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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.

A block of mass 1kg is given a velocity of 5m/s on a horizontal flat surface. What will be the change in internal energy of the block-surface system, when the block comes to rest. The coefficient of kinetic friction is 0.3 and coefficient of static friction is 0.4.(a) 25J(b) 12.5J(c) 0(d) 30JThe question was asked in an internship interview.This intriguing question comes from First Law of Thermodynamics topic in chapter Thermodynamics of Physics – Class 11

Answer»

Right OPTION is (B) 12.5J

The best explanation: The kinetic ENERGY of the BLOCK will change into internal energy of the system.

Initial kinetic energy = 0.5*1*25 = 12.5J.

Therefore the internal energy change = 12.5J.

2.

Two bodies in thermal equilibrium can have different pressures. True or False?(a) True(b) FalseI had been asked this question in an international level competition.Enquiry is from Thermal Equilibrium in chapter Thermodynamics of Physics – Class 11

Answer»

The correct option is (a) True

Easy explanation: Two bodies are said to be in THERMAL equilibrium if they don’t exchange heat ENERGY when they are in physical CONTACT. For this only their temperatures have to be the same. Pressure and VOLUME will depend upon OTHERS properties like mass.

3.

20J of heat energy is extracted from a cold reservoir when 30J of work is done on a refrigerator. What is the coefficient of the refrigerator?(a) 2/3(b) 5/3(c) 3/5(d) 1/3I have been asked this question during an interview.This question is from Thermodynamics topic in portion Thermodynamics of Physics – Class 11

Answer»

Right CHOICE is (a) 2/3

Explanation: The coefficient of a refrigerator is defined as α = Q2/W,where Q2 is heat extracted from a COLD RESERVOIR and W is work done.

α = 20/30 = 2/3.

4.

What is the relation between work obtained in an reversible and irreversible process?(a) Wrev > Wirr(b) Wrev < Wirr(c) Wrev = Wirr(d) It depends on change in temperatureThe question was asked in quiz.I'd like to ask this question from Thermodynamics in division Thermodynamics of Physics – Class 11

Answer»

Correct OPTION is (a) Wrev > Wirr

Explanation: A process is irreversible due to dissipative forces or free EXPANSION or EXPLOSIVE chemical reactions and so on. This causes it to lose the amount of USEFUL work that can be done in an irreversible process. This is not the case for a reversible process. Hence, Wrev > Wirr.

5.

What is a quasi-static process?(a) Irreversible(b) Reversible(c) In equilibrium at every state(d) Not involving frictionI have been asked this question during an interview.I would like to ask this question from Thermodynamics topic in division Thermodynamics of Physics – Class 11

Answer»

Right option is (c) In equilibrium at every state

To explain: A quasi static process is one in which each stage is in equilibrium with its SURROUNDINGS. There may be a process which may be quasi static and also involve heat transfer with SURROUNDING and will THEREFORE be irreversible. A process may not involve friction and be a free expansion of GAS and therefore can’t be quasi static.

6.

Which law of thermodynamics says that efficiency of a heat engine cannot be 1?(a) First(b) Zeroth(c) Second(d) ThirdThis question was posed to me in exam.Origin of the question is Second Law of Thermodynamics in section Thermodynamics of Physics – Class 11

Answer» RIGHT option is (c) Second

Explanation: The second law of thermodynamics fundamentally disallows many processes that may be consistent with the law of conservation of energy. It SAYS that ENTROPY change in an irreversible PROCESS has to be positive. This means that heat given to an engine can’t all be converted into work. Therefore, efficiency cannot be 1.
7.

Select the correct statement.(a) Internal energy is a path variable(b) Heat is a path variable(c) Work done is a state variable(d) Internal energy is a microscopic variableI have been asked this question by my school teacher while I was bunking the class.This intriguing question originated from Thermodynamics topic in chapter Thermodynamics of Physics – Class 11

Answer»

Correct choice is (b) HEAT is a path variable

Explanation: INTERNAL energy CORRESPONDS to the mechanical energy of molecules. It is a state variable as it doesn’t DEPEND on the path taken. While heat is the energy in transit, so it is a path variable. Internal energy is a thermodynamic variable and is therefore macroscopic as thermodynamics deals with bulk SYSTEMS.

