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A closed container contains 0.6m^3 of neon gas at 200K temperature and 1.3*10^5Pa. Find the rise in temperature when 8360 J of heat is supplied to it. The molar heat capacity of neon at constant volume is 3.2calK^-1mol^-1. Assume the container doesn’t expand on heating.(a) 13.3K(b) 15.8K(c) 13.9K(d) 15KThe question was posed to me by my college director while I was bunking the class.This is a very interesting question from Thermal Properties of Matter topic in chapter Thermal Properties of Matter of Physics – Class 11

Answer»

Correct CHOICE is (a) 13.3K

For explanation I WOULD say: no. of MOLES of neon gas = pV/RT

= (1.3*10^5*0.6) / (8.31*200)

= 46.9 moles ≅ 47 moles

ΔQ = nCVΔTΔT = ΔQ/nCV

= (8360/4.18) / (47*3.2)

= 13.3K.



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