Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Let S be the set of all real values of a for which the following system of linear equations : ax+2y+5z=1 2x+y+3z=1 3y +7z=1 is consistent . Then the set S is

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an empty set
equal to R
equal to R - {1}
equal to {1}

ANSWER :B
2.

Let alpha and beta be the roots of x^2-x-1=0, with alpha gt beta. For all positive integers n, define a_n=(alpha^n=beta^n)/(alpha-beta),nge 1. b_1=1 and b_b=a_(n-1)+a_n+1,n ge 2 Then which of the following options is/are correct ?

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`sum_(n=1)^(oo)(b_n)/(10^n)=(8)/(89)`
`b_n=ALPHA^n+beta^n " for all " n ge 1`
`a_1+a_2+a_3+.......+a_n=a_(n+2)-1" for all " n ge 1`
`sum_(n=1)^(oo)(a_n)/(10^n)=(10)/(89)`

Solution :Given quadratic EQUATION `x^2-x-1=0` having roots `alpha` and `beta,(alpha gt beta)`
So, `alpha=(1+sqrt(5))/(2)and beta =(1-sqrt(5))/(2)`
and `alpha +beta =1,alpha beta =-1`
`because a_n=(a^n-beta^n)/(alpha-beta),n ge1`
So,
`a_(n+1)=((alpha^n+1)-beta^(n+1))/(alpha-beta)=alpha^n+alpha^n-1beta+alpha^n-2beta+.......ALPHABETA^(n-1)+beta^(n)`
` =alpha^n-alpha^n-1-alpha^n-3beta......-beta ^n-2+beta^n`
`=alpha^n+beta^n-(alpha^n-1+alpha^n-3beta+....+beta^n-2)`
`=alpha^n+beta^n-a_(n-1)`
`[as a_(n-1)=(alph^n-1 -beta^n-1)/(alpha-beta)=alpha^n-2+alpha^n-3beta+....beta^n-2]`
`impliesalpha_(n+1)+alpha_(n-1)=alpha^(n)+beta^(n)=b_(n),AAnge1`
So,option (B) is incorrect
Now `Sigma_(n=1)^(oo) (b_n)/(10^n)=Sigma_(n=1)^(oo) (a^n+b^n)/(10^n)`
` =Sigma_(n=1)^(oo) ((alpha)/(10))^n+Sigma_(n=1)^(oo) ((beta)/(10))^n [because |(alpha)/(10)|lt 1 and |(beta)/(10)| lt 1 and |(beta)/(10)lt 1|`
` =((alpha)/(10))/(10(alpha)/(10))+((beta)/(10))/(1-(beta)/(10))=(alpha)/(10-alpha)+(beta)/(1-beta)`
` =(10alpha-alpha beta +10beta-alpha beta)/((10-alpha)(10-beta))=(10(alpha+beta)-2alphabeta)/(100-10(alpha+beta)+alpha beta)`
`=(10(1)-2(-1))/(100-100(1)-1)`
`=(12)/(89)`
So, option (a) is not correct.
`because alpha^2=alpha +1 and beta^2=beta+1`
`rArr alpha^n+1=alpha^n+1+alpha^n and beta^n+2=beta^n+1+beta^n`.
`rArr (alpha^n+2+beta^n+2)=(alpha^n+1+beta^n+1)+(alpha^n+beta^n)`
`rArr a_(n+1)=a_(n+1)+a_n`
SIMILARLY `a_(n+1)=a_n+a_n-1`
`a_n=a_n-1+a_(n-2)`
`.............`
`...................`
On adding , we get
`a_(n+2)=(a_n+a_n-1+a_n-2+....+a_2+a_1)+a_2`
`[because a_2=(alpha^2-beta^2)/(alpha-beta)=alpha+beta=1]`
So, ` a_n+2-1=a_1=a_1+a_2+a_3+......+a_n`
So, option (c) is aslo correct.
And, now `Sigma_(n =1)^(oo) (a_n)/(10^n)=Sigma_(n=1)^(oo) (alpha^n-beta^n)/((alpha-beta) 10^n)`
` =(1)/(alpha-beta)[Sigma _(n=1)^(oo) ((alpha)/(10))^n-Sigma _(n=1)^(oo) ((beta)/(10))^n]`
` =(1)/(alpha-beta) [((alpha)/(10))/(1-(alpha)/(10))-((beta)/(10))/(1-(beta)/(10))],[as |(alpha)/(10)|lt 1 and |(beta)/(10)|lt 1]`
`=(1)/(alpha-beta) ((alpha)/(10-alpha)-(beta)/(10-beta))=(1)/(alpha-beta)[(10alpha-alphabeta-10beta+alpha beta)/(100-10(alpha +beta)+alpha beta)]`
` =(10(alpha -beta))/((alpha -beta)[100-10(alpha+beta )+alpha beta])=(10)/(100-10-1)=(10)/(89)`
Hence options, (b),(c) and (d) are correct.
3.

