Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Find the locus of the point of intersection of two tangents to the hyperbola x^(2)/a^(2)-y^(2)/b^(2)=1. which makes an angle alpha with one another.

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Answer :`(X^(2)+y^2-a^(2)+B^(2))^(2)=(4a^(2)y^(2)-4B^(2)x^(2)+4a^(2)b^(2)) COT^(2) alpha`
2.

Determine the truth of falsity of theA sub A for any set A propositions with reasons.

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Solution :`A sub A ` is FALSE, as A is an improper SUBSET of itself, not a proper subset.
3.

There are three coins. One is a two headed coin (having head on both faces), another is a biased coin that comes up heads 75% of the time and third is an unbiased coin. One of the three coins is chosen at random and tossed, it shows heads, what is the probability that it was the two headed coin ?

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ANSWER :`(4)/(9)`
4.

Let P and Q be point on the line joining A(5,6) and B (3, -4) such that AP=PQ=QB. Then the midpoint of PQ is

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(4,2)
(4,1)
(3, 1)
(2, 2)

ANSWER :B
5.

If |z-2/z|=2then the greatest value of |z| is

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`SQRT3 - 1`
`sqrt3`
`sqrt3 + 1`
`sqrt3 + 2`

ANSWER :C
6.

Show that [[a_1,b_1,-c_1],[-a_2,b_2,c_2],[a_3,b_3,-c_3]]= [[a_1,b_1,c_1],[a_2,b_2,c_2],[a_3,b_3,c_3]]

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SOLUTION :`[[a_1,b_1,-c_1],[-a_2,-b_2,c_2],[a_3,b_3,-c_3]]=[[a_1,b_1,-c_1],[a_2,b_2,-c_2],[a_3,b_3,-c_3]](-1)`
(TALING COMMON (-1) from `R_2`)
`(-)(-)[[a_1,b_1,c_1],[a_2,b_2,c_2],[a_3,b_3,c_3]]=[[a_1,b_1,c_1],[a_2,b_2,c_2],[a_3,b_3,c_3]]`
(TAKING common (-1) from `C_3`)
7.

If f(x)=(x-2)/(x+2),x!= -2 then f^(-1)(x), is equal to

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`(4(x+2))/(x-2)`
`((x+2))/(4(x-2))`
`(x+2)/(x-2)`
`(2(1+x))/(1-x)`

ANSWER :D
8.

For the reaction CO(g) + CI_(2)(g) hArr COCI_(2)(g) the value of (K_(c))/(K_(P))is equal to :-

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`SQRT(RT)`
RT
`(1)/(RT)`
1.0

Answer :A
9.

Find theareaof the regionboundedby thecirclex^2+y^2=32,X - axisand the liney=x in the firstquadrant .

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ANSWER :` 4 PI` SP . UNITS
10.

Find the coefficient of x^3 in ( sqrt(x^5) + (3)/(sqrt(x^3)) )^6

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ANSWER :540
11.

Find the area bounded between the curves y=x^(2), y=sqrt(x)

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ANSWER :`(1)/(3)`
12.

If f'(a)=2 and f(a)=4 then lim_(xtoa)(xf(a)-af(x))/(x-a) equals to

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`2a-4`
`4-2a`
`2a+4`
`4+2a`

ANSWER :B
13.

For what values o m the equation (1+m)x^(2)-2(1+3m)x+(1+8m)=0 has (m epsilonR) (i) both roots are imaginary? (ii) both roots are equal? (iii) both roots are real and distinct? (iv) both roots are positive? (v) both roots are negative? (vi) roots are opposite in sign? (vii)roots are equal in magnitude but opposite in sign? (viii) atleast one root is positive? (iv) atleast one root is negative? (x) roots are in the ratio 2:3?

