Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

If I_(1) = int_0^(1) 2^(x^(2)) dx, I_(2) = int_0^(1) 2^(x^(3)) dx, I_(3) = int_1^(2) 2^(x^(2)) dx, I_(4) = int_1^(2) 2^(x^(3)) dx then,

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`I_1 GT I_2`
`I_2 gt I_1`
`I_3 gt I_4`
`I_3 = I_4`

ANSWER :A
2.

Find the area between the curves y = x and y = x^(2).

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ANSWER :AREA = `1/6` SQ. UNITS
3.

Using elementary row transformations , find the inverse of each of the matrices , if it exists in example number . [{:(1,-1),(2,3):}]

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ANSWER :`=[{:((3)/(5),(1)/(5)),(-(2)/(5),(1)/(5)):}]`
4.

Evaluate : inte^x((1 + sin x)/(1+ cos x))dx

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ANSWER :`LOG|(tan""(x)/(2))/((tan""(x)/(2)-1)^(2))|+c//(1)/(4) log|(cos x - 1)/(cos x + 1)|+(1)/(2)((1)/(1+cos x))+ tan""(x)/(2)+c`
5.

Evaluate the following integrals (iv) int_(0)^(1)sqrt((1-x)/(1+x))dx

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ANSWER :`pi/2 -1`
6.

If A is square matrix such that A^(2) +I = O, then A equals:

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`[(1,0),(0,1)]`
`[(1,2),(-1,1)]`
`[(-1,0),(0,-i)] `
`[(i,0),(0,i)]`

ANSWER :D
7.

Consider a right angled triangle ABC right angled at C with integer sides. List-I gives inradius. List-II gives the number of triangles.

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<P>

ANSWER :`A to P; B to P; C to T; D to S`
8.

A random variable X has the following probability distribution Determine P(X

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<P>

SOLUTION :`P(Xlt3)`=P(X=0 or 1 or 2)
=P(X=0)+P(X=1)+P(X=2)
=P(0)+P(1)+P(2)
(`because` X=0, X=1 and X=2 are THREE mutually EXCLUSIVE CASES)
=0+k+2k=3k=3/13
9.

Method of integration by parts : inte^(3x)cos 4xdx=e^(3x)(A sin 4x+B cos4x)+c then.....

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`4A=3B`
`2A=3B`
`3A=4B`
`4A+3B=1`

ANSWER :D
10.

Determine the inverse function and its domain of definition, if (a) y=tan hx, ""(b) y={{:(,x,"if "-oo lt x lt 1),(,x^(2),"if "1 le x le 4),(,2^(x), "if "4 lt x lt oo):}.

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ANSWER :(a) `X=1/2 ln (1+y)/(1-y) (-1 lt y lt 1);`
(B) `x={{:(,y,"for "-oo lt y lt 1),(,log_(2)" for "16 lt y lt oo):}`
11.

Three boxes B_(1), B_(2), B_(3) contain with different colours as shown below. {:(,"White","black","red"),(B_(1),2,1,2),(B_(2),3,2,4),(B_(3),4,3,2):} A die is thrown. B_(1) is chosen if either 1 or 2 turns up. B_(2) is chosen if 3 or 4 turns up and B_(3) is chosen if 5 or 6 turns up. Having chosen a box in this way, a ball is chosen at random from this box. If the ball found to be red, find the probability that it is drawn from box B_(2).

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ANSWER :`(5)/(12)`
12.

If the area of the triangle formed by the points z, z+iz and iz is 50 square units, then |z| is equal to

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`5`
`8`
`10`
`12`

ANSWER :C
13.

The plane 3x+4y+6z+7=0 is rotated about the line r=(hati+2hatj-3hatk)+t(2hati-3hatj+hatk) until the plane passes through origin. The equation of the plane is the new position is

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`x+y+z=0`
`6x+3y-4z=0`
`4x-5y-2z=0`
`x+2y+4z=0`

ANSWER :A
14.

int Cos^(-1)(2x^(2)-1)dx=

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`2(X SIN^(-1) x + SQRT(1 - x^(2))) + c `
`2 (x cos^(-1) x + sqrt(1 - x^(2))) + c `
`2 (x cos^(-1) x -sqrt(1 -x^(2)) )+ c`
`2 (x sin^(-1) x - sqrt(1 -x^(2)) )+ c `

Answer :C
15.

