At constant pressure P the volume of a gas increases from V1 to V2 when ‘Q’ amount of heat is removed from the system. What will happen to internal energy?(a) Remain the same if Q = P(V1 – V2)(b) Decrease by an amount P(V2 – V1) – Q(c) Decrease by an amount Q + P(V2 – V1)(d) Increase by some unknown amountThe question was posed to me during an internship interview.The doubt is from First Law of Thermodynamics in division Thermodynamics of Physics – Class 11

At constant pressure P the volume of a gas increases from V1 to V2 whe

1.	At constant pressure P the volume of a gas increases from V1 to V2 when ‘Q’ amount of heat is removed from the system. What will happen to internal energy?(a) Remain the same if Q = P(V1 – V2)(b) Decrease by an amount P(V2 – V1) – Q(c) Decrease by an amount Q + P(V2 – V1)(d) Increase by some unknown amountThe question was posed to me during an internship interview.The doubt is from First Law of Thermodynamics in division Thermodynamics of Physics – Class 11
Answer» Correct option is (c) DECREASE by an amount Q + P(V2 – V1) Easiest explanation: The internal ENERGY will definitely decrease as both factors heat removal and work done by gas support the same. ΔU = ΔQ – ΔW = -Q – P(V2 – V1) = -(Q + P(V2 – V1)). THUS, we can say that internal energy DECREASES by an amount = Q + P(V2 – V1).

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