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Solution :`:'(1+m)x^(2)-2(1+3m)x+(1+8m)=0`
`impliesD=4(1+3m)^(2)-4(1+m)(1+8m)=4m(m-3)`
(i) Both roots are IMAGINARY.
`:.Dlt0`
`implies4m(m-3)lt0`
`implies0ltmlt3`
or ` m epsilon (0,3)`
(ii) Both roots are equal
`:.D=0`
`implies4m(m-3)=0`
`impliesm=0,3`
(iii) Both roots are real and distinct
`:.Dgt0`
`implies4x(m-3)gt0`
`impliesmlt0` or `mgt3`
`:.m epsilon(-oo,0)uu(3,oo)`
(iv) Both roots are positive.
CASE I Lsum of the roots `gt0`
`implies(2(1+3m))/((1+m))gt0`
`impliesm epsilon (-oo,-1)uu(-1/3,oo)`
Case II Produc of the roots `gt0`
`implies((1+8m))/((1+m))gt0`
`m epsilon (-oo,-1)uu(-1/8,oo)`
Case III` D ge0`
`implies 4m(m-3)ge0`
`m epsilon (-oo,0]uu[3,oo)`
Combining all Cases, we get
`m epsilon (-oo,-1)uu[3,oo)`
(v) Both roots are negative.
Consider the following cases:
Case I Sum of the roots `lt 0implies(2(1+3m))/((1+m))lt0`
`impliesm epsilon (-1,-1/3)`
Case II PRODUCT of the roots `gt0implies((1+8m))/((1+m))gt0`
`impliesm epsilon (-oo,1)uu(-1/8,oo)`
Case III `Dge0`
`4m(m-3)ge0impliesm epsilon (-oo,0]uu[3,oo)`
Combining all cases we get
`m epsilon phi`
(vi) Roots are opposite in sign, then
Case I Consider the following cases:
Product of the roots `lt0`
`implies((1+8m))/((1+m))lt0`
` m epsilon (-1,-1/8)`
Case II `D gt0implies4m(m-3)gt0`
`implies m epsilon (-oo,0)uu(3,oo)`
Combining all cases we get
`m epsilon (-1,-1/8)`
(vii) Roots are equal in magnitude but opposite in sign, then Consider the following cases:
Case I Sum of the roots `=0`
`implies(2(1+3m))/((1+m))=0`
`impliesm=-1/3, m !=1`
Case `Dgt0implies4m(m-3)gt0`
`impliesm epsilon (-oo,0)uu(3,oo)`
Combining all cases we get
`m=-1/3`
(viii) Atleast one root is positive, then either one root si positive or bothh roots are positive
i.e. (d) `uu`(f)`
or `m epsilon (-oo,-1)uu(-1.-1/8)uu[3,oo)`
(ix) Atleast one root is negative, then either one root is negative or both roots are negative.
i.e. (e) `DUU` (f) or `m epsilon (-1,-1/8)`
(x) Let roots are `2 alpha` are `3 alpha`. Then
Consider the following cases:
Case I Sum of the roots `=2alpha+3 alpha=(2(1+3m))/((1+m))`
`implies alpha=(2(1+3m))/(5(1+m))`
Case II Product of the roots `=2 alpha.3 alpha=((1+8m))/((1+m))`
`implies6 alpha^(2)=((1+8m))/((1+m))`
From Eqs i and ii we get
`6{(2(1+3m))/(5(1+m))}^(2)=((1+8))/((1+m))`
`implies24(1+3m)^(2)=25(1+8m)(1+m)`
`implies24(9m^(2)+6m+1)=25(8m^(2)+9m+1)`
`=16m^(2)-81m-1=0`
or `m=(81+-sqrt((-81)^(2)+64))/32`
`impliesm=(81+-sqrt(6625))/32`
14.

The values of (1-sqrt3i)^(1//3) are

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`2^(1//3)CIS[(2kpi+pi//3)/(3)],k=0,1,2`
`2^(1//5)cis[(2kpi+pi//6)/(3)],k=0,1,2`
`2^(1//3)cis[(2kpi-pi//3)/(3)],k=0,1,2`
`2^(1//5)cis[(2kpi-pi//6)/(3)],k=0,1,2`

ANSWER :C
15.

