Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

If a*(b times c)=3 then

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`C*(a TIMES B)=-3`
`a*(c times b)=-3`
`b*(a times c)=3`
`(a times c)*b=3`

ANSWER :B
2.

If X is a poisson distribution such that P(X=1)=P(X=2)then,P(X=4)=

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`1/3e^(2)`
`2/3e^(2)`
`4/3e^(2)`
none

Answer :B
3.

If x+y ge 1, x ge y, 0 le x le 1, y ge 0 then the minimum value of f=3x+2y is

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1
2
2.5
3

Answer :C
4.

Differentiate the functions given in Exercises 1 to 11 w.r.t. x. (x+(1)/(x))^(x)+x^((1+(1)/(x)))

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ANSWER :`(X+(1)/(x))^(x)[(x^(2)-1)/(x^(2)+1)+LOG(x+(1)/(x))]+x^(1+(1)/(x))((x+1-logx)/(x^2))`
5.

According to Boil's law PV = C, where V = 600 cm^(3), P = 150 SI/cm^(2) and (dP)/(dt)=20 SI//cm^(2). Find (dV)/(dt).

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ANSWER :`80 CM^(3)`/MIN
6.

int_(-pi//4)^(pi//4)((x+pi//4)/(2-cos2x))dx=

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`(8pi sqrt(3))/(5)`
`(2PI sqrt(3))/(9)`
`(4 pi^(2)sqrt(3))/(9)`
`(pi^(2))/(6sqrt(3))`

ANSWER :D
7.

If f(x) = 2x secx + x and g(x) =3 tanx thenin interval x in (0, pi//2) is

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`F(X) GT g(x)`
`f(x) lt g(x)`
`f(x)=g(x)`
NONE of these

Answer :A
8.

Evaluate :1 + 3x + 6x ^(2) + 10 x ^(3)+……. upto infinite term, whre |x| lt 1.

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ANSWER :`(1)/((1 + X ) ^(3)) `
9.

If |{:(n^(2),(n+1)^(2),(n+2)^(2)),((n+1)^(2),(n+2)^(2),(n+3)^(2)),((n+2)^(2),(n+3)^(2),(n+4)^(2)):}|=Deltaand|(1,-4,7),(-2,3,-5),(3,x,-3)|=2Delta+1, then x=

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3
4
5
6

Answer :A
10.

(cos""(pi)/(6)+isin""(pi)/(6))^(1//2)+(cos""(pi)/(6)-isin""(pi)/(6))^(11//2)

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11.

Lists I, II and III contains conics, equation of tangents to the conics and points of contact, respectively. If the tangent to a suitable conic (List I) at (sqrt3(1)/(2)) is found to be sqrt3x+2y=4. then which of the following options is the only CORRECT combination?

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(II) (iii) (R)
(IV) (iv) (S)
(IV) (iii) (S)
(II) (iv) (R)

Solution :Tangent is `(SQRT3,(1)/(2))` is
`sqrt3x+2y=4`
Since slope of tangent at `(sqrt3,(1)/(2))` is `-ve`, possible curves are (I) and (II) only (draw the diagram and verify).
ALSO, given equation of tangent cannot match with
`my=x^(2)x+a`.
So, comparing eq. (I) with `y=mx+asqrt(x^(2)+1)`, we get
`a=2` and `m=(-sqrt3)/(2)`.
THEREFORE, equation of CURVE is `(x^(2))/(4)+y=1`.
The corresponding point of CONTACT is
`((-a^(2)m)/(sqrt(a^(2)m^(2)+1)),(1)/(sqrt(a^(2)m^(2)+1)))`
12.

Evaluate the following integral int (2x + 1)/(x(x^(2) + 4)^(2)) dx

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ANSWER :`(1)/(16) LOG x - (1)/(32) log (x^(2) + 4) + (1)/(8 (x^(2) + 4)) + (1)/(8) tan^(-1) ((x)/(2)) + (1)/(4) ((x)/(4 + x^(2))) + c `
13.

Lists I, II and III contains conics, equation of tangents to the conics and points of contact, respectively. If a tangent to a suitable conic (List I) is fond to be y = x+8 and its point of contact is (8, 16), then which of the following options I sthe only CORRECT combination?

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(II) (i) (P)
(III) (i0) (Q)
(II) (iv) (R)
(I) (ii) (Q)

Solution :TANGENT at (8, 16) is `y=x+8`
Since the SLOPE of tangent is `+ve`, possible curve will be
`y^(2)=4AX`.
Hence, equation of tangent is `my=m^(2)x+a` and point of contact is `((a)/(m^(2)),(2a)/(m))`.
14.

Integrate the following : int3x^2dx

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SOLUTION :`int3x^2dx`=`3x^3/3+C`=`x^3+C`
15.