8.

The variables like pressure, volume, temperature of a thermodynamic system are microscopic. True or False?(a) True(b) FalseI got this question in an online quiz.This is a very interesting question from Thermal Equilibrium in section Thermodynamics of Physics – Class 11

Answer» RIGHT choice is (b) False

For explanation: THERMODYNAMICS does not deal with molecular descriptions. The variables it describes like PRESSURE, VOLUME & temperature are for a very large COLLECTION of molecules. Hence, the thermodynamic properties are macroscopic.
9.

First law of thermodynamics is based on?(a) Conservation of energy(b) Conservation of mass(c) Conservation of momentum(d) Conservation of workThe question was asked in an online interview.I need to ask this question from First Law of Thermodynamics topic in portion Thermodynamics of Physics – Class 11

Answer»

The correct option is (a) Conservation of ENERGY

To elaborate: The first law of THERMODYNAMICS is based on the conservation of energy. It DEALS with work done and heat energy supplied or removed from a SYSTEM. It basically says that energy supplied to a system is CONSERVED.

10.

What will be the value of temperature of hot reservoir in a carnot cycle, if the temperature of cold reservoir is 25°C, heat absorbed from hot reservoir is 12J and heat rejected to cold reservoir is 4J?(a) 684K(b) 333.33K(c) 894K(d) 433.33KI got this question in an interview for job.My enquiry is from Thermodynamics in section Thermodynamics of Physics – Class 11

Answer»

Correct answer is (C) 894K

The BEST I can EXPLAIN: For a carnot CYCLE: Q2/Q2 = T2/T1.

T2 = 12/4 * 298 = 894K.

11.

What is the correct order of steps for a carnot cycle?(a) Isothermal expansion, adiabatic expansion, isothermal compression, adiabatic compression(b) Isothermal compression, adiabatic expansion, isothermal expansion, adiabatic compression(c) Adiabatic compression, adiabatic expansion, isothermal expansion, isothermal compression(d) Adiabatic compression, isothermal expansion, adiabatic expansion, isothermal compressionThe question was posed to me in semester exam.My question comes from Thermodynamics topic in portion Thermodynamics of Physics – Class 11

Answer»

The correct choice is (a) Isothermal expansion, adiabatic expansion, isothermal compression, adiabatic compression

Explanation: A carnot cycle is a reversible cyclic process having the maximum POSSIBLE EFFICIENCY. The STEPS of the cycle are: isothermal expansion of gas, adiabatic expansion, isothermal compression and then adiabatic compression. This is evident from its PV diagram:

12.

A process is carried out between 2 systems. It is possible for entropy of one system to decrease. True or False?(a) True(b) FalseThe question was asked during a job interview.The question is from Second Law of Thermodynamics topic in section Thermodynamics of Physics – Class 11

Answer» RIGHT choice is (a) True

Explanation: The net entropy CHANGE has to be positive. It is possible for the entropy of a SYSTEM to DECREASE, but the entropy of the second system should increase enough to ensure net entropy increases.
13.

What is the coefficient of performance of a refrigerator? Let Q1 be the heat released to hot reservoir, Q2 be the heat extracted from a cold reservoir & W be the work done on the refrigerator.(a) Q1/W(b) Q1/Q2(c) Q2/W(d) Q2/Q1The question was asked at a job interview.My doubt is from Thermodynamics in chapter Thermodynamics of Physics – Class 11

Answer»

Right answer is (c) Q2/W

To explain I would say: COEFFICIENT of performance of a refrigerator is DEFINED as the RATIO of heat EXTRACTED from the cold reservoir to the work DONE on the refrigerator.It is denoted by α = Q2/W.

14.

Which of the following variables is intensive?(a) Internal energy(b) volume(c) Temperature(d) Total massI had been asked this question during an online interview.I'm obligated to ask this question of Thermodynamic State Variables and Equation of State topic in chapter Thermodynamics of Physics – Class 11

Answer» RIGHT option is (c) TEMPERATURE

To explain: Intensive properties are those which don’t DEPEND on the AMOUNT of matter in the sample. For eg: temperature, PRESSURE, density.
15.

