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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Coefficient of standard deviation is:A. `(MD_(barx))/(barX)`B. `(MD_(m))/(M)`C. `(MD_(Z))/(Z)`D. all of these |
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Answer» Correct Answer - A A |
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| 2. |
…………………. Is the arithmetic average of the deviations of all the values taken from some average value of the series, ignoring signs of the deviations. (Mean Deviation/Standard Deviation) |
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Answer» Correct Answer - Mean Deviation Mean Deviation |
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| 3. |
Two sample of size 100 and 150 respectively have means 15 and 16 and standard deviations 3 and 4 respectively. Find the combined mean and standard deviation of Size 250. |
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Answer» Given: `N_(1)`=100, `barX_(1)`=15, `sigma_(1)`=3 `N_(2)`=150, `barX_(2)`=16, `sigma_(2)`=4 Now, `barX_(12)=(N_(1)barX_(1)+N_(2)barX_(2))/(N_(1)+N_(2))` `=(100xx15+150xx16)/(100+150)` `=(1,500+2,400)/(250)=(3,900)/(250)=15.6` `d_(1)=barX_(1)-barX_(12)=15-15.6=-0.6` `d_(2)=barX_(2)-barX_(12)=16-15.6=0.4` `sigma_(12)=sqrt(N_(1)sigma_(1)^(2)+N_(2)sigma_(2)^(2)+N_(1)d_(1)^(2)+N_(2)d_(2)^(2))/(N_(1)+N_(2))` `=sqrt(100xx(3)^(2)+150xx(4)^(2)+100xx(-0.6)^(2)+150xx(0.4)^(2))/(100+150)` `=sqrt(100xx9+150xx16+100xx0.36+150xx0.16)/(250)` `=sqrt((900+2,400+36+24)/(250))` `=sqrt((3,360)/(250))=sqrt(13.44)` 3.67 Hence, the combined mean is 15.6 and combined standard deviation is 3.67. |
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| 4. |
Find out the range and coefficient of range from the following data: 6,12,30,24,45,52,40 |
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Answer» Here, L=6, H=52 Range (R )=H-L =52-6 =46 Coefficient of Range (CR)`=(H-L)/(H+L)` `=(52-6)/(52+6)=(46)/(58)` =0.79 |
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| 5. |
`sigma=sqrt((N_(1)sigma_(1)^(2)+N_(2)sigma_(2)^(2)+N_(1)d_(1)^(2)+N_(2)d_(2)^(2))/(N_(1)+N_(2)))` is the formula of:A. combined mean deviationB. combined quartile deviationC. combined standard deviationD. coefficient of variation |
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Answer» Correct Answer - C C |
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| 6. |
Mean deviation can be calculation by using:A. meanB. modeC. medianD. all of these |
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Answer» Correct Answer - D D |
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| 7. |
Which is the following formulae is used to find out inter quartile range?A. `(Q_(1)-Q_(3))/(2)`B. `(Q_(1)+Q_(3))/(2)`C. `Q_(1)-Q_(3)`D. `Q_(1)+Q_(3)` |
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Answer» Correct Answer - C C |
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| 8. |
Range is estimated as the ………………………. Of highest and lowest values of the series. (difference/multiplicatin) |
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Answer» Correct Answer - difference difference |
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| 9. |
Coefficient of range is:A. `((H+L)/(H-L))xx2`B. `(H+L)/(2)`C. `(H+L)/(H-L)`D. `(H-L)/(H+L)` |
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Answer» Correct Answer - D D |
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| 10. |
Difference between third quartile and first quartile of a series, is called …………….. (Quartile Deviation/Inter Quartile Range) |
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Answer» Correct Answer - Inter Quartile Range Inter Quartile Range |
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| 11. |
Two sample of size 100 and 150 respectively have means 50 and 60 deviation of the combined sample of size 250. |
