Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.

At a given temperature a body emits energy of a single wavelength corresponding to that temperature. True or False?(a) True(b) FalseThe question was asked in quiz.This is a very interesting question from Thermal Properties of Matter in portion Thermal Properties of Matter of Physics – Class 11

Answer»

The correct choice is (b) False

The best explanation: THERMAL radiation from a body shows a CONTINUOUS spectrum of WAVELENGTHS. But at a given TEMPERATURE there is a particular short range of wavelengths which contributes the maximum to the total radiant energy. The graph given below shows the intensity of different wavelengths at different temperatures.

2.

Temperature is absolute. True or False?(a) True(b) FalseThis question was addressed to me in unit test.This interesting question is from Measurement of Temperature in portion Thermal Properties of Matter of Physics – Class 11

Answer»

The correct answer is (b) False

The best explanation: Temperature is a relative MEASURE. When we touch a BODY we say it is hold or cold. We use devices like thermometers to indicate temperatures but we don’t have any FIXED ABSOLUTE value. When we say that temperature is 25°, it is relative to a reference we have DECIDED like steam point and ice point.

3.

Quantitatively heat conduction can be described as?(a) Heat flow for a given temperature difference(b) Time rate of heat flow for a given temperature difference(c) Temperature difference caused due to heat flow per unit time(d) Temperature difference per unit quantity of heat transferredThis question was posed to me in examination.My question is taken from Thermal Properties of Matter in portion Thermal Properties of Matter of Physics – Class 11

Answer»

The correct option is (b) Time RATE of heat flow for a given temperature difference

For explanation I would say: Heat transfer by conduction occurs due to an INITIAL temperature difference. Heat flow per unit time for a given temperature difference can be a QUANTITATIVE description of heat flow by conduction. Note that temperature difference causes heat flow and not the other way AROUND.

4.

When water is kept in a very hot pan, the entire water heats up. Which mode of heat transfer is responsible for this?(a) Conduction(b) Convection(c) Radiation(d) Convection along with radiationThe question was asked during an internship interview.The question is from Thermal Properties of Matter in chapter Thermal Properties of Matter of Physics – Class 11

Answer» RIGHT option is (b) CONVECTION

To elaborate: Conduction involves transfer of heat energy due to vibration of molecules at their positions, convection involves transfer of heat energy by the motion of molecules themselves and radiation involves heat transfer by electromagnetic WAVES. When water is placed in a very hot pan, the molecules of water in immediate contact with the pan get heated and MOVE away allowing the colder molecules to settle down hence allowing them to touch the pan and get heated. This MOVEMENT of heated molecules corresponds to convection.
5.

What is regelation?(a) Refreezing of ice on addition of impurities(b) Refreezing of ice on reduction in pressure(c) Melting of ice at lower temperature than its melting point due to increase in pressure(d) Melting of ice at higher temperature than its melting pointThe question was posed to me by my school principal while I was bunking the class.I would like to ask this question from Thermal Properties of Matter topic in division Thermal Properties of Matter of Physics – Class 11

Answer»

The correct ANSWER is (b) Refreezing of ice on reduction in pressure

To EXPLAIN: When increase in pressure causes water to MELT. It may refreeze on removal of this extra pressure. This refreezing is CALLED RELEGATION.

6.

Melting point depends on pressure. True or False?(a) True(b) FalseThe question was posed to me at a job interview.My doubt stems from Thermal Properties of Matter topic in chapter Thermal Properties of Matter of Physics – Class 11

Answer»

The correct choice is (a) True

Easy explanation: Melting point is less for higher PRESSURE. For EG: we can keep a SMALL weight of 1kg on a block of ICE and we will SEE that the ice underneath the block starts melting at a lower temperature.

7.

What should be the temperature of 1g of ice, so that when it’s added to 9g of water, lowers the temperature of water by 10°C?Sw = 1cal/ g°C, Sice = 0.5cal/ g°C, Lfus= 80cal/g.(a) 20°C(b) -20°C(c) 0°C(d) 10°CI got this question by my college professor while I was bunking the class.The above asked question is from Thermal Properties of Matter in chapter Thermal Properties of Matter of Physics – Class 11

Answer»

Correct answer is (b) -20°C

For EXPLANATION: LET the initial temperature of ice be T°C.HEAT lost by ice will be the same as the heat lost by water.

1*0.5*(0-T) + 1*80 = 9*1*10⇒ T = -20°C.

8.

What is the relation between coefficient of area expansion(A) and coefficient of volume expansion(B)?(a) B = 1.5A(b) A = 1.5B(c) A = 3B(d) B = 3AThis question was posed to me in quiz.My doubt is from Thermal Expansion topic in section Thermal Properties of Matter of Physics – Class 11

Answer»

Right ANSWER is (a) B = 1.5A

To EXPLAIN: Let the coefficient of LINEAR EXPANSION be α.The coefficient of area expansion is 2α and the coefficient of volume expansion is 3α.∴ The coefficient of volume expansion is 1.5 times the coefficient of area expansion∴ B=1.5A.

9.

Two spheres, A & B, are made up of the same material. The radius of A is twice that of B, while the temperature of A is half that of B. What is their ratio of energy emitted per unit time (EA : EB)?(a) 1(b) 1/4(c) 1/2(d) 1/16The question was posed to me during an online interview.I would like to ask this question from Thermal Properties of Matter in division Thermal Properties of Matter of Physics – Class 11

Answer» CORRECT choice is (b) 1/4

The best I can explain: Energy EMITTED per UNIT time is given by Ae.

e & σ will be the same for both.

 A = 4πr^2

 ∴ EA : EB= rA^2*TA ^2/rB^2*TB^4

= 4*1 / 1*16 = 1/4.
10.

Getting burnt by steam is less dangerous than boiling water. True or False?(a) True(b) FalseThe question was posed to me in an interview for job.Origin of the question is Thermal Properties of Matter in portion Thermal Properties of Matter of Physics – Class 11

Answer»

Correct answer is (B) False

To EXPLAIN: To make steam, water has to be BOILED and then more heat energy has to be ADDED to convert it into steam. So, steam is more dangerous than boiling water.

11.

Change of phase occurs at a constant temperature, which implies that even on addition of heat to a substance temperature remains constant. True or False?(a) True(b) FalseI had been asked this question during an online exam.I'm obligated to ask this question of Thermal Properties of Matter topic in portion Thermal Properties of Matter of Physics – Class 11

Answer»

Correct option is (a) True

Easy EXPLANATION: The temperature change with heat supplied is SHOWN below. During change of phase heat supplied is used to MAKE changes in intermolecular distances while the temperature remains CONSTANT.

12.

What is the value of coefficient of area expansion for a sphere? Assume coefficient of linear expansion is α.(a) 2α(b) α(c) 3α(d) α/2This question was addressed to me in class test.Origin of the question is Thermal Expansion topic in chapter Thermal Properties of Matter of Physics – Class 11

Answer»

Right option is (a) 2α

For explanation: The AREA(A) of a SPHERE is 4πr^2.When the temperature INCREASES by ΔT, let CHANGE in areabe dA.Let the radius INCREASE by dr.The coefficient of area expansion is (dA/A)/ΔT.

∴ dA = 4π(r – dr)^2– 4πr^2 ≅ 8πrdr.

Also, dr = rαΔT.

The coefficient of area expansion is (dA/A)/ΔT

= (8πr*rαΔT/4π) / ΔT

= 2α.

13.

A rod is lying on the ground with both ends free. It has a length of 1m. Coefficient of linear expansion equal to 1.1*10^-5per &degC. Calculate the strain when the change in temperature is 10K.(a) 11*10^-5(b) 1.1*10^-5(c) 0(d) 311.3*10^-5I have been asked this question in exam.This key question is from Thermal Expansion topic in section Thermal Properties of Matter of Physics – Class 11

Answer» CORRECT option is (C) 0

To EXPLAIN I would say: When the ROD is heated it permanently increases in length. As there is no force holding it in its initial length from either side, there will be no internal forces to produce strain.
14.

What is the slope of line drawn for a graph between temperature in °C & °F?(a) 1.8(b) 5/9(c) slope is variable(d) 2The question was asked during an online exam.My enquiry is from Measurement of Temperature topic in division Thermal Properties of Matter of Physics – Class 11

Answer» RIGHT answer is (a) 1.8

The best I can explain: °F = (9/5)°C + 32.

 Therefore from this we can SAY that slope of line DRAWN for graph between TEMPERATURE in °C & °F is 9/5 = 1.8.
15.

Specific heat capacity depends on the mass of the substance. True or False?(a) True(b) FalseThe question was posed to me in an online interview.Origin of the question is Thermal Properties of Matter topic in section Thermal Properties of Matter of Physics – Class 11

Answer»

Right option is (b) False

The explanation is: Specific heat capacity is DEFINED as the heat capacity per unit MASS for a SUBSTANCE.s = ΔQ/mΔT.So, no matter what mass of a substance we take‘s’ will be equal to (ΔQ/ΔT) divided by that mass,which MEANS ‘s’ doesn’t depend on the mass.

16.

Same amount of heat is added to two substances of same mass having specific heat capacities s1 & s2 such that s1 > s2. Select the correct statement.(a) The change in temperature of 1 is greater than the change in temperature of 2(b) The change in temperature of 1 is less than the change in temperature of 2(c) Both will have the same change in temperature(d) Temperature changes can’t be related with specific heat capacitiesI have been asked this question by my college professor while I was bunking the class.My doubt is from Thermal Properties of Matter in portion Thermal Properties of Matter of Physics – Class 11

Answer» RIGHT ANSWER is (b) The CHANGE in TEMPERATURE of 1 is less than the change in temperature of 2

Explanation: Q = msΔT,so for the same mass and heat supplied, the product of ‘s’ and ΔT must be the same.Therefore more the value of ‘s’, less will be the value of ΔT.Hence, ΔT will be lesser for 1 as ‘s’ is greater for 1 than 2.
17.

When an object is heated its temperature definitely increases?(a) True(b) FalseThe question was asked in class test.Asked question is from Temperature and Heat in chapter Thermal Properties of Matter of Physics – Class 11

Answer» RIGHT answer is (b) False

To elaborate: When we supply HEAT to a body it’s not necessary for its temperature to INCREASE. The heat may increase temperature, it may expand or change state. For eg: when ice is melting, we provide heat but conversion from ice to WATER takes place at CONSTANT temperature.
18.

What is absolute zero?(a) It is the minimum temperature that has been achieved(b) It is the lowest temperature of air(c) It is -273K(d) It is the temperature at which an ideal gas will have zero pressure, assuming it stays a gasThe question was posed to me in a job interview.This intriguing question comes from Thermal Properties of Matter topic in division Thermal Properties of Matter of Physics – Class 11

Answer»

Right choice is (d) It is the temperature at which an IDEAL gas will have zero pressure, assuming it stays a gas

Easiest EXPLANATION: Absolute zero has been defined as the temperature at which an ideal gas would have zero pressure, assuming it remains a gas TILL then. The temperature value is obtained by extrapolating the graph of Pressure vs Temperature till the straight line cuts the temperature axis. This gives US a value of -273.15°C. NOTE that this temperature hasn’t been achieved yet.

19.

A liquid cools from 65°C to 55°C in 5 mins. If the surrounding temperature is 35℃, calculate the time taken for temperature to fall from 45°C to 35°C.(a) 25sec(b) 25min(c) 30min(d) 30secI have been asked this question in semester exam.Origin of the question is Thermal Properties of Matter topic in division Thermal Properties of Matter of Physics – Class 11

Answer»

The CORRECT answer is (b) 25min

The explanation is: Average temperature of liquid in the first case = 60℃.

Rate of FALL of temperature =65-55 / 5 = 2°C /min.

Which is also equal to k(60 – 35) = 25k, where k is a constant.

∴ 25k = 2 Or k = 2/25

Average temperature in the second case = 40°C

Rate of fall of temp = 45 – 35 / t = k(40-35)

∴ t = 25mins.

20.

The rate of cooling of water increases with fall in temperature. True or False?(a) True(b) FalseI have been asked this question at a job interview.Question is from Thermal Properties of Matter topic in chapter Thermal Properties of Matter of Physics – Class 11

Answer»

The correct OPTION is (b) False

The EXPLANATION is: The graph of temperature difference with time given below shows that as temperature decreases rate of cooling (or temperature difference per unit time) ALSO decreases. We can see that for the same time INTERVAL temperature difference BECOMES less at lower temperatures.

21.

The sun emits light having maximum intensity at a wavelength 468nm. Assume emissivity of sun is 1. Calculate its surface temperature. σ= 5.67*10^-8W/m^2K^4.(a) 6800K(b) 3400K(c) 6196K(d) 7200KI had been asked this question by my college professor while I was bunking the class.Origin of the question is Thermal Properties of Matter in section Thermal Properties of Matter of Physics – Class 11

Answer» RIGHT CHOICE is (c) 6196K

The explanation: USING WEIN’s displacement law: λT = 2.9*10^-3,

we get T = 2.9*10^-3/(468*10^-9)

= 6196 K.
22.

Select the correct statement.(a) Radiation doesn’t require any medium(b) Convection involves heat transfer by vibration of particles at their position(c) Conduction involves movement of particles to transfer heat(d) Radiation is responsible for heat of gas flame heating the cooking panThe question was posed to me in quiz.This interesting question is from Thermal Properties of Matter topic in portion Thermal Properties of Matter of Physics – Class 11

Answer»

The correct CHOICE is (a) Radiation doesn’t require any medium

The explanation: Radiation doesn’t require any medium for TRANSFER of heat. When a cooking pan is heated over a GAS stove, conduction is the PROCESS responsible for transfer of heat from flame to pan. Radiation involves electromagnetic waves transferring energy called radiant energy.

23.

For a constant volume gas thermometer select the correct statement.(a) It doesn’t use mercury for pressure measurement(b) We actually measure the pressure at constant volume and the scale is calibrated to give the temperature reading(c) Any high density gas can be used(d) Pressure ∝ Temp^2I had been asked this question in an interview for internship.My question is based upon Thermal Properties of Matter topic in chapter Thermal Properties of Matter of Physics – Class 11

Answer»

Correct option is (b) We actually measure the pressure at constant VOLUME and the scale is calibrated to give the temperature reading

Easy explanation: A constant volume gas thermometer has a MERCURY manometer connected to a gas bulb. With increase in temperature of the bulb, its volume is kept constant by external METHODS and the pressure of gas increases.The temperature scale is DEFINED as a function of this pressure.(T = kP, where k is a constant).

24.

An ice cube is kept on the surface of an aluminium block and another ice cube on the surface of a plastic block. Both blocks have the same temperature. Select the correct statement.(a) Ice will melt faster on the aluminium block(b) Ice will melt faster on the plastic block(c) Ice will melt equally fast on both the blocks(d) Ice will not melt on the plastic blockThe question was posed to me during an online exam.My question is taken from Temperature and Heat topic in chapter Thermal Properties of Matter of Physics – Class 11

Answer»

The correct CHOICE is (a) Ice will melt faster on the ALUMINIUM block

Easy explanation: Ice will melt faster on the aluminium block because it has a higher thermal CONDUCTIVITY than PLASTIC and hence conducts HEAT more rapidly than plastic. Which is why ice melts faster on aluminium.

25.

Why is mercury used in thermometers?(a) It volume is proportional to square of increase of temperature(b) It shows linear variation in volume with temperature(c) Its volume remains constant with temperature(d) Its volume decreases with increase in temperatureI have been asked this question in semester exam.Origin of the question is Measurement of Temperature in division Thermal Properties of Matter of Physics – Class 11

Answer»

Correct option is (b) It SHOWS linear variation in volume with temperature

Explanation: For measuring temperature in a thermometer we need a substance whose physical PROPERTIES change with temperature and can be easily RELATED with temperature. Mercury’s volume increases linearly with INCREASE in temperature and hence we can create a SCALE on the thermometer accordingly.

26.

What is the net amount of energy per unit time being received by a body having a temperature of 40 °C in a surrounding of 60°C? (The surface area of body = 2m^2, σ = 5.67*10^-8W/ m^2K^4 & emissivity of 0.4).(a) 122.4W(b) 0.47W(c) 33W(d) 86WI have been asked this question during an online exam.The above asked question is from Thermal Properties of Matter topic in division Thermal Properties of Matter of Physics – Class 11

Answer»

Correct option is (a) 122.4W

To EXPLAIN I WOULD say: The BODY will RECEIVE some energy from the surrounding and also lose some to it.

The net energy RECEIVED will be

= AeσT^4 – AeσTS^4

= 2*0.4*5.67*10^-8(333^4 – 313^4)

= 122.4 W.

27.

If we hold a metal rod from one end and dip the other in a source of fire, what will happen to the temperature of the rod at steady state?(a) Be uniform(b) Decrease with time(c) Remain constant at a single value throughout the length of the rod(d) Stay nonuniformI have been asked this question during an interview.This intriguing question comes from Thermal Properties of Matter in section Thermal Properties of Matter of Physics – Class 11

Answer»

Right choice is (d) Stay nonuniform

For EXPLANATION I would SAY: When a rod is held with one end in fire. That end will have a temperature equal to that of fire. The temperature will gradually decrease towards the other end. At steady STATE the rate of heat flow will be constant and temperature at each point will be constant, but will be varying non-uniformly through the LENGTH of the rod.

28.

A steel and a copper bar are joined end to end. The area of the steel bar is half the area of the copper bar. Their lengths are equal to 10cm each. Temperature of free ends of steel & copper rod are 0°C & 100°C respectively. KS = 50 J/smK & KC =384 J/smK. Calculate equivalent thermal conductivity of the combined bar.(a) 63°C(b) 63K(c) 336°C(d) 36KI had been asked this question in an online interview.This interesting question is from Thermal Properties of Matter topic in chapter Thermal Properties of Matter of Physics – Class 11

Answer»

Correct CHOICE is (a) 63°C

To ELABORATE: TEMPERATURE at the fixed ends of both RODS will be the same.

KS AS (T-0)/LS = KC AC (100-T)/ LC

∴ 50*1/2 LCT = 384* C (100-T)

⇒ 25T = 38400 – 384T

⇒ T = 63°C.

29.

An aluminium piece and a wooden piece have been left in a room for a few hours. When you go and touch them the aluminium seems colder than wood. Select the correct option. Assume room temperature to be 25°.(a) Both have the same temperature greater than 25°(b) Aluminium has a greater temperature than wooden piece(c) Aluminium has a lower temperature than wooden piece(d) Both have the same temperature equal to 25°I have been asked this question in an interview.My question comes from Temperature and Heat in division Thermal Properties of Matter of Physics – Class 11

Answer» CORRECT option is (d) Both have the same temperature equal to 25°

The explanation: Both have been left in a room for a few HOURS, so both will have the same temperature as that of the room. The only reason ALUMINIUM feels colder is because it CONDUCTS heat away from our body faster than wood.
30.

What is the value of coefficient of volume expansion for an ideal gas?(a) (ΔV/V)/Δ T(b) 2*coefficient of linear expansion(c) 1/3 * coefficient of linear expansion(d) (V/ΔV)/ Δ TThis question was addressed to me in a job interview.My question comes from Thermal Expansion topic in chapter Thermal Properties of Matter of Physics – Class 11

Answer» CORRECT answer is (a) (ΔV/V)/Δ T

Easy explanation: ΔV/V = α*ΔT⇒ α = (ΔV/V)/ΔT.Note that the coefficient of volume expansion is 3 TIMES the coefficient of LINEAR expansion.
31.

The value of coefficient of thermal expansion is always the same for a material. True or False?(a) True(b) FalseThis question was posed to me in an interview for job.My query is from Thermal Expansion topic in division Thermal Properties of Matter of Physics – Class 11

Answer»

Right answer is (b) False

Best explanation: The coefficient of thermal expansion is constant over a range of TEMPERATURE, but is not always constant. It DEPENDS on temperature. For eg: the GRAPH of coefficient of volume expansion of copper with temperature is shown below.

32.

Why can any low density gas be used in a constant volume gas thermometer?(a) All low density gases show the same expansion behaviour(b) They are easy to handle(c) Their pressure variation is proportional to square of the change in temperature(d) The given statement is not trueThe question was posed to me during an interview.Origin of the question is Thermal Properties of Matter in portion Thermal Properties of Matter of Physics – Class 11

Answer»

Correct ANSWER is (a) All LOW density gases show the same expansion behaviour

Explanation: It has been experimentally shown that low density gases show similar expansion behaviour. If we keep the gas’s VOLUME constant pressure increases monotonically with increasing temperature. HENCE, we can use any low density gas for a constant volume gas thermometer.

33.

A body has a temperature of 200°C and is kept in a room containing air at 25°C. We can use Newton’s law of cooling. True or False?(a) True(b) FalseThe question was asked in an interview for internship.Origin of the question is Thermal Properties of Matter in portion Thermal Properties of Matter of Physics – Class 11

Answer»

Correct answer is (B) False

To EXPLAIN: NEWTON’s law of cooling can only be USED when the temperature difference is small which is not the case in the given scenario. So, the given STATEMENT is false.

34.

Why is water used in automobiles as a coolant?(a) It is not toxic for the environment(b) It has a high specific heat capacity(c) It has a high lubricating property which in turn keeps the engine cool by reducing friction(d) It is available in abundanceI have been asked this question by my school teacher while I was bunking the class.I would like to ask this question from Thermal Properties of Matter topic in section Thermal Properties of Matter of Physics – Class 11

Answer» CORRECT option is (b) It has a high specific HEAT capacity

The best I can explain: Water has a high specific heat capacity because of which it can absorb LARGE amounts of heat before increasing its temperature. Hence, it is USED as a coolant.
35.

What is the value of gas constant?(a) 8.314 kJ mol^-1K^-1(b) 8.314 L atm mol^-1K^-1(c) 0.0821 L atm mol^-1K^-1(d) It is equal to the constant in PV/T = constantI had been asked this question in an interview for internship.Question is taken from Thermal Properties of Matter in portion Thermal Properties of Matter of Physics – Class 11

Answer»

Right CHOICE is (c) 0.0821 L ATM mol^-1K^-1

Explanation: The value of universal gas CONSTANT is 0.0821 L atm mol^-1K^-1.Or it is 8.314 J mol^-1K^-1.The constant in PV/T = constant depends on the number of moles taken.

36.

Boyle’s and Charle’s law are obeyed by low density gases only. True or False?(a) True(b) FalseThe question was posed to me in homework.The above asked question is from Thermal Properties of Matter topic in portion Thermal Properties of Matter of Physics – Class 11

Answer»

Correct answer is (a) True

To explain I would say: Boyle’s and Charle’s law are used to ARRIVE at the ideal gas law. And the ideal gas law is based on the ASSUMPTIONS of kinetic THEORY of gases, which are only valid for LOW density gases. For eg: the assumption that molecules exert no forces on each other can only be considered for low density.

37.

The electromagnetic energy emitted by a perfect radiator corresponding to a temperature T and surface area A is?(a) AσT^4Δt, in unit time Δt(b) AeσT^4Δt, in unit time Δt(c) Ae4 c) AeσT^4(d) AσT^4This question was posed to me in a national level competition.The question is from Thermal Properties of Matter in portion Thermal Properties of Matter of Physics – Class 11

Answer»

The correct OPTION is (a) AσT^4Δt, in UNIT time Δt

The EXPLANATION: The relation of ENERGY is given by Stefan-Boltzman law:Energy per unit time = AσT^4, where σ is called the Stefan-Boltzman constant.∴ Energy =AσT^4Δt, in unit time Δt.

38.

Select the correct statement for melting of any substance.(a) It occurs at the same temperature as that of vapourization(b) It is exothermic in nature(c) It occurs at 100°C(d) It requires heat to be supplied to the substanceThis question was addressed to me by my school teacher while I was bunking the class.Question is from Thermal Properties of Matter in chapter Thermal Properties of Matter of Physics – Class 11

Answer»

The correct choice is (d) It requires heat to be supplied to the SUBSTANCE

Easy explanation: Melting is the CONVERSION of solid to liquid at constant temperature. It is endothermic and the melting temperature varies from substance to substance and also on atmospheric CONDITIONS like pressure.

39.

Condensation temperature is the same as evaporation temperature. True or False?(a) True(b) FalseThe question was posed to me in an internship interview.This question is from Thermal Properties of Matter in division Thermal Properties of Matter of Physics – Class 11

Answer»

The CORRECT option is (a) True

To explain I would say: Condensation is the CONVERSION of vapour to liquid, while evaporation is the conversion of liquid to vapour. Both occur at the same temperature, the only DIFFERENCE being that heat is removed in the former and added in the latter. The graph as shown below is a straight LINE at constant temperature.

40.

30g water at 30°C is mixed with 1g of steam at 100℃. Calculate the final temperature of the mixture. Sw = 1cal/ g°C, Lvap= 540cal/g.(a) 49.67°C(b) 38.33°C(c) 53.67°C(d) 41.33°CThis question was addressed to me in an online quiz.My question is taken from Thermal Properties of Matter in section Thermal Properties of Matter of Physics – Class 11

Answer» CORRECT option is (a) 49.67°C

The best EXPLANATION: 30*1*(T-30) = 1*540 + 1*1*(100-T)

∴ 30T – 900 = 540 + 100 – T

31T = 1540

⇒ T = 49.67°C
41.

A closed container contains 0.6m^3 of neon gas at 200K temperature and 1.3*10^5Pa. Find the rise in temperature when 8360 J of heat is supplied to it. The molar heat capacity of neon at constant volume is 3.2calK^-1mol^-1. Assume the container doesn’t expand on heating.(a) 13.3K(b) 15.8K(c) 13.9K(d) 15KThe question was posed to me by my college director while I was bunking the class.This is a very interesting question from Thermal Properties of Matter topic in chapter Thermal Properties of Matter of Physics – Class 11

Answer»

Correct CHOICE is (a) 13.3K

For explanation I WOULD say: no. of MOLES of neon gas = pV/RT

= (1.3*10^5*0.6) / (8.31*200)

= 46.9 moles ≅ 47 moles

ΔQ = nCVΔTΔT = ΔQ/nCV

= (8360/4.18) / (47*3.2)

= 13.3K.

42.

CV of a gas is 8 calK^-1mol^-1. Find CP/CV. Assume R = 2 calK^-1mol^-1.(a) 1.4(b) 1.33(c) 1.25(d) 1.8The question was posed to me in an online interview.My question is from Thermal Properties of Matter in portion Thermal Properties of Matter of Physics – Class 11

Answer»

The correct ANSWER is (C) 1.25

To EXPLAIN: CP = CV + R = 8 + 2

= 10 calK^-1mol^-1.

CP/CV= 10 / 8 = 1.25.

43.

What happens to the boiling point of water in a container when the container is completely closed by a lid?(a) Increases(b) Decreases(c) Remains same(d) Boiling point is characteristic of a substanceI got this question by my college director while I was bunking the class.This intriguing question originated from Thermal Properties of Matter topic in division Thermal Properties of Matter of Physics – Class 11

Answer»

Correct answer is (a) Increases

Best explanation: BOILING occurs when vapour pressure of liquid is the same as atmospheric pressure. The vapour pressure increases with increase in temperature. So when temperature has been INCREASED sufficiently boiling starts. But with increase in pressure at HIGHER vapour pressure has to be REACHED which is obtained by INCREASING temperature and therefore we say boiling point increases.

44.

What is the definition of 1 calorie?(a) It is the heat required to raise the temperature of 1g of water from 14.5°C to 15.5°C at 760mm Hg(b) It is the heat required to raise the temperature of 1g of any substance by 14.5°C to 15.5°C at 760mm Hg(c) It is the heat required to raise temperature of 1g of water by 1°C at 760mm Hg(d) It corresponds to the heat supplied at 760mm Hg for 1°C raise in temperatureI got this question during an online interview.Question is from Thermal Properties of Matter in division Thermal Properties of Matter of Physics – Class 11

Answer»

Right answer is (a) It is the HEAT required to RAISE the temperature of 1g of water from 14.5°C to 15.5°C at 760mm Hg

Easy explanation: A CALORIE is the unit of energy and is defined as the amount of heat required to raise the temperature of 1g of water from 14.5°C to 15.5°C at 760mm Hg.Its VALUE is 4.18 joules.Note that the calories we read behind food packets correspond to the amount of heat that quantity of food provides to our BODY which it uses for functioning.