A carnot engine extracts 1200J of energy from a hot reservoir. What is the amount of work done by it? Temperatures of hot and cold reservoirs are 200K and 150K respectively.(a) 800J(b) 900J(c) 600J(d) 850JThis question was addressed to me during an online interview.The origin of the question is Thermodynamics topic in section Thermodynamics of Physics – Class 11

Answer»

The correct option is (b) 900J

For EXPLANATION: The EFFICIENCY of a carnot ENGINE is:

1- T2/T1 = 1-150/200 = 1/4.

Efficiency is also given by: 1 – Q2/Q1 = 1 – Q2/1200 = 1/4.

Q2 = 3/4 *1200 = 900J.

16.

Zeroth law of thermodynamics helped in the creation of which scale?(a) Temperature(b) Heat energy(c) Pressure(d) Internal energyThe question was asked in class test.This intriguing question comes from Zeroth Law of Thermodynamics in section Thermodynamics of Physics – Class 11

Answer»

The correct option is (a) Temperature

Easy explanation: Zeroth law of thermodynamics talks about thermal equilibrium or RELATES bodies having no heat flow. Temperature difference is what leads to heat flow. So, this law helped in MAKING temperature MEASURABLE and an UNIVERSAL property of MATTER.

17.

Which of the following is the Kelvin Planck statement?(a) Heat from a cold reservoir cannot be transferred to a hot reservoir without external work(b) Efficiency for a reversible cyclic process can be 1(c) Heat from a hot reservoir can be completely converted into work if process is reversible(d) Efficiency of a heat engine is less than 1I had been asked this question in unit test.This key question is from Second Law of Thermodynamics in division Thermodynamics of Physics – Class 11

Answer» CORRECT option is (d) Efficiency of a HEAT engine is less than 1

For explanation: Kelvin Planck STATEMENT is: No process is possible whose sole RESULT is the absorption of heat from a reservoir and complete conversion of that heat into work. So, this implies that efficiency of a heat engine is less than 1.
18.

Select the correct order of steps in which a working substance(gas) goes through in a refrigerator.(a) Expansion of gas, absorption of heat, heating of vapour, release of heat(b) Absorption of heat, expansion of gas, heating of vapour, release of heat(c) Heating of vapour, expansion of gas, absorption of heat, release of heat(d) Heating of vapour, absorption of heat, expansion of gas, release of heatI got this question during an online interview.The query is from Thermodynamics topic in section Thermodynamics of Physics – Class 11

Answer»

Right answer is (a) Expansion of gas, absorption of HEAT, heating of vapour, release of heat

Best explanation: In a REFRIGERATOR, the WORKING substance(gas) first gets expanded from high to LOW pressure which cools it into a vapour-liquid mixture. Then heat is absorbed from the region to be COOLED. Then the external work done on the system heats up the vapour. Finally, the vapour’s heat is released to the surroundings.

19.

If 315cal of heat is given to the system, and the system does 20cal of work, find the change in internal energy.(a) 295cal(b) 335cal(c) 0 cal(d) 335JI have been asked this question by my college director while I was bunking the class.I need to ask this question from First Law of Thermodynamics in division Thermodynamics of Physics – Class 11

Answer»

Correct choice is (a) 295cal

To elaborate: The first LAW states that ΔU=ΔQ – ΔW

= 315 – 20

= 295cal.

Work is POSITIVE as it is done by the system. HEAT is positive as it is supplied to the system.

20.

Zeroth law of thermodynamics can be derived. It is not based on observation. True or False?(a) True(b) FalseThe question was posed to me in class test.Question is from Zeroth Law of Thermodynamics topic in division Thermodynamics of Physics – Class 11

Answer» CORRECT answer is (b) False

Best explanation: The ZEROTH LAW of thermodynamics is BASED PURELY on observation. This law may seem obvious but if a person, A, knows B & B knows C it’s not at all necessary for A to know C.
21.

