Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Differentiate w.r.t x the function ("cos"^(-1) (x)/(2))/(sqrt(2x + 7)) where -2 le x le 2

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Answer :`-[(cos^(-1) ((x)/(2)))/((2X+ 7)^((3)/(2))) + (1)/(SQRT(2x + 7) sqrt(4-x^(2)))]`
2.

Let a sequence x_(1),x_(2),x_(3),… of complex numbers be defined by x_(1)=0, x_(n+1)=x_(n)^(2)-i for alln gt 1, where i^(2)=-1. Find the distance of x_(2000) from x_(1997) in the complex plane.

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ANSWER :`SQRT(5)`
3.

How many numbers with no more than three digits can be formed using only the digits 1 through 7 with no digit used more than once in a given number?

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259
249
257
252

Answer :A
4.

Derive the equation of the plane in the intercept form.

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ANSWER :1
5.

Integration of some particular functions : int(dx)/(sqrt(x^(2)-2x+3))=...+c

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`(1)/(2)tan^(-1)((x-1)/(2))`
`tan^(-1)((x-1)/(2))`
`log|x-1+sqrt(x^(2)-2x+3)|+C`
`log|x-1-sqrt(x^(2)-2x+3)|+c`

ANSWER :C
6.

Find dy/dx if x^(3)+x^(2)y+xy^(2)+y^(3)=81

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ANSWER :`dy/dx=(-(3X^(2)+2xy+y^(2)))/((X^(2)+2xy+3y^(2)))`
7.

The surface area of a cube is decreasing at the rate of 15 sq. cm/sec. Find the rate length of the edge is 5 cm.

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SOLUTION :Let s be the surface area of a cube. Let X be the length of each side of the cube.
`then s = 6x^2 rArr ds/dt = 12x dx/dt`
Given that `ds/dt = 15 SQ. cm/sec. and x = 5 cm`.
Then - 15 = 12 xx 5 dx/dt`
`rArr dx/dt = - 15/60 = - 1/4 = -0 cdot 25 cm/sec`.
therefore The edge is decreasing at the rate of 0 cdot 25 cm/sec`.
8.

A land in the form of a circular sector has been fenced by wire of 40 metre length. The area of the land will be maximum whenthe radius of the circular sector (in metre) is-

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25
20
10
15

Answer :C
9.

Let a,b and c be three non-coplanar vectors. The vector equation of a line which passes through the point of intersection of two lines, one joining the points a+2b-5c, -a-2b-3c and the other joining the points -4c, 6a-4b+4c is

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`r=2a -4b+3c+mu(a-6b+4c)`
`r=3a+6b-c+mu(a+2b+c)`
`r=2a+3b-c+mu(a+B+c)`
`r=-2b+3c+mu(a-4b+3c)`

ANSWER :B
10.

Find X and Y if, X+Y=[(5,2),(0,9)] and X-Y=[(3,6),(0,-1)].

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ANSWER :`X=[(4,4),(0,4)]`
`Y=[(1,-2),(0,5)]`
11.

Sum the series (1)/(3.6) +(1.3)/(3.6.9) +(1.3.5)/(3.6.9.12)+…

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SOLUTION :N/A
12.

Determine whether the relation R in the set A = {1,2,3,…..13,14} defined as R = {(x, y):3x -y=0} is reflexive symmetric and transitive.

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Answer :(i) Neither reflexive nor symmetric nor transitive.
(ii) Neither reflexive nor symmetric but transitive.
(iii) Reflexive and transitive but not symmetric.
(iv) Reflexive, symmetric and transitive.
(V) (a) Reflexive, symmetric and transitive.
(B) Reflexive, symmetric and transitive.
(c ) Neither reflexive nor symmetric nor transitive.
(d) Neither reflexive nor symmetric but transitive.
(E) Neither reflexive nor symmetric nor transitive.
13.

Find the value of c for which A(2,0),B(0,14//3) ,C(4,5) and D(0,c)are concylic.

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ANSWER :`75/72`
14.

Silver has work function of 4.7 eV when ultraviolet light of wavelength 100 nm is incident upon it, a potential of 7.7 volt is required to stop the photoelectrons from reaching the collector plate. What will be the minimum de-Broglie wavelength of photoelectrons when the wavelength of incident radiations is increased by 100% ?

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3.3 Å
5.6 Å
10 Å
12.27 Å

Solution :`7.7 = E-4.7 implies E = 12.4 eV`
When the wavelength is increased by 100% then
energy of incident photon wil be `6.2 eV` then
`K_("max") = E - 4.7 = 6.2 - 4.7 = 1.5 eV`
`:. lambda_(dB) = SQRT((150)/(V)) = sqrt((150)/(1.5))` Å = 10 Å.
15.

