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30g water at 30°C is mixed with 1g of steam at 100℃. Calculate the final temperature of the mixture. Sw = 1cal/ g°C, Lvap= 540cal/g.(a) 49.67°C(b) 38.33°C(c) 53.67°C(d) 41.33°CThis question was addressed to me in an online quiz.My question is taken from Thermal Properties of Matter in section Thermal Properties of Matter of Physics – Class 11

Answer» CORRECT option is (a) 49.67°C

The best EXPLANATION: 30*1*(T-30) = 1*540 + 1*1*(100-T)

∴ 30T – 900 = 540 + 100 – T

31T = 1540

⇒ T = 49.67°C


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