InterviewSolution
Saved Bookmarks
InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 351. |
1 hectare=____`m^(3)`A. `10^(2)`B. `10^(3)`C. `10^(4)`D. `10^(5)` |
|
Answer» Correct Answer - C 1 hectare=10000`m^(2)=10^(4)m^(2)` |
|
| 352. |
If the density of a sphere is reduced to `1//8` of its original value, then the radius of the sphere is `"_________"` times its original radius (assume that there is no change in mass). SA. 2B. 4C. `1//2`D. `1//4` |
|
Answer» Correct Answer - A Density = `"mass"/"volume"` When the density is decreased to `1/8`th of its original value, then volume increases by times the original value. `v=4/3pir^(3)` `v_(1)=8 " v "` `4/3pir_(1)^(3)=8 xx4/3pi r^(3)` `r_(1)=8 r^(3)` ` r_(1)=2 " 0 "` |
|
| 353. |
The density of a substance in C.G.S. system is 0.475 `gram//cm^(3)`. What is its value in SI system?A. `0.475 kg//m^(3)`B. `475 kg//m^(3)`C. `0.0475 kg//m^(3)`D. `4.75 kg//m^(3)` |
|
Answer» Correct Answer - b `rho=0.475 " gram/cm"^(3)` in C.G.S. system In SI system, `rho=0.475xx(10^(-3)kg)/(10^(-6)m^(3))=475kg//m^(3)` |
|
| 354. |
Assertion: Avogadro number is the number of atoms in one gram mole.Reason: Avogadro number is a dimensionless constant. (A) Assertion is True, Reason is True; Reason is a correct explanation for Assertion (B) Assertion is True, Reason is True; Reason is not a correct explanation for Assertion (C) Assertion is True, Reason is False (D) Assertion is False, Reason is False. |
|
Answer» Answer is (C) Assertion is True, Reason is False Avogadro number (N) represents the number of atoms in 1 gram mole of an element. i.e., it has the dimensions of mole-1 |
|
| 355. |
Assertion: The graph between P and Q is straight line, when P/Q is constant. Reason: The straight line graph means that P is proportional to Q or P is equal to constant multiplied by Q. (A) Assertion is True, Reason is True; Reason is a correct explanation for Assertion (B) Assertion is True, Reason is True; Reason is not a correct explanation for Assertion (C) Assertion is True, Reason is False (D) Assertion is False, Reason is False. |
|
Answer» Answer is (A) Assertion is True, Reason is True; Reason is a correct explanation for Assertion As the graph is a straight line , P ∝ Q, or P = Constant x Q i.e., \(\frac{P}{Q}\) = constant. |
|
| 356. |
The change in volume of a gas with change in temperature is plotted on a graph, as shown in he figure. Calculate the ratio of density at `50 ^(@)C and 100 ^(@)C` |
|
Answer» Volume at `50 ^(@)C = 20 " "cm^(3)` Volume at `100 ^(@)C =30" "cm^(3)` Density = "mass"/"volume" Ratio of density `30/20 = 3/2 = 3 : 2` |
|
| 357. |
An atlas of a country is shown in the figure, the distance between cities A and B is______ A. (a) 35 kmB. (b) 3500 mC. (c ) 350 kmD. (d) Both (a) and (b). |
|
Answer» Correct Answer - C 1 cm =50 km 7 cm = `7xx 50` = 350 km |
|
| 358. |
An atlas of a country is shown in the figure, the distance between cities A and B is______ A. (a) 35 kmB. (b) 3500 mC. (c ) 350 kmD. (d) Both (a) and (b). |
|
Answer» Correct Answer - C 1 cm =50 km 7 cm = `7xx 50` = 350 km |
|
| 359. |
An atlas of a country is shown in the figure, the distance between cities A and B is______ A. 35 kmB. 3500 kmC. 350 kmD. both a and b |
| Answer» Correct Answer - C | |
| 360. |
The side of a cube is 5.052 cm. What is the volume of this cube to appropriate significant figures?A. `V=118.9 cm^(3)`B. `V=128.9cm^(3)`C. `V=138.9cm^(3)`D. `V=148.9cm^(3)` |
|
