Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

If x = 1/2 and if (1-2x)/ (1-x+ x^(2)) + (2x-4x^(3))/ (1-x^(2) + x^(4))+ (4x^(3)-8x^(7))/(1-x^(4)+x^(6))+...infty = k, then

Answer»

`K = 8/7`
k is a RATIONAL NUMBER
`k = 4/7`
`7/16`

ANSWER :A::B
2.

Find the real numbers x and y so that (xI+yA)^(2)=A, where A=[{:(0,1),(-1,0):}].

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Answer :`X=(1)/(SQRT(2)),y=(1)/(sqrt(2))ORX=-(1)/(sqrt(2)),y=-(1)/(sqrt(2))`
3.

Equation of circle passing through (1,sqrt(3)), (1,-sqrt(3)) and (3,-sqrt(3)) is

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`(X-2)^(2)+y^(2)=4`
`(x+2)^(2)+y^(2)=4`
`(x-2)^(2)+y^(2)=2`
`x^(2)+(y-2)^(2)=4`

ANSWER :A
4.

Solution set of the in equality log_(10^(2)) x-3(log_(10)x)( log_(10)(x-2))+2 log_(10^(2))(x-2) lt 0, is :

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`(0,4)`
`(-OO,1)`
`(4,oo)`
`(2, 4)`

ANSWER :C
5.

If a in [-20,0],then the probability that the graph of the function y=16x^(2)+8(a+5)x-7a-5 touches or above the x-aixs is

Answer»

<P>`(3)/(20)`
`(13)/(20)`
`(7)/(20)`
`(1)/(2)`

SOLUTION :`a in [-20,0]`
`because` Graph of the function `y=16x^(2)+8(a+5)x-7a-5`TOUCHES or above the x-axis
`implies Dle0implies 64(a+5)^(2)+64(7a+5)le0impliesa^(2)+17a+30le0impliesa in [-10,-3]""therefore "Probability" P(7)/(20)`
6.

Select the Correct Option f(x)={((sinkx)/(2x),x!=0),(3,(x=0) at (x=0)):} is continuous then k+2=

Answer»

6
8
(3/2)
4

Answer :B
7.

Letz_(k) = cos ((2kpi)/(10)) + isin ((2kpi)/(10)), k = 1,2,,…,9.

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<P>`{:(""P,Q,R,S),(""(i),(ii),(iv),(III)):}`
`{:(""P,Q,R,S),(""(ii),(i),(iii),(iv)):}`
`{:(""P,Q,R,S),(""(i),(ii),(iii),(iv)):}`
`{:(""P,Q,R,S),(""(ii),(i),(iv),(iii)):}`

ANSWER :D
8.

The value of |(cos.(2pi)/(63),cos.(3pi)/(70),cos.(4pi)/(77)),(cos.(pi)/(72),cos.(pi)/(40),cos.(3pi)/(88)),(1,cos.(pi)/(90),cos.(2pi)/(99))| is equal to

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0
1
`2cos.(PI)/(9)`
`COS.(pi)/(11)`

Answer :A
9.

If A,B,C are the minimum values of 2x^3-3x^2-12x+5,x^3-9x^2+24x-12,x^3-6x^2+9x+1 then the ascending order of A,B,C is

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A,B,C
B,C,A
C,A,B
A,C,B

Answer :D
10.

If the circle x^(2) + y^(2) + 4x - 6y + c = 0 bisects the circumference of the circle x^(2) + y^(2) - 6x + 4y - 12 = 0, then c is equal to

Answer»

16
24
`-42`
`-62`

SOLUTION :Given circle is , `S -= x^(2) + y^(2) + 4x - 6y + c - 0` and ,
`S^(1) -= x^(2) + y^(2) - 6x + 4y - 12 = 0`
S = 0 bisects the CIRCUMFERENCE of `S^(1) = 0`
`implies 2 g^(1) (g - g^(1)) + 2F^(1) (f - f^(1)) = c - c^(1)`
`implies 2 (-3) (5) + 2 (-3, -2) - c + 12`
`implies c = - 30 - 20 - 12`
`:. c = - 62`
11.

A) Area of the figure bounded by y^(2)=9x and y=3x B) Area bounded by y=x^(2)+3 between x=-1 and x = 2 C) Area of the figure bounded by y=x^(2) and y=4x D) Area bounded by one arc of y=sin2x and X-axis Arrange the above statements in the ascending order of areas.

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A, D, C, B
B, A, D, C
C, A, B, D
D, B, A, C

Answer :A
12.

In a bank, principal increases continuously at the rate of r% per year.Find thevalue of r if Rs 100 double itself in 10 years (log_(e)2 = 0.6931).

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ANSWER :`6.93%`
13.

If p=a^2cos^2theta+b^2 sin^2 theta, where a^2+b^2+c^2,then 4p+(d^2p)/(d theta^2) is equal to

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`c^2`
`2c^2`
`4c^2`
`8c^2`

ANSWER :B
14.