Lists I, II and III contains conics, equation of tangents to the conics and points of contact, respectively. For a=sqrt2 if a tangent is drawn to a suitable conic (List I) at the point of contact (-1,1), which of the following options is the only CORRECT combination for obtaining its equation?

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(II) (ii) (Q)
(III) (i) (P)
(I) (i) (P)
(I) (ii) (Q)

Solution :For `a=sqrt2` and POINT `(-1,1)` on the CURVE, the only possible curve is `x^(2)+y^(2)=a^(2)`
Equation of tangent is `y=mx+asqrt(m^(2)+1)` and point of CONTACT is `((-ma)/(sqrt(x^(2)+1)),(a)/(sqrt(m^(2)+1)))`.
16.

If A is any square matrix then AA' is a ……….Matrix.

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Symmetric
Skew symmetric
Identity
Diagonal

Answer :A
17.

Find out wrongly matched pair.

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Tuber-Potato
Leaf buds-Banana
Offsets-Water Hyacinth
Rhizome-Ginger

Answer :B
18.

Compute : [(1,0),(1,0)][(0,0),(1,0)]

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ANSWER :`[(0,0),(0,0)]`
19.

A vehicle registration numebr consists of 2 letters of English alphabet followed by 4 digits,where the first digit in not zero.Then the total number of vehicles with distinct registration number is

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`26^(2)xx10^(4)`
`""^(26)P_(2)xx""^(10)P_(4)`
`""^(26)P_(2)xx13xx""^(6)P_(6)`
`26^(2)xx9xx10^(3)`

ANSWER :D
20.

Evaluate the following definite integrals . int_(a)^(b)xdx

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ANSWER :`1/2(B^(2)-a^(2))`
21.

Evaluate : (i) intsin3xsin2xdx (ii) intcos3xsin2xdx (iii) intcos4xcosxdx (iv) intsin^(3)xcos^(3)xdx

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Solution :(i) Using 2 sin a sin b = cos (a-b)-cos(a+b), we have
`intsin3xsin2xdx=(1)/(2)int2sin3xsin2xdx`
`=(1)/(2)int(cosx-cos5x)DX`
`=(1)/(2)intcosxdx-(1)/(2)cos5xdx`
`=(1)/(2)sinx-(sin5x)/(10)+C`.
(ii) Using 2 cos a sin b = sin (a+b)-sin(a-b), we get
`intcos3xsin2xdx=(1)/(2)int2cos3xsin2xdx`
`=(1)/(2)int(sin5x-sinx)dx`
`=(1)/(2)intsin5xdx(1)/(2)intsinxdx`
`=(-cos5x)/(10)+(cosx)/(2)+C`.
(iii) Using 2 cos a cos b = cos (a+b)+cos(a-b), we get
`intcos4xcosxdx=(1)/(2)int2cos4xcosxdx`
`=(1)/(2)int(cos5x+cos3x)dx`
`=(1)/(2)intcos5xdx+(1)/(2)intcos3xdx`
`=(sin5x)/(10)+(sin3x)/(6)+C`.
(iv) `intsin^(3)xcos^(3)xdx=intsin^(3)xcos^(2)xcosxdx`
`=intsin^(3)x(1-sin^(2)x)cosxdx`
`=intt^(3)(1-t^(2))DT," where"sinx=t`
`=intt^(3)dt-intt^(5)dt=(t^(4))/(4)-(t^(6))/(6)+C`
`=(1)/(4)sin^(4)-(1)/(6)sin^(6)x+C`.
22.

Find the equations of the circles for which the points given below are the end points of a diameter. (1,2), (4,6)

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Answer :` x ^(2) + y ^(2) - 5x - 8Y + 16 =0 `
23.

The value of (2 (sin2 theta-2 cos^(2)theta-1))/(cos theta-sin theta-cos 3 theta +sin 3 theta)=

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`cos THETA`
`SEC theta`
`cosec theta`
`sin theta`

ANSWER :C
24.

Mean and variance of binomial distribution are 3 and 2 respectively then parameter n is ………..

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9
3
8
6

Answer :A
25.

The set (A//B)uu(B//A) is equal to

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`[A//(ANNB)]NN[B//(AnnB)]`
`(AUUB)//(AnnB)`
`A//(AnnB)`
`bar(AnnB)//AuuB`

ANSWER :B
26.

Findint ( x^(3)-2x+3)/(x^(2)+x-2) dx .

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ANSWER :`(x^(2))/(2) - x + LOG | (x+2)^(1//3) (x - 1)^(1//3) | + c`
27.

A vertical dam has the form of a trapezoid whose upper base is 70m long, the lower one 50m, and the altitude 20m. Find the force of water pressure experienced by the dam

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ANSWER :`11333 (1)/(3)`
28.