If x=1/2 then (1-2x)/(1-x+x^(2))+ (2x-4x^(3))/(1-x+x^(4)) + (4x^(3)-8x^(7))/(1-x^(4)+x^(6))+.....infty is

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1
`8/7`
`4/7`
`7/16`

ANSWER :B
4.

Which of the following is a statement in logic?

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what a great fall it is !
Please MIND your own business.
Let us GO for a walk.
The quadratic EQUATION `x^2` -3X + 2 = 0 has two REAL roots.

Answer :D
5.

Evaluate the following integrals. (1)/(2x^(2)+3x-(11)/(4))dx

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Answer :`(1)/(SQRT(31))log|(4x+3-sqrt(31))/(4x+3+sqrt(31))|+C`
6.

If alpha, beta and gamma are direction cosines of the vector vec(x) then 1+cos2alpha+cos 2beta+cos 2lambda= …………..

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0
1
`-1`
2

Answer :A
7.

int3^xdx

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SOLUTION :`int3^xdx=3^x/(IN3) +C`
8.

How many 4 letter words can be formed using the letters of the word ARTICLEsuch that the word contains A but not E

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ANSWER :240
9.

Ifthe equation fo two circles whose radii are a, a ' areS = 0 and S^' = 0, then show that circles S/a + (S^')/(a^') = 0 and S/a - (S^')/(a') = 0 intersect orthogonally.

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ANSWER :`= (d^2 - AA') + (d^2 + aa') = 2d^2`
10.

If the sum of the coefficients in the expansion of (1 -3x + 10x^2)^(n) is a and the sum of the coefficients in the expansion of (1 - x^(2))^(n) is b, then

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`a = 3B`
`B = a^(3)`
`a = b^(3)`
`a = b`

ANSWER :C
11.

Formthe differentialequationof family ofcurcesy= ae^(2x) +be^(-2x)by eliminatingthe arbitaryconstantsa & b.

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ANSWER :`THEREFORE(d^2 y)/(DX^2)- (DY)/(dx) - 6y =0`
12.

Find the area of the surface formed by revolving the astroid x^(2//3) + y^(2//3) = a^(2//3) about the x-axis

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ANSWER :`(12)/(5) PI a^(2)`
13.

intsin( logx) dx=………+c

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`X/2[ COS( logx) - SIN( log x )]`
`x/2[ sin(logx) + cos( logx)]`
`x/2[ sin (log x)- cos ( log x)]`
`x[ sin (logx)- cos(log x)]`

Answer :C
14.

If vec(a) is vector perpendicular to both vec(b) and vec(c ), then

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`VEC(a)+(vec(B)+vec(c ))=vec(0)`
`vec(a)xx(vec(b)+vec(c ))=vec(0)`
`vec(a)xx(vec(b)xx vec(c ))=vec(0)`
`vec(a).(vec(b)xx vec(c ))=vec(0)`

ANSWER :C
15.

Does a^(2)+a^(4)+a^(6) for all value of a?

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ANSWER :No
16.

The two lines x=ay+b,z=cy+d and x=a'y+b', z=c'y +d' are pendicular to each other if

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`AA' + ALPHA =1`
`(a)/( a') + (C )/( c') = -1`
`(a)/( a') + ( c )/( c') =1`
`aa'+ c c'=-1`

ANSWER :D
17.

If z_(1)=2+3i, z_(2)=3-2i and z_(3)=-1-2sqrt3i, then which of the following is true? (where, i^(2)=-1)

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`ARG((z_(2))/(z_(3)))=arg((z_(2)-z_(1))/(z_(3)-z_(1)))`
`arg((z_(2))/(z_(3)))=arg((z_(3))/(z_(1)))`
`(1)/(2)arg((z_(2))/(z_(3)))=arg((z_(2)-z_(1))/(z_(3)-z_(1)))`
`2arg((z_(3))/(z_(2)))=arg((z_(3)-z_(1))/(z_(2)-z_(1)))`

ANSWER :C
18.