If veca,vecb and vecc are three non-coplannar vectors, then prove that (|hataxx(hatbxxhatc)|)/sinA=(|hatbxx(hatcxxhata)|)/sinB=(|hatcxx(hataxxhatb)|)/sin C = (prod|hata xx(hatbxx hatc)|)/(|sum sinalpha cosbeta cosgamma hatn_(1)|)

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Solution :Since `veca,vecb and VECC` are non - coplanar, vectors `VECAXXVECB,vecb xxveccandveccxxveca` are also non-coplanar. Let
`vecd=l(vecbxxvecc)+vecm(veccxxveca)+vecn(vecaxxvecb)`
now multiplying both SIDES of (i) scalarly by `veca` we have
`veca.vecd=lveca.(vecbxxvecc)+mveca.(veccxxveca)+nveca.(vecaxxvecb)=l[vecavecc veca]([veca vecc veca]=0=[veca veca vecb])`
`l=(veca.vecd)//[veca vecb vecc]`
putting these values oif l,nm and n and (i) , we get the required RELATION.
16.

A = {x : cos x gt - 1//2, 0 le x le pi}, B = {x : sin x gt 1//2,pi//3 le x le pi} then

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`A cap B = [PI/3, (2PI)/3]`
`A cap B = [- pi/3, (2pi)/3]`
`A cup B = [- (5 pi)/6, (5PI)/6]`
none

Answer :A
17.

x^(2) e^(x)

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Solution :` " LET I=" int x^(2) E^(x) dx`
`I=x^(2) int e^(x) dx- int [(d)/(dx)(x^(2)) int e^(x) dx]dx`
`=x^(2)e^(x) -int (2xe^(2))dx`
` rArr I= x^(2) e^(x) -{ 2X int e^(x) dx-2 int [(d)/(dx)(x) int e^(x) dx ] dx }`
`=x^(2) e^(x) -2xe^(x) +2 int e^(x) dx`
`=x^(2)e^(x) -2xe^(x) +2E^(x) +C`
`rArr I=e^(x)(x^(2)-2x+2)+C`
18.

If a=hati-2hatj-3hatk, b=2hati+hatj-k,c=hati+3hatj-2hatk, then [(axxb)xx(bxxc)(bxxc)xx(cxxa)(cxxa)xx(axxb)]=

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160000
`-8000`
400
`-40`

ANSWER :A
19.

(d)/(dx)[cot^(-1)((cot^(-1)x-1)/(2cotx))]=

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2
1
`-1`
`-(1)/(2)`

ANSWER :A
20.

Equation of the parabola with focus (-4,0) and vertex at the origin is

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`y^2 = 16 x`
`y^2 = 16X = 0`
`x^2= 16Y`
`x^2 + 16y = 0`

Answer :B
21.

If (x+1)/((x-a)(x-3))=2/(x-a)+b/(x-3), " then "(a, b)=

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(7, -1)
(-4, 1)
(4, 1)
(-4, -1)

ANSWER :A
22.

Let M be a 2 × 2 symmetric matrix with integer entries. Them M is invertible if

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the first column of M is the transpose of the second row of M
the second row of M is the transpose of the first column of M
M is a diagonal matrix with NONZERO entries in the main diagonal
the product of entries in the main diagonal of M is not the SQUARE of an integer

Answer :C::D
23.

Find the middle term (s) in the expansion of((3)/(p^3) + 5p^4)^20

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ANSWER :`T_11 = ""^20C_10.3^10.5^10.p^10`
24.

A point P is taken on the right half of the hyperbola (x^(2))/(a^(2))-(y^(2))/(b^(2))=1 having its foci as S_1 and S_2. If the internal angle bisector of the angle angleS_1PS_2 cuts the x-axis at poin Q(alpha, 0) then range of alpha is

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`[-a, a]`
`[0, a]`
`[0, a]`
`[-a, 0]`

ANSWER :C
25.

Given that the regression equation of y on x is y = a + 1/(m)x, find the value of m when r = 0.5 , sigma_(x)^2=1/4sigma_(y)^2 .

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ANSWER :`m=1`
26.

IFalphaandbetaaretherootsof theequationax ^2+bx+c=0and theequationhavingroots(1-alpha)/( alpha ) and(1- beta )/( beta) ispx^2+qx +r=0thenr=

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`a+2b`
`ab+bc +CA`
`a+b+C`
`ABC`

ANSWER :C
27.

Solve the equation tan x + (cosx)/(sqrt(1+sin2x))=2.

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Solution :`X = npi + ALPHA`, where `n int Z` and `tan alpha = (1+-sqrt(5))/(2)`
28.