Answer» Correct Answer - b Volume = `Lxxbxxh` but L = b = h `therefore V=[5.052]^(2)=128.9407026 cm^(3)` The final value of V should have four significant figures as the value of each side has four significant figures. `therefore V=128.9cm^(3)` |
|
| 361. |
Write the following steps in a sequential arder to show that the volume of a liquid displaced by a solid, which is insouble and completely immrsed in a liquid increases with increase in the volume of the solid. (a) The displaced liquid is collected in a beaker and its volume is measured with the help of a measuring cylinder.(b) Different objects, such as glass, stone, stc., of different liquid such as water, kerosene, etc.(c ) The phenomenon is observed at different places and different times.(d) It is observed that the volume of displaced liquid increases as the volume of the solid increases.A. a d b cB. c d a dC. b a c dD. b d c a |
|
Answer» Correct Answer - C Take different objects, such as glass , stone, etc., of different volumes and immerse in different liquids, such as water, kerosene,mercury, etc. The displaced liquid is collected in a beaker and its volume is measured with the help of a measuring cylinder. This phenomenon is observed at different places and different times. It is found that the volume of the object increases. |
|
| 362. |
The length and breadth of a rectangle are 2 m and 5m, respectively, the area of the reactangle is______.A. `10m^(2)`B. `100000cm^(2)`C. `1km^(2)`D. both a and b |
| Answer» Correct Answer - D | |
| 363. |
A student was given a task to find the destiny of a cube whose mass and side are 100 g and 5 cm, respectively. What is his answer? |
|
Answer» Density =`"mass"/"volume"` Volume of cube = `("length")^(3) =(5 cm)^(3) = 125 cm^(3)` ltbr. Mass of he cube = 100 g Density = `(100g)/(125 cm^(-3))= 0.8 " g " cm^(-3)` |
|
| 364. |
Density of the material of a paper is given a 0.5 g `cm^(-3)`. The mass of the paper is 1 g and its length and breadth are 10 c and 5 cm, respectively. Arrange the following steps in a sequence to find the thickness of the paper. (A). The 0thickness of the paper is `("Volume of the paper (m)")/("Vlume of the paper (V)")` (B) The density (d) of the material of the paper is `=("Mass of the paper (m)")/("volume of the paper (V)")` (C). then the volume (V) o the paper `=("Mass of the paper (m)")/("Density (d) of the paper")` (D). The volume (V) of the paper is=length`xx`breadth`xx`thickness of the paper.A. ABCDB. BADCC. ABDCD. BCDA |
| Answer» Correct Answer - D | |
| 365. |
A wire is wound over a pencil and placed over a scale as shown in the figure. The diameter of the given wire is `"________"`. A. (a) 1.45 cmB. (b) 2.9 mmC. (c ) 2.9 mD. (d ) 1.45 mm |
|
Answer» Correct Answer - D Number of turns=20 Distance =`(4.1 - 1.2)` = 2.9 cm So, the diameter of he wire = `("2.9 cm")/20 = 0.145` = 1.45 mm |
|
| 366. |
Write the following steps in a sequential order to show that the volume of a liquid displaced by a solid, which is insolube and completely immersed in a liquids, increases with increase in the volume of the solid. (a)The displaced liquid is collected in a beaker and its volume in measured with the help of a measuring cylinder.(b)Different objects such as glass, stone, etc. of different volumes are immersed in different liquids such as water, kerosene, etc. (c)The phenomenon is observed at different places and different times. (d) It is observed that teh volume of displaced liquid increases as the volume of the solid increases.A. a d b cB. c b a dC. b a c dD. b d c a |