Let A, B, C be angles of a triangle ABC and let D=(5pi+A)/(32), E=(5pi+B)/(32), F=(5pi+C)/(32), then : (where D, E, F ne (n pi)/(2), n in I, I denote set of integers)

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`cotD cotE+cotEcotF+cotDcotF=1`
`cotD+cotE+cotF=cotDcotEcotF`
`TAND tanE+tanE tanF+tanF tanD=1`
`tanD+tanE+tanF=tanD tanE tanF`

ANSWER :B::C
29.

If a point P is moving such that the length of tangents drawn from P to x^(2) + y^(2) - 2x + 4 y - 20= 0"___"(1). and x^(2) + y^(2) - 2x - 8 y +1= 0"___"(2). are in the ratio 2:1 Then show that the equation of the locus of P is x^(2) + y^(2) - 2x - 12 y +8= 0

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ANSWER :` X^(2)+ y^(2) -2X -12Y +8=0 `
30.

The maximum value of Delta=|{:(1,1,1),(1,1-sintheta,1),(1+costheta,1,1):}| is (theta is real number)".........."

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`1/2`
`sqrt3/2`
`SQRT2`
`(2SQRT3)/4`

ANSWER :A
31.

Compute the length of the astroid : x= a cos^(3) t, y= a sin^(3)t

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ANSWER :6A
32.

The radical centre of the circles x^(2) + y^(2) + a_(r)x + b_(r)y + c - 0 , r - 1,2,3is (a,b)

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(a,B)
(b.a)
(0,0)
NONE

ANSWER :C
33.

If the tangent at the point P on the circle x^(2)+y^(2)+6x+6y=2 meet the line 5x-2y+6=0 at a point Q on y-axis then PQ=

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`10`
`15`
`25`
`5`

ANSWER :D
34.

Discuss the continuity of the functions at the points given against them. If a function is discontinuous, determine whether the discontiunity is removable. In this case, redefine the function, so that it becomes continuous : {:(f(x)=(e^(5x)-e^(2x))/(sin3x)",", "for" x ne0),(=1",", "for" x=0):}}at x=0.

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ANSWER :`F(0)=2`
35.

Find dy/dx, x=at^2,y=2at and find the value at=1/2

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SOLUTION :`x=at^2,y=2AT`
Then dx/dt=2at,dy/dt=2A`
`RARR `dy/dx=(2a)/(2at)=1/t`
`therefore dy/dx]_(r=1/2)=1/(1/2)=2`
36.

Method of integration by parts : inte^(2x)*x^(4)dx=(e^(2x))/(2)f(x)+c then f(x)=.....

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`(1)/(2)x^(4)-2x^(3)+3x^(2)-3x+(3)/(2))`
`(x^(4)-x^(3)+2x^(2)-3x+2)`
`(x^(4)-2x^(3)+3x^(2)-3x+(3)/(2))`
`(x^(4)-2x^(3)+2x^(2)-3x+(3)/(2))`

ANSWER :C
37.

Evaluate the following inegrals int(1)/(sqrtx^(2)-3)dx

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ANSWER :`LOG|(X+sqrt(x^(2)-3))/(sqrt(3))|+c`
38.

The value of lim_(xrarr0)|x|/x is

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1
-1
0
Does not exist

Answer :D
39.

Consider a logarithmic equation log(x^(4)+1)=log(kx)(x^(2)+3x+1)….(i) {:(,"Column-I",,"Columnn-II",),(,"Values of k",,"No. of solutions of (i)",),((A),k=2,(P),0,),((B),k=-6,(Q),1,),((C),k=-12,(R),2,),((C),k=4,(S),4,),(,,(T),"even number",):}

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ANSWER :A::B::C::D
40.

If cos alpha, cos beta, cos gamma are the direction cosines fo a vector veca, then cos 2alpha + cos 2beta + cos 2gamma is equal to

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a.2
b.3
C.`-1`
d.0

Answer :C
41.

(i) Find the equation of director circle of 9x^(2) + 25 y^(2)=225 (ii) Find the equation of auxiliary circle of 9x^(2) + 1 6 y^(2) =144

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ANSWER :`X^(2)+y^(2)=34`
42.

A : If 4Sin^(-1)x+Cos^(-1)x=pi then the value of 4Cos^(-1)x+Sin^(-1)x" is "3pi//2 R : If a Cos^(-1)x+bSin^(-1)x=k then the value of bCos^(-1)x+aSin^(-1)x" is "(a+b)pi/2-k

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Both A and R are TRUE and R is the CORRECT EXPLANATION of A
Both A and R are true but R is not correct explanation of A
A is true but R is FALSE
A is false but R is true

Answer :A
43.

