1.

What will be the value of temperature of hot reservoir in a carnot cycle, if the temperature of cold reservoir is 25°C, heat absorbed from hot reservoir is 12J and heat rejected to cold reservoir is 4J?(a) 684K(b) 333.33K(c) 894K(d) 433.33KI got this question in an interview for job.My enquiry is from Thermodynamics in section Thermodynamics of Physics – Class 11

Answer»

Correct answer is (C) 894K

The BEST I can EXPLAIN: For a carnot CYCLE: Q2/Q2 = T2/T1.

T2 = 12/4 * 298 = 894K.



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