Which of the following types of kinetic energies contribute to internal energy?(a) Translational(b) Rotational(c) Vibrational(d) Translational, Vibrational & RotationalThis question was posed to me in an online interview.I'd like to ask this question from Thermodynamics topic in chapter Thermodynamics of Physics – Class 11

Answer»

The correct answer is (d) Translational, Vibrational & Rotational

Best explanation: Internal energy CONSISTS of the total KINETIC energy of all MOLECULES, which means all TYPES, namely translational, rotational & vibrational kinetic energies contribute to internal energy.

22.

Isothermal process can be represented by which law?(a) Charle’s law(b) Boyle’s law(c) Gay-Lussac’s law(d) 2nd law of thermodynamicsThe question was asked by my college professor while I was bunking the class.My enquiry is from Thermodynamic Processes topic in portion Thermodynamics of Physics – Class 11

Answer»

Right option is (b) BOYLE’s law

To explain I would say: In an isothermal process, PV=const. This is the same as Boyle’s law. Charle’s law is given by: V/T=const. Gay-Lussac’s law is given by: P/T=const and 2nd law of thermodynamics states that in EVERY process total entropy of the UNIVERSE MUST increase.

23.

The product of an extensive and intensive variable is?(a) Extensive(b) Intensive(c) Depends on temperature conditions(d) Depends on pressure conditionsThis question was posed to me in an online quiz.My question is taken from Thermodynamic State Variables and Equation of State topic in portion Thermodynamics of Physics – Class 11

Answer»

Correct answer is (a) EXTENSIVE

Easy explanation: The PRODUCT contains ONE term which is extensive, or which depends on mass, so we can say that their product also depends on mass and is therefore extensive.

24.

The second law of thermodynamics states that?(a) Entropy of an isolated system can never decrease over time(b) Entropy of a pure crystalline substance at 0K is 0(c) Energy is conserved(d) Entropy of a system can never decreaseThe question was posed to me by my school teacher while I was bunking the class.My question is based upon Second Law of Thermodynamics topic in section Thermodynamics of Physics – Class 11

Answer»

Correct answer is (a) Entropy of an isolated system can NEVER DECREASE over TIME

The explanation: The second LAW STATES that entropy of an isolated system can never decrease over time. There can be a system whose entropy decreases, but, at the same time in that process another system’s increase in entropy will more than compensate for that decrease.

25.

In a heat engine heat is converted to work and the process need not be cyclic. True or False?(a) True(b) FalseI had been asked this question in semester exam.The doubt is from Thermodynamics in section Thermodynamics of Physics – Class 11

Answer» CORRECT choice is (b) False

The explanation is: In HEAT engines heat is to be converted into work. The process is cyclic as we need the conversion of some heat into work for continuously CARRYING out our DESIRED OUTCOME.
26.

Which of the following variables is zero for a cyclic process?(a) Work done(b) Heat supplied(c) Total heat + Total work(d) Total heat – Total workI have been asked this question in an online interview.My doubt stems from Thermodynamic Processes in division Thermodynamics of Physics – Class 11

Answer»

Right answer is (d) Total heat – Total work

The best I can EXPLAIN: In a cyclic process, the starting POSITION is the same as the ENDING position. So, the change in all state variables is zero. So the NET change in internal energy is zero. ΔU = ΔQ – ΔW = 0.

27.

One end of a rod is held in a fire, while the other is held by one’s hand. Just assume his hand doesn’t get burned. After some time the rod-hand system is in thermal equilibrium. True or False?(a) True(b) FalseThis question was addressed to me in an interview.This question is from Thermal Equilibrium topic in chapter Thermodynamics of Physics – Class 11

Answer» CORRECT option is (b) False

Easiest explanation: In the given situation, after some time a STEADY STATE will be reached. That is temperature at INDIVIDUAL points will be constant, but there will be a DIFFERENCE of temperature between 2 points along the length of the rod. For, this heat flow will be continuous so we can’t call it thermal equilibrium.
28.

Calculate the work done by the gas in an isothermal process from A to B. PA = 1Pa, VA = 3m^3, PB = 3Pa.(a) 3.3J(b) 3J(c) -3.3J(d) -4.58JThis question was posed to me in a national level competition.My query is from Thermodynamic Processes in portion Thermodynamics of Physics – Class 11

Answer»

The correct OPTION is (c) -3.3J

To explain I would say: Since the process is ISOTHERMAL the PRODUCT PV will be constant.

