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What should be the temperature of 1g of ice, so that when it’s added to 9g of water, lowers the temperature of water by 10°C?Sw = 1cal/ g°C, Sice = 0.5cal/ g°C, Lfus= 80cal/g.(a) 20°C(b) -20°C(c) 0°C(d) 10°CI got this question by my college professor while I was bunking the class.The above asked question is from Thermal Properties of Matter in chapter Thermal Properties of Matter of Physics – Class 11

Answer»

Correct answer is (b) -20°C

For EXPLANATION: LET the initial temperature of ice be T°C.HEAT lost by ice will be the same as the heat lost by water.

1*0.5*(0-T) + 1*80 = 9*1*10⇒ T = -20°C.



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