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1.

In Hershey – Chase experiment, the DNA of T phase was made radioactive by using ___________ (a) 32P (b) 32S (c) 35P (d) 32S

Answer»

Correct Answer is : (a) 32P

2.

Whose experiment finally provided convincing evidence that DNA is the genetic material? (a) Griffith experiment (b) Avery, Macleod and McCarty’s experiment (c) Hershey-Chase experiment (d) Urey-Miller’s experiment

Answer»

(c) Hershey-Chase experiment

3.

Explain the properties of DNA that makes it an ideal genetic material.

Answer»

1. Self Replication: It should be able to replicate. According to the rule of base pairing and complementarity, both nucleic acids (DNA and RNA) have the ability to direct duplications. Proteins fail to fulfill this criteria.

2. Stability: It should he stable structurally and chemically. The genetic material should be stable enough not to change with different stages of life cycle, age or with change in physiology of the organism. Stability as one of property of genetic material was clearly evident in Griffith’s transforming principle. Heat which killed the bacteria did not destroy some of the properties of genetic material. In DNA the two strands being complementary.

if separated (denatured) by heating can come together (renaturation) when appropriate condition is provided. Further 2’ OH group present at every nucleotide in RNA is a reactive group that makes RNA liable and easily degradable. RNA is also known to be catalytic and reactive. Hence, DNA is chemically more stable and chemically less reactive when compared to RNA. Presence of thymine instead of uracil in DNA confers additional stability to DNA.

3. Information storage: It should be able to express itself in the form of ‘Mendelian characters’. RNA can directly code for protein synthesis and can easily express the characters. DNA, however depends on RNA for synthesis of proteins. Both DNA and RNA can act as a genetic material, but DNA being more stable stores the genetic information and RNA transfers the genetic information.

4. Variation through mutation: It should be able to mutate. Both DNA and RNA are able to mutate. RNA being unstable, mutates at a faster rate. Thus viruses having RNA genome with shorter life span can mutate and evolve faster. The above discussion indicates that both RNA and DNA can function as a genetic material. DNA is more stable, and is preferred for storage of genetic information.

4.

What are the properties that a molecule must possess to act as genetic material?

Answer»

1. Self replication 

2. Information storage 

3. Stability 

4. Variation through mutation

5.

Assertion (A) : Genophore is noticed in prokaryotes. Reason (R) : Bacteria possess circular DNA without chromatin organisation. (a) Both A and R are correct (b) A is correct R is incorrect (c) R explains A (d) A is incorrect R is correct

Answer»

(c) R explains A

6.

Retroviruses possess ________ as genetic material.

Answer»

Correct Answer is : RNA

7.

What is capping and tailing?

Answer»

In capping an unusual nucleotide, methyl guanosine triphosphate is added at the 5’ end of hnRNA, whereas adenylate residues (200- 300) (Poly A) are added at the 3’ end in tailing.

8.

If the length of E. coli DNA is 1.36 mm, the number of base pairs is ___________(a) 0.36 × 106 m (b) 4 × 106 m (c) 0.34 × 10-9 nm (d) 4 × 10-9 m

Answer»

(b) 4 × 106m

9.

In E.coli, three enzymes 0- galactosidase, permease and transacetylase are produced in the presence of lactose. Explain why the enzymes are not synthesized in the absence of lactose.

Answer»

In the absence of lactose, the repressor protein binds to the operator and prevents the transcription of structural gene by RNA polymerase, hence the enzymes are not produced. However, there will always be a minimal level of lac operon expression even in absence of lactose.

10.

Semi-conservative model of replication was proved by __________ (a) Hershey and Chase (b) Griffith (c) Meselson and Stahl (d) Macleod and McCarty

Answer»

(c) Meselson and Stahl

11.

Meselson and Stahl’s experiment proved _______ (a) Transduction (b) Transformation(c) DNA is the genetic material (d) Semi-conservative nature of DNA replication

Answer»

(d) Semi-conservative nature of DNA replication

12.

What is TATA box? State its function.

Answer»

In eukaryotes, the promoter has AT rich regions called TATA box or Goldberg-Hogness box. It acts as a binding site for RNA polymerase.

13.

Which of the following statements about DNA replication is not correct? (a) Unwinding of DNA molecule occurs as hydrogen bonds break (b) Replication occurs as each base is paired with another exactly like it (c) Process is known as semi – conservative replication because one old strand is conserved in the new molecule (d) Complementary base pairs are held together with hydrogen bonds

Answer»

(b) Replication occurs as each base is paired with another exactly like it

14.

The first codon to be deciphered was which codes for (a) AAA, proline (b) GGG, alanine (c) UUU, Phenylalanine (d) TTT, arginine

Answer»

(c) UUU, Phenylalanine

15.

Structural gene of eukaryotes differ from prokaryotes. How?

Answer»

In eukaryotes, the structural gene is monocistronic coding for only one protein whereas in prokaryotes the structural gene is polycistronic coding for many proteins.

16.

Which of the following statements is not true about DNA replication in eukaryotes? (a)) Replication begins at a single origin of replication. (b) Replication is bidirectional from the origins. (c) Replication occurs at about 1 million base pairs per minute. (d) There are numerous different bacterial chromosomes, with replication occurring in each at the same time.