Energy levels A, B and C of a certain atoms correspond to increasingvalues of energy, i.e. E_(A)lt E_(B)ltE_(c). If lambda_(1),lambda_(2), lambda_(3) are the wavelengths ofradiation correspondingto the transitions C rarr B, B rarrA and C rarr A respectively, then :

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`lambda_(1)=lambda_(2)=lambda_(3)`
`lambda_(3)=(lambda_(1)lambda_(2))/(lambda_(1)+lambda_(2))`
`lambda_(3)^(2)=lambda_(1)^(2)+lambda_(2)^(2)`
NONE of these

Solution :`E_(CB)+E_(BA)=E_(CA)RARR(1)/(lambda_(1))+(1)/(lambda_(2))=(1)/(lambda_(3))`
16.

If the planes x = cy + bz, y =az+cx and z = bx + ay pass througha line then

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`a^(2)+B^(2)+C^(2)+2ABC=0`
`a^(2)+b^(2)+c^(2)+2abc=1`
`a^(2)+b^(2)+c^(2)=2abc`
a+b+c=abc

Answer :B
17.

If A is a 3xx3 matrix and absA=2, then which matrix is represented by Axx adjA?

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SOLUTION :We have
`AXX adjA=(Axx adjA)/(ABSA) XX absA`
=`AxxA^-1xx2(because absA=2)`
=`2I=2[[1,0,0],[0,1,0],[0,0,1]]=[[2,0,0],[0,2,0],[0,0,2]]`
where `I=[[1,0,0],[0,1,0],[0,0,1]]`
18.

If f(x)= {(ax+b,1le x lt 5),(7x-5,5 le x lt 10),(bx + 3a,x ge 10):} is continuous, (a,b)= ……...

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(5, 10)
(5,5)
(10, 5)
(0, 0)

ANSWER :B
19.

Let f(x) ={{:( xe^(x), xle0),( x+x^(2)-x^(3), xgt0):} thenthe correctstatement is

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F iscontinuousand differentiablefor ALLX,
f iscontinuousbut notdifferentiable ATA x=0
f iscontinuousand DIFFERENTIABLE for all x.
f ' is continuousbutnot differentiableat x=0.

Answer :A::C
20.

Let P(x) =ax^(7) + bx^(3) +cx-5, where a,b,c are constants. Given P(-7) =7, find the value of P(7).

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ANSWER :`-17`
21.

Show that the points of intersection of the perpendicular tangets to an ellipse lie on a circle.

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ANSWER :`x^2+y^2=a^2+b^2`
22.

If lim_(xto)(f(x))/(x^(2))=k then lim_(xto1)f(x)=

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0
1
k
not defined

Answer :C
23.

If A is 3 × 4 matrix and B is 4 × 3 matrix,then the order of AB is

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`3 × 4`
`4 × 3`
`4 × 4`
`3 × 3`

ANSWER :D
24.

Let a function f(x), x ne 0 be such that f(x)+f((1)/(x))=f(x)*f((1)/(x))" then " f(x) can be

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`1-X^(2013)`
`sqrt(|x|)+1`
`(pi)/(2tan^(-1)|x|)`
`(2)/(1+k" In "|x|)`

SOLUTION :`(f((1)/(x))-1)=(1)/((f(x)-1))i.e., (f((1)/(x))-1)`
is reciprocal of `(f(x)-1).`
Now, for `f(x)=((pi)/(2))/(tan^(-1)|x|)`
`f(x)-1=(cot^(-1)|x|)/(tan^(-1)|x|),f((1)/(x))-1=(tan^(-1)|x|)/(cot^(-1)|x|)`
ALSO for `f(x)=(2)/(1+k" In " |x|)`
`f(x)-1=(1-k" In " |x|)/(1+k" In " |x|),f((1)/(x))-1=(1+k" In "|x|)/(1-k " In "|x|)`
25.

