Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The mean of a data set consisting of 20 observation is 40. If one observation 53 was wrongly recorded as 33, then the correctmean will be

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41
49
`40.5`
`42.5`

ANSWER :A
2.

Evaluate Lt_(n to oo)[(1)/(1+n)+(1)/(2+n)+(1)/(3+n)+"...."+(1)/(10n)]

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Solution :`underset(nrarr0)(LT)[(1)/(1+n)+(1)/(2+n)+(1)/(3+n)+"......"+(1)/(10N)] = underset(nrarroo)("Lt")underset(r=1)overset(9n)sum(1)/(r+n)`
`=underset(nrarroo)(Lt)underset(r=1)overset(9n)sum(1)/(n) (1)/((r/n)+1) = underset(0)overset(9)int(dx)/(x+1)=[ln(x+1)]_(0)^(9)=ln10`
3.

The perpendicular distance from the point (1,-1) to the line x + 5y-9=0 is equal to

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`SQRT((2)/(13))`
`sqrt((13)/(2))`
`(13)/(2)`
`(2)/(13)`

ANSWER :B
4.

from a bag containing 4 red and 2 black balls, two balls are drawn. the probability of getting two black balls is:

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`1/2`
`1/3`
`1/6`
`1/15`

ANSWER :D
5.

Find the remainder when 7^(103) is divided by 5.

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SOLUTION :N/A
6.

If three unequal real numbers are in G.P. then their reciprocals are in -

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`A.M. LT G.M.`
`A.M. le G.M.`
`A.M. GE G.M.`
`A.M. GT G.M.`

ANSWER :B
7.

Prove that :int_(0)^(pi) (x sin x)/(1+sinx) dx=pi((pi)/(2)-1)

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8.

If S.P and R are the sum, product and sum of the reciprocals of n terms of an increasing G.P respectively and S^(n) = R^(n).P^(k), then k is equal to

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1
2
3
None of these

Answer :B
9.

If f(x)=x^(3) and g(x)=x^(3)-4x in -2lt x lt 2, then consider the statements : (a) f(x) and g(x) satisfy Mean Value Theorem (b) f(x) and g(x) both satisfy Rolle's theorem (c ) Only g(x) satisfies Rolle's theorem. OF THE STATEMENTS

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(a) and (B) are CORRECT
(a) alone is correct
None is correct
(a) and (C) are correct

Answer :D
10.

C_0^2+3.C_1^2+5. C_2^2+….+(2n+1) .C_n^2=

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`(N-2)((2N)!)/((n!)^2)`
`(n-1)((2n)!)/((n!)^2)`
`(n+2)((2n)!)/((n!)^2)`
`(n+1)((2n)!)/((n!)^2)`

ANSWER :D
11.

The negation of p rarr (~p.vee q) is

Answer»

<P>p `^^` (~Q)
p `^^` (~ q)
p` ^^` q
(~ p )` ^^` q

ANSWER :A
12.

Evaluate int_(0)^(1)e^(2-3x)dx as a limit of a sum.

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ANSWER :`(1)/(3)(E^(3)-(1)/(e))`
13.

For the curve x = e^(t) cos t, y = e^(t) sin t the tangent line is parallel to x-axis when t is equal to

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`-(PI)/(4)`
`(pi)/(4)`
0
`(pi)/(3)`

ANSWER :A
14.

If three six faces fair dice are thrown together, then the probability that the sum of the numbers appearing on the dice is (p le k le 14) is

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`(k^(2)-21k+83)/(216)`
`(k^(2)+21k+83)/(216)`
`(21k-k^(2)-83)/(216)`
`(21k-k^(2)+83)/(216)`

Answer :C
15.

If x, y, z are positive real numbers, then minimum value of (z)/(x+y)+(x)/(y+z)+(y)/(x+z) is

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ANSWER :1.5
16.

Let f(x) = [{:((2^(x)+2^(3-x) - 6)/(sqrt(2^(-x))-2^(1-x))",","if",x gt 2),((x^(2) - 4)/(x - sqrt(3x - 2))",","if",x lt 2):},then

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`f(2) = 8 rArr f` is continuous at x = 2
`f(2) = 16 rArr f` is continuous at x = 2
`f(2^(-)) ne f(2^(+)) rArr f` is discontinuous
f has a REMOVABLE DISCONTINUITY at x = 2

Answer :C
17.

Show that the direction cosines of a vector equally inclined to the axes OX, OY and OZ are (1)/(sqrt3). (1)/(sqrt3). (1)/(sqrt3).

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Answer :`therefore L = m = N = (1)/(SQRT3)`
18.

Lt_(ntooo){(n+1)/(n^(2)+1^(2))+(n+2)/(n^(2)+2^(2))+.......+1/(n)}

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`pi/4 + 1/4 LOG 2`
`pi/2 + 1/4 log 2`
`pi/2 + 1/2 log 2`
`pi/4 + 1/2 log 2`

ANSWER :D
19.

