` |
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| 39. |
The slope of the tangent to the curve x=t^(2)+3t-8,y=2t^(2)-2t-5 at the point (2,-1) is |
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Answer» 1)`(22)/(7)` |
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| 41. |
Let f(x) = 1 + 4x - x^(2), AA x in Rg(x) = max {f(t), x le t le (x + 1), 0 le x lt 3min {(x + 3), 3 le x le 5} Verify conntinuity of g(x), for all x in [0, 5] |
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| 42. |
Find the area of the triangle formed by three points on the ellipse x^2/a^2+y^2/b^2=1 whose eccentric angles are alpha, beta and gamma. |
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| 43. |
If int (x^(2) + 2)/((x^(2) + 1)(x^(2) + 4))dx = A tan^(-1) x + B tan^(-1)""(x)/(2)+ c then (A, B) = |
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| 45. |
Find the equation of the circum circle of the triangle formed by the lines x+ 3y =1, x+y + 1=0, 2x + 3y -4=0 |
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| 46. |
Consider the expansion of (2x-1)^(15) |
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Answer» ALGEBRAICALLY least coefficient is `T_(5)` `rle(16)/(1+|(2x)/(-1)|)` `rle(16)/(3)=5` `impliesT_(6)` gives numerically greatest coefficient `T_(6)= .^(15)C_(5)(-1)^(5)(2)^(10)(x)^(10)` `N.G.C= .^(15)C_(5)(2)^(10)` `N.I.C=1` `A.L.C= .^(15)C_(4)(2)^(10)` `A.G.C= .^(15)C_(4)(2)^(11)` |
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| 47. |
""^15C_2 + 2.""^15C_3 + 3. ""^15C_4 + …..+ 14.""^15C_15 = |
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Answer» `13.2^14 - 1` |
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| 48. |
Definite integration as the limit of a sum : lim_(ntooo)sum_(r=1)^(n)(1)/(n)e^(r/(n))=............. |
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Answer» e |
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