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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.

Stress in a solid body is defined as ___________ per unit area.(a) external force applied(b) strain(c) pressure(d) internal forces developed due to externally applied forcesI had been asked this question during a job interview.My question is from Solids Mechanical Properties topic in section Mechanical Properties of Solids of Physics – Class 11

Answer» CORRECT choice is (d) internal forces DEVELOPED due to externally applied forces

Explanation: When a force is applied on a SOLID BODY, internal forces develop inside it. Pressure is the external force per unit area while stress is the internal force per unit area. Note that pressure and stress aren’t the same.
2.

A completely elastic solid body partially regains its shape after removal of external force. True or False?(a) True(b) FalseThe question was posed to me during an interview.I would like to ask this question from Elastic Behaviour of Solids in chapter Mechanical Properties of Solids of Physics – Class 11

Answer»

Correct answer is (B) False

Easiest explanation: A solid body which partially regains its SHAPE after complete removal of force is CALLED partially ELASTIC body. It is called COMPLETELY elastic when it completely regains its shape.

3.

What does the area under the stress-strain curve represent?(a) Toughness(b) Total deformation(c) Modulus of elasticity(d) Average force appliedThis question was addressed to me in a job interview.My question comes from Solids Mechanical Properties in portion Mechanical Properties of Solids of Physics – Class 11

Answer»

Correct OPTION is (a) Toughness

To EXPLAIN: Area under the stress-STRAIN curves represents toughness. Total deformation is given by the NET strain multiplied by original length. Modulus of ELASTICITY is the ratio of stress to strain under elastic limit.

4.

A partially elastic body can never be permanently deformed. True or False?(a) True(b) FalseI had been asked this question by my college director while I was bunking the class.This interesting question is from Elastic Behaviour of Solids topic in portion Mechanical Properties of Solids of Physics – Class 11

Answer» CORRECT choice is (b) False

Easiest explanation: Only a completely elastic BODY can never be permanently deformed before breaking point. All partially elastic bodies REGAIN a LITTLE shape and undergo some permanent deformation after YIELD point.
5.

Which of the following statements is correct for brittle materials.(a) It breaks soon after elastic limit is crossed(b) It shows significant plastic deformation before breaking(c) It is used to make wires(d) Stress is never proportional to strainThe question was posed to me during an internship interview.The above asked question is from Solids Mechanical Properties topic in portion Mechanical Properties of Solids of Physics – Class 11

Answer»

Right ANSWER is (a) It breaks SOON after elastic limit is crossed

Easiest EXPLANATION: Brittle MATERIALS break soon after elastic limit. They show no significant plastic deformation and HENCE can’t be used for making wires. Their stress-strain curve looks like:

6.

Stress, like pressure, is always perpendicular to a plane. True or False?(a) True(b) FalseI got this question at a job interview.Question is from Solids Mechanical Properties topic in section Mechanical Properties of Solids of Physics – Class 11

Answer»

Correct choice is (b) False

For explanation: Stress can act along any direction to a PLANE. If it is PARALLEL to the plane it is called shearing stress & if it is perpendicular to the plane it’s called NORMAL stress. Pressure is always perpendicular to a unit area.

7.

Which of the following stresses causes change in density, as long as force acts on the body?(a) Shear stress(b) Compressive Stress(c) Tensile stress(d) Volumetric stressThe question was asked in quiz.This interesting question is from Solids Mechanical Properties topic in chapter Mechanical Properties of Solids of Physics – Class 11

Answer»

Right option is (d) Volumetric stress

For EXPLANATION: Volumetric stress is due to forces APPLIED on the surface of a body from all directions such force is along normal at each point. This causes a change in volume while mass, OBVIOUSLY, remains the same. So, there is a slight change in DENSITY. NOTE that it is negligible but this change of density doesn’t occur in any other type of stresses, as the change in longitudinal length is compensated by change in lateral length in case of longitudinal stresses.

8.

Strain can be negative. True or False?(a) True(b) FalseThis question was posed to me in my homework.This question is from Solids Mechanical Properties in portion Mechanical Properties of Solids of Physics – Class 11

Answer»

Right choice is (a) True

The best explanation: Strain is DEFINED as change in length or volume divided by initial length or volume respectively. There can be cases when length or volume DECREASES LIKE when rod is compressed or body is inserted in fluid (it volume decreases due to pressure from all SIDES). Hence, strain can be negative.