If lines (x+l)/(3)=(y+3)/(5)=(z+5)/(7) and (x-2)/(1)=(y-4)/(3)=(z-6)/(5) are coplanar, thenl is equal to

Answer»

0
1
2
3

Answer :B
15.

int sin^(-1)(cos x)dx=....

Answer»

`(pix)/(2)`
`(PI)/(12)`
`(pix-x^(2))/(2)`
`(pix+x^(2))/(2)`

ANSWER :C
16.

If 1+sin x+sin^(2)x+…………… upto oo=4+2sqrt(3),0ltxltpi and x!=(pi)/2, then x=

Answer»

1)`pi//6`
2)`pi//4`
3)`pi//3`
4)`3pi//4`

ANSWER :C
17.

If omega is a imaginary cube root of unity , then 225 + (3 omega + 8 omega^(2))^(2) + (3 omega^(2) + 8 omega)^(2) =

Answer»

`72`
192
200
248

Answer :D
18.

int_(-pi//2)^(pi//2) sin^(4)x.cos^(6) x dx=

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`(3PI)/(128)`
`(3pi)/(256)`
`(3pi)/(572)`
`(3pi)/(64)`

ANSWER :B
19.

Using elementary transformations, find the inverseof the matrices

Answer»


ANSWER :`[(4,-1),(-7,2)]`
20.

If α, β are the eccentric angles of the extremeties of a focal chord of the ellipse (i) e cos (alpha+beta)/(2)=cos (alpha-beta)/(2) (ii) tan (alpha/2)tan (beta/2)=(e-1)/(e+1)

Answer»
21.

If f(x)=(x+2)/(2x+3), then intsqrt((f(x))/(x^2))dxequals : (1)/(sqrt(2))g((1+sqrt(2f(x)))/(1-sqrt(2f(x))))-sqrt((2)/(3))h((sqrt(3f(x))+sqrt(2))/(sqrt(3f(x))-sqrt(2)))+c, where :

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`G(X)=log|x|,H(x)=tan^(-1)x`
`g(x)=h(x)=tan^(-1)`
`g(x)=tan^(-1)x,h(x)=log|x|`
`g(x)=log|x|,h(x)=log|x|`.

ANSWER :D
22.

Find the locus of the point of intersection of tangents to the ellipse x^2/a^2+y^2/b^2=1 at the points the sum of whose ordinates are constant.

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ANSWER :`(2Y)/LAMDA`
23.

If alpha, beta , gammaare the roots of x^(3) + 3x + 4 = 0 then the equation whose roots (beta)/(gamma) + (gamma)/(beta) , (gamma)/(alpha) + (alpha)/(gamma), (alpha)/(beta) + (beta)/(alpha)is

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`16x^(3) + 48X^(2) + 75X + 70 = 0`
`16x^(3) - 48x^(2) + 75x + 70 = 0 `
`16x^(3) + 48x^(2) - 75x + 70 = 0 `
`16x^(2) - 48x^(2) + 75x - 70= 0`

Answer :1
24.

Determine all pairs (a,b) real numbers such that 10 ,a , b, ab are in arithmetic progression.

Answer»


ANSWER :`(4,2), ((5)/(2),-5)`
25.

I : The foot of the perpendicular of (3, -5) in y-axis is (-5, 3). II. If (2, -3) is the foot of the perpendicular from (-4, 5) on a line then the equation of the line is 3x-4y=18.

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only I is TRUE
only II is true
both I and II are true
NEITHER I nor II are true

ANSWER :B
26.

Let x be any real number, then [x+y]=[x]+[y] holds for :

Answer»

`YINR,y!INQ`
`yinQ`
`yinR`
`yinI`

ANSWER :D
27.

ABCisa rightangledtriangle withangleB = 90 ^@, a=6cm if theradiusof the circumcircleis 5 cmthen theareaofDeltaABC is

Answer»

25CM `""^2`
30cm `""^2`
36CM `""^2`
24cm `""^2`

ANSWER :D
28.

If a straight line perpendicular to 2x-3y+7=0 forms a triangle with the coordinates axes whose area is 3 sq unit, then the equation of the straight line is

Answer»

`3x+2y=pm2`
`3x+2y=pm6`
`3x+2y=pm4`
`3x+2y=pm8`

ANSWER :B
29.

Determine if the set A=x:xisa prime number }is a proper subset of the set B={2n-1:n=1,2,3…..}

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SOLUTION :A `={2,3,5,7,11……..}`
B `={1,3,5,7……}:.A CANCEL SUB B`, Because `2 in A `but 2 but `2 in B`.
30.

The number of vectors of unit length perpendicular to the vectors a = (1,1,0) and b = (0,1,1) is

Answer»

one
two
three
infinite

Answer :B
31.

If A+B=(pi)/(4)," then "(d)/(dx){[1+tan(A-x)][1+tan(B+x)]}=

Answer»

`-1`
1
`TANATANB`
0

Answer :D
32.

Integrate the function (1)/(sqrt(x^(2)-1))

Answer»
33.

The measure of two sides of a triangle is 10 m and 15 m. The angle between them is increasing at the rate of 0.01 radi./sec. when the angle between them is (pi)/(3), find the rate of change of increase in third side.