Write the component statement "Every parallelogram is a trapezium or a rhombus" compound statements and check whether the compound statement is true or false.

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SOLUTION :The component STATEMENTS are
p :Every PARALLELOGRAM is a trapezium
q : Every parallelogram is a RHOMBUS . The truth value of the compound statement is "false"
26.

Match the following {:(I.,"Centroid of the triangle formed by (2,3,-1),(5,6,3),(2,-3,1)" ,"a)(1,1,0)"),(II.,"Circumcentre of the triangle formed by (1,2,3),(2,3,1),(3,1,2)","b) (3,1,4)"),(III.,"Orthocentre of the triangle formed by (2,1,5),(3,2,3),(4,0,4)","c)(2,2,2)"),(IV.,"Incentre of the triangle formed by (0,0,0),(3,0,0),(0,4,0)","d)(3,2,1)"):}

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d, a , B ,C
a,b,c,d
d,c,b,a
a,c,d,b

Answer :C
27.

If barc=3bara-2barb, then prove that [bara barb barc]0

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Solution :Given `""vecc=3veca-2vecb`
`therefore""[vec a vec B vec c]=veca . (vecb xx vec)`
`=veca . [vecb xx (3 veca xx2vecb)]`
`=veca. (3 vecb xx veca - 2 vecb xx vecb)`
`=veca.(3VECB xx vec a -0)`
`(because vecb xx vec b=0)`
`=3xx0=0"Hence PROVED"`
28.

If x is so small, higher powers of x may be neglected then sqrt(x^2 + 25)-sqrt(x^2 +9)=

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`2-(x^2)/(15)`
`3+(x^2)/(15)`
`3-(x^2)/(15)`
`2+(x^2)/(15)`

ANSWER :A
29.

Evaluate : int_((pi)/(4))^((3pi)/(4))(x)/(1+sinx)dx

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ANSWER :`PI (SQRT(2)-1)`
30.

Find the particular solution of the following differential equaitonx(x^(2) - 1)(dy)/(dx) = 1, y = 0 when x = 2.

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Answer :`y = 1/(2) LOG (x^(2) - 1)/(x^(2)) -(1)/(2) log(3)/(4)`
31.

Examine the consistency of the system of linear equtions in 1 to 6 x+y+z=1 2x+3y+2z=2 ax+ay+2az=4

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ANSWER :`ANE0`
32.

A line makes equal angles with coordinate axes. Direction cosines of this line are :

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`PM LT 1, 1,1 gt`
`pm lt 1/SQRT3, 1/sqrt3 , 1/sqrt3 gt`
`pm lt 1/3, 1/3, 1/3, gt`
`pm lt 1/sqrt3 , -1/sqrt3, (-1)/sqrt3 gt `

Answer :B
33.

Find | veca| , if ( veca - hatp ) . (veca +hatp ) = 15

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ANSWER :` |VEC a | =4`
34.

The plane containing the line (x-1)/(1) =(y-2)/( 2) =(z-3)/(3)and parallel to the line(x)/(1) =(y)/(1) =(z)/(4)passes through the point

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`(1,-2,5) `
` (1,0,5)`
` ( 0, 3,-5)`
` ( -1,-3,0)`

Answer :B
35.

Find an equation of the line of shortest distance between the lines r=lambda(i-j+k)andr=(i-j)+mu(-2j+k) In the vectorial notation and Cartesian notation. Also find the shortest distance between them.

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ANSWER :`(2)/(SQRT(6))`
36.

f(x)=|x| is increasing in

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`(-OO,oo)`
`(-oo,0)`
`(0,oo)`
`(-oo,-1)`

ANSWER :C
37.

The points representing the complex number z for which arg((z-2)/(z+2)=pi/3 lie on

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A circle
A STRAIGHT line
An ellipse
A parabola

Answer :A
38.

Co - ordinates of the foot of the perpendicular from the point (a,b,c) on the Z - axis are

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`(a,B,0)`
`(0,0,C)`
`(a,0,0)`
`(0,b,0)`

ANSWER :b
39.

