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51.	If we supply equal amounts of heat to equal masses of two different substances, the rise in temperature will be the same for both. True or False?(a) True(b) FalseThis question was addressed to me during an online exam.This intriguing question originated from Thermal Properties of Matter in chapter Thermal Properties of Matter of Physics – Class 11
Answer» CORRECT option is (b) False The BEST I can EXPLAIN: Each body has a heat capacity which indicates the amount of heat it requires to raise its temperature by 1°C. Different SUBSTANCES require different AMOUNTS of heat for the same rise in temperature.

52.	It is possible that with decrease in temperature volume may increase. True or False?(a) True(b) FalseI had been asked this question in a job interview.Question is from Thermal Expansion topic in chapter Thermal Properties of Matter of Physics – Class 11
Answer» RIGHT OPTION is (a) True For EXPLANATION: Usually with increase in temperature volume increases. But water shows ANOMALOUS behaviour when cooled from 4℃ to 0℃. Its volume increases when it is cooled from4℃ to 0℃, while ONE would expect volume to decrease with decrease in temperature.

53.	What is the expression for heat current? Q is heat, t is time, T is temperature.(a) ΔQ/Δt(b) ΔQ/ΔT(c) ΔT/Δt(d) ΔQ/ΔTΔtThe question was asked at a job interview.My doubt is from Thermal Properties of Matter topic in division Thermal Properties of Matter of Physics – Class 11
Answer» Correct answer is (a) ΔQ/Δt To ELABORATE: Heat current is the amount of heat crossing per UNIT time through any cross SECTION. So, its EXPRESSION can be written as ΔQ/Δt.

54.	In a constant volume gas thermometer, the pressure of liquid, at a temperature of 27°C, being measured corresponds to 50cm of mercury. If the temperature increases by 20K, find the pressure.(a) 53.33cm(b) 87.03cm(c) 65.33cm(d) 97.03cmThe question was asked during an interview for a job.This is a very interesting question from Thermal Properties of Matter topic in portion Thermal Properties of Matter of Physics – Class 11
Answer» Right choice is (a) 53.33cm To ELABORATE: For a CONSTANT volume GAS thermometer, P/T =constant. P1/T1 = P2/T2∴ P2 = P1/T1 * T2 = 50/300 * 320 = 53.33cm.

55.	A calorimeter does not involve measurement of temperature. True or False?(a) True(b) FalseI have been asked this question in semester exam.I want to ask this question from Thermal Properties of Matter in division Thermal Properties of Matter of Physics – Class 11
Answer» Right choice is (b) False For explanation I would say: A calorimeter is a DEVICE which measures heat FLOW. It calculates the temperature change and ALONG with the knowledge of mass and SPECIFIC heat, it we can calculate heat by using the formula: Q = msΔT.

56.	CP > CV always. True or False?(a) True(b) FalseThis question was posed to me in final exam.I'd like to ask this question from Thermal Properties of Matter in section Thermal Properties of Matter of Physics – Class 11
Answer» Correct option is (a) True To elaborate: When heat is added at constant pressure the heat is USED to INCREASE temperature and increase VOLUME or we can say does work. But when heat is added at constant volume the heat only INCREASES temperature and volume REMAINS the same (work = 0). So For the same rise in temperature at constant pressure we have to provide more heat.

57.	A rod having α = 110^-5per °C and length of 70cm has one of its end rigidly connected to another rod of length 1m and α= 0.510^-5per °C. Find the new length of the two joined rods when their temperature is increased by 30℃.(a) 170.021cm(b) 169.021cm(c) 171.031cm(d) 170.031cmThis question was posed to me in semester exam.My doubt is from Thermal Expansion in division Thermal Properties of Matter of Physics – Class 11
Answer» Correct OPTION is (a) 170.021cm For explanation I would say: The NEW length of first rod: I1 = 70(1+110^-530) = 70.021cm Similarly I2 = 100(1+ 0.510^-530) = 100.015cmTherefore, new length = 70.021 + 100.015 = 170.036cm.

58.	What is the unit of coefficient of area expansion?(a) per °C(b) °C(c) per (°C)^2(d) (°C)^2The question was posed to me during an interview for a job.Question is taken from Thermal Expansion topic in chapter Thermal Properties of Matter of Physics – Class 11
Answer» The CORRECT ANSWER is (a) per °C Explanation: The coefficient of area expansion is defined as (ΔA/A)/ΔT. So we see that its unit is per °C. Note that all the coefficients of THERMAL expansion, NAMELY LINEAR, area & volume have the same unit.

59.	What is considered as zero point on the Kelvin scale?(a) -273.15K(b) -273.15°C(c) 0°C(d) -273.15°CI have been asked this question during an online exam.The above asked question is from Thermal Properties of Matter in section Thermal Properties of Matter of Physics – Class 11
Answer» The CORRECT choice is (B) -273.15°C Best explanation: Zero point on the KELVIN scale is absolute zero point.This corresponds to the temperature of -273.15°C.Also note that the kelvin scale and celsius scale have the same SIZE of unit,so K = 273.15 + °C.

60.	The temperature of 50g of water has to be risen from 15°C to 85°C by using steam at 120°C. What is the amount of steam, in gms, required for the same? Sw= 1cal/ g°C, Lvap = 540cal/g, Ssteam =0.48cal/g°C.(a) 6.29g(b) 8.34g(c) 7.22g(d) 6.19gThis question was addressed to me during an interview for a job.The origin of the question is Thermal Properties of Matter topic in section Thermal Properties of Matter of Physics – Class 11
Answer» The correct choice is (d) 6.19g To explain: HEAT lost by steam = Heat gained by WATER. Let ‘m’ be the mass of steam required. ∴ mSsteam (120-100) + mLvap + MSW (100-85) = 50Sw (85-15)The only variable is ‘m’. On CALCULATING it from the above equation, we get: m = 6.19g.