The efficiency of a carnot engine is 50%. The temperature of the hot reservoir is kept constant. By what amount should the temperature of the cold reservoir be decreased so that efficiency becomes 60%.(a) 1K(b) 2K(c) 30K(d) 83KThe question was asked in semester exam.This intriguing question originated from Thermodynamics in portion Thermodynamics of Physics – Class 11

The efficiency of a carnot engine is 50%. The temperature of the hot r

1.	The efficiency of a carnot engine is 50%. The temperature of the hot reservoir is kept constant. By what amount should the temperature of the cold reservoir be decreased so that efficiency becomes 60%.(a) 1K(b) 2K(c) 30K(d) 83KThe question was asked in semester exam.This intriguing question originated from Thermodynamics in portion Thermodynamics of Physics – Class 11
Answer» CORRECT answer is (a) 1K The best I can explain: 0.5 = 1 – TC/TH. And 0.6 = 1 – (TC + x)/TH. From the first equation we get: 5/10 = TC/TH. From the second equation we get: 4/10 = (TC + x)/TH. Now, we SEE that the value of x must be 1K.

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