A coin and six faced die, both unbaised are thrown simultaneously . The probability of getting a head on the coin and an odd number on the die is

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`1//2`
`3//4`
`1//4`
`2//3`

ANSWER :C
20.

Derive the equation of a plane perpendicular to a given vector and passing through a given point in both vector and Cartesian form.

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ANSWER :`A ( x-x_1) + B(y-y_1) + C ( z-z_1) = 0` is Cartesian form
21.

Iff(x)=abs(x) and g(x)= [x] thenf@g(-1/2) is

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0
1
-2
-1

Answer :B
22.

The number of ways in which 5 different coloured flowers be strung in the form of a garland is

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24
12
16
22

Answer :B
23.

Given that a alpha^(2)+2b alpha +c!=0 and that the system of equations (a alpha =b)x+ay+bz=0, (b alpha+c)x+by+cz=0, (a alpha+b)y+(b alpha+c)z=0 has a non -trivial solution, then a,b,c lie in

Answer»

ARITHMETIC progression
GEOMETRIC progression
Harmonic progression
Arithmetic geometric progression

Answer :B
24.

If (x+c)/(1+x^2) where c is a constant , then when y is stationary , xy is equal to

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`1//2`
`3//4`
`5//8`
1

Answer :A
25.

Let X denote the number of hours you study during a randomly selected school day. The probability that X can take the values x, has the following form, where k is some unknown constant. P(X=x)={{:(0.1, "if "x =0),(kx, "if "x = 1or 2 ),(k(5-x), "if " x=3 or 4),(0,"otherwise"):} (a) Find the value of k. (b) What is the probability that you study at least two hours ? Exactly two hours? At most two hours?

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ANSWER :(a) k=0.15, (B) 0.55
26.

If 1, w, w^(2) are three cube roots of unity, then (1 - w+ w^(2)) (1 + w-w^(2)) is _______

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1)4
2)3
3)2
4)1

Answer :A
27.

Find the second order derivatives of the functions given in Exercises 1 to 10. x. cos x

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ANSWER :`-X COS x-2 SIN x`
28.

When any two sides and one of the opposite acute angle are given, under certain additional conditions two triangles are possible. The case when two triangles are possible is called the ambiguous case. In fact when any two sides and the angle opposite to one of them are given either no triangle is posible or only one triangle is possible or two triangles are possible. In the ambiguous case, let a,b and angle A are given and c_(1), c_(2) are two values of the third side c. On the basis of above information, answer the following questions Two different triangles are possible when

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`B SIN A LT a`
`b sin A lt a and b GT a `
`b sin A lt a and b lt a `
`b sin A lt a and a =b`

ANSWER :B
29.

Integrate the functions (x^(3))/(sqrt(1-x^(8)))

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ANSWER :`1/4sin^(-1)(X^(4))+C`
30.

Find the particular solution of the differentialequation (dy)/(dx) = - 4xy^(2) given that y = 1, when x = 0.

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ANSWER :`y = (1)/(2X^(2) + 1)`
31.

If theta is the angle between the vectors overset(^)(i) + overset(^)(j) and overset(^)(j) + overset(^)(k), then theta=

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`pi//2`
`pi//3`
`pi//4`
`pi//6`

ANSWER :B
32.

I : The angle between the asymptotes of the hyperbolax^(2) - 3y^(2) =3 "is" pi //3 II: The angle between the asymptotes of the hyperbolaxy =c^(2) "is" pi //2

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only I is true
only II is true
both I and II are TURE
neither I nor II true

Answer :C
33.

Find the equation of the circle which cuts the following circles orthogonally. x^2 + y^2 + 4x - 7 = 0.2x^2 + 2y^2 + 3x + 5y -9 =0, x^2 + y^2+ y = 0.

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ANSWER :`x^2 + y^2 - 4X - 2Y - 1= 0`
34.

A : If x+y+z=xyz " then " sum(3x-x^(3))/(1-3x^(2))=Pi(3x-x^(3))/(1-3x^(2)) . R : Iftan A + tan B + tan C= tan A tan B tan C " then " A+B+C=npi .

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A is TRUE , R is true and R is CORRECT explanation of A
A is true , R is trueand R is not correct explanation of A
A is true , R is FALSE
A is false , R is true

ANSWER :A
35.

Let z be a complex numbersatisfying z^(2) + 2zlambda + 1=0 , where lambdais a parameter whichcan take any realvalue. Forevery large value of lambda the roots are approximately.