Answer»

(d) There are numerous different bacterial chromosomes, with replication occurring in each at the same time.

d)There are numerous different bacterial chromosomes, with replication ocurring in each at the same time.

17.

What are non-sense codons?

Answer»

UGA, UAA and UAG are the non-sense codons, which terminates translation.

18.

Differentiate – Leading strand and lagging strand

Answer»

1. DNA polymerase I Involved DNA repair mechanism 

2. DNA polymerase II Involved DNA repair mechanism 

3. DNA polymerase III Involved in DNA replicaton

19.

Give reasons: Genetic code is ‘universal’.

Answer»

The genetic code is universal. It means that all known living systems use nucleic acids and the same three base codons (triplet codon) direct the synthesis of protein from amino acids. 

For example, the mRNA (UUU) codon codes for phenylalanine in all cells of all organisms. Some exceptions are reported in prokaryotic, mitochondrial and chloroplast genomes. However similarities are more common than differences.

20.

_______ number of codons, codes for cystine.

Answer»

Two number of codons, codes for cystine.

21.

Point out the exceptional categories to universality of genetic code.

Answer»

Exceptions to universal nature of genetic code is noticed in prokaryotic mitochondrial and chloroplast genomes.

22.

One of the aspect is not a feature of genetic code? (a) Specific (b) Degenerate (c) Universal (d) Ambiguous

Answer»

(d) Ambiguous

23.

Which of the triplet codon is not a code of proline? (i) CCU (ii) CAU (iii) CCG (iv) CAA (a) i only (b) ii and iv (c) iii only (d) all the above

Answer»

Correct Answer is : (b) ii and iv

24.

Degeneracy of codon – comment.

Answer»

A degenerate code means that more than one triplet codon could code for a specific amino acid. For example, codons GUU, GUC, GUA and GUG code for valine.

25.

Identify the triplet pairs that code for Tyrosine (a) UUU,UUC (b) UAU, UAU (c) UGC, UGU (d) CAU, CAC

Answer»

Correct Answer is : (b) UAU, UAU

26.

In sickle cell anaemia, the __________ codon of β – globin gene is modified. (a) Eighth (b) Seventh (c) Sixth (d) Nineth

Answer»

Correct Answer is: (c) Sixth

27.

State the role of following codons in translation process 1. AUG 2. UAA

Answer»

1. AUG is the initiator codon and also codes for methionine. 

2. UAA is a terminator codon.

28.

Define translation unit.

Answer»

A translation unit in mRNA is the sequence of RNA that is flanked by the start codon on 5’ end and stop codon on 3’ end and codes of polypeptide.

29.

Mention the inhibitory role of tetracycline and streptomycin in bacterial translation.

Answer»

Tetracycline inhibits binding between aminoacyl tRNA and mRNA.Streptomycin inhibits initiation of translation and causes misreading.

30.

Mention the dual functions of AUG.

Answer»

AUG has dual functions. It acts as a initiator codon and also codes for the amino acid methionine.

31.

Distinguish between exons and introns.

Answer»

1. Exons: Expressed sequences (Coding sequences) of an eukaryotic gene 

2. Introns: Interveining sequences (noncoding sequences) of an eukaryotic gene

32.

What are the two major components of prokaryotic RNA polymerase? How do they act?

Answer»

Bacterial (prokaryotic) RNA polymerase consists of two major components, the core enzyme and the sigma subunit. The core enzyme (β1, β, and α) is responsible for RNA synthesis ” whereas a sigma subunit is responsible for recognition of the promoter.

33.

Name the various types of prokaryotic DNA polymerase. State their role in replication process.

Answer»

1. DNA Polymerase I Involver in DNA repair mechanism 

2. DNA Polymerase II Involver in DNA repair mechanism 

3. DNA Polymerase III Involver in DNA replication

34.

What is S – D sequence?

Answer»

The 5’ end of the mRNA of prokaryotes has a special sequence which precedes the initial AUG start codon of mRNA. This ribosome binding site is called the Shine – Dalgamo sequence or S-D sequence. This sequences base-pairs with a region of the 16Sr RNA of the small ribosomal subunit facilitating initiation.

35.

Whqt is nucleosome? How many base pairs are there in a typical nucleosome?

Answer»

The negatively charged DNA is wrapped around the positively charged histone octamere to form a structure called nucleosome. A typical nucleosome contains 200 bp of DNA helix.

36.

What are UTR’s?

Answer»

mRNA also have some additional sequences that are not translated and are referred to as Untranslated Regions (UTR). UTRs are present at both 5’ end (before start codon) and at 3’ end (after stop codon).

37.

State Chargaff’s rule.

Answer»

According to Erwin Chargaff, 

1. Adenine pairs with Thymine with two hydrogen bonds. 

2. Guanine pairs with Cytosine with three hydrogen bonds.

38.

Pick out the incorrect statement. (a) tRNA acts as a adapter molecule (b) Stop codons donot have tRNA’s (c) Addition of aminoacid leads to hydrolysis of tRNA (d) tRNA has four major loops

Answer»

(c) Addition of aminoacid leads to hydrolysis of tRNA

39.

Explain the formation of a nucleosome.

Answer»

Komberg proposed a model for the nucleosome, in which 2 molecules of the four histone proteins H2A, H2B, H3 and H4 are organized to form a unit of eight molecules called histone octamere.

The negatively charged DNA is wrapped around the positively charged histone octamere to form a structure called nucleosome. A typical nucleosome contains 200 bp of DNA helix. The histone octameres are in close contact and DNA is coiled on the outside of nucleosome.

40.

What do you mean by charging of tRNA? Name the enzyme involved in this process.

Answer»

The process of addition of amino acid to tRNA is known as aminoacylation or charging and the resultant product is called aminoacyl- tRNA (charged tRNA). Aminoacylation is catalyzed by an enzyme aminoacyl – tRNA synthetase.

41.

It is established that RNA is the first genetic material. Justify giving reasons.

Answer»

Three molecular biologists in the early 1980’s (Leslie Orgel, Francis Brick and Carl Woese) independently proposed the ‘RNA world’ as the first stage in the evolution of life, a stage when RNA catalysed all molecules necessary for survival and replication. The term ‘RNA world’ first used by Walter Gilbert in 1986, hypothesizes RNA as the first genetic on Earth. There is now enough evidence to suggest that essential life processes (such as metabolism, translation and splicing etc.,) evolved around RNA. RNA has the ability to act as both genetic material and catalyst. There are several biochemical reactions in living systems that are catalysed by RNA. This catalytic RNA is known as ribozyme. But, RNA being a catalyst was reactive and hence unstable.

This led to evolution of a more stable form of DNA, with certain chemical modifications. Since DNA is a double stranded molecule having complementary strand, it has resisted changes by evolving a process of repair. Some RNA molecules function as gene regulators by binding to DNA and affect gene expression.

Some viruses use RNA as the genetic material. Andrew Fire and Craig Mellow (recipients of Nobel Prize in 2006) were of the opinion that RNA is an active ingredient in the chemistry of life.

42.

Why tRNA is called an adapter molecule?

Answer»

The transfer RNA, (tRNA) molecule of a cell acts as a vehicle that picks up the amino acids scattered through the cytoplasm and also reads specific codes of mRNA molecules. Hence it is called an adapter molecule. This term was postulated by Francis Crick.

43.

Chemically DNA is more stable than RNA – Justify.

Answer»

In DNA, the two strands being complementary, if separated (denatured) by heating can come together (renaturation) when appropriate condition is provided. Further 2 OH group present at every nucleotide in RNA is a reactive group that makes RNA liable and easily degradable. RNA is also known to be catalytic and reactive. Hence, DNA is chemically more stable and chemically less reactive when compared to RNA. Presence of thymine instead of uracil in DNA confers additional stability to DNA.

44.

DNA and RNA are similar with respect to (a) Thymine as a nitrogen base (b) A single-stranded helix shape (c) Nucleotide containing sugars, nitrogen bases and phosphates (d) The same sequence of nucleotides for the amino acid phenyl alanine

Answer»

(c) Nucleotide containing sugars, nitrogen bases and phosphates

45.

What are the three structural differences between RNA and DNA?

Answer»

DNA: 

1. Sugar is deoxyribose sugar. 

2. Double stranded structure. 

3. Nitrogen bases are Adenine, Guanine, Cytosine and Thymine.

RNA: 

1. Sugar is ribose sugar. 

2. Single stranded molecule. 

3. Nitrogen bases are Adenine, Guanine, Cytosine and Uracil

46.

Anoperonisa: (a) Protein that suppresses gene expression (b) Protein that accelerates gene expression (c) Cluster of structural genes with related function (d) Gene that switched other genes on or off

Answer»

(d) Gene that switched other genes on or off

47.

Ribosomes are composed of two subunits; the smaller subunit of a ribosome has a binding site for and the larger subunit has two binding sites for two

Answer»

mRNA,  tRNA.

48.

Differentiate between Heterochromatin and Euchromatin.

Answer»

Heterochromatin: 

1. Region of nucleus where the chromatin are loosely packed and stains light are called Heterochromatin. 

2. Transcriptionally inactive.

Euchromatin: 

1. Region of nucleus where the chromatin are tightly packed and stains dark are called Euchromatin. 

2. Transcriptionally active.

49.

Differentiate leading strand from lagging strand

Answer»

Leading strand: 

1. Leading strand has the polarity 3’ → 5’. 

2. Replication is continuous. 

Lagging strand: 

1. Lagging strand has the polarity 5’ → 3’.

2. Replication is discontinuous.

50.

Explain the nature of eukaryotic ribosome.

Answer»

The ribosomes of eukaryotes (80 S) are larger, consisting of 60 S and 40 S sub units. ‘S’ denotes the sedimentation efficient which is expressed as Svedberg unit (S). The larger subunit in eukaryotes consist of a 23 S RNA and 5Sr RNA molecule and 31 ribosomal proteins. The smaller eukaryotic subunit consist of 18Sr RNA component and about 33 proteins.