9.

Select the correct option. B is bulk modulus.(a) Bgas > Bliquid > Bsolid(b) Bliquid > Bgas> Bsolid(c) Bsolid > Bliquid > Bgas(d) Bliquid > Bgas > BsolidI have been asked this question in quiz.This question is from Solids Mechanical Properties topic in portion Mechanical Properties of Solids of Physics – Class 11

Answer»

Right answer is (C) Bsolid > Bliquid > Bgas

To ELABORATE: Bulk modulus is the inverse of compressibility. Solids are the least compressible, FOLLOWED by liquids and then gases being the most compressible. THUS solids have the maximum B, and liquids the least.

10.

Which of the following represents volumetric strain?(a) -ΔV/V(b) ΔV/V(c) Pressure/Volume(d) -P / (ΔV/V)I got this question in an interview.The question is from Solids Mechanical Properties in portion Mechanical Properties of Solids of Physics – Class 11

Answer»

Right choice is (B) ΔV/V

To explain I WOULD SAY: The volumetric strain is defined as ratio of CHANGE in volume to original volume. It can be either positive or negative. The option -P / (ΔV/V) is the bulk modulus which is basically the ratio of volumetric stress to volumetric strain.

11.

A wire has a young’s modulus of 10^5N/m^2, length 1m & radius 3mm. Assuming a uniform cross sectional area, find the radius of wire after it is under a force of 1N from both ends.(a) 2.58m(b) 2.30m(c) 3.54m(d) 2.24mI had been asked this question by my school principal while I was bunking the class.The question is from Solids Mechanical Properties topic in chapter Mechanical Properties of Solids of Physics – Class 11

Answer» CORRECT choice is (a) 2.58m

Easiest explanation: Force = 1N. Initial area = πr^2 = 2.82*10^-5m^2.

Stress = Y*Strain

Δl = F/A * l/Y = (1/2.82*10^-5)*(1/10^5) = 0.35m

As volume will REMAIN same (we can also say that PRODUCT of l & r^2 will be constant as other terms in EXPRESSION of volume are constants).

 1*3^2 = 1.35*R^2

 ⇒R = 2.58m.
12.

A material have a stress strain curve which can look similar to the equation y = x^2 (for all x>0). True or False?(a) True(b) FalseThe question was asked in an interview for job.The question is from Solids Mechanical Properties topic in section Mechanical Properties of Solids of Physics – Class 11

Answer»

The CORRECT OPTION is (a) True

To explain: The stress strain CURVE of some elastic tissues of our bodies look similar to the curve represented by equation y = x^2. For EG, the elastic tissue of aorta has a curve like:

13.

A lake has a depth of 500m. The bulk modulus of water is 2*10^9N/m^2. Calculate the fractional compression, ΔV/V, of water at the bottom of the lake.(a) 2.5*10^-3(b) 7*10^-3(c) 3.5*10^-3(d) 5*10^-3I had been asked this question in semester exam.The origin of the question is Solids Mechanical Properties in division Mechanical Properties of Solids of Physics – Class 11

Answer»

Correct OPTION is (a) 2.5*10^-3

For explanation I would SAY: PRESSURE at the bottom ‘P’ = ρgh = 1000*10*500 = 5*10^6Pa.

B = -P/(ΔV/V)

∴ ΔV/V = -P/B = 5*10^6/2*10^9 = 2.5*10^-3.

14.

A wire has a cross sectional area ‘A’, length ‘L’ and young’s modulus ‘Y’. It is pulled by a force ‘F’ which causes a total extension of length ‘l’. The force F is so adjusted that the wire is only slowly stretched. Find the work done by the force in pulling the string by a length ‘dx’ when extension is x (0 > x > l).(a) ½*stress*strain*volume(b) (AY/L)xdx(c) F*l(d) ½*stress * strainThis question was addressed to me in an international level competition.Question is from Solids Mechanical Properties in division Mechanical Properties of Solids of Physics – Class 11

Answer»

The correct OPTION is (b) (AY/L)xdx

For explanation I WOULD say: The force F at any instant will be EQUAL to internal force developed as the wire is to be slowly stretched.