PAVA =PBVB.

∴ VB = 1*3/3 = 1m^3.

Work done in an isothermal process is given by:

NRT*ln(VB/VA)

= PAVAln(VB/VA)

= 3ln(1/3)

= -3.3J.

29.

Which of the following is an extensive variable?(a) Volume(b) Pressure(c) Boiling point(d) ColorI had been asked this question in homework.My doubt stems from Thermodynamic State Variables and Equation of State in portion Thermodynamics of Physics – Class 11

Answer» RIGHT ANSWER is (a) VOLUME

Explanation: EXTENSIVE properties are those which depend on the amount of matter in the sample.For eg: Volume, Internal energy, mass.
30.

In which of the following processes is heat transfer equal to zero?(a) Isentropic(b) Isochoric(c) Isothermal(d) DiathermicThis question was addressed to me in an international level competition.The above asked question is from Thermodynamic Processes in division Thermodynamics of Physics – Class 11

Answer» RIGHT CHOICE is (a) Isentropic

For explanation: ENTROPY is defined as DQ/T. In an isentropic process dQ/T = 0 which means dQ = 0. Diathermic is a process in which heat flow is easily possible. Isochoric process is one in which VOLUME is constant. Isothermal process is one in which temperature stays constant.
31.

A body has 15J of heat energy in a particular state. At the same state it has an internal energy of 30J. Assume no work is done, what will happen to the internal energy if 5J of heat is added to the system?(a) Heat energy = 20J, Internal energy = 35J(b) Heat energy = 15J, Internal energy = 30J(c) Heat energy = 15J, Internal energy = 35J(d) A body cannot have heat energy in a particular stateI had been asked this question in an international level competition.Question is taken from Thermodynamics in division Thermodynamics of Physics – Class 11

Answer»

Correct ANSWER is (d) A BODY cannot have heat energy in a PARTICULAR state

Easiest explanation: Heat energy is the energy in transit. A SYSTEM’s state cannot be defined by heat energy, it is defined by internal energy. Heat and WORK are path functions. Heat can be supplied or removed from a system but can’t define a system in a state.

32.

At constant pressure P the volume of a gas increases from V1 to V2 when ‘Q’ amount of heat is removed from the system. What will happen to internal energy?(a) Remain the same if Q = P(V1 – V2)(b) Decrease by an amount P(V2 – V1) – Q(c) Decrease by an amount Q + P(V2 – V1)(d) Increase by some unknown amountThe question was posed to me during an internship interview.The doubt is from First Law of Thermodynamics in division Thermodynamics of Physics – Class 11

Answer»

Correct option is (c) DECREASE by an amount Q + P(V2 – V1)

Easiest explanation: The internal ENERGY will definitely decrease as both factors heat removal and work done by gas support the same. ΔU = ΔQ – ΔW = -Q – P(V2 – V1) = -(Q + P(V2 – V1)). THUS, we can say that internal energy DECREASES by an amount = Q + P(V2 – V1).

33.

If some heat is provided to a system and work is done on it, it is possible that internal energy will decrease. True or False?(a) True(b) FalseThe question was asked in class test.I'm obligated to ask this question of Thermodynamics in chapter Thermodynamics of Physics – Class 11

Answer» CORRECT ANSWER is (b) False

Explanation: Internal energy corresponds to the mechanical energy of the MOLECULES. When these molecules are provided with heat and are compressed their mechanical energy will increase. Both factors support the increase of internal energy hence the given statement is false.
34.

An engine works between 2 reservoirs of temperature 500K and 300K. A company claims that this engine of theirs takes 200J of energy from the hot reservoir and rejects 110J of energy. Is this True or False?(a) True(b) FalseThis question was addressed to me in examination.This question is from Thermodynamics in division Thermodynamics of Physics – Class 11

Answer»

Right answer is (b) False

The explanation: The maximum POSSIBLE efficiency is GIVEN by:

1 – Tcold/Thot = 1 – 300/500 = 0.4.

The company claims that their ENGINE has an efficiency of (200-110)/200 = 0.45.

This is not possible as maximum efficiency is 0.4.

35.