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ANSWER :`(3)/(20)SQRT((3)/(7))m//s`
34.

int_(0)^(1)e^(x)(x^(x)+1)^(3)dx=

Answer»

`((E+1)^(4))/(4)`
`1/4((e+1)^(4)-2^(4))`
`1/4 ((e+1)^(4)-1)`
`(e^(4))/(4)`

ANSWER :B
35.

Who is the author of this chapter?

Answer»

Shakespeare
Leo Tolstoy
Ramaswami lyer Krishnamurthy
None of the above

Answer :C
36.

Integrate the following intsin^(-1)x/(sqrt(1-x^2))dx

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Solution :`int(SIN^(-1)X)/sqrt(1-x^2)DX`
[put `sin^(-1)x=t then `dx/(sqrt(1-x^2)=DT`
`inttdt`
`(1/2)t^2+C=(1/2)(sin^(-1)x)^2+C`
37.

The slope of the line, which is drawn through the point (1, 2) so that its point of intersection with the line x+y+3=0 is at a distance 3sqrt(2) is :

Answer»

`(1)/(SQRT(3))`
`sqrt(3) `
1
`(sqrt(3)-1)/(2)`

ANSWER :C
38.

6 balanced dice are tossed 729 times. At least how many times 3 dice shows number 5 or 6 ?

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ANSWER :233
39.

intsqrt(1+cos2x)dx

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SOLUTION :`intsqrt(1+cos2x)dx=intsqrt2 cosxdx`
=sqrt2sinx+C
40.

intsqrt(1-cos2x)dx

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SOLUTION :`intsqrt(1-cos2x)DX=intsqrt(2sin^2x)dx`
=`sqrt2intsinxdx=-sqrt2cosx+C`
41.

Obtain the following integrals : int(e^(6logx)-e^(5logx))/(e^(4 logx)-e^(3logx))dx

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ANSWER :`:.I=(X^(3))/(3)+C`
42.

observethefollowinglists:(##VMC_MAT_WOR_BOK_05_C16_E02_022_Q01.png" width="80%">

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ANSWER :`A- 4 ; b-2; c-2;d-1`
43.

Let f(x)=f_(1)(x)-2f_(2)(x), where where f(x)={(min{x^(2)","|x|}",",|x| le 1),(max{x^(2)","|x|}",",|x| gt 1):} andf_(2)(x)={(min{x^(2)","|x|}",",|x| gt 1),(max{x^(2)","|x|}",",|x| le 1):} and let g(x)={(min{f(t):-3 le t le x", "-3 le x lt 0}),(max{f(t): 0let le x"," 0 le x le 3}):} Forx in (-1,0), f(x)+g(x) is

Answer»

`X^(2)-2x+1`
`x^(2)+2x-1`
`x^(2)+2x+1`
`x^(2)-2x-1`

SOLUTION :For `x in (-1,0),F(x)+G(x)=x^(2)+2x-1.`
44.

int(dx)/(a^2 sin^2x+b^2cos^2x)=

Answer»

`(-1)/(ab)TAN^(-1)((btanx)/(a))+C`
`(1)/(ab)tan^(-1)((btanx)/(a))+c`
`(-1)/(ab)tan^(-1)((ATANX)/(b))+c`
`(1)/(ab)tan^(-1)((atanx)/(b))+c`

ANSWER :D
45.

IF r.a = 0, r. b = 0 and r. c= 0 for some non-zero vector r. Then, the value of [a b c] is

Answer»

0
`(1)/(2)`
1
2

Solution :The given condition MEAN their that R is a PERPENDICULAR to all three vectors a,b and c, This is possible only if they are coplanar.
`[abc]=0`
46.

Distance between the pair of lines represented by the equation x^(2)– 6xy +9y^(2)+ 3x - 9y -4 = 0 is

Answer»

`(15)/(sqrt(10))`
`(1)/(2)`
`sqrt((5)/(2))`
`(1)/(sqrt(10))`

Answer :C
47.

If z satisfies the inequality |-1|lt|z+1|, then one has

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`|z-2-i|lt|z+2-i|,i=sqrt(-1)`
`|arg(z+i)|lt(PI)/(2),i=sqrt(-1)`
`Re(z)lt0`
`Im(ibarz)gt0,isqrt(-1)`

Answer :a,B,d
48.

Let f:R to R be a continuous function and f(x)=f(2x) is true AA x in R. If f(1) = 3 then the value of int_(-1)^(1) f(f(x))dx=

Answer»

6 or 2F(0)
0
3f(X)
3f(0)

Answer :1
49.

Let A=[[2,4],[3,2]] , B=[[1,3],[-2,5]] , C=[[-2,5],[3,4]] Find each of the folowing A+B , A-B

Answer»

SOLUTION :`A-B=[[2-1,4-3],[3+2,2-5]]=[[1,1],[5,-3]]`
50.

Find the value of x and y from the following equation: 2[(x,5),(7,y-3)]+[(3,-4),(1,2)]=[(7,6),(15,14)]

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ANSWER :x=2 and y=9