A,B,C are 3 newspaper from a city. 20% of the population red A, 16% read B, 14% read C, 8% both A and B, 5% both A and C, 4% both B and C, 2% all the three. Find the percentage of the populations who read atleast one newspaper.

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ANSWER :0.35
16.

y = sin^(-1) x + sin^(-1)sqrt(1 - x^2), 0 lt x lt 1 find (dy)/(dx).

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ANSWER :`0`
17.

If a line y = x touches the curve y=x^(2)+bx+c at (1, 1) then ………..

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B=1, c = 2
`b=-1, c=1`
b = 1, c = 1
b = 0, c = 1

ANSWER :B
18.

{:(,"Column-I",,"Column-II"),((A),BCl_(3),(P),3C -4e^(-)"bond is present in dimer"),((B),BeCl_(2),(Q),"Planar"),((C),PCl_(3),(R),"Change in hybridisation of the central atom during dimerisation"),((D),AsCl_(3),(S),"Tautomerism is observed during final product formation in hydrolysis process"),(,,(T),"Basicty of one of the hydrolysed product is three"):}

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Solution :(A) `BCl_(3)` does not dimerise, it is `sp^(2)` hybridised so planar on hydrolysis it gives `H_(3)BO_(3)` whose basicity is one.
(B) sp hybridised planar `BeCl_(2)` dimerise give `Be_(2)Cl_(4)` in which Be is `sp^(2)` hybridised and hydrolysis product is `Be(OH)_(2).`
(C ) `sp^(3)` hybridised `AsCl_(3)` is pyramidal in shape which gives `H_(3)AsO_(3)` which does not show tautomerism due to large size of As and basicity of`H_(3)AsO_(3)` is THREE. ]
19.

Find the order of the differential equation corresponding to (i) y = c(x-c)^(2) where c is an arbitrary constant. (ii) y = Ae^(x) + Be^(3x) + Ce^(5x) where A, B, C are arbitrary constant. (iii) xy = c e^(x) + b e^(-x) + x^(2) where b, c are arbitrary constants. (iv) The family of all circles in the xy-plane with centre at the origin.

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Answer :(i) Since there is only one arbitrary constant, the order is 1
(ii) since there are 3 independent arbitrary constants order 3.
(iii) Since there are 2 independent arbitrary constants order 2.
(IV) `X^(2) + y^(2) = a^(2)`, a is a PARAMETER has only one arbitrary constant, order 1.
20.

Let a and b natural numbers such that 2a - b, a - 2b and a + b are all distinct squares. What is the smallest possible value of b ?

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ANSWER :21
21.

Let A and B be two matrices different from identify matrix such that AB=BA and A^(n)-B^(n) is invertible for some positive integer 'n'. IfA^(n)-B^(n)=A^(n+1)-B^(n+1)=A^(n+2)-B^(n+2), then

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I-A is non singular
I-B is non singular
I-A is singular
I-B is singular

SOLUTION :`A^(n+2)-B^(n+2)=(A+B)(A^(n+1)-B^(n+1))-AB(A^(n)-B^(n))`
`impliesA^(n)-B^(n)=(A+B)(A^(n)-B^(n))-AB(A^(n)-B^(n))`
`impliesI=A+B-AB""[becauseA^(n)-B^(n)"is invertible"]`
`implies(I-A)(I-B)=0`
As A, `B ne l`, we GET
I-A and I-B are singular matrices.
22.

(1 + x^(2))dy + 2xy dx = cot x dx (x ne 0)

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ANSWER :`y = (1 + x)^(-1) LOG |sin x|+ C(1 + x^(2))^(-1)`
23.

State with reason whether following functions have inverse : g:{5,6,7,8} rarr {1,2,3,4}with g:{(5,4),(6,3),(7,4),(8,2)}

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SOLUTION :N/A
24.

"If"f(x) ={underset(x^(2)+1.2 le x le 3)(2x+1.1 le x le 2), then evaluate int_(1)^(3) f(x) dx.

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ANSWER :`(34)/(3)`
25.

If the mean of poisson distribution is 2.56 them find the standard deviation.

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ANSWER :1.6
26.