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Answer» `{:("Given":,N_(1)=100",",barX_(1)=50",",sigma_(1)=5),(,N_(2)=150",",barX_(2)=60",",sigma_(2)=6):}` Now, `barX_(12)=(N_(1)barX_(1)+N_(2)barX_(2))/(N_(1)+N_(2))` `=(100xx50+150xx60)/(100+150)=(5,000+9,000)/(250)` `(14,000)/(250)=56` `d_(1)=barX_(1)-barX_(12)=50-56=-6` `d_(2)=barX_(2)-barX_(12)=60-56=+4` `sigma_(12)=sqrt((N_(1)sigma_(1)^(2)+N_(2)sigma_(2)^(2)+N_(1)d_(1)^(2)+N_(2)D_(2)^(2))/(N_(1)+N_(2)))` `=sqrt((100xx(5)^(2)+150xx(6)^(2)+100xx(-6)^(2)+150xx(4)^(2))/(100+150))` `=sqrt((100xx25+150xx36+100xx36+150xx16)/(250))` `=sqrt((2,500+5,400+3,600+2,400)/(250))=sqrt((13,900)/(250))` `=sqrt(55.6)=7.46` Hence, the Combined Mean =56 and the Combined Standard Deviation=7.46. |
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| 12. |
Which of the following equations is correct?A. Variance=`sigma`B. Variance=`sigma^(2)`C. Variance=`sigma^(4)`D. Variance=`sqrt(sigma)xx2` |
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Answer» Correct Answer - B B |
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| 13. |
Coefficient of variation is a percentage expression of:A. Mean deviationB. quartile deviationC. standard deviationD. None of these |
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Answer» Correct Answer - C C |
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| 14. |
Which is the relative measure of dispersion?A. RangeB. Mean deviationC. Coefficient of standard deviationD. None of these |
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Answer» Correct Answer - C C |
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| 15. |
………………… measure of dispersion is known as coefficient of dispersion. (Absolute/Relative) |
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Answer» Correct Answer - Relative Relative |
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| 16. |
If sum of aquares of items =2,430, arithmctic mean =7, and number of items=12, find the coefficient of variation. |
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Answer» Given: `sumX^(2)=2,430, barX=7`, N=12 `sigma=sqrt((sumX)/(N)-(barx)^(2))` `=sqrt((2,430)/(12)-(7)^(2))=sqrt(202.5-49)` `=sqrt(153.5)=12.39` `CV=(sigma)/(barX)xx100` `=(12.39)/(7)xx100=177` Coefficient of Variation =1.77. |
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| 17. |
If the mean and standard deviation of 75 observations is 40 and 8 respectively, find the new mean and standard deviation if (i) each observation is multiplied by 5. (ii) 7 is added to each observation. |
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Answer» Given: `barX=40,sigma=8, N=75` (i) A "change of scale" affects the value of both `barX` and `sigma`. A change of scale occurs when each observation is multiplied by a constant. As a result to that, `barX` and `sigma` also get multiplied by that constant. Hence, New `barX="Old "barXxx5` `=40xx5` =200 and, New `sigma="Old "sigmaxx5` `=8xx5` =40 (ii) A "change of origin " affects the value of `barX` but not that of `sigma`. A change of origin occurs when eachobservation is increased by a constant .As a result to that, `barX` also increases by the same constant, while `sigma` remains unchanged. In our question, that constant is 7. Hence, New`barX="Old "barX+7` `=40+7` =47 While, New `sigma="Old "sigma` =8 |
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| 18. |
Coefficient of standard deviation is a ……………….. Measure of the dispersion of series. (absolute/relative) |
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Answer» Correct Answer - relative relative |
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| 19. |
The coefficient of variation of a series is 58. The standard deviation is 21.2. What is the arithmetic mean? |
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Answer» Given: CV=58,`sigma`=21.2 `CV=(sigma)/(X)xx100` `implies " " barX=(21.2)/(58)xx100` Substituting the values, we get `barX=(21.2)/(58)xx100=36.6` Arithmetic Mean=36.6 |
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