Write the differential equation whose general solution is y=ce^(2x)

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SOLUTION :Given equation is `y=ce^(2x)rArrdy/dx=2ce^(2x)=2Y`THEREFORE The required DIFFERENTIAL equationis `dy/dx-2y=0`
19.

int_(0)^(pi//2) e^(x) (cos x - sin x ) dx =

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1
-1
0
`1/2`

ANSWER :B
20.

Find the number of words with or without meaning which can be made using all letters of the word 'AGAIN'. If these words are written as in a dictionary, what will be the 50^(th) word?

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ANSWER :48
21.

If (-1/3-1) is a centre of similitude for the circles x^(2)+y^(2)=1 and x^(2)+y^(2)_2x-6y-6=0 then the length of common tangent of the circles is

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`1/3`
`4/3`
`1`
cannot be determined

Answer :C
22.

Find the second order derivatives of the functions tan^(-1)x

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ANSWER :`(-2X)/((1 + X^(2))^(2))`
23.

Let X be a random varibale such that P(X = -2) = P(X = -1) = P(X = 2) = P(X = 1) = (1)/(6) and P(X = 0) = (1)/(3).

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ANSWER :`0, (5)/(3)`
24.

Write the locusof a point p which moves in space such that its distance from origin is 4 units.

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SOLUTION :The CENTROID is `((1+2+3)/3,(2+1+0)/3,(3+2+1)/3)=(2,12)`
25.

Which of the following is not correct combination?

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ANSWER :D
26.

From the origin chords are drawn to the circle (x-1)^(2)+y^(2)=1 then equation of locus of mid ponts of these chords is

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`X^(2)+y^(2)+x=0`
`x^(2)+y^(2)-x=0`
`x^(2)+y^(2)-2x=0`
`x^(2)+y^(2)-2x-2y=0`

ANSWER :B
27.

Find the Binomial probability distribution whose mean is 3 red veriance is 2 .

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`((2)/(3)+ (1)/(3))^(9)`
`((5)/(3) + (2)/(3))^(9)`
`((3)/(2) + (1)/(2))^(9)`
None of these

ANSWER :A
28.

If a^(logb^c)=3.3^(log4^3) .3^((log 4^3)^(log 4^3)).3^((log4^3)^((log4^3)^log4^3))...oo where a,b,cin Q the value of abc is -+

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9
12
16
20

Answer :C
29.

Sum of coefficients of terms of odd powers of x in (1 - x + x^2 - x^3)^9 is

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`-2^17`
`2^17`
`2^13`
`2^12`

ANSWER :A
30.

Find the equation of a curve passing through the point (0,1).Ifthe slope of the tangent to the curve at any point (x,y) is equal to the sum of the xcoordinate(abscissa) and the product of the x coordinate and y coordinate (ordinate) of that point.

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ANSWER :`y = -1 + 2E^((X^(2))/(2))`
31.

If the equatio of one tangent to the circle with centre (2,-1) from the origin is 3x+y=0, then the equation of the other tangent through the origin is

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`3x-y=0`
`x+3y=0`
`x-3y=0`
`x+2y=0`

ANSWER :C
32.

If A is any square matrix of order 3x3 such that absA=3, then the value of abs(adjA)

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3
(1/3)
9
27

Answer :C
33.

Using the result of the preceding problem obtain the following formula : 1 - (C_(n)^(1))/(3) + (C_(n)^(2))/(5) - (C_(n)^(3))/(7) + . . . . . + (-1)^(n) (C_(n)^(n))/(2 n + 1) = ((2n)!!)/((2n + 1)!!),where C_(n)^(k)are binomial coefficients.

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ANSWER :1 we GET
34.

A player tosses two coins. Hewins Rs. 1 if 1 head appears, Rs 2 if 2 heads appear. But he lose Rs 5 if no head appears. The mean of the prized money is

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`(1)/(2)`
`(1)/(4)`
`-(1)/(4)`
`(1)/(5)`

Answer :C
35.

A ladder 5 cm long is leaning against a wall. The bottom of the ladder is pulled along the ground, away from the wall, at the rate of 2cm/s. How fast is its height on the wall decreasing when the foot of the ladder is 4 cm away from the wall ?

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ANSWER :`(8)/(3)` CM /s
36.