Compute the following: [[2,1],[3,2],[-1,1]] [[1,0,1],[-1,2,1]]

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SOLUTION :`[[2,1],[3,2],[-1,1]], [[1,0,1],[-1,2,1]]=[[2-1, 0+2, 2+1],[3-2, 0+4, 3+2],[-1-1, 0+2, -1+1]]=[[1,2,3],[1,4,5],[-2,2,0]]`
29.

Show thatRe(z_1z_2)=Rez_1Rez_2-Im z_1Imz_2Im(z_1z_2)=Re z_1 Im z_2+Re z_2 Im z_1

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SOLUTION :LET `z_1=a+ib,z_2=c+id`
`:. z_1z_2=(a+ib),(c+id)`
`=ac+iad+ibc+i^2bc`
`=(ac-bd)+i(ad+bc)`
`:."Re"(z_1z_2)=ac-bd="Re"z_1."Re"z_2-"IM" z_1."Im"z_2`
`"Again,Im"z_1z_2=ad+bc="Re" z_1."Im"z_2,"Re"z_2`
30.

On theset Z of allintegers , consider the relation R={(a,b):(a-b) is divisible by 3}. Show thatR isanequivalencerelationon Z. Also findthepartitioning of Z intomutuallydisjointequivalenceclasses .

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Solution :the relationR on Z satisfiesthe followingproperties :
(i) Reflexivity
Let ` a in Z`
then,`(a-a)=0,` whichisdivisibleby 3 .
`thereforea Ra AAa in Z.`
So,R isreflexive .(ii)SYMMETRY
Let` a ,bin Z` suchthat`a ,R,b` then
`a R bimplies(a-b) ` isdivisibleby 3
`implies -(a-b)` isdivisibleby 3
`implies (b-a) ` is divisible by 3
`impliesb R a .`
`thereforea R b impliesbRa AAa,bin Z .`
So,R issymmetric .
(iii)Transitivity
Leta,b,c `in Z ` such thata R bandb R c. then
`a R b,bRc implies (a-b)` isdivisibleby3 and(b-c)isdivisibleby 3
`implies [(a-b)+(b-c)] `isdivisibleby 3
`implies(a-c)` is DIVISIBLEBY 3.
thus,`a R b ,B R cimplies aR cAA a,b,cin Z.`
` therefore ` R isequivalencerelation on Z.
Now ,letusconsider [0],[1] and [2]
we have :
`[0]={x in Z : x R O }`
` ={x in Z: (x-0)` is divisibleby 3}
`={. . . . . .,-6,-3,0,3,6,9,. . . . }.`
`therefore [0] {. . . .,-6,-3,0,3,6,9,....}.`
Similarly ,`[1] ={x INZ: xR 1}`
`={x inz : (x-1) ` is divisibleby 3}
`={. . . . .,-5,-2,1,4,7,10,. . . . . .,}.`
and,`[2] ={x inZ: x R 2}.`
`={x in Z : (x-2)` is divisibleby3}
`={. . . ,-4,-1,2,5,8,11,. . .}.`
` therefore [2] ={. .. ..,-4,-1,2,5,8,11,. . . .}.`
CLEARLY[0] ,[1]and [2]aremutuallydisjoint
and`Z=[0] cup[1]cup [2].`
31.

Write the derivative of sin^-1x with respect to cos^-1x.

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SOLUTION :`(DU)/dx=1/SQRT(1-x^2)`and `(DV)/dx=(-1)/sqrt(1-x^2)` Thus `(du)/(dv)=(((du)/dx))/(((dv)/dx))=-1`
32.

A plane cutting the axes in P,Q,R passes through (alpha,beta,beta-lambda,lambda-alpha). If O is origin, then locus of center of sphere OPQR is

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`alphax+betay+lambdaz=4`
`(alpha-beta)X+(beta-lambda)y+(y-alpha)z=0`
`(alpha-beta)yz+(beta-y)zx+(lambda-alpha)xy=2xyz`
`(1/alpha^(2)+1/beta^(2)+1/lambda^(2))(x^(2+y^(2)+z^(2)))=XYZ`

ANSWER :C
33.

Integrate the following functions cotx log(sinx)

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Solution :Let t = log(sinx). Then
DT = 1/sinx cosx DX = cotxdx
THEREFORE `INT cotx log(sinx)dx = int t dt = t^2/2+c = [log(sinx)]^2/2 +c`
34.

If A+B+C=(3pi)/(2), prove that cos 2A+ cos 2B+ cos 2C=1-4 sin A sin B sin C .

