This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The sum of three numbers in A.P. is 27, and their product is 504, find them. |
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| 2. |
ABCD is a square of side l. A line parallel to the diagonal BD at a distance 'x' from the vertex A cuts two adjacentsides. Express the area of the segment of the square with A at a vertex, as a function of x. Find this area at x=1//sqrt(2) and at x=2, when l=2. |
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Answer» Solution :There are TWO CASES CASE -I : when `x=AP le OA, i.e., x le (l)/(sqrt(2))` `:. Ar(triangle AEF)=(1)/(2)x,2x=x^(2) "" ( :' PE =PF=AP=x)` Case-II : when` x=AP gt OA, i.e., x gt (l)/(sqrt(2)) " but " x le sqrt(2) l` `ar(ABEFDA)=ar(ABCD)-ar( triangle CFE)` `=l^(2)-(1)/(2)(sqrt(2)l-x)*2(sqrt(2)l-x) "" [ :' CP=sqrt(2)l-x]` `=l^(2)-(2L^(2)+x^(2)-2sqrt(2)lx)=2sqrt(2)lx-x^(2)-l^(2)` So, the required function s(x) is `s(x) ={(x^(2)","0le x le (l)/(sqrt(2))),(2sqrt(2)lx-x^(2)-l^(2)","(l)/(sqrt(2)) lt x le sqrt(2)l):}` ` :. s(x) ={((1)/(2)" at " x=(1)/(sqrt(2))),(8(sqrt(2)-l)" at " x=2):}` |
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| 5. |
Find the equation of the circle for which the point given below are the end points of a diameter. (0,0) ,(8,5) |
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| 6. |
If 7l^(2)-9m^(2) + 8l + 1 = 0and we have to find equation of circle having lx + my + 1 = 0 is a tangent and we can adjust given condition as16l^(2) + 8l + 1 = 9(l^(2) + m^(2)) or (4l + 1)^(2) = 9(l^(2) + m^(2)) rArr (|1 4l+1|)/(sqrt((l^(2) + m^(2)))) = 3 Centre of circle = (4, 0) and radius = 3 when any two non parallel lines touching a circle, then centre of circle lies on angle bisector of lines. On the basis of above information, answer the following questions : If 4l^(2) – 5m^(2) + 6l + 1 = 0, then the centre and radius of the circle which have lx + my + 1 = 0 is a tangent is |
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Answer» `(0, 4), SQRT(5)` |
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| 7. |
For the circle C with the equation x^(2)+y^(2)-16x-12y+64=0 match the list-I with the list-II given below: |
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Answer» I) d. ii). B, iii). a, iv). C |
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| 8. |
If 7l^(2)-9m^(2) + 8l + 1 = 0and we have to find equation of circle having lx + my + 1 = 0 is a tangent and we can adjust given condition as16l^(2) + 8l + 1 = 9(l^(2) + m^(2)) or (4l + 1)^(2) = 9(l^(2) + m^(2)) rArr (|1 4l+1|)/(sqrt((l^(2) + m^(2)))) = 3 Centre of circle = (4, 0) and radius = 3 when any two non parallel lines touching a circle, then centre of circle lies on angle bisector of lines. On the basis of above information, answer the following questions : If 16l^(2) + 9m^(2) = 24lm + 6l + 8m + 1 and if S be the equation of the circle having lx + my + 1 = 0 is a tangent when the equation of director circle of S is |
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Answer» `X^(2) + y^(2) + 6X + 8y = 25` |
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| 9. |
The sum of last ten coefficients in the expansion of(1+x)^(19) when expanded in ascending powers ofxis |
| Answer» Answer :B | |
| 10. |
Whenf: R to Rand g: R to Rare two functions defined by f(x)= 8x^(3)and g(x) == x^((1)/(3)) respectivelyand (g of ) (x) = k (f o g ) (x) , then k is |
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Answer» `4` |
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| 11. |
Using the letters of the word 'RAM' How many 6 letter words can be prepared so that all the 3 letters are to appear in the same word atleast once. |
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| 12. |
If 7l^(2)-9m^(2) + 8l + 1 = 0and we have to find equation of circle having lx + my + 1 = 0 is a tangent and we can adjust given condition as16l^(2) + 8l + 1 = 9(l^(2) + m^(2)) or (4l + 1)^(2) = 9(l^(2) + m^(2)) rArr (|1 4l+1|)/(sqrt((l^(2) + m^(2)))) = 3 Centre of circle = (4, 0) and radius = 3 when any two non parallel lines touching a circle, then centre of circle lies on angle bisector of lines. On the basis of above information, answer the following questions : If 16m^(2) – 8l– 1 = 0, then equation of the circle having lx + my + 1 = 0 is a tangent is |
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Answer» `X^(2) + y^(2) + 8x = 0` |
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| 13. |
The normal at a point P on the ellipse x^(2)/a^(2)+y^(2)/b^(2)=1(a gt b) meets the axis in M and N so that (PM)/(PN)=2/3. Then the value of eccentricity is |
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Answer» `1-E^(2)` |
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| 14. |
Consider a 2xx2 matrix A=[a_(ij)] , where a_(ij)=(i+2j)^2/2 Find A+A^T |
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Answer» SOLUTION :`a_11=(1+2xx1)^2/2=9/2,` `a_12=(1+2xx2)^2/2=25/2` `a_21=(2+2xx1)^2/2=16/2=8`. `a_22=(2+2xx2)^2/2=36/2=18`, HENCE, `A=[[9/2, 25/2],[8, 18]]` |
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| 16. |
int((1+x^(2))(2+x^2))/((xco sx+sinx)^(4))dx equals |
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Answer» `tan(x+cot^(-1)x)+(tan^(3)(x+cot^(-1)x))/(3)+C` |
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| 17. |
If f:R rarr [(pi)/(3),pi) defined by f(x)=cos^(-1)((lambda-x^(2))/(x^(2)+2)) is a surjective function, then the value of lambda is equal to |
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Answer» 0 |
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| 18. |
For a > 0, let the curves C_(1) : y^(2) = ax and C_(2) : x^(2) = ayintersect at origin O and a point P. Let the linex = b(0 lt b lt a) intersect the chord OP and the x-axis at points Q and R, respectively. If the line x = b bisects the area bounded by the curves, C_(1)and C_2, and the area of triangleOQR = 1//2, then 'a' satisfies the equation: |