If f and g are defined on [0, oo) by f(x) = underset(n rarr oo)(lim) (x^(n)-1)/(x^(n)+1) and g(x) = int_(0)^(x) f(t) dt. Then

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G has local MAXIMUM at x=1
g has local minimum at x=1
g is an INCREASING function on `(0, oo)`
g is a DECREASING function on `(0,oo)`

Answer :B
37.

Equation of plane equidistant form planes 3x+4y+5z-6=0 and 3x+4y+5z+6=0 is

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3x+4y+5z=0
3x+4y+5z=3
3x+4y+5z=12
4x+5y+3z=0

Answer :A
38.

In a class 30% of the student fail in Mathematics,20% of the student fail in English and 10% fail in both.What is the probability that he has failed in both ?

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<P>

SOLUTION :Probability that he has FAILED in both
`i.e.,P(A cap B)=10/100=1/10`
39.

Prove the tan75^@ + cot75^@ = 4

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SOLUTION :L.H.S `tan75^@+cot75^@=tan75^@+(1)/(tan75^@) = (tan^2 75^@+1)/(tan75^@) = (2)/(((2tan75^@)/(1+tan^2 75^@)))= (2)/sin(2xx75^@) = (2)/sin150^@ = (2)/(((1)/2) = 4` R.H.S.
40.

Find the projection of the vector hati-hatj on the vector hati+hatj.

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ANSWER :VECTOR `VEC(a)` on the vector `vec(B)` is ZERO.
41.

Show that A'A and A A ' are both symmetric matrices for any matrix A .

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ANSWER :`thereforeA*A`'
42.

Differentiate x^8+x^7

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SOLUTION :LET `y=x^8+x^7`
Then `dy/dx=8x^7+7x^6`
43.

If (3sqrt(3)+5)^(2n+1)=x" and "f=x-[x] where ([x] is the integral part of x), find the value of x.f.

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ANSWER :`:." XF"=2^(2n+1)`
44.

If P(A) = 0.8, P(B) = 0.5 and P(B/A)= 0.4, find P (A/B)

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<P>

SOLUTION :P(A/B)=(P`(ANNB))/(P(B))` =0.32/0.5
=32/50=16/25=0.64
45.

If a ne b, x ne n pi n in Z and y^(2) = a^(2) cos^(2) x +b^(2) sin^(2)x, " then " (d^(2)y)/(dx^(2))+y =

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`((ab)/(y))^(2)`
`(1)/(y)((ab)/(y))^(2)`
`((ab)^(2))/(y)`
`(ab)/(y^(3))`

Answer :B
46.

There are 3 bags, each containing 5 white and 3 black balls. Also, there are 2 bags, each containing 2 white and 4 black balls. A white ball is drawn at random. Find the proqability that this ball is from a bag of the first group.

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<P>

Solution :Let `E_1` = event of selecting a bag from the first GROUP, and
`E_2` = event of selecting a bag from the SECON group.
Then, `P(E_1)=3/5 and P(E_2)=2/5`
Let E = event that the ball drawn is WHITE. Then,
`P(E//E_1)=5/8,P(E//E_2)=2/6=1/3`.
`:. P(E_1//E)=(P(E//E_1).P(E_1))/(P(E//E_1).P(E_1)+P(E//E_2).P(E_2))`
47.

A = ({:(1),(2),(3):}),"find " A * A^(T)

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ANSWER :`[(1,2,3),(2,4,6),(3,6,9)]`
48.

Integrate the following functions 1/sqrt(9-25x^2)

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Solution :`INT 1/sqrt(9-25x^2)DX = int 1/sqrt(3^2-(5x)^2) dx`
=`1/5 sin^-1 ((5x)/3)+C`
49.

Iff(theta)=sum_(n=1)^(6)cos ec(theta+((n-1)pi)/(4))cos ec(theta+(npi)/(4)), where 0ltthetalt(pi)/(2), then find the minimum valueof f(theta).

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ANSWER :`2sqrt(2)`
50.

Assertion(A) : if x^4 -x^3 -6x^2 +4x +8=0hasamultiplerootthentheequationhavingthesamerootis4x^3-3x^2- 12 x +4=0 Reason (R ):Ifalphais repeatedrootoff(x)=0thenalphaisalsoa rootoff ^1(x ) =0

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BOTHA and RaretrueR isthe correctexplanationof A
both AandRare TRUEAND RIS notcorrectexplanationof A
AIS trueand Risfalse
A isfalseand Ristrue

Answer :A