InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 6401. |
If A,B,C are 3 points on a parabola , Delta _1, Delta_2are the areas of triangles is formed by the points A, B,C and the tangents at A, B, C . IfDelta_1, Delta _2are the roots of px^(2) +qx +r=0then condition is |
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Answer» `9Q^(2) =2pr` |
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| 6402. |
A six faced dice is thrown a dozen times. Probability that six is not obtained even one is |
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Answer» `((5)/(6))^(12)` |
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| 6404. |
1 +(2^3)/(1!) x + (3^3)/(2!) x^2 + ....oo= |
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Answer» `(x^3+6X^(2) -7x -1)e^(x)` |
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| 6405. |
Find thevalues of the following : tan""^(-1)(1)+"cos"^(-1)-1/2+""sin"^(-1)-1/2 |
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Answer» |
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| 6406. |
Which of the following order is CORRECT according to given property ? |
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Answer» N-N GT P-P : BOND strength |
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| 6407. |
Consider the graph ofy = f(x) as shown in the following figure. (i) Find the sumof the roots of the equation f (x) = 0. (ii) Find the product of the roots of the equation f(x) = 4. (iii) Find the absolute value of the difference of the roots of theequationf(x) = x+2 . |
Answer» Solution : (i) Roots of theequation f(x) = 0 OCCUR where thegraph of y = f(x) and y = 0 INTERSECT. From the diagram, the points of intersection ofintersectionare x =- 2 and x= 1. HENCE sum of the roots is - 1. (ii) Roots of the equation f(x) = 4 occur where thegraph of y = f(x) and y = 4 intersect. From thediagram, the points of intersection are x =- 3 and x = 2. Hence the PRODUCT of theroots is -6. (iii) Roots of the equation f(x) = x+2 occur where the graph of y = f(x) and y = x+2 intersect. From thediagram, the points of intersection are x =- 2 and x = 2. Hence the difference of the roots is 4. |
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| 6408. |
If the vectors a, b and c are coplanar, then |(a,b,c),(a.a,a.b,a.c),(b.a,b.b,b.c)| is equal to |
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Answer» 1 `ax+yb+zc=0""…(i)` ON multiplyaing both sids of Eq (i) by a and b respectively we get `xaa+ya.b+za.c =0:""…(II)` `ab.a+yb.b+zb.c=0""...(iii)` On eliminating x,y and z from Eqs, (i), (ii) and (iii), we get `|{:(a,b,c),(a.a., a.b.,b.c),(b.a, a.b, b.c):}|=0` |
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| 6409. |
The probability that a number selected at random from theset of number {1,2,3,…100) is a cube ,is |
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Answer» `(1)/(25)` |
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| 6410. |
Prove that the orthocentre of the triangle formed by any three tangents to a parabola lies on the directrixof the parabola |
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Answer» |
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| 6411. |
Solution of the differential equation (2sin((y)/(x))+2xtan((y)/(x))-ycos((y)/(x))-ysec^(2)((y)/(x)))dx+(xcos((y)/(x))+xsec^(2)((y)/(x)))dy=0 |
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Answer» `X^(2)(SIN((y)/(x))-tan((y)/(x)))=c` |
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| 6412. |
Integrate the function (x^(2))/(sqrt(x^(6)+a^(6))) |
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Answer» |
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| 6413. |
Fill int the blanks choosing correct answer from the bracket. If sinA = sinB and b = 1/2 then a = _____. |
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Answer» 2 |
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| 6414. |
The solution of differential equation : x(dy)/(dx)+2y=x^2 is : |
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Answer» `y= (X^(4) + C)/(4X^(2))` |
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| 6415. |
Find the equation and length of the common chord of the two circles S=x^2+y^2+3x+5y+4=0 and S=x^2+y^2+5x+3y+4=0 |
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| 6416. |
If the magnitude of the coefficient of x^(7) in the expansion of (ax^(2) + (1)/(bx) )^(8), where a, b are positive numbers,is equal to the magnitude of the coefficient of x^(-7) in the expansion of (ax+(1)/(bx^(2)))^(8), then a and b are connected by the relation |
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Answer» `AB=1` |
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| 6417. |
If I_(n)=int_(0)^(pi)x^(n). sin x dx then the value of I_(5)+20I_(3)= |
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Answer» `((PI)/(2))^(5)` |
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| 6418. |
Prove that if the lines x = ay + b, z = cy + d and x = a'y + b', z = c'y + d' are perpendiclar to each other aa' + cc' + 1 = 0. |
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Answer» `ac_1 + a_1 c = 1` |
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| 6419. |
The tangent to y^(2)=axmakes an angle 45^(@) with x-axis . Then its point of contact is |
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Answer» A.P. |
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| 6420. |
Figure shows ................. |
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Answer» `a_(B)=50/250=1/5 m//s^(2)` `v_(b)=0+1/5xx5=1 m//s` Acceleration of BOX, `a_("box")=50/500=1/10 m//s^(2)` `v_("box")=0+1/10xx5=0.5 m//s` `v_(b)," box"=1-(-0.5)` `=1.5 m//s`. |
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| 6421. |
Differentiate x^(sinx) , x gt 0 with respect to x. |
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Answer» |
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| 6422. |
If x = y and x + y = 10, then 2x + y = |
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Answer» 3 |
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| 6423. |
Find the number of ways to arrange 8 persons around circular table if two specified persons wish to sit together |
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Answer» |
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| 6425. |
Definite integration as the limit of a sum : lim_(ntooo)(1)/(n)+(1)/(n+1)+(1)/(n+2)+.......+(1)/(2n) |
| Answer» Answer :D | |
| 6426. |
If f(x) = underset(nrarroo)lime^(xtan(1//n)log(l//n),andint(f(x))/(3sqrt(sin^(11)xcosx))dx=g(x)+C (C being the constant of intergrtion), then. |
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Answer» `g(pi//4) = 3//2` |
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| 6427. |
lf baru and barv are any two vectors, then : ((1-baru.barv)^(2)+(baru+barv+baruxxbarv)^(2))/(1+v^(2))= |
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Answer» 0 |
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| 6428. |
Find gof and fog , if f (x) = |x| and g(x) = |5x-2|. |
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Answer» |
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| 6429. |
The least positive integral value of n for which ((1-i)/(1+i))^(2n) = 1 is |
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Answer» only I is TRUE |
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| 6430. |
sin^(4)frac(pi)(8) + sin^(4) frac(2pi)8 + sin^(4) frac(3pi)8+sin^(4) frac(4pi)(8) +sin^(4)frac(5pi)(8) + sin^(4) frac(6pi)8 + sin^(4) frac(7pi)(8)= |
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Answer» A `3/2` |
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| 6431. |
if siny=xsin(a+y) then show that dy/dx=sin^(2)(a+y)/(sina). |
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Answer» |
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| 6432. |
Find the number of possible common tangent that exits for the following pairs of circle. (a)x^(2) + y ^(2) -4x -2y +1= 0, x^(2) +y^(2) -6x -4y +4=0 (b)x^(2) + y ^(2)-4 x + 2y -4=0 , x^(2) + y ^(2)+ 2x - 6y + 6=0 |
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| 6433. |
A stone thrown upwards has its equation of motion S=490t-4.9t^2. Then the maximum height reached by it is |
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Answer» 24500 |
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| 6434. |
Examine the continuity of the following functions at indicated points.f(x)={(frac{[x]}{x}ifxne0 at x=0),(0 if x=0):} |
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Answer» SOLUTION :f(0)=0 L.H.L `=lim_(hto0)|-h|/(-h)` `=lim_(hto0)h/-h=-1` `R.H.L==lim_(hto0)|h|/h` `=lim_(hto0)h/h=1` As L.H.L. ne R.H.L. ne f(0)` `therefore` f is DISCONTINUOUS at x=0 |
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| 6435. |
Differentiate w.r.t.x the function in Exercises 1 to 11. cos( a cos x+ b sin x), for some constant a and b. |
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| 6436. |
Which of the correct order for a given number alpha, alpha gt 1 |
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Answer» `log_(2)ALPHA LT log_(3)alpha lt log_(e)alpha lt log_(10)alpha` |
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| 6437. |
The equation of the tangent to the parabola y^(2)=4x at the end of the latus rectum in the fourth quadrant is |
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Answer» X-y+2 =0 |
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| 6438. |
ABCD is a parallelogram. Equations of overset(" "harr)(AB) and overset(" "harr)(AD)are 4x+5y=0, 7x+2y=0 and the equation of the diagonal overset(" "harr)(BD)is 11x+7y=9. Then the equation of overset(" "harr)(AC) is |
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Answer» `x=y` |
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| 6439. |
A polygobn has 44 diagonals .The number of the sides is |
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Answer» 10 |
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| 6440. |
Let f(x) = [x]and g(x) = x - [x], then which of the following functions is the zero function ? |
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Answer» (f+g) (X) |
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| 6441. |
A kite is flying with the string inclined at 75^(@) to the horizon. If the length of the string is 25 m, the height of the kite is |
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Answer» `(25//2) (sqrt(3) - 1)^(2)` |
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| 6442. |
If bar(a) = 3 overset(^)(i) + 2 overset(^)(j), bar(b) = 2 overset(^)(i) + 2 overset(^)(j) + overset(^)(k) , bar(c ) = 5 overset(^)(i) - overset(^)(j) + overset(^)(k) then the unit vectorbar(a) + bar(b) + bar(c ) 1 in opposite direction is |
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Answer» `OVERSET(^)(i)` |
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| 6444. |
Find the shortest distance between the linesvecr=(lambda-1)hati+(lambda+1)hatj-(1+lambda)hatk and (vecr=(1-mu)hati+(2mu-1)hatj+(mu+2)hatk. |
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| 6445. |
If ane1,bne-1,cne-1 and the system of equations, x=a(y+z),y=b(z+x),z=c(x+y) has a non-trivial solution, then. |
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Answer» `a/(a+1)+B/(b+1)+C/(c+1)=0` |
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| 6446. |
I : The image of the point (2, 1) with respect to the line x+1=0 is (-4, 1). II. If the point (1, 2) is reflected through origin and then through the line x = y then the new coordinates of the point are (-2, -1). |
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Answer» only I is TRUE |
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| 6447. |
If the function g(x) is defined by g(x)= (x^(200))/(200) + (x^(199))/(199)+ …..+ (x^(2))/(2)+ x + 5, then g'(0)=________ |
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Answer» 1)5 |
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| 6448. |
If |x|lt1 and y=x-(x^(2))/(2)+(x^(3))/(3)-(x^(4))/(4)+..., then x = |
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Answer» `y+(y^(2))/(2!)+(y^(3))/(3!)+…OO` |
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| 6449. |
A bag contains 8 red and 7 black balls . Two balls are drawn at random . Probability that both the balls are of the same color is |
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Answer» `14/15` |
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| 6450. |
Differentiate tan^(-1) e^(2x) |
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Answer» SOLUTION :`y = TAN^(-1) (e^(2x)) dy/dx = 1/(1+(e^(2x)^)^2) cdot d/dx(e^(2x)) = 1/(1+e^(4X)).2E^(2x) ={2e^(2x)}/(1+e^(4x))` |
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