∴ F=(AY/L)x

∴ Work done for dx EXTENSION = F*dx = (AY/L)xdx.

15.

A wire with a radius of 5mm is hung freely from the ceiling. A load of 5N is applied to its free end. Find the elongation in the wire if its volume is 7.85*10^-5m^3 & young’s modulus is 10^11N/m^2.(a) 6.21*10^-7m(b) 7.00*10^-7m(c) 6.36*10^-7m(d) 8.00*10^-9mThis question was addressed to me in a job interview.I'm obligated to ask this question of Solids Mechanical Properties topic in chapter Mechanical Properties of Solids of Physics – Class 11

Answer»

Right option is (c) 6.36*10^-7m

Explanation: The INITIAL length of wire is VOL / πr^2= 7.85*10^-5/ π*0.005^2 = 1m.

Stress = Y*strain. F/A = Y*Δl / l.

Δl = F/A * l/Y= (5/πr^2)*(1/10^11)

= 6.37*10^-7m.

16.

Bulk modulus is defined as -P / (ΔV/V). Therefore it can be negative. True or False?(a) True(b) FalseThis question was posed to me in my homework.This interesting question is from Solids Mechanical Properties topic in division Mechanical Properties of Solids of Physics – Class 11

Answer»

Correct answer is (b) False

Explanation: Bulk modulus is defined as the ratio of volumetric stress to volumetric strain. And volumetric stress is force APPLIED per unit area which is pressure. Now, when pressure is applied on a body its volume DECREASES, therefore a minus sign is used to make bulk modulus POSITIVE. Hence, it is positive.

17.

A 10N forceis uniformly distributed over the surface of a sphere of radius 20cm. The force at each point acts inward along the normal at that point. Find the fractional change in volume if the compressibility of the sphere is 10^-11m^2/N.(a) 3*10^-10(b) 1.5*10^-11(c) 1.98*10^-10(d) 2*10^-11I have been asked this question in an online quiz.My query is from Solids Mechanical Properties topic in portion Mechanical Properties of Solids of Physics – Class 11

Answer»

Right choice is (c) 1.98*10^-10

Best explanation: Bulk MODULUS ‘B’ is defined as -P / (ΔV/V). And B is the RECIPROCAL of compressibility.

∴ B = 1/10^-11= 10^11N/m^2.

 ΔV/V = P/B.

P = 10/(4π*0.04)

∴ ΔV/V = -P/B = – 10/(4π*0.04*10^11) = 1.98*10^-10.

18.

Which of the following quantities have the same S.I. unit as that of modulus of elasticity?(a) Energy per unit volume(b) Force per unit length(c) Energy(d) Change in lengthI had been asked this question in quiz.My question comes from Solids Mechanical Properties in division Mechanical Properties of Solids of Physics – Class 11

Answer»

Right choice is (a) ENERGY per unit VOLUME

Best explanation: Modulus of ELASTICITY is the ratio of stress to STRAIN. Its unit is, therefore, N/m^2. Energy per unit volume has the unit Nm/m^3 = N/m^2. FORCE per unit length has the unit N/m. So, the correct answer is energy per unit volume.

19.

Hooke’s law states that _________(a) stress is always proportional to strain(b) stress is proportional to strain before ultimate tensile strength(c) stress is proportional to strain under elastic limit(d) stress and strain are never directly proportionalThe question was asked in quiz.I'm obligated to ask this question of Hooke’s Law in portion Mechanical Properties of Solids of Physics – Class 11

Answer»

Right answer is (c) stress is proportional to strain under elastic limit

To EXPLAIN: Hooke’s LAW states that when DEFORMATION is small, stress is proportional to strain for ALMOST all materials. The region where this law is followed is SAID to be under elastic limit.

20.

All materials follow hooke’s law in its initial stages. True or False?(a) True(b) FalseThe question was asked by my college director while I was bunking the class.I would like to ask this question from Hooke’s Law topic in division Mechanical Properties of Solids of Physics – Class 11

Answer»

Correct option is (B) False

Explanation: Hooke’s law STATES that stress is proportional to strain under elastic limit. There are a few materials like elastomers which don’t FOLLOW hooke’s law. There are very few EXAMPLES like these in NATURE.

