The temperature of 50g of water has to be risen from 15°C to 85°C by using steam at 120°C. What is the amount of steam, in gms, required for the same? Sw= 1cal/ g°C, Lvap = 540cal/g, Ssteam =0.48cal/g°C.(a) 6.29g(b) 8.34g(c) 7.22g(d) 6.19gThis question was addressed to me during an interview for a job.The origin of the question is Thermal Properties of Matter topic in section Thermal Properties of Matter of Physics – Class 11

The temperature of 50g of water has to be risen from 15°C to 85°C by

1.	The temperature of 50g of water has to be risen from 15°C to 85°C by using steam at 120°C. What is the amount of steam, in gms, required for the same? Sw= 1cal/ g°C, Lvap = 540cal/g, Ssteam =0.48cal/g°C.(a) 6.29g(b) 8.34g(c) 7.22g(d) 6.19gThis question was addressed to me during an interview for a job.The origin of the question is Thermal Properties of Matter topic in section Thermal Properties of Matter of Physics – Class 11
Answer» The correct choice is (d) 6.19g To explain: HEAT lost by steam = Heat gained by WATER. Let ‘m’ be the mass of steam required. ∴ mSsteam (120-100) + mLvap + MSW (100-85) = 50Sw (85-15)The only variable is ‘m’. On CALCULATING it from the above equation, we get: m = 6.19g.

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