If an engine takes 5J of heat energy from a reservoir and rejects 3J to the surroundings, what is its efficiency?(a) 2/5(b) 3/5(c) 1/5(d) 0I have been asked this question in my homework.I'm obligated to ask this question of Thermodynamics topic in portion Thermodynamics of Physics – Class 11

Answer»

The correct ANSWER is (a) 2/5

Explanation: EFFICIENCY is DEFINED as work done/heat input.

Work done = 5-3=2J.

Heat input = 5J.

Thus, efficiency = 2/5.

36.

Which of the following is an example of reversible process?(a) Wood to ashes(b) Burning of matchstick(c) Making roti from wheat flour(d) Frictionless to and fro motionI had been asked this question by my college director while I was bunking the class.This intriguing question comes from Thermodynamics in section Thermodynamics of Physics – Class 11

Answer»

The correct option is (d) Frictionless to and FRO motion

For explanation I would say: In frictionless to and fro motion, no form of energy is lost so the PATH followed from one point to another can be exactly RETRACED. While the other three are chemical CHANGES and cannot be reversed.

37.

The efficiency of a carnot engine is 50%. The temperature of the hot reservoir is kept constant. By what amount should the temperature of the cold reservoir be decreased so that efficiency becomes 60%.(a) 1K(b) 2K(c) 30K(d) 83KThe question was asked in semester exam.This intriguing question originated from Thermodynamics in portion Thermodynamics of Physics – Class 11

Answer» CORRECT answer is (a) 1K

The best I can explain: 0.5 = 1 – TC/TH.

And 0.6 = 1 – (TC + x)/TH.

From the first equation we get: 5/10 = TC/TH.

From the second equation we get: 4/10 = (TC + x)/TH.

Now, we SEE that the value of x must be 1K.
38.

According to the first law of thermodynamics, a book lying on a table can fly upwards on its own by using the internal energy of the table. True or False?(a) True(b) FalseThe question was asked during an online interview.I'm obligated to ask this question of Second Law of Thermodynamics topic in chapter Thermodynamics of Physics – Class 11

Answer»

Right option is (a) True

Explanation: In the above said process, energy is conserved and ACCORDING to FIRST law, this is VALID. It only violates the second law. So, the GIVEN statement is true.

39.

In an isothermal process for an ideal gas, change in internal energy is zero. True or False?(a) True(b) FalseThis question was posed to me in unit test.My query is from Thermodynamic Processes topic in division Thermodynamics of Physics – Class 11

Answer»

The correct answer is (a) True

Explanation: For an ideal gas INTERNAL energy depends only on temperature. In an ISOTHERMAL process CHANGE in temperature is zero, hence internal energy ALSO remains the same.

40.

Equilibrium state of a thermodynamic system is described by path variables. True or False?(a) True(b) FalseI have been asked this question in quiz.This intriguing question comes from Thermodynamic State Variables and Equation of State topic in chapter Thermodynamics of Physics – Class 11

Answer»

Correct option is (b) False

Best explanation: PATH variables like WORK and HEAT can only tell us the difference between state variables of two states. For describing a particular state of a thermodynamic system we need state variables like pressure, temperature and volume.

41.

Internal energy of a system is defined as?(a) The sum of kinetic energies of all molecules of the system(b) The sum of kinetic and potential energies of all molecules of the system(c) The sum of potential energies of the system(d) The average kinetic energy of all moleculesThe question was asked during an interview.This is a very interesting question from Thermodynamics in division Thermodynamics of Physics – Class 11

Answer»

The correct OPTION is (b) The sum of kinetic and POTENTIAL energies of all molecules of the system

Explanation: The internal ENERGY of a system corresponds to the energy POSSESSED by all molecules. Thus it is the sum of kinetic and potential energies of all molecules in the system considered. Also note that potential energy is frame dependent, so we choose a frame in which the centre of mass is at rest.

42.