Solve as directed: 5x le 20 in positive integers, in integers.

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Solution :`5X LE 20`
`rArr (5x)/5 le (20)/5 rArr X le 4`
Ifis apositive INTEGER, then the solution set is {1,2,3,4}
If x is a integer,then the solution set is :
S = { x:x in Z and x `le` 4]
27.

Two planes barr_1.barn_1=p_1" and "barr_2.barn_2=p_2 are parallel if

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`barn_1.barn_2=1`
`barn_1.barn_2=0`
`barn_1=lambda barn_2`
`barn_1-barn_2=0`

ANSWER :C
28.

The vertices of a rectangle are (-1, -2), (4,2), (4,3) and (-1,3). When the rantangle is graphed in the standard (x, y) coordinate plane below, what precent of the total area of the rectangle lies in Quadrant III?

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0.08
0.12
0.125
0.32

Answer :A
29.

Find the area of the region bounded by the line y = 3x +2, the x-axis and the ordinates x = -1 and x = 1.

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ANSWER :`(13)/3`
30.

By using the properties of definite integrals, evaluate the integrals int_(0)^(pi)(xdx)/(1+sinx)

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31.

Solve cosx+cos3x-2cos2x=0

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32.

If y = tan^(-1) x, provethat (1 + x^2)y_2 + 2xy_1 = 0

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SOLUTION :`y = TAN^(-1) IMPLIES y_1 = 1/(1 + x^2)
implies (1 + x^2)y_1 = 1
implies (1 + x^2)y_2 + 2xy_1 = 0`
33.

The points of intersection of the perpendicular tangents drawn to the ellipse 4x^(2) + 9y^(2) = 36 lie on the curve.

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`X^(2) + y^(2) = 13`
`x^(2) - y^(2) = 5`
`x + y = 5`
`(x^(2))/(9) + (y^(2))/(4) = 1`

ANSWER :A
34.

The most phagocytic WBC, are :-

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Neutrophill and MONOCYTES
Neutrophill and eosinophill
Lymphocytes and macrophages
Eosinophils and lymphocytes

Answer :A
35.

In the group (Z,*) if a ** b= a + b -n AA a, b in Z, where n is a fixed integer, then the inverse of (-n) is

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N
`-n`
`-3N`
`3n`

ANSWER :D
36.

If : int(2x^(2)+3)/((x^(2)-1)(x^(2)-4))dx=log[((x-2)/(x+))^(a).((x+1)/(x-1))^(b)]+c then : (a, b)-=

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`1/2, 3/4`
`-1, 3/2`
`1, 3/2`
`-1/2, 3/4`

ANSWER :A
37.

intx^(5)cos^(2)logsqrtxdx=

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`(x^(6))/(12)+(x^(6))/(74)(6coslogx+sinlogx)+c`
`(x^(6))/(12)-(x^(6))/(37)(6coslogx+sinlogx)+c`
`((x^(3)-1)(x^(3)+1))/(12)+(x^(6))/(37)(6coslogx+sinlogx)+c`
`((x^(3)-1)(x^(3)+1))/(12)+(x^(6))/(74)(6coslogx+sinlogx)+c`

ANSWER :A::D
38.

In the function f(x)= 2x^(3) + bx^(2) + qx satisfies conditions of Rolle's theorem in [-1, 1] and c= (1)/(2) then the value of 2b + q is…….

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0
1
`-(1)/(2)`
`-1`

ANSWER :D
39.

Optimization of the objective function is a process of

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MAXIMIZING the OBJECTIVE function
maximizing or MINIMIZING the objective function
minimizing the objective function
only minimizing the objective function

Answer :B
40.

Find the vectorequtionsof a linepassingthroughthe point(2,3,2)andparallelto theline vec(r )=(-2hat(i)+3hat(j) ) + lambda (2hat(i) - 3hat(j) + 6hat(k))Alsofind thedistancebetweentheselines .