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Answer» `x^(6) - 12X^(3) + 4=0` |
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| 19. |
Locus of the point of intersection of the tangents at the points with eccentric angle theta and (pi)/(2)+thetais |
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Answer» `x^(2)+y^(2)=a^(2)` |
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| 20. |
Integrate the following functions sinx sin(cosx). |
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Answer» SOLUTION :Let t = COSX. Then dt = -sinx dx therefore `int sinx SIN(cosx) dx = int sintxx-dt` =`-int sintt dt = -(-cost)+C` =`cost=c = cos(cosx)+c` |
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| 21. |
IFa = x hati+ y hatj+ z hatkthen( a xx hati) . ( hati+ hatj )+ ( a xxhatj) . ( hatj + hatk ) + ( axx hatk ) . ( hatk + hati ) = |
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Answer» `X-y+z` |
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| 22. |
Using integration find the area of the triangular region whose sides have the equations y =2x+1, y =3x +1 and x= 4. |
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| 23. |
If f(x)=x+(1)/(x), then : |
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Answer» RELATIVE MINIMUM gt relative MAXIMUM |
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| 24. |
Integrate the following functions w.r.t. x: (i) sinmx (ii) 2xsin(x^(2)+1) (iii) (tan^(4)sqrtxsec^(2)sqrtx)/(sqrtx) (iv) (sin(tan^(-1)x))/(1+x^(2)) |
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Answer» (III) `(2)/(5)TAN^(5)( sqrt(x))+c, (iv) -cos(tan^(-1)x)+c` |
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| 26. |
Find the point of contant of the tangent line 4x+y-7=0 with the ellipse x^(2)+3y^(2)=3 |
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| 27. |
From any point on the hyperbolax^(2) -y^(2) =a^(2) -b^(2)two tangents are drawn to the ellipsex^(2)//a^(2) +y^(2) //b^(2) =1Then they make anglesalpha and betasuch that |
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Answer» ` tan alpha -tan beta +1` |
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| 28. |
If z_(0) is one of the roots of the equation z^(n)cos theta_(0)+z^(n-1)cos theta_(1)+…+z cos theta_(n-1)cos theta_(n)=2, where theta_(i) in R, then |
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Answer» `|z_(0)|lt (1)/(2)` |
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| 29. |
The value of the determinant |{:(x,x+y,x+2y),(x+2y,x,x+y),(x+y,x+2y,x):}|" is "".........." |
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Answer» `9x^2(x+y)` |
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| 30. |
For any three vectors bara,barb,barc prove that [barb+barc barc+bara bara+barb] = 2[bara barb barc]. |
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| 32. |
Two persons A and B toss a die. The person who first throws 6 wins. If A starts then find the probability of A winning the game. |
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| 33. |
A biased die is tossed and the respective probabilities for the face to turn up are given below : {:("Face",1,2,3,4,5,6),("Probability",0.1,0.24,0.19,0.18,0.14,0.15):} If an odd face has turned up, then the probability for the face turned up is 3 or 5 is |
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Answer» `(3)/(4)` |
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| 35. |
There are 5% defective items in a large bulk of items. What is the probability that a sample of 10 items will include not more than one defective item? |
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| 36. |
int(sec^(4)x+tan^(4)x)dx= |
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Answer» `2/3tan^(3)x-2/3tanx+x+C` |
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| 37. |
If P is a point on the parabola y^(2)=8x and A is the point (1,0) then the locus of the mid point of the line segment AP is |
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Answer» `y^(2)=4 (X-(1)/(2))` |
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| 38. |
Find the approximate volume of metal in a hollow spherical shell whose internal and external radii are 3 cm and 3.0005 cm, respectively. |
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| 39. |
y=sinxcdotsin2xcdotsin4xcdotsin8x |
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| 40. |
Find the coefficient of x^(7) in the expansion of (1-x-x^(2)+x^(3))^(6). |
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| 41. |
Show that A(-3,0) lies on x^(2)+y^(2) + 8x+ 12 y + 15 = 0 and find the other end of diameter thorugh A. |
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| 42. |
If |2x-3| lt |x+5| , then x lies in the interval |
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Answer» `(-3,5)` |
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| 43. |
A man has 5 male and 4 female relatives. His wife has 4 male and 5 female relatives. The number of ways in which they can invite 5 male and 5 female relatives so that 5 of them are man's relatives and remaining 5 are his wife's relatives |
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Answer» A5426 |
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| 44. |
Evaluate int_(0)^(pi)ln(1+bcosx) dx, 'b'being parameter. |
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| 47. |
Whichof thefollowingfunctionhas / havea reaovablediscontinuityattheindicated point ? |
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Answer» `F(x) =(x^(2)-2x-8)/(x+2)at x=-2` |
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| 48. |
IF theequationk ( 6 x^2+ 3)+ rz+ 2x^2-1=0and6k( 2 x^2+1) + px + 4x ^2-2=0haveboththerootcommon, thenthe valueof2r-pis |
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Answer» 0 |
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