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`-2lambda, 1//lambda`
`-lambda,-1//lambda`
`-2lambda, -(1)/(2lambda)`
none of these

Solution :`z = - lambda PM sqrt(lambda^(2) -1)`
Case I:
When `-1 lt lambdalt 1`, we have
`lambda^(2) lt 1 RARR lambda^(2) - 1 lt 0`
`z = - lambda pmisqrt(1-lambda^(2))`
`rArr y^(2) = 1 - x^(2) or x^(2) y + y^(2) = 1`
Case II:
`lambda gt 1 rArr lambda^(2) - 1 gt0`
` z=- lambda pmsqrt(lambda^(2) -1)`
`or x = - lambda pm sqrt(lambda^(2) -1),y = 0`
Roots are`(-lambda + sqrt(lambda^(2) -1,0),(-lambda - sqrt(lambda^(2))-1,0)`.One root lies inside the units circle and the other root lies outside the unit circle.
Case III:When `lambda` is verylarge, then
`z = - lambda- sqrt(lambda^(2) -1) ~~ - 2lambda`
`z=- lambda+sqrt(lamda^(2) -1) =((-lambda + sqrt(lambda^(2) -1))(-lambda -sqrt(lambda^(2)-1)))/((-lambda - sqrt(lambda^(2) -1)))`
`= (1)/(-lambda-sqrt(lambda^(2)-1)) =- (1)/(2lambda)`
36.

What is the equation to the hyperbola if its latusrectum is 9/2 and eccentricity is 5/4.

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ANSWER :1
37.

The slope of the tangent to the curve y=x^(3)+x+54 which also passes through the originis

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ANSWER :28
38.

int (1)/(sqrt(5x-6-x^2))dx=

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ANSWER :`SIN^(-1)(2x-5)+C`
39.

n bitstrings aremadebyfillingthedigits0 or1 . Thenumberof stringin whichthereare exactlykzeroswithnotwo '0' s consecutive is

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`""^((n-k))C_k`
`""^((n-k+1))C_k`
`""^((n-k-1))C_k`
none

Answer :B
40.

Definite integration as the limit of a sum : lim_(ntooo)[(n!)/(n^(n))]^(1/n)=.........

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E
`(1)/(e)`
`(PI)/(4)`
`(4)/(pi)`

Answer :B
41.

int (x^3)/(sqrt(1+x))dx=

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`SQRT(1+x^2)-(x)/(3)(1+x^2)^(3//2)+C`
`xsqrt(1+x^2)+(2)/(3)(1+x^2)^(3//2)+c`
`x^2sqrt(1+x^2)-(2)/(3)(1+x^2)^(3//2)+c`
`x^2sqrt(1+x^2)-(1)/(3)(1+x^2)^(1//2)+c`.

Answer :C
42.

An urn contains 5 red and 2 black balls. Two balls are randomly drawn. Let X represent the number of black balls. What are the possible values of X?

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ANSWER :X=0,1,2;
43.

Let f (x) be a twice differentiable function defined on (-oo,oo) such that f (x) =f (2-x)and f '((1)/(2 )) =f' ((1)/(4))=0. Then int _(-1) ^(1) f'(1+ x ) x ^(2) e ^(x ^(2))dx is equal to :

Answer»

1
`PI`
2
0

Answer :D
44.

The positive root of x^(2)-78.8=0 after first approximation by Newton Raphson method assuming initial approximation to the root is 14, is

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9.821
9.814
9.715
9.915

Solution :Here, `x_(0)=14, f(x)=x^(2)-78.8`
`and f'(x)=2x`
`THEREFORE x_(1)=x_(0)-(f(x_(0)))/(f'(x_(0)))`
`=14-((14)^(2)-(78.8))/(2xx14)=9.814`
45.

If f(x)=|{:(0,x-a,x-b),(x+a,0,x-c),(x+b,x+c,0):}|, then "............"

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F(a)=0
f(B)=0
f(0)=0
f(1)=0

Answer :C
46.

Statement-1 : fog = gof rArr f^(-1) = g or g^(-1) = f. and Statement-2 : fog != gof.

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STATEMENT-1 is True, Statement-2 is True, Statement-2 is a CORRECT EXPLANATION for Statement-1.
Statement-1 is True, Statement-2 is True, Statement-2 is NOT acorrect explanation for Statement-1.
Statement -1 is FALSE, Statement -2 is False
Statement -1 is False, Statement -2 is True

Answer :B
47.

overset((pi)/(2))underset(0)int sqrt(1-sin(2x))dx=.....

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`2sqrt(2)`
`2(SQRT(2)+1)`
2
`2(sqrt(2)-1)`

ANSWER :D
48.

The mean age of a combined group of men and women is 30 years. If the means of the age of men and women are respectively 32 and 27, then the percentage of women in the group is

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30
40
50
60

Answer :B
49.

By using the properties of definite integrals, evaluate the integrals int_(0)^(a)(sqrtx)/(sqrtx+sqrt(a-x))dx

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50.

Verify that the function y = e^(-3x) is a solution of the differential equation (d^(2)y)/(dx^(2)) + (dy)/(dx) - 6y = 0

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`(DY)/(DX ) - 3y =0`
` (d^2 y)/( dx^2) +(dy )/(dx) -6y =0`
`(d^2 y)/(dx^2)-9Y =0`
`(dy )/(dx)-9y =0`

ANSWER :C