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Solution : The givenline is`L_(1) : vec(r ) =(-2hat(i) +3hat(j)) + lambda (2hat(i) -3hat(j) +6hat(k))`
Therequired line is `L_(2) :vec( r)=(2hat(i) +3hat(j) +2hat(k))+ MU (2hat(i)-3hat(j) +6hat(k))`
Now, FIND thedistancebetweenthe PARALLELLINES `L_(1)" and" L_(2)`.
41.

Differentiate the functions given in Exercises 1 to 11 w.r.t. x. cos x. cos 2x. Cos 3x.

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ANSWER :`-COS x cos 2x cos 3x [tan x +2 tan 2x+3 tan 3x]`
42.

If f(x)=1+x^(2)+x^(4)+x^(6)+…..oo then int_(0)^(x)f(x)dx=

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`LOG(1-x)`
`log(1+x)`
`log((1+x)/(1-x))`
`(1)/(2)log((1+x)/(1-x))`

ANSWER :A
43.

Evaluate the following integrals inte^(x)((cosx-sinx)/(1-cos2x))dx

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ANSWER :`-(E^(X))/(2)cosec+C`
44.

Acoording to Newton's law of cooling, the body cools from 110^(@)C" to "60^(@)C at room temperature of 10^(@)C in 1 hour. The body coolsto 30^(@)C after another

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`(LOG5)/(LOG2)-1"HOURS"`
`(log5)/(log2)+1"hours"`
`(log5)/(log2)"hours"`
`(log2)/(log5)"hours"`

ANSWER :A
45.

Write the negation of each of the following statements and write equivalent statement after simplification. Justify each step : (1) p^^(qtor) (2) ~pvv(qto~r) (3) (~pvv~q)^^(p^^~q).

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ANSWER :(1) `~(qvvp)` (2) `~pvvq` (3) `~p^^Q` (4) `(p^^~q)VV(~r)`
(5) `~q^^(rvv~p)` (6) `(pvv~q)vv(~r)`
46.

Evaluate : (i) (dx)/(4cosx+3sinx) (ii) int(dx)/((2sinx+3cosx)^(2))

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SOLUTION :(i) Put `4=rsinthetaand3=rcostheta" so that"`
`r^(2)=25andtheta=TAN^(-1)((4)/(3))`.
`:.int(dx)/(4cosx+3sinx)=int(dx)/(rsinthetacosx+rcosthetasinx)`
`=(1)/(r)int(dx)/(sin(theta+X))=(1)/(r)int"cosec"(theta+x)dx`
`=(1)/(r)log{tan((theta+x)/(2))}+C`
`=(1)/(5)log{:[tan{(1)/(2)tan^(-1)((4)/(3))+(x)/(2)}]:}+C`.
(II) Put `2=rcosthetaand3=rsintheta" so that "r^(2)=13andtheta=tan^(-1)((3)/(2))`.
`becauseint(dx)/((2sinx+3cosx)^(2))=int(dx)/((rcosthetasinx+rsinthetacosx)^(2))`
`=(1)/(r^(2))int(dx)/(sin^(2)(theta+x))=(1)/(13)*int"cosec^(2)(theta+x)dx`
`=-(1)/(13)cot(theta+x)+C`
`=-(1)/(13)cot{tan^(-1)((3)/(2))+x}+C`.
47.

if the system of equations: {:(2x+3y-z=0),(3x+2y+kz=0),(4x+y+z=0):} have a set of non-zero integral solutions then , find the smallest positive value of z.

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ANSWER :5
48.

a xx (b xx c) =

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(a.B) C = (a.c) b
(a.c) b - (a.b) c
(c.a) b - (c.b) a
(c.b)a - (c.a) t

Answer :B
49.

Epress matrix A = [(1,2),(2,-1)] as the sum of a symmetric and skew-symmetric matrix.

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<P>

ANSWER :`P + Q = A`
50.

Leta_(1), a_(2), a_(3), ………be terms of an A.P. if (a_(1) + a_(2) + ...... a_(p))/(a_(1) + a_(2) + ...... a_(q))= p^(2)/q^(2),p != q, then a_(6)/a_(21) equals

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`41/11`
`7/2`
`2/7`
`11/41`

ANSWER :D