A box contains 10^5 molecules. The average kinetic energy of each molecule is 0.5*10^-6J. With respect to an observer at rest the box, having a mass of 1kg, is moving with a velocity of 2m/s. What is the value of kinetic energy that will contribute to the internal energy?(a) 0.05J(b) 2.05J(c) 0(d) 2JThe question was asked in semester exam.This interesting question is from Thermodynamics in section Thermodynamics of Physics – Class 11

Answer»

The correct option is (a) 0.05J

To ELABORATE: When calculating internal ENERGY of molecules, the system is to be studied from a FRAME in which the centre of mass is at rest.So the kinetic energy due to movement of the ENTIRE box will not be CONSIDERED.Only the individual kinetic energies of molecules will be considered, and their value is:10^5*0.5*10^-6

= 0.05J.

43.

Consider a gas contained in a rigid container of volume 20m^3. What will be the change in internal energy if 50J of heat is provided to it? Assume the gas exerts a pressure of 1atm on the walls.(a) 50J(b) 0(c) 70J(d) 20JI had been asked this question during an interview.My question is based upon First Law of Thermodynamics topic in chapter Thermodynamics of Physics – Class 11

Answer»

Correct CHOICE is (a) 50J

Easy explanation: All the heat supplied will be equal to change in internal energy.

The WORK DONE is zero because the container is rigid hence no VOLUME change.

Thus, ΔU = ΔQ – ΔW = 50 + 0 = 50J.

44.

The coefficient of a refrigerator can be greater than 1. True or False?(a) True(b) FalseThis question was addressed to me during an online exam.Origin of the question is Thermodynamics in section Thermodynamics of Physics – Class 11

Answer» RIGHT option is (a) True

The explanation is: The coefficient of a refrigerator is defined as α = Q2/W,

where Q2 is heat EXTRACTED from a cold reservoir and W is work done.

α = Q2/( Q1 – Q2).

Therefore α can be less than or greater than ONE.
45.

Efficiency of a refrigerator can be greater than 1. True or False?(a) True(b) FalseThe question was posed to me during an internship interview.This interesting question is from Thermodynamics in division Thermodynamics of Physics – Class 11

Answer»

Right answer is (b) False

For EXPLANATION I would say: Efficiency by DEFINITION can NEVER be greater than 1.Else the law of energy conservation will be VIOLATED.

46.

A cyclic process is always reversible. True or False?(a) True(b) FalseThe question was asked in an international level competition.The origin of the question is Thermodynamics topic in section Thermodynamics of Physics – Class 11

Answer»

Correct option is (b) False

To EXPLAIN I would say: A cyclic process is one in which the initial and final state is the same. The path need not be retraceable as in the case of a reversible process. For eg: a process COULD GO from A to B And then BACK to A, but via a DIFFERENT path.

47.

A disc spinning with 24J of kinetic energy is kept in a container containing a fluid having a heat capacity of 2000J/K. When the disc comes to rest what will be the change in internal energy if ΔU = 3.5ΔT.(a) 0(b) 0.042J(c) 0.021J(d) 0.028JThe question was posed to me in semester exam.This intriguing question originated from First Law of Thermodynamics topic in division Thermodynamics of Physics – Class 11

Answer»

Right answer is (B) 0.042J

The best I can explain: When the disc comes to REST all its kinetic energy will have been CONVERTED into INTERNAL energy of the system.

The fluid has a heat capacity of 2000J/K which MEANS that for 24J the change in temperature will be 24/2000 = 0.012K.

Given: ΔU = 3.5ΔT

⇒ ΔU = 3.5*0.012

= 0.042J.

48.

For any gas the equation is state is PV=nRT. True or False?(a) True(b) FalseI got this question by my college director while I was bunking the class.The question is from Thermodynamic State Variables and Equation of State in portion Thermodynamics of Physics – Class 11

Answer»

Correct OPTION is (B) False

For explanation I would say: Equation of state is a RELATION between state variables.Only in the case of ideal GASES it is PV=nRT.So, there is a difference between the ideal gas equation and the equation of state in general.

49.

ΔU=0 means that the process is isothermic. True or False?(a) True(b) FalseI had been asked this question during a job interview.This is a very interesting question from First Law of Thermodynamics topic in portion Thermodynamics of Physics – Class 11

Answer»

The CORRECT ANSWER is (a) True

Explanation: Internal energy is a function of temperature only. So if ΔU=0 implies that the process will have CONSTANT temperature, or it is ISOTHERMIC.