Differentiate w.r.t x the function sin^(-1) (x sqrtx), where 0 le x le 1

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ANSWER :`(3)/(2) SQRT((X)/(1-x^(3)))`
44.

Three balls are drawn at random from collection of 7 white, 12 green and 4 red balls, The probability that each ballis of different colours is……….

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`(.^(7)C_(1)xx.^(12)C_(1)xx.^(4)C_(1))/(.^(23)C_(3))`
`(8)/(253)`
`(4)/(253)`
`(1)/(253)`

ANSWER :A
45.

Evaluate the following integrals : (i) int(cosx)/(2sinx+3cosx)dx (ii) int(2sinx+cosx)/(7sinx-5cosx)dx ,br. (iii) int(5sinx+6)/(2cosx+sinx+3)dx

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Solution :`(i)` We have
`cosx=K(2sinx+3cosx)+m(2cosx-3sinx)`
`impliescosx=(2k-3m)sinx+(3k+2m)cosx`
Equating the COEFFICIENTS `sinx` and `cosx` from both sides
`3k+2m=1`
`2k-3m=0`
when `k=(3)/(13)` and `m=(2)/(13)`
Thus `int(cosx)/(2sinx+3cosx)DX=(3)/(13)intdx+(2)/(13)int((2cosx-3sinx))/(2sinx+3cosx)dx`
`=(3)/(13)x+(2)/(13)ln|2sinx+3cosx|`
`(ii)` Let `2sinx+cosx=k(7sinx-5cosx)+m(7cosx+5sinx)`
`implies2sinx+cosx=(7k+5m)sinx+(7m-5k)cosx`
`implies7k+5m=2`
and `7m-5k=1` when `m=(17)/(74)` and `k=(9)/(14)`
Thus `int(2sinx+cosx)/(7sinx-5cosx)dx=(9)/(74)intdx+(17)/(74)int(7cosx+5sinx)/(7sinx-5cosx)dx`
`=(9)/(14)x+(17)/(74)ln|7sinx-5cosx|+C`
`(iii)` Let`5sinx+6=k(2cosx+sinx+3)+m(-2sinx+cosx)+n`
`implies5sinx+6=(2k+m)cosx+(k-2m)sinx+3k+n`
`implies2k+m=0`, `k-2m=5`, `3k+n=6`
`impliesk=1`, `n=3`, `m=-2`
Thus `int(5sinx+6)/(2cosx+sinx+3)dx=intdx-2int((cosx-2sinx))/(2cosx+sinx+3)dx+3int(1)/(2cosx+sinx+3)dx`
`=x-2ln|2cosx+sinx+3|+3l_(1)`, say
`l_(1)=int(1)/((2cosx+sinx+3)dx=int(1)/(2((1-tan^(2).(x)/(2))/(1+tan^(2).(x)/(2)))+(2tan.(x)/(2))/(1+tan^(2).(x)/(2))+3)dx`
`=int(1+tan^(2).(x)/(2))/(2-2tan^(2).(x)/(2)+2tan.(x)/(2)+3+3tan^(2).(x)/(2))dx`
`=int(sec^(2).(x)/(2))/(5+2tan.(x)/(2)+tan^(2).(x)/(2))dx`
Let us put `tan.(x)/(2)=u`
so that `sec^(2).(x)/(2)dx=2du`
`=int(2)/(4+(1+u)^(2))du`
`=2*(1)/(2)tan^(-1)((1+u)/(2))+C`
`=tan^(-1)((tan.(x)/(2)+1)/(2))+C`
Hence the given integral is
`int(5sinx+6)/(2cosx+sinx+3)dx=x-2ln|2cosx+sinx+3|+3tan^(-1)((sin.(x)/(2)+cos.(x)/(2))/(2cos.(x)/(2)))+C`
46.

Find the values of 'a' in equation 'a+0.65 (n+1) which gives value of effective nuclear charge experience by last electron of 2^(nd) period elements. (wheren is number of electrons in 2^(nd) shell)

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ANSWER :`1.30`
47.

Find the equation of the circle which cuts each of the following circles orthogonally. x^2+y^2+3x+2y+1=0 x^2+y^2-x+6y+5=0 x^2+y^2+5x-8y+15=0

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ANSWER :`x^2+y^2-6x-4y-14=0`
48.

Findthe sumto 50 terms of 1+(2)(3)+4+(5)(6)+7+(8)(9)+….

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ANSWER :`49675`
49.

The orthocentre of the triangle formed by the lines x = 0, y = 0 and x + y = 1 is

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`((1)/(2), (1)/(2))`
`((1)/(3), (1)/(3))`
(0, 0)
`((1)/(4), (1)/(4))`

ANSWER :C
50.

If the slope of the line joining the points (3, 4) and (-2, a) is equal to (-2)/(5) then the value of a is equal to

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6
4
3
2

Answer :A