45.

What is the principle of a calorimeter?(a) Heat loss rate is directly proportional to temperature difference(b) The total heat lost by a hot body is same as the total heat gained by the cold body provided no heat is lost to the surroundings(c) Heat loss depends only on specific heat of a substance(d) For the same amount of heat flow from a sample to two different samples of same mass is a product of their specific heats and temperature differenceThis question was posed to me at a job interview.I want to ask this question from Thermal Properties of Matter topic in section Thermal Properties of Matter of Physics – Class 11

Answer»

Right choice is (b) The total heat lost by a HOT body is same as the total heat gained by the cold body provided no heat is lost to the surroundings

To elaborate: The principle of calorimeter STATES that heat lost by a hot body is the same as the heat gained by the cold body provided no heat is lost to the surroundings. The other statement that states that the AMOUNT of heat flow from a sample to TWO different samples of same mass is a product of their specific heats and temperature difference is true but it is not the principle of CALORIMETRY. It is just a mathematical way of understanding heat transfer.

46.

Boyle’s law and Charle’s law together form which law?(a) PV/T = constant(b) PV^2/T = constant(c) PV = constant(d) V/T = constantI got this question in final exam.I would like to ask this question from Thermal Properties of Matter in chapter Thermal Properties of Matter of Physics – Class 11

Answer»

Correct option is (a) PV/T = constant

For explanation: BOYLE’s law states that P ∝ 1/V.Charle’s law states that V ∝ T.

From this we can say thatV ∝ T/P OR PV/T = constant.Note that this is the ideal GAS law.

47.

A uniform metal sheet has a hole in its centre. What happens to hole when the sheet is uniformly heated?(a) Its size increases(b) Its size decreases(c) It changes shape(d) Remains the same sizeThis question was posed to me in semester exam.I'd like to ask this question from Thermal Expansion in section Thermal Properties of Matter of Physics – Class 11

Answer»

Right option is (a) Its SIZE increases

The explanation: The hole’s circumference is made of metal. When the sheet is heated this circular circumference will EXPAND and THEREFORE the size of hole will INCREASE. The hole will not get deformed as the sheet is uniform in all directions from the centre of hole and is also heated uniformly.

48.

Temperature is 300K. Convert it into ℉.(a) 47°F(b) 80.6°F(c) 27°F(d) 16.6°FThis question was posed to me by my college professor while I was bunking the class.I'm obligated to ask this question of Measurement of Temperature in division Thermal Properties of Matter of Physics – Class 11

Answer»

The correct OPTION is (b) 80.6°F

The explanation is: TEMPERATURE in K = 273 + temp in °C.

∴ Temp in °C = 300-273 = 27

°F = (9/5) °C + 32

= (9/5)*27 + 32

= 80.6°F.

49.

If 5g of a solid requires 30cal of heat to change into liquid at the same temperature, calculate the latent heat of fusion in cal/g.(a) 150(b) 0.167(c) 6(d) 3I had been asked this question at a job interview.I'm obligated to ask this question of Thermal Properties of Matter topic in division Thermal Properties of Matter of Physics – Class 11

Answer»

The correct CHOICE is (C) 6

Easiest explanation: For changing a solid into liquid, HEAT has to be supplied and this change occurs at constant temperature.Q = mL

⇒ 30 = 5L

⇒ L = 6 cal/g,

50.

What is the value of Wien’s constant?(a) 2.9*10^-3mK(b) 2.9*10^-4mK(c) 2.9*10^-3cmK(d) 2.9*10^-4cmKThis question was addressed to me in a job interview.Asked question is from Thermal Properties of Matter topic in chapter Thermal Properties of Matter of Physics – Class 11

Answer»

Right answer is (a) 2.9*10^-3mK

The BEST explanation: Wein’s displacement law states that the PRODUCT of temperature and wavelength CONTRIBUTING the most to ENERGY is a constant equal to 2.9*10^-3mK.