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`1-4 SIN A sin B sin C `
`1-4 cos A cos B cos C `
`4 sin A sin B sin C `
`1+ 2 cos A cos B cos C `

ANSWER :A
35.

Evaluate the following integrals. int_(0)^(2)|x^(2)+2x-3|dx

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1
2
3
4

Answer :D
36.

The relation between pressure p and volume V is given by pV^(1/4)= constant. If the percentage decrease in volume is 1/2, then the percentage increase in pressure is

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`-1/8`
`1/16`
`1/8`
`1/2`

ANSWER :C
37.

A function f(x) is defined as follows :f(x)={(x sin ""1/x "," x ne 0),(0 "," x=0):} Discuss its continuity at x=0

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Solution :At x=0
f(0)=0
R.H.L `=UNDERSET(xrarr0^+)limf(x)=underset(hrarr0)limf(0+h)`
`=underset(hrarr0)limhsin"" (1)/(h)`
`=0xx`(a definite value )
=0
`(therefore)"SIN" (1)/(h) ` ALWAYS lies between -1 and 1)
gt L.H.L`=underset(xrarr0^-)lim f(x)=underset(hrarr0)limf(0-h)`
` =underset(hrarr0)lim(-h)sin (1/-h)=underset(hrarr0)(lim) h sin ""1/h`
`=0xx` (a definite value )=0
`therefore`R.H.L = f(0)=L.H.L
`therefore`f(x) is continuous at x=0.
Prove that(x) is CONTINOUS at x=2.
38.

How many factors does 210 have ?

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Solution :
` :.`We can CHOOSE at least one 2,3,5,7 to be a factor of 210.
`:."The number of factors. = ""^4C_1+ ""^4C_2 + ""^4C_3+ ""^4C_4= 2^2-1=15`(Including 215 itself and EXCLUDING 1).
39.

If total numberof runs secored is n matches is (n+1)/(4) (2^(n+1) -n-2)wheren ge 1 , and the runs scored in thek^(th)match is given by k.2^(n+1 - k) , where1 lek le n, nis

Answer»

8
9
7
6

Answer :3
40.

If x^(2)=y^(2) and (x-y)^(2)=2x, then which of the following is a possible value of y?

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`64`
`16`
`8`
`4`

ANSWER :D
41.

If (sqrt3 + i) = (a + ib) (c + id) then tan^(-1) (b)/(a) + tan^(-1) (d)/(c) =

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`2n pi + (pi)/(3) , n in Z`
`n pi + (pi)/(6) , n in Z`
`2 n pi + (pi)/(6) , n in Z`
`2n pi + (pi)/(6) , n in Z`

Answer :B
42.

Let N be number of ways four different integers be chosen from the set {1,2,3,4, . .104, 105} so that their sum is divisible by 4, then [(N)/(10^(5))] is equal to : ([.] denote greatest integer function).

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ANSWER :7
43.

A bag contains 2n + 1 coins . It is known that n of these coins have a head on both sides, whereas the remaining n + 1 coins are fair . A coin is picked up at random from the beg and tossed . If the probability that the toss results in a head is (31)/(42), then n is equal to

Answer»

10
11
12
13

Answer :A
44.

Assume that each born child is equally likely to be a boy or a girl. If a family has two children, what is the conditional probability that both are girls given that  (i) the youngest is a girl, (ii) at least one is a girl?

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ANSWER :`(i) (1)/(2), (II) (1)/(3)`
45.

Compute the limit underset(n rarr oo)("lim") ((1)/(sqrt(4n^(2)-1)) + (1)/(sqrt(4n^(2)-2^(2))) +……+ (1)/(sqrt(4n^(2)-n^(2))))

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ANSWER :`(PI)/(6)`
46.

Find the number of onto functions that can be defined from a set A={a_1,a_2,…..,a_n) onto another set B= (x,y) such that a_1 is always mapped to x

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ANSWER :`2^(n-1)-1`
47.

The numberof waysof dividing 12 boys into2 groups of 7,5 boysrespectivelyis

Answer»

`(8!)/(6!5!)`
`(9!)/(5!4!)`
`(10!)/(3!2!)`
`(12!)/(7!5!)`

Answer :D
48.

A and B are two events such that P(A) ne0 , find P (B/A)if A is a subset of B.

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0
1
`1/2`
NONE of these

Answer :B
49.

If the plane ax + by + cz = 5 passes through the points (1, 2, 1), (1, 1,0), (- 2, 2, - 1) then the decreasing order of a, b, c is

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a, B, c
b, c, a
c, a, b
c, b, a

Answer :C
50.

State the geometrival interpretation of int _c^(d) phi (y) dy

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ANSWER :9 square units
(ii) `(1)/(3) (8-2sqrt2) `square units