21.

The forces responsible for a body regaining its shape after removal of deforming forces are ________(a) gravitational forces between atoms(b) electromagnetic forces between atoms(c) nuclear forces within an atom(d) combination of gravitational & nuclear forces between atomsI had been asked this question by my school principal while I was bunking the class.Origin of the question is Elastic Behaviour of Solids in chapter Mechanical Properties of Solids of Physics – Class 11

Answer» RIGHT answer is (b) electromagnetic forces between atoms

To explain I would say: In a solid body, the atoms are held together in structures by interatomic forces which are electromagnetic in nature. When forces deform the solid STRUCTURE, the atoms are displaced from their equilibrium POSITIONS. On removal of these external forces the atoms try to regain their original positions because of these INTERMOLECULAR forces.
22.

A small body having mass 1kg is rotating in a circle of radius 10cm. It is connected to the centre with the help of a string having young’s modulus = 10^11N/m^2. Find change in length of wire while the mass is rotating with constant speed of 2m/s. The cross sectional area of string is 1cm^2.(a) 0.4μm(b) 4μm(c) 40μm(d) 0.4mThis question was addressed to me in semester exam.My question is based upon Solids Mechanical Properties in chapter Mechanical Properties of Solids of Physics – Class 11

Answer»

The correct CHOICE is (a) 0.4μm

Explanation: Tension ‘T’ in string will be GIVEN by T = mv^2/R = 1*4/0.1 = 40N.

Stress = Y*STRAIN, where Y is young’s modulus. T/A=Y*ΔL/L

∴ ΔL = TL/AY = (40*0.1)/(0.0001*10^11)

= 4*10^-7m = 0.4μm.

23.

Hooke’s law is an empirical law. True or False?(a) True(b) FalseI had been asked this question in unit test.The doubt is from Hooke’s Law in portion Mechanical Properties of Solids of Physics – Class 11

Answer» CORRECT answer is (a) True

To EXPLAIN: An EMPIRICAL law is one which is induced from observation or experiment. Hooke’s law is BASED on observations and is not derived from THEORETICAL concepts.
24.

The stress corresponding to fracture point is called ______(a) ultimate stress(b) breaking stress(c) yield stress(d) plastic stressThe question was asked in an interview for job.Enquiry is from Solids Mechanical Properties in chapter Mechanical Properties of Solids of Physics – Class 11

Answer»

Correct option is (B) BREAKING stress

The explanation: Breaking stress refers to the stress at which the material FRACTURES. Ultimate stress is the maximum stress a material can handle before breaking. The material doesn’t FRACTURE at this stress. Yield stress refers to the stress after which PLASTIC deformation begins.

25.

Select the correct order with regard to elasticity of materials.(a) Steel > Glass > Rubber(b) Glass > Rubber > Steel(c) Rubber > Glass > Steel(d) Rubber > Steel > GlassThis question was addressed to me in a national level competition.Question is from Elastic Behaviour of Solids topic in section Mechanical Properties of Solids of Physics – Class 11

Answer»

The correct answer is (a) Steel > Glass > Rubber

Easiest explanation: Elasticity is the PROPERTY of a material to regain shape when deforming FORCES are REMOVED. Out of the three, for the same stress, steel will SHOW MUCH less or maybe no permanent deformation as compared to glass which in turn will show less permanent deformation than rubber. Remember all this comparison is for the same amount of stress.

26.

Which of the following statements is correct for ductile materials.(a) Large deformation takes place between elastic limit and fracture point(b) Have no proportional limit(c) Break immediately after proportional limit(d) Cannot be drawn into wiresThis question was posed to me during a job interview.This question is from Solids Mechanical Properties in portion Mechanical Properties of Solids of Physics – Class 11

Answer»

The correct choice is (a) Large DEFORMATION takes place between elastic limit and FRACTURE point

The explanation is: DUCTILE materials are those which can be drawn into wires as they deform by a significant amount between elastic limit and fracture point. The stress-strain CURVE of a ductile MATERIAL looks like: