The sun emits light having maximum intensity at a wavelength 468nm. Assume emissivity of sun is 1. Calculate its surface temperature. σ= 5.67*10^-8W/m^2K^4.(a) 6800K(b) 3400K(c) 6196K(d) 7200KI had been asked this question by my college professor while I was bunking the class.Origin of the question is Thermal Properties of Matter in section Thermal Properties of Matter of Physics – Class 11

The sun emits light having maximum intensity at a wavelength 468nm. As

1.	The sun emits light having maximum intensity at a wavelength 468nm. Assume emissivity of sun is 1. Calculate its surface temperature. σ= 5.67*10^-8W/m^2K^4.(a) 6800K(b) 3400K(c) 6196K(d) 7200KI had been asked this question by my college professor while I was bunking the class.Origin of the question is Thermal Properties of Matter in section Thermal Properties of Matter of Physics – Class 11
Answer» RIGHT CHOICE is (c) 6196K The explanation: USING WEIN’s displacement law: λT = 2.910^-3, we get T = 2.910^-3/(468*10^-9) = 6196 K.

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