|
Answer» Correct Answer - C Take different objects such as glass, stone, etc. of different volumes and immerse in differnet liquids sucj as water, kerosene, mercury, etc. (b). Te displaced liquid is collected ina beaker and its volume is measured with the help of a measuring cyclinder (a). This phenomenon is observed at different places and different times (c). It is found that the displaced liquid increases as the volume of the object increases (d). |
|
| 367. |
Unit of energy is SI system is |
|
Answer» Correct Answer - Foule The SI unit of energy is joule. |
|
| 368. |
Density of the material of a paper is o.4g `cm^(-3)`.The mass of the paper is 0.5 g and its length and breadth are 10 cm and 4 cm, respectively. Determine the thickness of the paper. |
|
Answer» Density of paper =` 0.4 " g " cm^(-3)` Mass of paper = 0.5 g Volume of paper =` 0.5/0.4 = 1.25 " "cm^(3)` Volume = `( length xx breadth xx thickness)` Thickness =`1.25/(10xx4)=1.25/40 = 0.03125` |
|
| 369. |
The metric system of units was created by the _____ in 1790. (a) Greek (b) Australians (c) Russians (d) French |
|
Answer» Correct answer is (d) French |
|
| 370. |
S.I unit for Volume is _____(a) m2 (b) m (c) m3 (d) none |
|
Answer» Correct answer is (c) m3 |
|
| 371. |
Twenty decimetre is equal to _____ (a) 2 km (b) 20 cm (c) 2 metre (d) 200 mm |
|
Answer» Correct answer is (c) 2 metre |
|
| 372. |
The distance between two places is 43.65 km. Convert it into metre and cm. |
|
Answer» (a) Convert km into metre 1 km = 1000m ∴ 43.65 km = 43.65 × 1000 = 43650.00 = 43650 = 43650 m. (b) Convert km into cm. 1 km = 1000 m 1 m = 100 cm 1 km = 1000 × 100 cm 1 km = 100000 cm ∴ 43.65 km = 43.65 × 100000 = 4365000.00 = 4365000 cm. |
|
| 373. |
Define measurement. |
|
Answer» The comparison of an unknown quantity with some known quantity is known as measurement. |
|
| 374. |
What are the rules to be followed to make an accurate measurement with scale? |
|
Answer» 1. To avoid the parallax error. 2. Your eye must be exactly in front of vertically above the point where the measurement has to be taken. |
|
| 375. |
The mean length of an object is `5cm`. Which of the following measurement is most accurate?A. 4.9cmB. 4.805cmC. 5.25cmD. 5.4cm |
|
Answer» Correct Answer - A Givenlength, `l=5cm` Now , checking the error with each option one by one, we get `Deltal_(1)=5-4.9=0.1cm` `Deltal_(2)=5-4.805=0.195cm` `Deltal_(3)=5.25-5=0.25cm` `Deltal_(4)=5.4-5=0.4cm` Error `Deltal_(1)` is least. |
|
| 376. |
Which among the folloeing is the unit of energy?A. jouleB. wattC. newtonD. All the above |
|
Answer» Correct Answer - A Joule is a unit of energy |
|
| 377. |
If the smallest measurement that can be measured by using a scale is 0.1 mm, then the length of 1 m in the scale is divided inot __________ equal parts.A. 1000B. 5000C. 10000D. 50000 |
|
Answer» Correct Answer - C Smallest measurement = 0.1 mm = `0.1^(-3)" "10^(-3) " m "=10^(-4) " m "` So, the length of 1 m is divided into `1/10^(-4)` equal parts,that is `10^(4)` = 10000 |
|
| 378. |
The mass of a density bottle when it is filled with a liquid of density 3000 kg `m_(-3)` is 400 g and the mass of the bottle when it is filled with water is 200 g. The mass of the empty density bottle is ` "__________"` g.A. 10B. 100C. 50D. 500 |
|
