A small body having mass 1kg is rotating in a circle of radius 10cm. It is connected to the centre with the help of a string having young’s modulus = 10^11N/m^2. Find change in length of wire while the mass is rotating with constant speed of 2m/s. The cross sectional area of string is 1cm^2.(a) 0.4μm(b) 4μm(c) 40μm(d) 0.4mThis question was addressed to me in semester exam.My question is based upon Solids Mechanical Properties in chapter Mechanical Properties of Solids of Physics – Class 11

A small body having mass 1kg is rotating in a circle of radius 10cm. I

1.	A small body having mass 1kg is rotating in a circle of radius 10cm. It is connected to the centre with the help of a string having young’s modulus = 10^11N/m^2. Find change in length of wire while the mass is rotating with constant speed of 2m/s. The cross sectional area of string is 1cm^2.(a) 0.4μm(b) 4μm(c) 40μm(d) 0.4mThis question was addressed to me in semester exam.My question is based upon Solids Mechanical Properties in chapter Mechanical Properties of Solids of Physics – Class 11
Answer» The correct CHOICE is (a) 0.4μm Explanation: Tension ‘T’ in string will be GIVEN by T = mv^2/R = 14/0.1 = 40N. Stress = YSTRAIN, where Y is young’s modulus. T/A=YΔL/L ∴ ΔL = TL/AY = (400.1)/(0.000110^11) = 410^-7m = 0.4μm.

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