Let bara, barb, barc be three non-coplanar vectors and barr be any vector in space such that barr.bara=1,barr.barb=2 and barr.barc=3 If [barabarb barc]=1, then : barr=

Answer»

`bara+2barb+3barc`
`(barbxxbarc)+2(barcxxbara)+3(BARAXXBARB)`
`(barb.barc)bara+2(barc.bara)barb+3(bara.barb)barc`
none of these

Answer :B
40.

If alpha is non real root of x^(6)=1, then (alpha^(5)+alpha^(3)+alpha+1)/(alpha^(2)+1) is equal to

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`ALPHA^(2)`
0
`-alpha^(2)`
`alpha`

ANSWER :C
41.

If f(1) = 1, f(n+1)= 2f (n) + 1, n ge 1then f(n) = .........

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`2^(N)+1`
`2^n`
`2^(n)-1`
`2^(n-1)-1`

SOLUTION :N/A
42.

(Allocation problem) A cooperative society of farmers has 50 hectare of land to grow two crops X and Y. The profit from crops X and Y per hectare are estimated as rs. 10,500 and Rs. 9,000 respectively. To control weeds, a liquid herbicide has to be used forcrops X and Y at rates of 20 litres and 10 litres pre hectare. Further, no more than 800 litres of herbicide should be used in order to protect fish and wild life using a pond which collects drainage from this land. How much land should be allocated to each crop so as to maximise the total profit of the society?

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ANSWER :30 HECTARES for CROP X and 20 hectares for crop Y.
43.

Show that number of equivalence relation in the set {1,2,2} containing (1,2) and (2,1) is two.

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ANSWER :`R _(1)`
44.

int_(0)^(2) [x^(2)-1]dx=

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`4-SQRT(3)-sqrt(2)`
`4+sqrt(3)+sqrt(2)`
`sqrt(3)-1`
`sqrt(2)+1`

ANSWER :A
45.

If 1 + (1 + 2)/2 + (1 + 2 + 3)/3 + ...... to n terms is s, then s is equal to

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`(n(n + 3))/4`
`(n(n + 2))/4`
`(n(n + 1)(n + 2))/6`
`n^(2)`

ANSWER :A
46.

Find two number whose sum 24 and whose product is as large as possible.

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ANSWER :12 and 12
47.

If f (x) = u//v then f '' (x) =

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`(1)/(V^(3))`
`(1)/(v ^(3)) |{:(v ,0, U),(v _(1) , v , u _(1)),( v _(2) , 2 v _(1), u _(2)):}|`
`v ^(3)`
none

ANSWER :B
48.

Sum of the series P=(1)/(2sqrt(1)+sqrt(2))+(1)/(3sqrt(2)+2sqrt(3))+.........+(1)/(100sqrt(99)+99sqrt(100)) is

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`(1)/(10)`
`(3)/(10)`
`(9)/(10)`
`(1)/(2)`

Solution :Put `y=x+(3+5)/(2)=x+4`
The EQUATION becomes
`(y-1)^(4)+(y+1)^(4)=16`
`implies2{y^(4)+6y^(2)+1}=16 ""implies""y^(4)+6y^(2)-7=0`
`implies (y^(2)+7)(y^(2)-1)=0""implies " "y^(2)=-7" or "y^(2)=1`
`implies y=pmsqrt(7i)" or "y= pm1 ""implies ""x=-4pmsqrt(7i) " or " x=-4pm1=-5" or"-3`.
Thus, the given equation has TWO real roots.
49.

The roots of the equation 8x^(2)+22x+5=0 are thetaandphi. Then

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(a) `sin^(-1)thetaandsin^(-1)phi`, both the REAL
(b) `SEC^(-1)thetaandsec^(-1)phi`, both the real
(c) `tan^(-1)thetaandtan^(-1)phi`, both the real
(d) NONE of these

Answer :C
50.

If A=[{:(2,lambda,-3),(0,2,5),(1,1,3):}], then A^(-1) exists if"............"

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`LAMBDA=2`
`lambda NE 2`
`lambda ne -2`
NONE of these

ANSWER :D