Answer» Correct Answer - B Mass of the empty bottle = `m_(1)` Mass of the bottle with water, `m^(2)` = 200 g Mass of he bottle with liquid, `m_(3)` =400 g Density of the liquid = `3000 " Kg "m_(-3) = 3 " g " cm^(-3)` Density of liquid =`(m_(3)-m_(1))/(m^(2)-m_(1)` `3=(400-m_(1))/(200-m_(1))` `400-m_(1)=600-3m_(1)` `2m_(1)= 200 " g ",m_(1)=100 " g "`. |
|
| 379. |
The mass of a density bottle when it is filled with a liquid of density 3000 kg `m_(-3)` is 400 g and the mass of the bottle when it is filled with water is 200 g. The mass of the empty density bottle is ` "__________"` g.A. (a)10B. (b) 100C. (c )50D. (d) 500 |
|
Answer» Correct Answer - B Mass of the empty bottle, `M_(1)` Mass of the bottle with water, `m_(2)` = 200 g Mass of the bottle with liquid, `m_(3)` = 400 g Density of the liquid = 3000 kg, `m^(-3)` = 3 g `cm^(-3)` density of liquid = `(m_(3)-m_(1))/(m_(2)-m_(1))` `3 = (400-m_(1))/(200-m^(1))` `400-m_(1)` = 600 - `3m_(1)` ` 2m_(1)` = 200 g,` m_(1)` = 100 g. |
|
| 380. |
A stone of density `5xx 10^(3)` Kg `m_(-3)` and mass 2 kg is immeresed into a liquid, inside a graduted cylinder. The reading on the graduated cylinder is `1000 cm^(3)`before the stone is immersed into it, the reading after the stone is immersed in it is`"________"` `cm^(3)` .A. (a) 14000B. (b) 500C. (c ) 5000D. (d) 1400 |
|
Answer» Correct Answer - D `Density = mass/volume` `Volume = mass/ density=`2/(5xx10^(3)) xx0.4xx10^(-3) m^(3)` = `0.4xx10^(-3)xx10^(6) cm^(3)` = 400 `cm^(3)` |
|
| 381. |
The readings in a graduated cylinder are`10 cm^(3)` and` 20 cm^(3)`, respectively, before and after a metal alloy piece of mass 200 g is put in it. Thedensity of the material of the alloy is `"________"`kg `m^(-3)`A. (a)` 2xx 10^(3)`B. (b) 2xx10^(4)C. (c ) `2xx10^(5)`D. (d) 2xx 10^(6)` |
|
Answer» Correct Answer - B Volume of the metal = `10 cm^(3)` =`10xx10^(-6) m^(3) = 10^(-5) M^(3)` Mass of the metal = 200 g = 0.2 kg Density = mass/volume =`(2xx10^(1))/10^(-5) = 2xx10^(4) " kg "m^(-3)` |
|
| 382. |
The weight of the givensolid cylinder rodis 2512 N. The density of the body is `"________"` Kg `m_(-3)`.`(take g =10 m s_(-2))` A. (a) 2512B. (b) 25xx 12C. (d) `10^(3)`SD. (d)10^(6)S |
|
Answer» Correct Answer - D Volume = `pixx(radius)^(2)xxheight` =`pixx(0.02)^(2)xx0.2 = 25.12 xx 10^(-5) m^(3)` Weight = mxxg Mass = `weight/2 =2512/12 =251.2 `kg `"Density" =("mass")/("volume") = 251/(25.12xx10^(-5)) = (25.12xx10^(1))/(25.12xx10^(-5)` =`10^(6) kg m_(-3)` |
|
| 383. |
A stone of density `5xx 10^(3)` Kg `m_(-3)` and mass 2 kg is immeresed into a liquid, inside a graduted cylinder. The reading on the graduated cylinder. The reading on the graduated cylinder is `1000 cm^(3)`before the stone is immersed into it, the reading after the stone is immersed in it is`"________"` `cm^(3)` .A. (a) 14000B. (b) 500C. (c ) 5000D. (d) 1400 |
|
Answer» Correct Answer - D `Density = mass/volume` `Volume = mass/ density=`2/(5xx10^(3)) xx0.4xx10^(-3) m^(3)` = `0.4xx10^(-3)xx10^(6) cm^(3)` = 400 `cm^(3)` |
|
| 384. |
The dimensional formula for Reynold’s number is(A) [L0 M0 T0] (B) [L1 M1 T1] (C) [L-1 M1 T1] (D) [L1 M1 T-1] |
|
Answer» Answer is (A) [L0 M0 T0] |
|
| 385. |
The viscous force acting on a body moving through a liquid is proportional to its velocity. What is the dimensional formula for the constant of proportional to its velocity. What is the dimensional formula for the constant of proportionality?A. `[M^(1)L^(1)T^(-1)]`B. `[M^(1)L^(1)T^(-2)]`C. `[M^(1)L^(0)T^(-1)]`D. `[M^(0)L^(1)T^(-1)]` |
|
Answer» Correct Answer - c `Fpropv therefore F=kv or k=(F)/(v)` `therefore [k]=[(M^(1)L^(1)T^(-2))/(L^(1)T^(-1))]=[M^(1)L^(0)T^(-1)]` |
|
| 386. |
The damping force acting on an oscillating body is proportional to its velocity i.e. F = Kv. What is the dimensional formula for K?A. `[M^(1)L^(1)T^(-1)]`B. `[M^(1)L^(0)T^(-1)]`C. `[M^(0)L^(1)T^(-2)]`D. `[M^(1)L^(0)T^(1)]` |
|
Answer» Correct Answer - b `because F=KvorK=(F)/(v)` `therefore [K]=[(F)/(v)]=[(M^(1)L^(1)T^(-2))/(L^(1)T^(-1))]=[M^(1)L^(0)T^(-1)]` |
|
| 387. |
A scientist took a physical balance and an object of weight 10 kgwt from the Earth to the surface of the Moon. There on the Moon, if he placed this 10 kgwt object on one of the pansof physical balance, find the mass of the object required to balance the physical balance. |
| Answer» Mass of the object is 10 kg. So, mass of the object required is equal to 10 kg. | |
| 388. |
One micron is related to centimetre as (A) 1 micron = 10-8 cm (B) 1 micron = 10-6 cm (C) 1 micron = 10-5 cm (D) 1 micron = 10-4 cm |
|
Answer» Answer is (D) 1 micron = 10-4 cm |
|
| 389. |
The wavelength of a light is of the order of `6400 Å`. Express this in micron and metre.A. `0.64` micronB. 0.84 micronC. 0. 24 micronD. 0. 34 micron |
|
Answer» Correct Answer - A As, `1 Å=10^(-10)` `:.` Wavelength of light `=6400 Å=6400xx10^(-10)m=6.4xx10^(-7)m` Also 1 micron`=10^(-6)`metre Wavelength of light (in micron) `=(6.4xx10^(-7))/(10^(-6))`micron `=0.64` micron |
|
| 390. |
Subtract 0.2 J from 7.26 and express the result with correct number of significant figuresA. 7.1B. 7.06C. 7D. None of these |
|
Answer» Correct Answer - D `11.05+11.05=22.10` and not 22.1 becouse the result of addition must contain the least number of digit (of adding figure) after decimal. Here it is 2(digits). |
|
| 391. |
Multiply 107.88 by 0.610 and express the result with correct number of significant figures.A. 65.8068B. 64.807C. 65.81D. 65.8 |
|
Answer» Correct Answer - D Out of `107.88and 0.610`, least number of significant digit is 3, so the product must cintain 3 significant digit. So, the rigt answer is 65.8. |
|
| 392. |
1 `m^(1)=1000cm^(3)` |
| Answer» 1 ml=`1cm^(3)` | |
| 393. |
As the temperature of gases increases, its density also increase. |
| Answer» As the temperature of a gas increases, its volume increases or its density decreases. | |
| 394. |
`kg" "1^(-1)` is a unit of density. |
|
Answer» Correct Answer - 1 kg `1^(-1)` is a unit of density |
|
| 395. |
SI unit of weight is Newton. |
|
Answer» Correct Answer - 1 SI unit of weight is newton |
|
| 396. |
Mathi’s date of birth was 25.07.2000. What is her age on 29.08.2017? |
|
Answer» Convert the given date in YY MM DD format Age = 2017.08.29 Date of birth = 2000 .07 .25 Age = 17. 01. 04 She is 17 years one month 04 days old. |
|
| 397. |
If 11th of January 2018 is Thursday, what is the day on 20th July of the same year? |
|
Answer» January – 21 Days (31 – 10) Required day is the first day after Thursday. ∴ 20th of July is Friday. |
|
| 398. |
3 weeks = _____ days.(a) 21(b) 7(c) 14(d) 28 |
|
Answer» (a) 21 3 weeks = 21 days. |
|
| 399. |
Manickam joined a chess class on 20.02.2017 and due to exam, he left practice after 20 days. Again he continued practice from 10.07.2017 to 31.03.2018. Calculate how many days did he practice? |
|
Answer» From the date of joining = 20 days From 10.07.2017 to 31.03.2018 July – 22 Total no of practice days = 265 + 20 = 285 days |
|
| 400. |
Find the number of days between the republic day and kalvi valarchi day in 2020. |
|
Answer» 2020 is a leap year republic day – 26.01.2020 Jan – 5 |
|